0 like 0 dislike
2.2k views
整數的運算會因為整數所佔的記憶體大小而有限制,無法計算太大以及太小的數字,但是如果利用字元以及陣列的結合,就可以大大的提升整數運算的範圍,請設計一個程式,讓使用者輸入兩個很大的整數,程式會把兩個整數相加後輸出。

輸入說明:輸入會包含兩個正整數,兩個正整數之間會用一個空白隔開,兩個正整數相加的結果不會超過五十位數。'

輸出說明:請將兩數相加的結果輸出。

輸入範例:

999999999999999999999999999999 999999999999999999999999999999

輸出範例:

1999999999999999999999999999998
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 2.2k views

16 Answers

0 like 0 dislike
Hidden content!
* *** * * * ***
* * **** **** **





int main()
**** * ** a, b, c;
** * ** * * ** * * *** * **
* *** ** = a + b;


***** * ****** ** c);


* * ** * * **** * * ** * ** *



return 0;
**** ** *
answered by (-98 points)
0 like 0 dislike
Hidden content!
*** *** * *** **


** ** ** ** * *


******** * **


* *** ** ***




* ** ( * * )

{


* * *
** * = ** ** * * *
** * * * ** * * * **




= *** + * *




* * ** ** ** *










*** 0;

}
answered by (-276 points)
0 like 0 dislike
Hidden content!
* * ** ** * * **

#include ** *** *

int main (void)

{
* ** c;
* * a,b;
* * * **** ** ***** * *** *** *
*** *** * **** * ** ****
* ** *
*** *** * ** **
***** * * 0;

}
answered by (42 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * ****** ****

void rect(int ,int,int *);

int main(void)

{
* ** ** * **** * * a,b;
*** ** ** ** ** sum;


* * ***** ** ** * * * * *


* ** *** * *** *** * ** ** *
* ** * * * ** * ** *** * * *** * ** * **


** * ** * ** **** ** * * *** * ** ** **
** * **** ** **** 0;

}
** ** ** *** *** rect(int x,int y,int*p1)
* *** * * * *
* ** **** ***** * * ** * ** **


** * * **** * ***
answered by (-114 points)
0 like 0 dislike
Hidden content!
* * * * ****** * *
* ** **** *** *



int main()



{
* ** * * * *** *
** * *** **** ** ** *** * **** ** * * *****
* = num[i] + num[j] ;
*** * * * * **** * *** * *
**** **** * 0;



}
answered by (-50 points)
0 like 0 dislike
Hidden content!
#include * *** **** * *



int main (void)

{
*** * * * ** ** ** * num1,num2,sum;
** ** *** * * * ** **** **** * * ** * * ** * *
* ** * * ** ** ******* * = num1 + num2;


* **** *** *** ** *** * ** ** ****** **
****** ** ***** ** 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.178.12
©2016-2025

Related questions

0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 6.8k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 4k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 5.4k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.4k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users