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Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

[Exercise] Coding (C) - asked in Chapter 3: Branching, Looping and Functions by (5.9k points)
ID: 30241 - Available when: Unlimited - Due to: Unlimited
| 5.4k views

24 Answers

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Hidden content!
*** * ****** *
* * *** * * * * ****
int main(){
int i;
* * * ** char a;
* ** * * * * *** * * ** ** your input: * ** *
* ** ** **** * * * ** ** * * *** ** ***
** * *** ** * *** *
* ** * * ** * * ****** * **** * ** * ***
** * * *** * * * *** ** ** * if(i==65 ||i==69 || i==73 || i==79 *** *
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* ** *** * * ****** * ** ** ** ** * }
* * *** ****** * **** * ** * ***** else{
** * *** ** * * ***** * ** ** * * ***** * * ** * **** * **
*** * *** * * ** ** * ** * }
** * * **** ** * *** * }
* *** * }
}

//INPUT
//Enter your input: A

* **
//Enter your input: A
***** *** * ** **
50/100 answered by (271 points)
0 0
Case 0: Wrong output
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Hidden content!
* * * *** *
***** *** **** ** *** *

/* run this * **** the ** ** * or add your own * ** * * * ** * * * or * loop */

int *** * * * **** {
* * ** ** * a; ******** * ** ** *** * ** ** * * ** ** * *** *** * * *** **** ** ** * * * ** * ** * *** *** ** * **** ***
***** ** * *** * * * your * * *
*** * * *** ** ****** ***** *
** *** * ** *
* ** * ** * for (a == 'A'; a * * *

**** * * * * * **
* ** * ** **** * if (a == * a == 'E' || a == 'I' || a == 'O' || a == *
** * * * ** ** * * * * * **** *** *
*
* *** * * ** * * ** * ** ** *** ** * ** * *
* * ***
}
* ** **** * ****
* * ** ** * 0;
}
100/100 answered by (252 points)
0 0
Case 0: Wrong output
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Hidden content!
#include **** ** * *
#include ** * ** *

int main(int argc, char *argv[]) {
    char a; * ****** ** *** ***** *** **** * *** * * * * ** ***** ** * *** * ** * ** * ** *** *** ** * ** ** * * **** can be changed
* ***   * ** * ** * your **** * ** //DO NOT CHANGE
** **   ** ** * * * ******* *
   
* ***** ** * * * **** *** * ** *
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** *** ** * ** *
   
    return 0;
}
100/100 answered by (268 points)
0 1
Case 0: Correct output
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Hidden content!
#include ** * ** * ** *
#include * * * * *

int main(int argc, char *argv[]) {
* * char a;
* * * * ** * *** * ** your ***** *
* * * ** ** *** * * * ***
* * ** ** **
* *** * *** *** * * *
* * ** * ** ****** if * * ***** * *** * *
* ** *** *** * *** *** **** *** * * * * * **** ** * * **
*** *** * * * ** * ** * * }else
* ******* ** ** ** * ***** * ** *** * ** a);
** * ** }
* ** * * *****
** ** ** * return 0;
}
answered by (5.9k points)
0 1
Case 0: Correct output
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