Toggle navigation
Courses
Questions
Tags
Users
AC 20161201 第二次期中考 第五題
0
like
0
dislike
1.9k
views
整數的運算會因為整數所佔的記憶體大小而有限制，無法計算太大以及太小的數字，但是如果利用字元以及陣列的結合，就可以大大的提升整數運算的範圍，請設計一個程式，讓使用者輸入兩個很大的整數，程式會把兩個整數相加後輸出。
輸入說明：輸入會包含兩個正整數，兩個正整數之間會用一個空白隔開，兩個正整數相加的結果不會超過五十位數。'
輸出說明：請將兩數相加的結果輸出。
輸入範例：
999999999999999999999999999999 999999999999999999999999999999
輸出範例：
1999999999999999999999999999998
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
(
18k
points)
ID: 18075 -
Available when:
2016-12-01 18:30:00
-
Due to:
2016-12-01 21:00:00
reshown
Dec 1, 2016
by
Shun-Po
|
1.9k
views
comment
Please
log in
or
register
to add a comment.
16
Answers
0
like
0
dislike
Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
char a[50]={0};
char b[50]={0};
char c[50]={0};
int n,t=0;
* * ** * * * ** * *** ** * * *
** * ** * * * * * *** * * ** ** ** *** *
{
** * *** * * * ** * * * ** * * * * ** *** * * **
* *** ** * * * * ** ** ** *** * * ** *** * * ** * *
* * * ** *** * * ** * * * * * * * * * ** * ** * * * * * * * * * ** * *** *** * * * * ** * *
* * * * * ** **** * * ***** * * * * *** **** *** * ** * * * *** ** * * ** * * *** * * * ** * *** * * = a[n] + b[n];
* ** * ** *** * * * * * * ** * * * * ** * * * ** ** * * ** * * * ** * * * if(a[n]+b[n]>='10')
** * * * * * * * ** * * * ** * * ** * **** *** * * ** * **
* ** * * * * *** ** * * *** *** ** * * * * ** * * * * * * ** * * * * *** * ** * * * = a[n] + b[n] - '10';
*** * ** **** * * * * * * ** ** * * * * * * * * * * * * * ** ** *** * * ** *** ** * *** ** * * * * * ** *** **
* * ** * **** * * * * ** * * * **** * * * ** * *** ** **** ** *
* ** * ** * * * * * * * * * * * * *
** *** * * *** * * ** * * * ****** ** * ** * if(t == 1)
* ** * * * * * ** * * ** * * * * * ** *****
* * * ** * ** * * * * ** *** * * * * * ** * * ** ** ** * * * **
* * * * * * * *** * ** * * * * * * *** ** * * ** *** * * ** * **** * * * * * * * ** ** * ** * = a[n] + b[n] + '1';
* * * * *** ***** * * * * * ** * * * **** ***** * ** ** ** * * **** * * * * ** * if(a[n]+b[n]>='9')
* * ** * * * * * *** * * * * * * * * * * * * ** * *** **
*** * * * ** ** **** * * * * ** * *** * * * * * * * ** ** * ** * * * * * * * ** * * * * * * *** * * = a[n] + b[n] - '9';
* * * * ** * * * ** ** * **** ** * * * ** **** * * * *** * ** * *** * * ** * * *** * *
* * * * * * * ** * ** * ** ** * * *** * * * ** ** * ** ***
* * * ** ***** ** * * * **** *** * * * * * * * ** ** *
}
* * * * ** * * * * * * * **** * * * * * **
{
* ** * * * * ** * * * * * * ** * * * *** * ** * * * **** *** * *
}
return 0;
}
answered
Dec 1, 2016
by
410323020
(
-85
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!* * ** **** ** * * *
* * * * * * ** ****
int main ()
{
int **
** *** * * ** ** ** * ** * **
*** * * * * * ** * **
** * 0;
}
answered
Dec 1, 2016
by
林佳慧
(
-85
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include <stdio.h>
#include * * * * * * *** **
#include <ctype.h>
#include <math.h>
#include <stdlib.h>
int main(){
**** * * * * * * ***** * * ** * a[100],b[100];
* ** * * * ** * * ** * * * sum[200];
* ** ** * * ** ** *** * * *** * la,lb,lm,i,j,k;
*** * * * ** * **** * * * * %s",a,b);
** ** ** * * *** * * ** **** ** = strlen(a);
** * * ** * * ** * * * * * * = strlen(b);
* *** * ** *** * * ** * ** ** ** * * * * ** *
