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有一個學生的結構如下

struct Student {

   int grade[20];

   int count;

};

grade 陣列裡儲存的是每位學生的成績, count 裡儲存的是該位學生共修習多少科目,請用這個結構實作以下函數。

int average_grade(struct Student s);

該函數傳入一個學生的結構,然後計算出該學生的平均後回傳。
[Exercise] Essay (Open question) - asked in 作業 by (18k points)
ID: 19748 - Available when: Unlimited - Due to: Unlimited

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int * ***** Student s)

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}
answered by (-248 points)
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Hidden content!
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answered by (102 points)
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int * * *** * * a){
* * *** ** * * * *** = 0, total = 0;
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}
answered by (-122 points)
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Hidden content!
**** * ** ** *

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* * * ****** ** * * * grade[20];



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}
answered by (-72 points)
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Hidden content!
int average_grade(struct Student s)

{
* * * **** ** * *** **** * i=0,j=0,k=0,r=0;
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}
answered by (-8 points)
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Hidden content!
* * * * * * * * *



struct Student {
* ** ** * ** *** * ** * grade[20];
* * * * ***** * * * count;



};



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}
answered by (-105 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <string.h>



struct Student {


* **** * ** ***** grade[20];


* **** ** ** count;



};



int average_grade(struct Student s)

{


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}
answered by (-157 points)
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Hidden content!
** * * ** ** * **** *

***** * * ** * *

* * * * *



struct student

{

** * ** * * * ***** * * * ** grade[20];

*** ** * *** * * * count;

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int **** **** * student s);



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{

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** * *** ** *** ** ** = sum + s.grade[j];

**** * * ***** ** ** ** * * = sum/s.count;

*** ***** * ** average;

}
answered by (-102 points)
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Hidden content!
* **** * ***** **
* * * * * ******
* *** ***** * * ** *



struct Student

{
* ** * ** * ** * grade[20];
**** ** ** ** * *** * ** * count;

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int * * * * ** Student s);



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{

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}



int * ** ** * Student s)

{
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*** ** ** ** * *** = b+s.grade[k];
**** ** **** *** * * = b/s.count;
* *** * * *** ** ** * ***** ** * *

}
answered by (-136 points)
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Hidden content!
#include <stdio.h>

#include * ** * ***** *

struct student

{
*** * *** * * *** ** * * ** grade[20];
* * * * ** ** ** * count;

}s;

int main(void)

{
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*** * * * * * * ** grade[20];
** * * *** *** * * ***** * count;
* ** ** * ** ****** * *** i;
* * * ***** ** * *** sum = 0;
* * ** ** ** ** * * * ** * aver = 0;
* * ** * * * ** * ** * * ** * * * *
* * ** *** * * * * * = 1;i <= count;i++)
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* * * ******** * *
* * * * * * * ** * ********* = sum / count;
** ** * * * ** ** ***** **** ******
* ** ** *** **** * ****** * 0;

}
answered by (-320 points)
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