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有一個學生的結構如下

struct Student {

   int grade[20];

   int count;

};

grade 陣列裡儲存的是每位學生的成績, count 裡儲存的是該位學生共修習多少科目,請用這個結構實作以下函數。

int average_grade(struct Student s);

該函數傳入一個學生的結構,然後計算出該學生的平均後回傳。
[Exercise] Essay (Open question) - asked in 作業 by (18k points)
ID: 19748 - Available when: Unlimited - Due to: Unlimited

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int * * * * * Student s)

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}
answered by (-248 points)
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answered by (102 points)
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int ** ****** * * ** a){
** * *** ** ** * ** = 0, total = 0;
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}
answered by (-122 points)
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Hidden content!
** * * * * *** * * **

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}
answered by (-72 points)
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Hidden content!
int average_grade(struct Student s)

{
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** * ** * ****** * * *
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}
answered by (-8 points)
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Hidden content!
* ** * ** *****



struct Student {
*** * ** ***** *** * ** * grade[20];
* ** ** **** * ******* * ** count;



};



int ***** *** Student *s) {
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}



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}
answered by (-105 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <string.h>



struct Student {


* * * *** ** * * **** grade[20];


* * * ** count;



};



int average_grade(struct Student s)

{


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}
answered by (-157 points)
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Hidden content!
* * *** ***** *

* ***** * * * * **

** ** * * * * ****



struct student

{

**** **** * * *** grade[20];

* * ***** * * * *** ** count;

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int * ** ***** * * student s);



int main(void)

{

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int ** * * student s)

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******* * * **** * = sum + s.grade[j];

** * ** * * * * ** ** ****** * = sum/s.count;

***** ** ***** ** ***** * average;

}
answered by (-102 points)
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Hidden content!
* * ** * *
* * ** ******* ***
* *** *** **** *



struct Student

{
** * ** ** ***** ** * grade[20];
* * ** * * * ** count;

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int * ** *** Student s);



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{

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int ** * ** ** Student s)

{
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* * ****** * * ** ** * *** * = b+s.grade[k];
* * * * *** * = b/s.count;
* ** * * ** * * * * *** * ** * ** *

}
answered by (-136 points)
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Hidden content!
#include <stdio.h>

#include ** * ******

struct student

{
* ****** * ***** grade[20];
* * * * * * *** ** * * count;

}s;

int main(void)

{
** * * *** *** * ** * * student s;
* ** ** **** * ** * grade[20];
*** ** *** * **** *** **** * count;
** ** * ** * * * * * * **** i;
** * *** * *** ** ** * sum = 0;
* ******* * ******** aver = 0;
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****** * * * ** * * = 1;i <= count;i++)
** * * * * * ** *
** ** ** ** * * * *** **** ***** * * * * ** ** * *** ** * **** **
*** ** ** * ** * * ** * **** * * * * ** ** += grade[i] ;
* * * * ** * * * *
* * **** ** **** * * * = sum / count;
* * *** ** **** ** * *** * * * * * *** ***
* **** * ****** * * *** 0;

}
answered by (-320 points)
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