0 like 0 dislike
11.1k views
翻譯的工作有時候是依翻譯的字數來計價的,請設計一個程式計算一個句子中有幾個單字,在一個句子中被標點符號或是泛白字元隔開的可視為一個單子。

輸入說明:輸入會包含英文字母、數字以及標點符號,當程式遇到句點(.)時代表輸入結束。

輸出說明:請輸出一個整數代表輸 入的句子當中包含幾個單字。

輸入範例:

According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers.

輸出範例:

22
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 11.1k views
0 0
Called for Help

86 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
* ** *** * * * ** * i=0;
* * * * * ** * * *** ***
* ** * ****** ** * * * * ** * * * *
** ***** * * ** ** ****** * ** ** ** **** ***** ** * **
*** * ** *** ** * ** ** ** * ** *
* ** ********* * * * ******** i;

}



int check2(char c)

{
** * * *** * **** j=0;
*** * * *** * ** *****
* * **** * ** ***** *** ******* *
** * * **** * *** ** * * ** * *** * *** * ** **
* ** * ** ** ** ** * * * * * * ****** *
** * * *** **** * ** * * * j;

}

int main(void)

{
** * **** ** * ** * ****** c;
* * * * * * ** ** ** *** i=0,j=0;
* * ** * * * *** * * * * ** * **** * ***** * * *
* * * * ** ** ** ** c!='.')
*** ** *** * * ** * * *


* * ** * ********* * **** **** *** * * * *** *
* *** **** * ** *** ***** *** ** ** * * ** **
***** * * * *** * ** **** **** * * **** * *** ** * ** * * *

    }
* * ** * * **** * * * * * * *** * *** **** **** *** ** * ** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include * ** *** *

#include <ctype.h>



void check (char c);

int main (void)

{
* * * * **** ** * space;
* ** * * * c;
** *** * * * * *** * * * **** **** **
** ***** ***** * * *** (c!='\n')
* **** ** *
* ********** * ****** ** * ** * ** * **** * *
* * * * * * ** ** ** * ** (c);
** *** * *** ** * *
* * *** ** * * * * * * ** * *

}

void check (char c)

{
* ***** ** * ** space = 0;
***** * *** * (isspace (c))
* ** * * * * * ** * * ** * * ***
** * * **** ** ** * * (ispunct(c))
***** * * ***** * * * * ***** ******** * ****
***** * ** * ****

}
answered by (-42 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
** * *** ** ** * * i=0;
** *** ** ** * ** * *
* * ** ** * ** * ** ** *** ***
* * ** * ** ** *** ** ** ** * ** ** ** *** * * ** *** *
** ** * * *** ** ** * ** * * *
****** ** * * ** *** i;

}



int check2(char c)

{
** * * * * ** * * ****** j=0;
****** **** **** **** * ** ** *
**** **** *** **** ** *** *** *** * * **
* **** ** * ** * * * ******** **** ** ** ** * * ** * * *
* * **** * *** **** *** * ** * * ****
* * * * ** ** ** * * ** j;

}

int main(void)

{
* * * ** * ** * ** c;
****** ****** *** i=0,j=0;
** ** **** *** ** ** * * *** * *** **
** * ***** * * ** c!='.')
* * * *** * ** * *


* ** ** ** * * *** ** **** * ** * ** * ****** ***
* * **** * ** * ******** *** * ** *** * *
********** ** * **** ** *** * ** * ** ** * * *** ** *** *****

    }
* * * * *** *** * *** ** **** * ***** * ** * ** **** ***** **** * *** *



return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
//  Created by HoMingJui on 2016/11/3.