* * * * * * * * * ** ** ** * *** * ** * * * = a[i];
* *** * ** ** * * ** * * * ** * ** ** ****** *** ** * * *** ** *
* ** * * ****** ** * * **
* ** * * * * * * * * * ** * * *** * **
* * ** ** * * ***** ** * * * * ** * * * ** * *** * * += b[i]-48;
* * * ** * * * * **** * * * * ** * * * * * * ** * *
*** ** ** *** * * *** *** *
*** * * * * **** * ** * = strlen(sum);
** ** * ** * * * * * ** * ** * * * *
* *** * * * * * *** * *** * * * ** **** * ** * * * *** * ** * ** **
* *** * * * *** ** ** * * ** **
* * * ****** * * ** * * ** 0;
}
answered
Dec 1, 2016
by
loyfree0706
(
-216
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content! *** * ** * * *
** ***** * * *
int main ()
{
* ** a , b ;
* * * ** * * *** , * ***** *
* *** ** * * * *** , *** ** *
* * * * * ** * * ** *** ,a+b);
* ** * * *** * ** ** * 0 ;
}
answered
Dec 1, 2016
by
leochen
(
-87
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
char a[50]={0};
char b[50]={0};
char c[50]={0};
int n,t=0;
* * * **** * ** ** * *** * ** *** * ** * *
* * * ** * * * * * ** *** ** **
{
* * *** * ** ** ***** * * * * * * ** ** **** * * ** *** ** * * *
** *** ** * * ****** * ** * * * * * * ** *** ** ** *
*** * * * ** * * * * **** ** * * * * * ** * ** * * ** **** * * ** * * * * * * *
* ** * * * * ** * *** * * *** * * * ***** * * * * *** * * * ***** ** * ********* ** ** ** * * = a[n] + b[n];
** * * * * * * * * * *** * *** * * ** ** * * * * * * * * *** * * if(a[n]+b[n]>=10)
* * * * ** * * ** * * * * * *** ** ***** ** * * * ** * * * *
* ** * * * * * * * * * * * *** * * * * * * * * * * * * * *** * * * **** * * * *** ** = a[n] + b[n] - 10;
* * ** ** * * *** * *** * *** * * * * * * *** * * * * * * * * * * * ** * * ** * * ** * * * *
** *** * * ** * ** ** ** * * * ** * ** * * * * * * * * *
* ** * * * * * * ** ** * **** * * * * *** * ** ** * ** **
* * * * * * *** * * * ** * * * * * * * * * * * if(t == 1)
* *** *** **** ** *** * * ** * ** ***** * * * * **
* * ** *** ** * * * * * ** * * ** * * * * * * *** ** ** * * * * * * ** *
*** * ** * * ** ** * * ** ** ** * * * * *** * ** * *** ** * * ** ** * * * * * * * * * * = a[n] + b[n] + 1;
* ** * * * * ** * ** * * ** ** * * * * ** * *** * * * ** ** * * * * * * * if(a[n]+b[n]>=9)
** * ** *** ** * * ** ** **** ** ** * * * * * * * ** * * * * * * * * ** * * * * * *
*** ** * * * **** * * *** * **** *** * * * * * * * * * * * * * * * ** ** ** * * * * *** ** = a[n] + b[n] - 9;
** *** ** ** * *** * * *** * * * * * * * * * * *** * * * * * * ** ** *** * ** * ** * * * *
* ** * * * **** ** * ** * * * * * * ** *** * * * * ** * *** * * ** *
* * * * * ** * * * ** * * ** * * * * * ** *
}
* *** * ** * ** ** ** * * * * * **
{
* * ** ** * * ** ***** * * * * *** * ***** ***** * * * ** * ** * * * *
}
return 0;
}
answered
Dec 1, 2016
by
410323020
(
-85
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!# include <stdio.h>
# include <ctype.h>
int main()
{
* ** *** * ** ** ** * data[2];
* * * * *** * * * * ** sum;
* * ** **** ** * * **** i;
** ** * * ** * * * ** ****** ** * * ***
* * * * * * * * ** *** **
** * * * * ** * * * ** * * * * *** ** * * * * * * * * ***** *** * *
* * * ** * * * * * * * ** *
* ** ** * * * * * ** *** ** * ** * *
