0 like 0 dislike
2.4k views

You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數),計算其總合。C語言不提供大數資料型態,但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2.4k views

4 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

char input[500],s1[500],s2[500],temp;

int i,space,sum[500],carry,temp2,flag=0;

int main(){
* ** * ** ** ** *** ** %s",&s1,&s2);
* * ****** *** ** * **** ** * ***

///get space
*** **** ** ***** ** ** * **** ** * * ** ***
** ******* * ** *** *** * **** * * ***** * '){space=i;}
    }

///get s1
** ***** * **** * * *** * * * ';i++){
* ** * ** ** * *** * ** ** * ********** **
    }

* * ** * ** * * * * * * * * *
///reverse input
**** ** * *** ** ** **** *** * ******* * *****
* ** * * * ** * ** ***** ***** * * ** ** * *
* * * * ** ** *** *** ** * * ** ** * ****** * ** ** ** * *
** **** ** ** ** * * ** * * *** ***** ** ** * *** * ****** *
    }

///get reversed s2
*** ** *** ** ****** ** * * ';i++){
* *** * * * * * * * * * ***** *** **** *** *** **
    }

///reverse s1

* **** * * ***** * ** ** ** * ***** *
*** * ** * **** * * ** ** **** * * * **

* ** * ** * * * *** ** * * * **** * ***** ** * ***
******* ** ** * * ** ** ** * *** ** *** * **** * *** ****
    }

///sum s1 and s2
* * * *** **** * **** * * ** **
*** *** * * * * * * ****** **** * *** * * **
* ** * *** * ******* * ** *** * * ** * **** ***
** * ** **** ** ** *** *** *** * * **** ** ** ** *** *** **
* * ** *** ** **** ** ***** * ** * ** * ** * * * *** *
****** * ****** * ** * * ** ******* * **** * *
**** *** *** * **** ***** * * ** * * * ** **

    }

* * * ** * * * **** * ** * rev:%s\n",input);
**** ** ***** ***** * ****** * *** rev:%s\n",s1);
** * * ** ** * ** ** ** * rev:%s\n",s2);
***** *** * ** **** * **** * * ** * * *** * * ** **** ** * * * * ** **

///reverse output
*** * * * * * ** *** * ** ** **
* ** * * * *** * * * ** ** ** ***** ** **

* * * *** *** * * ** ** * *** ** * * **** ***********
*** ** * ** * ** ** ** ** * * * * *** * * *
    }

///print
* * ***** ** * * ** * * **** **
** * ** ** * ***** * ** **** ***** *** **** *** **** * ** ***** * *** *
** *** * ** * * * * * * * ***** ** *** ** ** **** *********** **** **** ** ** ***
* * ****** * * * *** * **** *** ** * * *** * * * * ** * * ***** * ** * **** * * ** *** *** * ** ** ***** ***
* ** ** * ** ** ** * *** ** ****** ** ** * **** ** ** * ** ****** ** * ****** ***** **
*** **** ** * **** *** * * * **** * ** ** ** * * ** ** **** * * * *

* * * ** * ** *** **** * **** **** **** ****

    }
***** * *** **** ***** * ** *****
    return 0;
}
answered by (-286 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
prog.c: In function 'main':
prog.c:80:12: warning: multi-character character constant [-Wmultichar]
     printf('10');
            ^~~~
prog.c:80:12: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:80:5: warning: format not a string literal and no format arguments [-Wformat-security]
     printf('10');
     ^~~~~~
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* * ******* * **** string1[50];
* ***** * *** *** ** string2[50];

* ***** ** *** * * * * *** * * *** * ** string1);
** * ** ** *** * ** * * * string2);
* * * * * ** * **** arr[51]={0},i;

* ****** * ** *** ** * * i<strlen(string1); i++)
** * **** * * * ******* *
*** * * **** * * * *** * ** * * ** ** *** += string1[strlen(string1) - 1 - i] - 48;
    }

* * *** ** * * * ***** i<strlen(string2); i++)
* ** ** **** ** **
* ****** ** * * * * *** * ** *** * * * * * ** += string2[strlen(string2) - 1 - i] - 48;
****** * ** * * **

* *** ** ** ** * ** ** i<50; i++)
** * * *** * *** ***
** *** * *** * * ** * ** ** * ** * ** * * * > 9)
*** *** * * ** *** **** * * * ***
* * * * * ********* ***** *** ** * * **** * * * * * * * ********* ** -= 10;
*** * * * ** * ** * **** ** *** * ** ** *** * * ** *** * * *
* ** * * * * * ** * **** * ** ** **** ***
* ** * **** * *

* * * * *** * ** * * * i>=0; i--)
**** * * **** * * * *** *
*** *** *** *** **** * ** * *** ** ** ** * != 0)
** ** * **** ** * **** * * **** * ** *** * * ****** ******* ***** * **
* * * ** * **

