0 like 0 dislike
2.2k views
整數的運算會因為整數所佔的記憶體大小而有限制,無法計算太大以及太小的數字,但是如果利用字元以及陣列的結合,就可以大大的提升整數運算的範圍,請設計一個程式,讓使用者輸入兩個很大的整數,程式會把兩個整數相加後輸出。

輸入說明:輸入會包含兩個正整數,兩個正整數之間會用一個空白隔開,兩個正整數相加的結果不會超過五十位數。'

輸出說明:請將兩數相加的結果輸出。

輸入範例:

999999999999999999999999999999 999999999999999999999999999999

輸出範例:

1999999999999999999999999999998
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 2.2k views

16 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
* * * **** ****** * ** *** * * * * * * **
* ** ** ** **** **** * * **** * *

    {
* ***** ** * **** ****** **** * ** **** * ** * * * *
* * ***** * *** ** ***** ** ** ** *
*** * ** ** * * ** ** **** * * * ******* ** * ** *** *** * ** * * * ** **
* *** ** **** ** * ** * * *** * ** ** * *** * ** * * *** **** ****** * ** ** ** * * *** = a[n] + b[n];
*** **** ** * *** * * * * * * ** ** * * ** * * ** *** * if(a[n]+b[n]>='10')
** * * ** * ** ***** * * **** *** * * *** * ***** *** *** *** *** **
* * * * ** * * * * *** ****** * * ** * * ** ** * ** ** *** * ** *** * ** * * * = a[n] + b[n] - '10';
** ** **** * ** ** * * ** *** ** * * **** * * *** * ** ** * * * * * ** ******* ** * * ** *
* ** * **** *** * *** * * ** ** * ** * * * * ** *** * *
** * * * ** * * ** * * * * * * *
* * * *** * * * ** * * * * * *** **** if(t == 1)
* * * ****** ***** * ** * ** ** ** *******
* * ** * * * *** ** ** * *** * **** ** ** * ** * ****** * ******* * ** * ***
* **** ** *** * * *** * * * * ** * * ** **** ** * * **** * * * *** ** ** = a[n] + b[n] + '1';
* * **** ** ** **** * **** * ********** * ** ****** *** * * *** * if(a[n]+b[n]>='9')
*** * * * *** ** * *** * * ** * ** * * *** ** * ** * *
*** ** ** * * * ** ** * * *** * ** * * ******* * *** ** * ** ** * ** * * * = a[n] + b[n] - '9';
* * * *** * * * * *** *** ***** * * * * ** * * ** * * * ** * * * **** ***
*** * * ** ** * ** * ** * *** ** **** ** *** *** * ** ***
* * ** ** * * ****** ** * **** ** **** ****

    }
* *** ** ** ** ** * * * ** *** ** *

    {
* * ** * **** * * *** * * * * * *** * * ** **** ** ** ***

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
** * * ** ** ***
** ** * * **

int main ()

{

int *


* **** * * ******* * * ******
* *** * *** **


0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include * ** ** * * *

#include <ctype.h>

#include <math.h>

#include <stdlib.h>



int main(){
* * ***** ** * *** * * a[100],b[100];
* ** ** ***** ** ** sum[200];
** **** *** *** * la,lb,lm,i,j,k;
*** * * *** * ** *** * **** ** %s",a,b);
**** * * ** * * * ** = strlen(a);
* * **** * * * * ** = strlen(b);
* * * ** ** ** ** **** ****** ** * * ****
* *** ** * ** * * ** *** * ** ** ***** *** * * ** * = a[i];
** **** *** * * * ** ** ** * * ** *** ** * *** * ** * * ******
* * **** ** * *
*** *** * ** * * ** * * * * * * ** ** **
** * ** ****** * * * * *** * * ** * * ** += b[i]-48;
* ******* ** ** * ** *** * * ****** * * * ** ** * * * * *
* ** * ** * * * * * **
** **** * ******* * * *** * = strlen(sum);
* * ** ** **** *** **** ** ***** * ***
*** *** * ****** * ** ****** * ********* ***** * * * ** ***
** ** * *** * **** **** *
**** *** *** * ** ** * 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
*** ** * *** * ***
* ** ** ** * * ** *





int main ()

{
* a , b ;
** *** * ** * * , *
** ** ** * * * ** , ** * *
** * ***** ,a+b);
* * ** * * * ****** * * 0 ;



}
answered by (-87 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
*** *** ** *** ** ***** * ** * *** * * ** *
**** * *** * *** * * * *** * * * *

