0 like 0 dislike
3.6k views
整數的運算會因為整數所佔的記憶體大小而有限制,無法計算太大以及太小的數字,但是如果利用字元以及陣列的結合,就可以大大的提升整數運算的範圍,請設計一個程式,讓使用者輸入兩個很大的整數,程式會把兩個整數相加後輸出。

輸入說明:輸入會包含兩個正整數,兩個正整數之間會用一個空白隔開,兩個正整數相加的結果不會超過五十位數。'

輸出說明:請將兩數相加的結果輸出。

輸入範例:

999999999999999999999999999999 999999999999999999999999999999

輸出範例:

1999999999999999999999999999998
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 3.6k views

16 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
*** * * *** ** * * * * * *** ***** * ******
** ***** ** * ** *** * * ** *** *** **

    {
* * ** * * * ** * ** ** * ** * *****
** ** ** * * * ***** * **** * * ***** * *
* ** **** * *** ** ** ** ** ** *** ** * * *** ***** * ** * * ** * * *** *
* * *** ** * **** * ***** * * * * * *** *** * **** * * ** ** * * * * ** * * * = a[n] + b[n];
* ** * * **** * ** * * ** * ** **** ** * * if(a[n]+b[n]>='10')
* * * *** ** * * * ** * * * *** **** *********** ** *** *** * *
* * ** * * ** ** * *** * ** * ***** * * *** ** * ***** * * * ** * ** ** * *** = a[n] + b[n] - '10';
** **** * ** ** ** **** * * * * ** * * * * * * ***** * * * * ** * ** * * ***
*** ** ******* ** * *** * **** * *** * * *** * * * * ** ** *
* *** * *** * ** * * * **** * * * ** * ******
**** ** * * * ** * * *** *** * **** ** * * * if(t == 1)
* * * * * * * **** **** * ***** **
**** **** * ** * * ** *** ** ** * ** ** * *** *** **** * * ***** *
* ** ** * * * ** *** ** ******* * ** * * ***** ** *** * ** ***** * * *** * **** * = a[n] + b[n] + '1';
* ** ********* ** * ***** ** * * ** *** * ** ***** ***** * ** * ** ** if(a[n]+b[n]>='9')
**** * ***** ** ****** ***** ** ** * *** **** * *** **
* * * *** * * ** * ** ***** * *** *** ** * * * * * ** * * * * * * ** *** *** * *** ***** * ** = a[n] + b[n] - '9';
******* ** * * * * ******* * * * **** * **** ** *** *** ** ** **** * * * * ** ** * **** * * **
* * * * ****** * ** ******* * * * ** **** * * ** ** ** *
**** ** ** * * * **** * ** ** *** ** **

    }
* *** * ***** *** ** ** * * ** *

    {
** * ** ** ** * ** * * ** * * * *** ** **** * * ** *********** * **

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
* * * ****
* ** **** * ***

int main ()

{

int *


* *** * * * * ** * * ****
** *** **** **** * *


* 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include ** * *

#include <ctype.h>

#include <math.h>

#include <stdlib.h>



int main(){
* *** *** *** * * * ** a[100],b[100];
* *** *** * ********** sum[200];
**** ** * * ** * *** la,lb,lm,i,j,k;
***** ** ** * * ** * * ** ** ** ** * %s",a,b);
*** *** * * * = strlen(a);
* **** *** ** *** * = strlen(b);
** * * ** * ** * * * ** **** ** ****** *
* ** *** ** ***** **** **** * ** ** ** * * = a[i];
** *** *** * ** * *** * * **** ** ** * * ** * * * * * *
**** * * ** * * *** *
* ***** * * * * * * * * * * * * ** *
* * *** *** **** * *** **** ** *** * ***** += b[i]-48;
* *** * ** ** * * **** * * **** * *** ** * * ** **** * ** ** * *
** **** ** ** * **
* * * *** ******* ** * * = strlen(sum);
* ******** * * * * * ** * ** ** *
*** ***** * ** *** * * *** ** ******* ***** * * * ** ** *
*** ****** * * ** * *** *
* * * ** * * * *** * ** 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
* * ******** *
***** ** * ***





int main ()

{
*** a , b ;
* ** *** * * **** * , * * *
** ***** * * * * , ****** *
* * * * * *** * * ,a+b);
** ** * ****** *** ** * * ** 0 ;



}
answered by (-87 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
* * * *** * **** * ** * * * ** * ***
** ***** ** * * *** * ** **** **** * *

