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Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

[Exercise] Coding (C) - asked in Chapter 3: Branching, Looping and Functions by (5.9k points)
ID: 30241 - Available when: Unlimited - Due to: Unlimited
| 7.1k views

24 Answers

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Hidden content!
* * * **** * **
*** * *** * ** * **
int main(){
int i;
* * * * char a;
**** ** * * * ** * * ** your input: * ****
** * * * * * **** ** ** *** * * ** * *
** * * * * **
* **** ** ** ** * * *** **** ** * * * *
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* **** * * ** * ** ** ** ** }
* * * ***** ** * * *** }
* ** ** * * }
}

//INPUT
//Enter your input: A

**
//Enter your input: A
* * ** * ** ****
50/100 answered by (271 points)
0 0
Case 0: Wrong output
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Hidden content!
** *** ***
** * * * ** ******* **

/* run this * * * the *** *** or add your own *** ** * * ** ** or * loop */

int * * * * {
** * * * * * a; * * * *** * * * *** * *** * * * ** *** **** ** * * **** ** * * ** * * * *** ** * * * *** ** *
* * *** *** **** * your ** * *
* **** * * * * ** * ** ** *** *
* * ** *
* ** * * *** for (a == 'A'; a ** *** *

** * ** * *
*** * * * *** ** * if (a == ** a == 'E' || a == 'I' || a == 'O' || a == ****
* * *** ** * * * * *** ** *
***
**** * **** ** * ** ** ** * * * * * ***
* **** *** ***
}
*** ** * * ** ****
* * * * 0;
}
100/100 answered by (252 points)
0 0
Case 0: Wrong output
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Hidden content!
#include ** * *
#include ** * * *

int main(int argc, char *argv[]) {
    char a; ** ** * * * * **** * ** ** * ***** **** ***** ** *** ** ** *** * * * ***** * ** * ** * * * * **** * can be changed
* *   **** **** * your * * ** //DO NOT CHANGE
* ***   ** * *** *** ** * * *
   
** ** * * ***** ** *** ***** ** *
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*** **** * **** * * **
   
    return 0;
}
100/100 answered by (268 points)
0 1
Case 0: Correct output
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Hidden content!
#include ** * * **
#include * * *******

int main(int argc, char *argv[]) {
* ** * * * char a;
** * ** ** *** * *** * your **** ** *
*** **** * ** * * ** ***** **
**** ** ******
* ** * ** **** * * *****
* * * * * **** * *** * * if * ** * * * * **** **
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* ** ** * * ** * * }else
* * * ** *** * *** ** * ** a);
* * * }
** * ** **
* ** ** return 0;
}
answered by (5.9k points)
0 1
Case 0: Correct output
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