0 like 0 dislike
474 views

You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數),計算其總合。C語言不提供大數資料型態,但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 474 views

4 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

char input[500],s1[500],s2[500],temp;

int i,space,sum[500],carry,temp2,flag=0;

int main(){
** ** * **** ** * ** ** %s",&s1,&s2);
*** * *** * ** ****** * * *

///get space
**** ** * * **** * * * * ** ** * * * *
** * *** ** ** *** * * ** * *** * ******* ** ** ** '){space=i;}
    }

///get s1
*** **** *** ** * * *** * * * *** ';i++){
** * * * * * * *** ** *** ** * ** * *** ***
    }

*** ** ** * * *** * * **** *
///reverse input
** * **** * ** ** ** * * *** * * ** * * **
*** * **** ** * ** ** *** ** * * * * * ** * * * * ** *
**** * ** * * *** ** * * * * * ** ** ** * ** * * ****
** * * ** * * * * **** * * * * ** ** **** * ** ** *
    }

///get reversed s2
* ****** ** **** * ** ** *** ****** * ';i++){
* *** * ** ** ** * * ** **** **** * ** * ***
    }

///reverse s1

* * ** ****** ** * * ** * ** * **
* ** ******* ** ***** * * * * ** * ***** *** * * *

* * * * *** ** * * * * **** ** * ** **** * *** ** * * **** * *
*** * *** * * * ** * ** *** * ***** * * * *** ** * ** **
    }

///sum s1 and s2
** * * *** *** **** ***
* * * * *** ** ** ***** * * * *
** ** ** * ** ** ****** ****** * * *** ***** ** **** ***
* ** ** *** * * **** *** ** * ** **** * **** *** *** * *** * **
* * *** * * ***** **** ** * **** * * * * * *** ***
***** * * * * * **** * * ** ** *********** **** *
* *** **** *** * ******** * *** ** * * **** *** * ******* **

    }

* * * ** *** * * * ** ** * * * ***** * * ** rev:%s\n",input);
* * * *** **** *** **** ** * ** * rev:%s\n",s1);
***** * * *** ** ** * ** *** *** * rev:%s\n",s2);
***** ** * ** ** ** * ** * * ***** **** ** * *** ** ** * *

///reverse output
** * ** * ** * * **** * ** * ***
** * * * **** ****** ** * * ** * * ** * * ** ****** ***

* ** **** *** * ** ** * * **** * * * *
* * * * * ** * * * * * *** ** *** * * * *
    }

///print
* * *** * * * *** * * * *
* * ** * *** ** * * ** ** *** * * * ******** ** * * * *** * *** ***
* ** ******* * **** * *** * *** * ** ** * ****** * * * * * ** ** * * ***
* *** ** ** * *** * **** ***** ** ****** *** *** ** * * * * * ***** * * * * ** *** * ***** * *** *
***** * **** ** * * * *** ** * **** ** ** **** * * * ** * * * ***** **** **** *
**** ** * ***** ** * * ** * * * * * * * * * **** ***** *** *

* * * ** ** * * * *** ** * ** **

    }
* *** ** * *** **** ** *** * * ***** ** *** *
    return 0;
}
answered by (-286 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
prog.c: In function 'main':
prog.c:80:12: warning: multi-character character constant [-Wmultichar]
     printf('10');
            ^~~~
prog.c:80:12: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:80:5: warning: format not a string literal and no format arguments [-Wformat-security]
     printf('10');
     ^~~~~~
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
**** ** * * *** ******* * ** string1[50];
******** * * ****** * ** string2[50];

** * * ***** * ** * ** * * ** string1);
** *** *** **** * ***** ** * * string2);
* **** * * ***** * ** arr[51]={0},i;

***** * * ** **** * ** i<strlen(string1); i++)
**** *** ** * * *** *
* * ** * * * * * ** *** * * ** * += string1[strlen(string1) - 1 - i] - 48;
    }

* *** ** ****** * * ** * i<strlen(string2); i++)
* ** * ** * ** **
* ** **** ** ** * ********* * ** * ** * *** += string2[strlen(string2) - 1 - i] - 48;
** ***** **** * ***

* ** *** * ** *** * *** ** i<50; i++)
* *** * ** ** * ** **
**** **** * ** **** * ** * * *** *** **** * **** * > 9)
** * * ** * ** *** ** ** * ** * * *** **** *
** * * **** * * **** * ** * * * * * ** *** ** * -= 10;
* * * ** ** * *** * * **** ** * * * *** *** ** ** ****** * ** * * **
*** * * ** * *** * ** ** * ** * * * * ** ** *
*** * * * ** * * *** *

* * *** ** **** * ** ** i>=0; i--)
* **** ** *****
* * * * * ** ** ** * *** ** * ** * ** * *** ** ** * * != 0)
**** ** * ** * * ** ******* * ** * ***** **** * ********* **** ** *** ** * ****
* ***** * * **