** * * * * * * ** **** ** *** * i--)
** *** ** * *** ** * ** **** *** * * **** * ** * ** *** *** ** arr[i]);
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main (){
int s1,s2,l1,l2;
int num1[50],num2[50],sum[50];
printf("enter input 1: ");
* **** * ** ******
printf("enter input 2: ");
* * * * *** * *** *
for(l1=s1[l1]!='\0')
* * ** * *** ** **
for(l2=s2[l2]!='\0')
*** * ** ** * * *** * ** ****
int carry=0;
int k=0;
int i=l1-1;
int j=l2-1;
* ** ** * * ** * * ***
{
* * * ** * * **** ** * * * ** **
****** **** * ** * * * *
* ** * * * * ** * * * * ** *** * * * ***** *** *
*** ** *** * ** ** **** ** * *** * *** ** **** **** ** ***** ***** *** ** ** **
* * * * *** ***** * * * * * ** *** ** * * ***** *** ** **** ** **** ** ** ***** ******
* * ****** ** ** * ** if (j>=0)
* *** * ** ****** ***** ** * * * *
** ** * * * * ** **** * **** ** ** ** * ***** ** * *** ** * * *** ** **** ** **
**** ** * ** * * * * ** * ** *** * ** ******* * *** **** * *** ***** * * * ** *
* *** ** *** ** * * * * * * * ** * * * * ** ** *** if(carr>0)
* ******** * * * *** * * ******* * * **
* ** ** **** ***** *** ** ****** ** ** ** *** ** * * ");
** * * * * ** * * * * * * *** * * *
}
for(k--;k>=0;k--)
* *** *** * * **
* * ** ****** *** ** * * *** * * * **** * *
* * ** * *** ** * ** *
  return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:9:10: error: subscripted value is neither array nor pointer nor vector
 for(l1=s1[l1]!='\0')
          ^
prog.c:9:20: error: expected ';' before ')' token
 for(l1=s1[l1]!='\0')
                    ^
prog.c:9:20: error: expected expression before ')' token
prog.c:10:10: error: subscripted value is neither array nor pointer nor vector
   num1=s1[l1]-'0';
          ^
prog.c:11:10: error: subscripted value is neither array nor pointer nor vector
 for(l2=s2[l2]!='\0')
          ^
prog.c:11:20: error: expected ';' before ')' token
 for(l2=s2[l2]!='\0')
                    ^
prog.c:11:20: error: expected expression before ')' token
prog.c:12:12: error: subscripted value is neither array nor pointer nor vector
     num2=s2[l2]-'0';
            ^
prog.c:17:15: error: expected ')' before ';' token
 for(;i>=0;j>=0;i--;j--;k++)
               ^
prog.c:23:13: error: expected ';' before 'carry'
             carry=(num1[i--]+num2[j]+carry)/10;
             ^~~~~
prog.c:27:13: error: expected ';' before 'carry'
             carry=(num1[j--]+num2[j]+carry)/10;
             ^~~~~
prog.c:28:18: error: 'carr' undeclared (first use in this function)
         }else if(carr>0)
                  ^~~~
prog.c:28:18: note: each undeclared identifier is reported only once for each function it appears in
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>


int main()
{
* * ** *** ** * ** * * ***** a[50],b[50];
** * ** ** ** *** *** ** c[51]={0};
** * *** * * * * ***** i;
** ** * ***** * *** * x=0;

* ******* * * * * * * * * * %s",a,b);

* * * * * * ** ** **** ** ** **** **
    {
** *** *** ** ** ***** * ** * * ***** * ** * * **** *
    }

*** * *** * ** * ** * * * *** * * *
* ** * ** ** * * * *
* ***** * ** * ** * ** * ** ******* * * * * * ** *** *
** * * * * ** ** * *


** * ** * * * ** * ** * **** ** * * *
***** ** * ** * * **
* * ** ** * * * ** ***** * * * ***** * * ***** **
* *** * * **** * ** ** * ** **** *****
** * * * * *** * * * ****** * * **** ********* *** ****** *** *** ***
* * ** * * **** ** * *** * * ** * * ** * ** * * ** **** * * * * *
* * **** **** * ** ** ** ******** *** ***
    }

* * * **** * ** *** *** ** * * *
* ********** *** * ** *
* * * ***** ** ****** * * * * *** * * * * *** != 0)
** * ** * * * * **** *** * ** ** **** *** **
* ** ** ** ** ****** * ******* * * ** ** * * * * ** * * * * * ***** *
**** * ** ** * * **** * ******* ****** ***** * ** ** ** ** *** * * * *
* ** * * * ** *** ** * ** *** ****** * * *
    }

* * ** *** ** * ** * * *** * * **** **
    {
*** * ** *** * ** * * ** * * * * * * *** * ** * * * * * ** * * *
    }


* *** * * * * * ** ** ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.241
©2016-2025

Related questions

0 like 0 dislike
13 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43463 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 3.9k views
0 like 0 dislike
6 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43462 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2k views
0 like 0 dislike
8 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43461 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2.4k views
0 like 0 dislike
12 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43459 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 4k views
1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 11.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users