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有一個學生的結構如下

struct Student {

   int grade[20];

   int count;

};

grade 陣列裡儲存的是每位學生的成績, count 裡儲存的是該位學生共修習多少科目,請用這個結構實作以下函數。

int average_grade(struct Student s);

該函數傳入一個學生的結構,然後計算出該學生的平均後回傳。
[Exercise] Essay (Open question) - asked in 作業 by (18k points)
ID: 19748 - Available when: Unlimited - Due to: Unlimited

edited by | 2.7k views

20 Answers

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}
answered by (-248 points)
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answered by (102 points)
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int *** ***** ** a){
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answered by (-122 points)
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Hidden content!
** * * * ** *

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* * **** ** * ** ** ** count;



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}
answered by (-72 points)
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Hidden content!
int average_grade(struct Student s)

{
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}
answered by (-8 points)
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Hidden content!
** ** *** * * *



struct Student {
*** ***** * * ***** grade[20];
** ** ** ** * ** count;



};



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}
answered by (-105 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <string.h>



struct Student {


* **** ** *** grade[20];


*** ***** * * count;



};



int average_grade(struct Student s)

{


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}
answered by (-157 points)
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Hidden content!
* * *** ** * ** *

** * * * * *

* * *** ** * *



struct student

{

* ** ** * * **** * * grade[20];

*** ** * * **** * ** count;

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int *** * * student s)

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* * * * * * ** * ** * * = sum/s.count;

* ** * ********* * * *** * * average;

}
answered by (-102 points)
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Hidden content!
** * ** ****** ****
** * * * **
*** * *** ** **



struct Student

{
* * * ****** ** ** grade[20];
* *** * *** ** * * * * * * count;

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int * * * Student s);



int main(void)

{

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int *** * *** Student s)

{
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*** **** ** ** * * = b+s.grade[k];
* * * ** * * * **** * * ** * * = b/s.count;
* ** ** ** *** * ** ***** ** ** ** * **

}
answered by (-136 points)
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Hidden content!
#include <stdio.h>

#include * * * * * **

struct student

{
*** ** * * ********** * **** ** grade[20];
*** ** ** * *** ** *** *** count;

}s;

int main(void)

{
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*** * * * * * * * * ** count;
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* * ** *** * ** ** * ** aver = 0;
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**** * * * ** *** *
**** ** * * ** ** ** *** * ***** ** * * * * * **** ****** *
* ** **** ** *** * * * ** += grade[i] ;
* * * *** ** *** **
* * ** * * ** * = sum / count;
*** * ** * ***** * * ***** ** ** * * * *
** * ** **** *** * 0;

}
answered by (-320 points)
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