**** *** ** * * *** * * i--)
** * ****** * * * * ** *** *** *** ** * ****** * arr[i]);
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main (){
int s1,s2,l1,l2;
int num1[50],num2[50],sum[50];
printf("enter input 1: ");
****** ** **** * * * **** **
printf("enter input 2: ");
*** *** * * ** * * * ** *
for(l1=s1[l1]!='\0')
***** **** ****** * *
for(l2=s2[l2]!='\0')
*** * *** ** ** * * ** * *
int carry=0;
int k=0;
int i=l1-1;
int j=l2-1;
*** * * * * * * * ***
{
*** *** * ** * ** **
* * * **** ***** ** *
**** * * * **** * * * * *** *** ** * * ****** *** * * *
* * * ** ** * ** ** * * *** * * ** * * *** * ** ** * *** * *** * * * **
* * * *** * * *** *** * ** ******* * *** **** * * * * * * ****** **** * * *
* * * * * *** * ******* if (j>=0)
** ****** ** * ****** ** ***** * *** ***
*** ** * * * * ****** **** ** ** ** * * * * *** *** * * *** ***** * * * * * * **
* * ** * * * * * ** *** * ** * *** * ** * * ******* *** ** * * * * ** * ** * * *** * *
*** *** * ** * ** * ** *** * *** * ** * * *** if(carr>0)
***** **** * *** **** *** ** ** * *** * ** **
* ****** **** * * **** ** *** *** *** ** *** *** ");
* *** * ** **** * * * * ** * * * **
}
for(k--;k>=0;k--)
* **** ***** ** * ***
** *** * ** * ** ** * * * ** ** ****** * *
* * * ******* * ** * * *
  return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:9:10: error: subscripted value is neither array nor pointer nor vector
 for(l1=s1[l1]!='\0')
          ^
prog.c:9:20: error: expected ';' before ')' token
 for(l1=s1[l1]!='\0')
                    ^
prog.c:9:20: error: expected expression before ')' token
prog.c:10:10: error: subscripted value is neither array nor pointer nor vector
   num1=s1[l1]-'0';
          ^
prog.c:11:10: error: subscripted value is neither array nor pointer nor vector
 for(l2=s2[l2]!='\0')
          ^
prog.c:11:20: error: expected ';' before ')' token
 for(l2=s2[l2]!='\0')
                    ^
prog.c:11:20: error: expected expression before ')' token
prog.c:12:12: error: subscripted value is neither array nor pointer nor vector
     num2=s2[l2]-'0';
            ^
prog.c:17:15: error: expected ')' before ';' token
 for(;i>=0;j>=0;i--;j--;k++)
               ^
prog.c:23:13: error: expected ';' before 'carry'
             carry=(num1[i--]+num2[j]+carry)/10;
             ^~~~~
prog.c:27:13: error: expected ';' before 'carry'
             carry=(num1[j--]+num2[j]+carry)/10;
             ^~~~~
prog.c:28:18: error: 'carr' undeclared (first use in this function)
         }else if(carr>0)
                  ^~~~
prog.c:28:18: note: each undeclared identifier is reported only once for each function it appears in
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>


int main()
{
* * **** * * ** **** *** * a[50],b[50];
***** ** * * ** * ***** * c[51]={0};
* * * * *** * * * ** * * i;
* * * ** * ** * x=0;

* *** ** * ** ** *** * * *** %s",a,b);

* ** ** * * **** * ** ** * *
    {
* ** *** * * ** * * *** * ****** * ** * * * **
    }

* * **** * * * * * * * * * * * *** **
**** *** ***** * *
* * * * * * ***** ** * ** ** ** ** * ** *****
* ** *** ** ****** *****


** *** * ***** * ** ** * *** ***
* *** * ** *
**** * ********** *** * * ** ** *** * * *** * * *
* * * *** ******* *** ** **** ** ** **** ****
** * ***** * * * * * *** * * * ** * ** * ** *** * ** * * *** ** ****
*** ** *** * ** ** * *** * ** * **** * **** ** * ** * * ** ** *
* ** * ****** * * * ** * * ** ** * * ** ***
    }

* * ** **** * ** ** * * * * *
* ** * * ***** * ** *
* ****** * ** ** **** ** * * ** * ******** ** != 0)
*** ** **** **** **** * * * ** ** *** * *** ** **
* **** *** ** * * ** *** * *** ** ***** ** * * * ** * *
* * *** ** * ***** ** **** * * * * ***** ** **** * * ***** * * * * *
** ** ** * **** *** *** *** * * * **** * *
    }

* * * *** * ** **** ****** ****** ***
    {
* * ** ** * *** * *** * * * **** * * ** * ** ** * ** *
    }


* ** * ** *** * *** ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.49
©2016-2024

Related questions

0 like 0 dislike
13 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43463 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 748 views
0 like 0 dislike
6 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43462 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 391 views
0 like 0 dislike
8 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43461 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 463 views
0 like 0 dislike
12 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43459 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 882 views
1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 2.5k views
12,783 questions
183,443 answers
172,219 comments
4,824 users