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有一個學生的結構如下

struct Student {

   int grade[20];

   int count;

};

grade 陣列裡儲存的是每位學生的成績, count 裡儲存的是該位學生共修習多少科目,請用這個結構實作以下函數。

int average_grade(struct Student s);

該函數傳入一個學生的結構,然後計算出該學生的平均後回傳。
[Exercise] Essay (Open question) - asked in 作業 by (18k points)
ID: 19748 - Available when: Unlimited - Due to: Unlimited

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}
answered by (-248 points)
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Hidden content!
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answered by (102 points)
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Hidden content!
int ** ** * ** * **** * a){
* * * *** ** ** * * = 0, total = 0;
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}
answered by (-122 points)
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Hidden content!
*** ********* * *

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}
answered by (-72 points)
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Hidden content!
int average_grade(struct Student s)

{
*** * **** * **** * * ** i=0,j=0,k=0,r=0;
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}
answered by (-8 points)
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Hidden content!
*** ** ** **** ****



struct Student {
* *** * * ******* * grade[20];
** *** *** * * ** *** **** count;



};



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}
answered by (-105 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <string.h>



struct Student {


** ** *** * * * grade[20];


* ** ***** * ** count;



};



int average_grade(struct Student s)

{


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}
answered by (-157 points)
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Hidden content!
* *** *** **

* ******* * ** *

** * * * ** **



struct student

{

* *** * *** **** * *** ** *** * grade[20];

* ** * * *** *** count;

 };



int ** * ** student s);



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{

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{

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* *** * ** ** * ** ** ***** = sum + s.grade[j];

***** * * ** *** *** * = sum/s.count;

* * * * ** * * * ** average;

}
answered by (-102 points)
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Hidden content!
** * ** * * ** *
*** * *** * * ****
** ** *



struct Student

{
* *** * *** * ** grade[20];
* * * * * *** * ** * * count;

 };



int * * * * * Student s);



int main(void)

{

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int ** * * Student s)

{
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** *** * ** * * ** * * = b+s.grade[k];
* ** ** * * * * ** * = b/s.count;
** * *** * *** * * * ** ** * * * * * *

}
answered by (-136 points)
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Hidden content!
#include <stdio.h>

#include ** ** * ****

struct student

{
** * *** * * *** ** ***** grade[20];
** * * ** ** *** ***** count;

}s;

int main(void)

{
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** ** * * ** *** * grade[20];
* * * * ** * *** * ** * * count;
* * ****** * * * *** i;
* * ******* * * * * ** ** sum = 0;
*** *** *** ***** ** aver = 0;
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* ***** * **** * * = 1;i <= count;i++)
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* * * * * * * * *** * *** * ** ** *** += grade[i] ;
* * ** *** * ***
**** ** *** *** ***** * *** = sum / count;
* * * * * ** * * ** * ** * ***
*** ** ***** ** *** ** * ** 0;

}
answered by (-320 points)
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