//



#include <stdio.h>

#include <stdlib.h>

#include <ctype.h>





int main(){

    char a,t=0,flag=0;
* * * * **** * * **** * * * * * ** *
** **** **** * * ** !='.'){
* * * * ** * ***** ** ** * * **** * * * * **
* * ******* *** ** **** * **** **** *********** * * *** * *** ** ** *** *
* **** * ** ** * ** ** *** * * * * ***** * ** ** *** ** * * ******** * * ** ** ** **** *** * ****
** * **** *** * ** ******** ** *** * **** * ** * **** ** * ** * * * **** **
** * * * * * ****** * * * * * * * ** * ******* * * * ** * *
**** ** * ** * *** * ** * ** * ***
* * ***** * **** * * * * * ** **** * * ***
* **** ******* **** * * *** ** * *** ** ******* * ** * * ***
** **** *** ** ** * * * *** * *** * *
* **** ** * *** ******* * * * * ** * * * * * * *** * * **

    }
* ** * * *** * ** * * * * ** ****
* * * ** ** ** 0;

}
answered by (-126 points)
0 like 0 dislike
Hidden content!
#include ***** *

#include ****** * ** *



int * {
* * * * * * input[80];


* * *** * * * *** * * * * * * input);


* *** ** * ** length = ** ***
** * ** ** * * **** * ** * ** *** **** * ** * length);


**** * ** * * * ***** 0;

}
answered by (-90 points)
0 like 0 dislike
Hidden content!
#include ** * ** *
*** ** *** ** *
******* main()



{
**** * ** *** * a[9999];


** * ***** * * ****** n;
* * ** ** * *** *


** ** *** **** ** * ** = ** *


* *** * * * * ** ** *** *** **** **** n);


** * ** ******

return 0;



}
answered by (-72 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include ***** * *

int main()

{
* * * * * * ** ** * * c;
**** ** * **** alnum=0;
* **** * ** * * ** * ** **** &c);
* ** * ** * * ** * != '\n')
***** * ** *


**** *** * ** * *** **
* **** *** * **
* ** **** * **** * * ** * **** ** * = alnum + 1;
*** * ** * ** * *
* ** * * ** *** * * ** * * * *** &c);
* * * * * *
* ***** * * * * ** ***** **** ****** ** *
** ** * * * * *** * *** 0;

}
answered by (-52 points)
0 like 0 dislike
Hidden content!
* *** ** ** *
* ** * ** **** ***

int main (void)

{
* ** c;
** * i;


* * ** ** ******* * * *** **
*** ** *** c!= '\n')
* ***
* ** *** ( ** **** (c))
** ****** ** * *
**** **
** * ** * * **** ** *


* *** ** 0;



}
answered by (42 points)
0 like 0 dislike
Hidden content!
** * * * ** * * *
*** * **** *****

int main (void)

{
* * ** c;
** * * **** i;


** ***** * *** **** ** **
** *** * c!= '\n')
** *
** ****** ( * * (c))
* * **** * * **
**** ****
*** * * * ** *** * *


* * * ** 0;



}
answered by (42 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

#include <ctype.h>

int check1(char c)

{
******** **** * ** ** * i=0;
******** * ** ** ** ** ** * ** *
********* ** * * * ** * * ** **
* * ** * ***** ** * **** * * * * * ** * **** *
* ** * ******* ** ** * ** *** ***
*** * **** ***** * * *** * *** * i;

}



int check2(char c)

{
** ** * ** * * * * ** j=0;
** * *** * ** * * *
***** * ** * ** * ** *** * * * * **
* * ****** * *** **** * **** * **** *** **** * *** * **
* ** *** * * **** * * * * ****** * * *
* ** *** * *** ******** j;

}

int main()

{
* ** **** * * *** ** ** **** c;
** *** * ** **** * i=0,j=0;
* * ****** ** ** ** ** * * ***
*** * ** * * * * * * * *** c!='.')
** **** * **


****** *** *** * ** * ***** * * * ** ****
* * * ***** * ** * * * ** ****** * * ** *
* **** ** * * * * * * * ****** ** *** * * * ** * ***** ** ** * *

    }
* * ** * ******* * * ****** * * *** **** * ** * * *** *** *



return 0;

}
answered by (-248 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.248
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.3k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 6.3k views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8.8k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.8k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users