    {
* * ** * ** **** * * * * * * ** * ** ****
* *** ** *** * * * * ** ***** ** ** * ****
***** * ** * ***** * ****** *** * * ****** * ** ** ** ** ** ** * ** *
* * ** * * * * *** **** ** * * ** **** * * * ** *** **** **** ** ******* * * = a[n] + b[n];
** ** *** ** ** *** * * ** * * ** * *** * * * ** ** **** ** * if(a[n]+b[n]>=10)
* ** ** ** * * ** * ** ** * ** ** ** * * * *** * * *** * **
**** * *** * * * * ** * ** * * * * *** ** *** ** ******** ** ** * *** ***** ** ** = a[n] + b[n] - 10;
* *** *** * **** ********* ***** * * ** ****** * *** * *** * * ** ** ** * *** ** * * * **
** * * ***** **** * ** * * * * * ** * * ** * ** ** ***** *** * * * ** *** ** ****
* ** * *** * * *** * * ** ** * *** * *
** * * *** * * * * *** * * * ** * ***** * * if(t == 1)
*** * ** * ** ** * *** ****** * ** ** ** *
* * *** ****** ***** ** ***** * * ** ** * * ** ***** **** **** * * * * * **** **
*** ***** * * * * *** ** * * ** ** * * *** ** * * ** * * **** * ***** * ** = a[n] + b[n] + 1;
** ** ****** * * **** * * ** *** * ** * * ** * *** * * * ** ** * if(a[n]+b[n]>=9)
* * ** ** * * * ** * * *** * * ** *** ** * * ** ****** *
**** * ** * *** * * * ** *** ** ** * * * *** * ** * *** ******** ** ** * ** * ** ** = a[n] + b[n] - 9;
* ** ** ** * * * **** * **** * * * * * **** * **** * * ** *** ** * * * ** *** *
* ** * *** * ** * *** ** * * * *** *** **** * * * ** *** * ********* ***** **
** * * * ** ** ** * * ****** * * **

    }
** *** ** * ** ******* *** ** **

    {
* ** **** * * ***** * ** ** *** * ** * ***** * ***** * * ***

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>

int main()

{
* ** **** * * ** *** data[2];
* * **** **** ** * * ** sum;
** ** **** ** * ** * * i;
**** ** ** * ** **** *
*** * * * * ****
* * * * * *** ** ***** * * ** * * * *** ** * * **** ** ** ***
* * * *** * * * ***** * *
*** * * * ** ***** **** *** * *
** * * * **** * * * * * *
* * *** * *** * ** **

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include * ** * **
** * * *
* * * *** ** *
** **** * * * *







int ** **

{


*** * ** * * int *** **** ** *
* * * **

* *** **** scanf * * ** * * **
*** ** * *

* *** * * while (a[i]!= ' ')

{
******* ***

** * i++;
*** * **** * * *

* ** * scanf ** * * ***** * * ** * ***

* * *** *

}


* * ** ** scanf * ******** * *


*** ** ** * while ** ** * * ** * *
** * ** * **

**** * *** * {
* * * * ** ** * ** **

****** * * ****** * *** * j++;
** * *** * ** ***

*** ** ** ** * ** * * * scanf * **** * * ****** ** **

** **** * * ** *** **

** ** *** *** * }
* *

}
* * *** **

* ** **** for (i = 0,j = 0;;i++)
***** ****

* ** *** * return 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
include <stdio.h>

#include *** ** * **

int main()

{
* ** * ***** * ** a,b,c;
* ** * ** * ** **** * *** **** * * ** ***
* * * * * *** * * ** = a + b;
* * ** * ** ** *** ***** ** ****** ** ** * * * *
* * ***** *** * ** ** * ** * **
* * * * * *
** ***** ** ** * * * ** * ** **
* * * ** * * * 0;

}
answered by (-42 points)
0 like 0 dislike
Hidden content!
#include * * *

int ** * y=999999999;

int main()

{
* * ** * ******** * *** *** *** * **
***** ***** * *
*** *** **** **** ***** * ***** *

}
answered by (-162 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * ** ** **

int main(){
* *** ** * * * ******** * * a,b,c=0;
*** * * * * ** ** * * * * * ** ** *** *
*** *** * * *** * * * * * ******* **** ** * **
* * ***** ***** * * * ** * *
* * * *** * **** * ** ** * * *** ****
* * * * ** ******** ** ** 0;





}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.64
©2016-2026

Related questions

0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 12k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 6.7k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 9.5k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.1k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users