    {
* * * * * * *** * ******* *** ***** * ** *
* ** * **** * *** ***** *** *** ** * ** ***
***** ** * * * * ** **** * * * *** * * * ****** * ****** * * * ** ** *** *****
* * * ** **** * *** ** ** *** ** ** * ** * * * *** *** ******* *** * **** * * ** = a[n] + b[n];
* * ** **** ** * ****** * * * * ** *** ** * * * * * ****** * if(a[n]+b[n]>=10)
* * ****** * * ** * ** ** * * **** * * ** ** ** ***
* * * * * *** **** * ** * *** ** ***** * * **** * * ** * ** ** ***** * = a[n] + b[n] - 10;
*** **** * * ** ****** **** ** * * * **** * * *** * * * ***** * * ** ** * ** * ** *** *
** *** ****** *** * * * ***** ** *** *** * * * * * ** **
* ** * *** *** * ** * * * ** ** *** *
* **** * *** **** ** * * *** * ***** *** if(t == 1)
* *** * ** **** ** * *** * * * ** **
*** * * * *** *** * ** * **** * *** * ** ** * *** ** **** ***** ******* *** *
** ***** * *** * * * * * * ** * * ** * * * * * ***** * ** * **** * ** * = a[n] + b[n] + 1;
** ** ** *** * * * * * * *** * *** **** * * * **** **** ** * * * * if(a[n]+b[n]>=9)
* ** * ** * ** * * *** *** ** ***** * **** ******** *** * ** **
******** * ** *** ** * * ** * **** * * * ** ** ** * **** * * * * * * ** * **** *** * * = a[n] + b[n] - 9;
* * * * * * *** * * * *** ***** * ** * * * * ** * * * * * * ***** ** * * * * * *
* ***** * * **** * * * *** * * * *** * **** * * ** ** * * * * **
* *** * * * * *** ** * * * * * * ** * **

    }
*** *** * *** ** * ** * * **** * *

    {
*** * * ********* * * * ** ** * *** ** * * * * ** ** ****

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>

int main()

{
** ** * *** * **** ** * data[2];
***** * * * * * *** sum;
* *** ** * * ** * ** i;
* ** ** *** ***** * *** ** ****
* *** ** ****
** ** ***** ** * * ** *** * * * **** * ****** * *** **
***** * **** * ** ****
* ** ** ** *** *** ** * **** **
** * * ** ** * * * * ** ** * * * * *
* ** ****** ** * **

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include ** ** **** **
* * * * **** * ***
* * *** *** * **
* * * * ** *







int * * **

{


* ******* * ** * int ** *** * *
* ***** ** * *

* * ** scanf ** * * * ** * **** ***
****** ***

***** * * ** while (a[i]!= ' ')

{
** ** *** * **

* ** * i++;
*** ** ** *

* **** **** ** scanf * * * ** * **** * * ** ** *

*** * * * ** *

}


* * *** * * * * scanf ** ** ** * * ***


* *** * * * ** while **** * * ** ** * * * *
** *** * *

*** * * ** {
* * * * ** ****

* * * * * * * ** * j++;
*** ** ** * * ** * ***

* * ** * ** * ****** scanf * * * ** * ** ****** * *** * *

**** ** ** *** * *** ***

* * ** ** }
* * * * **

}
* * **** * * *

* ** * * *** for (i = 0,j = 0;;i++)
* **** *

** ** ** return 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
include <stdio.h>

#include **** ***

int main()

{
* * ** ** ** ** a,b,c;
** * *** ***** * * * * * * * * * *
* * ** * **** ** = a + b;
* *** * **** * * * * * * * *** * * **** *** ** *
* ******* ******* * * ***** * *
* * * * * *
** * ** ** ** ** * ** * * * **
***** * ** * ** * *** 0;

}
answered by (-42 points)
0 like 0 dislike
Hidden content!
#include ** * ***** ** **

int * * ** y=999999999;

int main()

{
** ****** ** * *** *
* ** * ** ** * * * * ***
* * *** ** ** * ********* * *****

}
answered by (-162 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * ** ** ** *

int main(){
* * * ** *** ** ** ** a,b,c=0;
** *** ** ** *** ** *** * * *** * * * * * ****
* * * ** ** **** * * ** * * **** **** **
* * *** ** ****** **
****** ** *** * * * *** **** * *** **** * ***
* ** * **** * * ** *** * * * 0;





}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.174
©2016-2025

Related questions

0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 6.7k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 4k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.3k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.4k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users