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Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

[Exercise] Coding (C) - asked in Chapter 3: Branching, Looping and Functions by (5.9k points)
ID: 30241 - Available when: Unlimited - Due to: Unlimited
| 4.2k views

24 Answers

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Hidden content!
** * * * ******
* * ** **
int main(){
int i;
* ** * * * char a;
* * * * * * * **** ***** your input: * *
**** ** ** *** **** ** ** * ** * **** **
**** * ** * *
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** * * **** **** * * * *** if(i==65 ||i==69 || i==73 || i==79 ** *
* * * ****** * **** * **** * * * *** * ****** *** * ***** *
* *** * *** ** * *** * ** * ** }
* **** ** *** ** ** *** ** **** * *** else{
* ** ** *** * *** * * * * ****** ** * * *** * ** ** * ** *
* **** ** ** **** ** ** ** * }
** *** ** * * ** *** *** }
**** *** }
}

//INPUT
//Enter your input: A

**
//Enter your input: A
** ** * ** ****
50/100 answered by (271 points)
0 0
Case 0: Wrong output
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Hidden content!
* * **** * * * * *****
**** * ** ** **** *

/* run this * * **** the * * * *** or add your own * * ** ** ** *** * * or * loop */

int *** ** * * ** *** {
*** **** a; ** * * * * ** * * * * * * * ** **** **** * * * ** * ** * * ** * ** * * **** ** * * ** * *** **
* * ** ** ** * **** your **** *
* ** * *** * * ** ******
** *** * *
*** * * for (a == 'A'; a * * **** *

* * ** * *** *
* ** ** * * * ** *** if (a == ** a == 'E' || a == 'I' || a == 'O' || a == **
* ** * ***** ** * * ****** * *** * *
*
* * *** ** * ** * **** * **** *** ***
* ** * ****
}
* * *** *
**** ** ** 0;
}
100/100 answered by (252 points)
0 0
Case 0: Wrong output
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Hidden content!
#include ***** ** * * *
#include * ** * **** **

int main(int argc, char *argv[]) {
    char a; *** * ** ****** *** ** ** *** ******* * * *** ** *** * * ** ** *** *** ** ** *** *** ************* * *** * can be changed
* *   ****** ** * your ** * * //DO NOT CHANGE
*   *** * * * * * * * ***
   
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* ****** * * * *** ** ** * * * * * ***** * ** * * ** ***** **** **** ** * * *
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** * * * * * * ** * ***
   
    return 0;
}
100/100 answered by (268 points)
0 1
Case 0: Correct output
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Hidden content!
#include *** *** **** *
#include * * * * ***

int main(int argc, char *argv[]) {
* ** * * char a;
* ** * * ** ** * your ** * * ** **
* ** ** *** * * * **** * * *
*** ** *
** ** ** ******* *
* ** ** * ** * ** * if * ****** * **** * * **
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** ** * * ** * ** }else
* * ** ** *** * *** * ** * ** **** * * a);
*** * * * }
*** * *** *
** * * return 0;
}
answered by (5.9k points)
0 1
Case 0: Correct output
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