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有一個學生的結構如下

struct Student {

   int grade[20];

   int count;

};

grade 陣列裡儲存的是每位學生的成績, count 裡儲存的是該位學生共修習多少科目,請用這個結構實作以下函數。

int average_grade(struct Student s);

該函數傳入一個學生的結構,然後計算出該學生的平均後回傳。
[Exercise] Essay (Open question) - asked in 作業 by (18k points)
ID: 19748 - Available when: Unlimited - Due to: Unlimited

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}
answered by (-248 points)
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Hidden content!
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answered by (102 points)
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int *** * * * * a){
* * ***** * * * ** = 0, total = 0;
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answered by (-122 points)
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Hidden content!
* **** **** *

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struct student



{



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}
answered by (-72 points)
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Hidden content!
int average_grade(struct Student s)

{
* * * **** * ** ** * i=0,j=0,k=0,r=0;
** * ** ******* * * * * * **
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}
answered by (-8 points)
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Hidden content!
* * * *** ***



struct Student {
** **** * *** ** ** ** *** * grade[20];
** ** ** * *** * * * ** count;



};



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}



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}
answered by (-105 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <string.h>



struct Student {


* **** ** ** grade[20];


* * * * *** **** **** count;



};



int average_grade(struct Student s)

{


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}
answered by (-157 points)
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Hidden content!
* ** * * *

****** * ****

*** ** *** * * **



struct student

{

** * *** * * * * ** ** grade[20];

*** ********** ****** ** count;

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int * *** student s);



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{

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{

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*** ** **** ******* **** = sum + s.grade[j];

* ** **** * * ** ** = sum/s.count;

*** *** * ***** ** ** * * average;

}
answered by (-102 points)
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Hidden content!
**** * ** *** **
* * * ** * * ***
******* * * * * * * *



struct Student

{
*** * ** ** *** *** grade[20];
***** * ***** ** * count;

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int * ** *** Student s);



int main(void)

{

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int * *** Student s)

{
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* **** ** ** * * * ** * **** **** * **
* ** * ** ** * *** * = b+s.grade[k];
* * * * ***** = b/s.count;
******* ** * ** *** * * **** * **

}
answered by (-136 points)
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Hidden content!
#include <stdio.h>

#include * * ** **

struct student

{
** * *** *** * * ** grade[20];
* * * * ** *** ** count;

}s;

int main(void)

{
* * ** ** *** student s;
* * ** * * ** ** * ** ** grade[20];
** * * ** * *** *** count;
* * *** * ***** ** ***** i;
** ** ** * *** *** * sum = 0;
* * *** *** * * *** ** ** * * aver = 0;
* * * * * * ** * * * * * * * * *
**** ** * * * * * * ** * * = 1;i <= count;i++)
* * * ** * ** * ** * * *
** *** *** ** ** *** **** * *** * **** *** * ****** * ** * * *
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*** * * *** * * *** * *
* **** * * **** ** * = sum / count;
** ** * * * * *** **** ** * ***
** *** ** ** * * *** * 0;

}
answered by (-320 points)
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