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Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

[Exercise] Coding (C) - asked in Chapter 3: Branching, Looping and Functions by (5.9k points)
ID: 30241 - Available when: Unlimited - Due to: Unlimited
| 6.7k views

24 Answers

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Hidden content!
***** * ** * *
**** * ** * * *****
int main(){
int i;
****** ** char a;
* * * * ** * * ** your input: * *
* * ** * * *** * * **** * * ** * * **
* ** ** * * ** * *
*** ** * * ** ** * ** ** * **** * * *** * **
* * * ** * * * * * * * * ** if(i==65 ||i==69 || i==73 || i==79 * *
* ***** * * ** *** ** * * ** ** * ** **** *** *** * * * * * *** ** * **** * * *
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* *** * * * * ** * * * * * ** * *** }
**** *** *** * *** ** }
* *** * * }
}

//INPUT
//Enter your input: A

*** *
//Enter your input: A
***** * * *** *
50/100 answered by (271 points)
0 0
Case 0: Wrong output
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Hidden content!
*** ** ** * *
* * * * * ** ****

/* run this * the ** * or add your own *** ****** * ** ** * * or * loop */

int * * * ** ** {
*** * **** * a; * ** * ** ***** * * * ***** *** * *** **** * * *** **** *** * * * ** ****** * ** * ** * * * * *
* ** ** * * * ***** * your ** ****
* * **** * * * ** * * * * *** ***
** * *
* **** * ** * for (a == 'A'; a *** * *

* ** *** * * ** *
*** ** * * ** **** ** ** if (a == * a == 'E' || a == 'I' || a == 'O' || a == *
*** * * ** ** * * * **** ** * *** * ** * *
*
** * * * * * ** ** * ******** * ** ** *
* * ***
}
*** **** *
** *** 0;
}
100/100 answered by (252 points)
0 0
Case 0: Wrong output
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Hidden content!
#include * * ***
#include **** *** * *

int main(int argc, char *argv[]) {
    char a; * ** * * * ** * * ** * * **** * * * *** * *** * * ***** * * * * * * *** ** * * *** *** * can be changed
* **   *** * **** * your ** *** //DO NOT CHANGE
* ****   ** * ** *** ** * **
   
**** * **** ** * * * * * * ** ** **
* * **** * ** * *** *** * * * ** ** * * ** ** * * * * * ***
****** * * * * **** * ** ** * ***
** ** * * * ******* ***** * *** * * ** *** * ** * ****** ** ***** **** ** **
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** *** ** *** * * * * ** * *** *** *** * **** *** * * *** * a);
** ** ******** *** ** * *** *
   
    return 0;
}
100/100 answered by (268 points)
0 1
Case 0: Correct output
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Hidden content!
#include * ** ** **
#include * ** *** **

int main(int argc, char *argv[]) {
* **** ** * char a;
* * ** *** * * * * * your * * * * *
** * * ** ** * * * *
* * * * * * *
* * ** ** * **** ***
* ***** * ** * * * * ***** if * ** ** * * *** *
*** * * * * * * * * *** * * * * ***** * * *** ****
** ** * * ** * ** ** ** *** * }else
** * *** * * * ** * * *** ** * * * *** a);
* * * ** }
* * *** ** *
* * ** * ** return 0;
}
answered by (5.9k points)
0 1
Case 0: Correct output
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