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有一個學生的結構如下

struct Student {

   int grade[20];

   int count;

};

grade 陣列裡儲存的是每位學生的成績, count 裡儲存的是該位學生共修習多少科目,請用這個結構實作以下函數。

int average_grade(struct Student s);

該函數傳入一個學生的結構,然後計算出該學生的平均後回傳。
[Exercise] Essay (Open question) - asked in 作業 by (18k points)
ID: 19748 - Available when: Unlimited - Due to: Unlimited

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* ** * *** *** *** ** /= s.count; * *** ** * * * ** **** * get average score
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}
answered by (-248 points)
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Hidden content!
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answered by (102 points)
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int * ** ** * **** a){
* * *** **** ** * *** * = 0, total = 0;
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}
answered by (-122 points)
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Hidden content!
** * ** ** ** * * *

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{



* *** ***** * * * * * ** grade[20];



* ** * ** * **** count;



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}
answered by (-72 points)
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Hidden content!
int average_grade(struct Student s)

{
** * *** * *** * ** * * * ** i=0,j=0,k=0,r=0;
* ** *** ** ** * * * ** **** ** *
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}
answered by (-8 points)
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Hidden content!
* *** * * * *



struct Student {
*** *** * *** *** ** grade[20];
* **** * ** * count;



};



int * * ** * Student *s) {
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}



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}
answered by (-105 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>

#include <string.h>



struct Student {


* ** ** * * * grade[20];


** ** * * *** * * * count;



};



int average_grade(struct Student s)

{


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* ******* * * *
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{
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*** ***** *** * ** * * * 0;
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}
answered by (-157 points)
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Hidden content!
***** * ***** *

* ** * *

* *** * * ***



struct student

{

** ** ** ** ** * * *** grade[20];

* *** *** * * ** *** count;

 };



int ** * student s);



int main(void)

{

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***** *** * * * * ** student s;

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}



int ***** student s)

{

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*** ** * * * *** * ** *** * * ** **

** **** *** * = sum + s.grade[j];

* ******** * ** ** ** = sum/s.count;

* ******* **** *** ** average;

}
answered by (-102 points)
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Hidden content!
*** * * ***** *
**** * ** **
* * * ** *



struct Student

{
* * * ** * ** * * grade[20];
** * ** * *** * * ** count;

 };



int * * *** * ** * Student s);



int main(void)

{

 int i;
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}



int * * * * * Student s)

{
* * ** * * * * ** * ** k,b=0;
** * ** * ** * ** * ** * ** * *
** * ** * ** * *** = b+s.grade[k];
** * ** *** * = b/s.count;
* *** * ** * ** * ** * * ** ******* * *

}
answered by (-136 points)
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Hidden content!
#include <stdio.h>

#include ** *** * ***

struct student

{
**** *** * *** * * * grade[20];
**** **** **** * ** *** count;

}s;

int main(void)

{
** * * * * ** ***** * * **** student s;
***** ** * ** **** ** *** grade[20];
** ** * **** * ** * * * ** count;
** *** * ************ * i;
* * ** * *** *** sum = 0;
** * ** * * *** * aver = 0;
**** ** ******** **** * ** * *** * * *** ***** **
* ** *** * * *** * ** = 1;i <= count;i++)
** * *** ** *** * *
* ** * ** ** * **** *** *** ** * ** * * *** * * * **** ****** ***
* * ** * *** * * ** ** * * * *** **** += grade[i] ;
* * * * * *** * *
*** * * *** * * * * * *** = sum / count;
* * ** *** * * ** ** ** * ** * * ***
****** *** * *** ** ** 0;

}
answered by (-320 points)
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