** * ** ** ** * ** * * * ** * * * *
** * ** * * *
}
answered
Dec 1, 2016
by
410425016
(
-124
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include * *** * *
* * * * * * **
* * * * * **** *
* * ** ** * ** ** *
int * *
{
* *** * int * * * * * *****
** * ** * *
* * *** *** scanf ** ** * * * * ** * * *
* * * * *
* * ** * * * while (a[i]!= ' ')
{
* *
** ** ** * * * i++;
* ** * * *
* ** * *** * scanf * * * * * * * * * ** * * * * * *
* ** * **** **
}
* * * * scanf * *** ** ** ** * * * * *
* * * ** while ** * ** * ** * ** * *** *
* * * * * *
* ** * * * {
** *** * ** * ** * * * ** **
* * * ** * ** * * * * * j++;
** *** ** * * * ** **** *** *
* ** * ** * *** * * * *** scanf ** ** ***** * ** * ** * *** * * *
* * * * * ** * * * **
* * *** * * }
* *** ** *
}
** * * * * ** *
** ** ** for (i = 0,j = 0;;i++)
** * ** *
* ** ** return 0;
}
answered
Dec 1, 2016
by
410523007
(
-157
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!include <stdio.h>
#include *** ** ** ****
int main()
{
* * *** * * * * * * a,b,c;
* * * **** * * * * * *** ** ** * * * * *** * ** **
* ** *** ** * * ** = a + b;
* * * **** * * ** ** * * *** * * * * ** * * ** * ***** * *
* * * * * * * * * * * ** * *** * * **
** * * * * * * * *
* * ** * * ** ** * * ** * ** * **** * *
* * * * ***** ** * * ** * 0;
}
answered
Dec 1, 2016
by
莊長穎
(
-42
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include * * * * * ***
int * ** y=999999999;
int main()
{
* * * * ** ** * ** ** * ** ******** * * *
** * * * * * ** ** **** *** **
* * ** * * * * * * ** * * * ** *
}
answered
Dec 1, 2016
by
410425014
(
-162
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include<stdio.h>
* * * * * * *
int main(){
* *** * ** ** * * * * ** ** * * a,b,c=0;
* * * *** ** * * * * * * * *** * ** * **
* ** * ** ** * * * ** ** * * *** * *
* *** * *** ** * * * *** * *
* ** * * * *** * ** * * * * **** ** * * * *
** ** * ** ** * * 0;
}
answered
Dec 1, 2016
by
SRFX
(
-140
points)
ask related question
comment
Please
log in
or
register
to add a comment.
Page:
1
2
next »
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English
中文
Tiếng Việt
IP:108.162.216.29©2016-2025
Related questions
0
like
0
dislike
86
answers
AC 20161201第二次期中考 第四題
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
(
18k
points)
ID: 18071 -
Available when:
2016-12-01 18:30:00
-
Due to:
2016-12-01 21:00:00
|
5.8k
views
0
like
0
dislike
49
answers
AC 20161201 第二次期中考 第三題
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
(
18k
points)
ID: 18070 -
Available when:
Unlimited
-
Due to:
Unlimited
|
3.4k
views
0
like
0
dislike
62
answers
AC 20161201 第二次期中考 第二題
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
(
18k
points)
ID: 18067 -
Available when:
2016-12-01 18:30:00
-
Due to:
2016-12-01 21:00:00
|
4.5k
views
0
like
0
dislike
21
answers
AC 20161201 第二次期中考 第一題
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
(
18k
points)
ID: 18066 -
Available when:
2016-12-01 18:30:00
-
Due to:
2016-12-01 21:00:00
|
2k
views
0
like
0
dislike
0
answers
AC 20161201 第二次期中考公告
[Resource]
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
(
18k
points)
ID: 18085 -
Available when:
Unlimited
-
Due to:
Unlimited
|
10
views
12,783
questions
183,442
answers
172,219
comments
4,824
users