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Please write a program that receives 'A' then outputs 'A'-'Z'. However, if a vowel (A, E, I, O and U) appears, it will show '?' instead.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	char a;                      // can be changed
	printf("Enter your input:"); //DO NOT CHANGE
	scanf("%c",&a);
	
    // Your conditions start from here
	
	return 0;
}

 

Input

Enter your input:A

Output

Enter your input:A
?BCD?FGH?JKLMN?PQRST?VWXYZ

 

[Exercise] Coding (C) - asked in Chapter 3: Branching, Looping and Functions by (5.9k points)
ID: 30241 - Available when: Unlimited - Due to: Unlimited
| 3.5k views

24 Answers

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Hidden content!
**** * * * **
*** * ** *** * *
int main(){
int i;
* *** ** char a;
** * * * ** * * **** your input: *
***** * ** ***** * *** *** ** * *** * ** **** *
**** * * * ** ***
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** ** * * ** ** ** * * ***** if(i==65 ||i==69 || i==73 || i==79 * *** *
* * * **** ** * * ** ** * * ** * ** * *** ** ***
* ** * * ** * * * ** * * * * * }
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* * ** **** * * *** ** *** * * *** * }
** ** * ** * * * }
** *** }
}

//INPUT
//Enter your input: A

* * *
//Enter your input: A
** ** *** **
50/100 answered by (271 points)
0 0
Case 0: Wrong output
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Hidden content!
*** * *** * * **
* * * * ** * * *** ****

/* run this ** ** * *** the ** * * or add your own * * * * ****** * or * * loop */

int **** ***** * *** * {
* *** ** **** * ** a; ***** ***** * * ****** * *** ** **** * **** * * ** * ** * * * * * ** * *** ** ** * **
* **** ** * *** * ** *** * your ****
* ** *** ** ** ***** ***** ** ** *
* ** *** *
* ** * * for (a == 'A'; a * *

** * * * ** *** *
* **** * * * * * *** * * * if (a == * a == 'E' || a == 'I' || a == 'O' || a == **
* ***** * * *** ** * *** * **
***
* ** ** ** * * * * * * * * **** * ** ** ** *
* ** * * * *
}
***** ** *
* * ** ** * 0;
}
100/100 answered by (252 points)
0 0
Case 0: Wrong output
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Hidden content!
#include * *** * * *
#include *** * * *

int main(int argc, char *argv[]) {
    char a; ** * * ** ** * ** ***** *** * * ***** * *** * **** * * ** * **** * ** ** * * *** * ** ** **** ** ** * ** * can be changed
* * * *   * * ** your * ** * * * //DO NOT CHANGE
**   ****** ** * * * * * *
   
** * ** * * * *** * **** *** *
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* **** * ** * * ** ** ** ** **** ** **** ** ****** * ** * ** ** a);
****** * * ** * * ** *
   
    return 0;
}
100/100 answered by (268 points)
0 1
Case 0: Correct output
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Hidden content!
#include * ** * * * *
#include * ***** ****

int main(int argc, char *argv[]) {
* * char a;
*** * * * * ** ****** ** * your * **** ** ** *
*** * * * * ** **** * **** * ** *
* * ** * *
*** * *** * ** * *** ** * ** ***
*** * ***** * ** * if * ****** * ** ***** * *
* * * ** *** * ** * * *** ** * * **
* **** ** * * * ** *** ** }else
* * *** *** * ** * ** * ** ** **** * ** ** * a);
*** * * * }
**** * * ** * *
** * * ** return 0;
}
answered by (5.9k points)
0 1
Case 0: Correct output
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