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AD 20161103 作業1
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請設計一程式，使用者輸入一個正整數N，程式會輸出相對應的費氏數列第N項。
sample input:
10
sample output:
55
[Exercise]
Coding (C)
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asked
Nov 3, 2016
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Shun-Po
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ID: 16957 -
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int plus11(int num)
{
* * ** * * ** * * ** *** a,b=0;
* * * * * * ** * * ** * * ** **** ** * * * * **
* * ** ** * * * ** ** * * * * * * ** ** *** = b+a;
* * * ** * ** * * * ** ** * * * *** ** * ***
** *** ** * *** *** * * * * *** ** * *
* ** * * * * *** * ** * *
* ** * * * * *** * * * ** *
int main()
{
*** * * * **** * * * * *** ** num;
***** * ** * * * ** * * * * * * ** * ** * *
* * * ** *** * *
* * *** * * *** * **** *
** ** * * *
* * * * ****** * * *** * ** * * ** ** * *
** ** * * * *** * * * ** ** ** 0;
* ** ** * * ** ** ** * **
* * * ** * **
*** * * * * **** * **
** * * * * * * *** * * *
**** * * ** * * * * * * **
* * * **** ** * * * **** * * ** *
answered
Nov 3, 2016
by
andreas lu
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
** ****** ** * ** * * * ** i,n,fi,last1 = 1,last2 = 1;
* * * ** * * * * * * * * ** * * ***
* * ** *** ** * * * * ** * ** * *** * * * * **** * ** *
* ** ** * * * * ** * ***
** * * ** * * ***** * *** * * == 1||n == 2)
* * * * ** *** * *** ** * * ** ** * ** * ** * ** ** *
** * * * * ** * *** * *
* ** * * ** * ** * ***** * ** **
** * * ** * * * * **** * ** * * ** = 3;i <= n;i++)
* *** *** * * * * ** * * * ** ** * + last2;
*** *** ** * ** ****** * * ** **** ** = last1;
* ** ***** * ** ** ** * * * ** ** = fi;};
** * * * ** * ** * * * * * * * * ** * * * * *
** ** * * ** ** * * * * * *
* * * * * * ** * * * * * ** * ** * * **** * * *
* * * * * ** * * *** ** ** ** *** * 0;
}
answered
Nov 3, 2016
by
謝秉弘
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(int num)
{
* * * * ** ** * * * i, num1 = 1, num2 = 1, sum = 0;
** * * * * * * * ** * * **** ((num == 1) || (num == 2))
* * ** * *** * ****** * *** *
* ** ** * ** ** ** * ** * * * ** * **** * * ** * * 1;
** * * * *** ** * ** *
* * * * * * * * ** *
* * **** ** * ** **
* * * ** ** * * * ** * * * ** ** * *** * * * * * * (i = 3; i <= num; i++)
* * * *** * * * * *** * * * ** ** *
* * * * * * * * * ** ** * * * * * * ***** **** * * * * * * *** ** * = num1 + num2;
* ** * ***** ** * * ** * * *** ** * * ** * ** * * * * * * * * * *** ** * **** = num2;
* * *** * * ** * * ** * ** * * * * **** ** * * * *** * ** * * *** * ** = sum;
* * * * * ** ** * *** *** ** ** * * ** *** * * *
*** * **** *** * * * * * * * * ** ** * * *** sum;
** ** * * * *** ** *** **
}
int main()
{
* * * *** * *** * * num, sum;
* ** ** * * * ** * * * * * * &num);
* * * * * ** * * ** **** * * = sumNfiS(num);
** ******* ** * * * **** * * * *** * **** ** sum);
* * ** * ** * *** * * * *** 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * ** ***** ** * * * int num;
**** * ** ** * * * * * a,n,b=1,c=1;
** ** * * * * * * * * * * ** * ** *** ** * **
* * * * * * * * * ** ** * ** **
