0 like 0 dislike
2.7k views
整數的運算會因為整數所佔的記憶體大小而有限制,無法計算太大以及太小的數字,但是如果利用字元以及陣列的結合,就可以大大的提升整數運算的範圍,請設計一個程式,讓使用者輸入兩個很大的整數,程式會把兩個整數相加後輸出。

輸入說明:輸入會包含兩個正整數,兩個正整數之間會用一個空白隔開,兩個正整數相加的結果不會超過五十位數。'

輸出說明:請將兩數相加的結果輸出。

輸入範例:

999999999999999999999999999999 999999999999999999999999999999

輸出範例:

1999999999999999999999999999998
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 2.7k views

16 Answers

0 like 0 dislike
Hidden content!
* * ** * ***
**** * ** ** **





int main()
* * * a, b, c;
* ** ** **** * * * ******
* * * = a + b;


* * * * ** * c);


* * ** ** * **** *** **** * * ***



return 0;
** *****
answered by (-98 points)
0 like 0 dislike
Hidden content!
* * ** * *


**** * **** * *


**** * ******


**** *** ****




** * ( * )

{


* *
* * = ** * * **
* *** ****** ** * ** * *




= * + *




* * ***** * ** * ** *










* 0;

}
answered by (-276 points)
0 like 0 dislike
Hidden content!
* **** ***** **

#include * *** * * ***

int main (void)

{
** * c;
* *** a,b;
**** * * * ** ** * **
** * ****** ** ** * ***
* * * **
* * * * * * *** *
**** * 0;

}
answered by (42 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * * *

void rect(int ,int,int *);

int main(void)

{
**** ** *** *** * ** ** a,b;
* * * *** *** * * sum;


** * ******** * *** * * * **** * ****


*** * ****** ***** *
**** ** ***** *** ** * * * ** ** * **


*********** ** * ***** * * *** * * ** *
* * * ** ***** 0;

}
* * * * * *** rect(int x,int y,int*p1)
* ** * ** *** * *
*** * ***** * * * *** * * * * *** * *


** ** * * *
answered by (-114 points)
0 like 0 dislike
Hidden content!
** *** **
** * ** * * * ** ** *



int main()



{
* *** * * **** *** * **
* * ** * *** * * * *** ** ** * * * **** *
* = num[i] + num[j] ;
** * ** * * **** ****** *
** ** * ** 0;



}
answered by (-50 points)
0 like 0 dislike
Hidden content!
#include * ** * * ** *



int main (void)

{
* *** ** * ** ** ** ** * num1,num2,sum;
* * * *** * * * * * * ** * * * * * * *** *
* ** * ** ** ** * = num1 + num2;


** ** * * * ** * **** * ** * * *
* * ** *** 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.82
©2016-2025

Related questions

0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8.8k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 5.1k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 7.1k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.1k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users