{
* * * * ** * * * * * *** * ** * * * ** * * * * *
* * ** * *** *** * *** ** * * * * * * * * ** ** * **** * ** * ** *
}
* * *** *** * ** * * *
{
* * * * ** * * * * ** * * ** **** * *** ** ** * ** * ** ** *
** * * * * * * * *** * * * ** ** * * ** *
* ** ** * * ** ** * ** * ** ** * * * * * * * * * * *** ** ** * ** * ****** *
* **** ** * * * * ** *** * * * ** * ** * * ** * *** * * * ** * * * * *
* * * * * * * * * * * * * * * * * ** * * ** ** ******* * **** * * *
**** * * ** * ** * * * * * ****** * * **** * ** *
** * ** * * * ** ** * * * * * * ** * ** * **** ** ** * ** * * *
}
* ** * ** * ** *** ** * *** ** *** *** * * * *
* * * * * ** * * ** ** ** * * * 0;
}
answered
Nov 3, 2016
by
steven0221
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(num)
{
* * **** * * * * ** * * i, num1 = 1, num2 = 1, sum = 0;
* * *** ** * * ** * * ((num == 1) || (num == 2))
** * * * * *** ** * ** *
* * * **** ** * *** * *** * * * ** ** * * * * *** 1;
** * *** * * * * * ** **
*** * * * * * ** * * *
** * * * * * ******* ** *
** ** * * ** * ** * * * * * * ** * **** * * * ** * * (i = 3; i <= num; i++)
**** * * * * * ** *** * *** * *** * ** * ** ** * *
* * * ** * ** * * * *** * * * ** ** ** * * * ** * * * = num1 + num2;
* ** * * ** * ** ** ** * * ** * * * * ** * ** ** ** * *** **** * = num2;
* * ** * * ******* * * * * * *** * **** * ** * * * *** * * * * * ** = sum;
* ** * * * * * ** * ** **** * * * * *
* * * ** ***** ** ** **** * ** * * * * * ** * * * * *** **** sum;
* * * **** ** * *** * * * * *
}
int main()
{
** * * * * *** * *** * ** num, sum;
* * * *** *** * ** * * ** ** ** * *** * * &num);
** * * * * * * * = sumNfiS(num);
* ** *** * * *** * *** * * * * * sum);
** * * * ** * * * * **** ** 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
* ** * * * * ** * * *
#include<math.h>
int main()
{
* * * * ** ** * * i,j,k=0,a=1,b=1;
* * * ** *** * * * * *** *** ** **** *
* * * * * * * * || i==1)
** * * *** ** ** * * * * * * **
* * * * ** *** * * *
{
* **** * *** * * * ** * *** * * * **
{
* * * * * * ** ** * * * * *
* *** * * * * *** * ***
** ** * * * *** ** * ** * *
}
* * *** ** * ** * * * * ** ** *
}
* * * ***** * * * 0;
}
answered
Nov 3, 2016
by
jack2234567
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* * * * k, num1, num2, i;
* ** * * * * * * *** = 1;
* *** ** * * ** * * ** * = 1;
** * * * *** ** * == 1 || x == 2)
* * *** * * * *** * ******* ** * * * * ** * * ** *
* * * * ****
* ** **** * *
* * * ** * ** * * * * * ** * * * * * * ** = 3;i <= x;i ++)
* * *** *** * * * *** * ** **
* * ** * ** * ** * ** * *** * * *** * ** * * * * ** = num1 + num2;
** * * * * ** * * * *** * * * * * * ** **** * * * = num2;
** * * * * * * ** * ** * *** *** ** * = k;
* * * * * ** * * ** * ** ***
* * * * * * * * *** ** ** * * * * * * * ** *** k);
* * * * * **
}
int main()
{
* * * * * * * * *** x;
* ** ** * ** * ** ** * &x);
* * * ** * * * * * *
* * * * * * * * 0;
}
answered
Nov 3, 2016
by
410511226
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int fas(int N)
{
* *** * * * * ** * * * * * ** i,sum=0;
** * * * * * * * * * x=1,y=1;
* * * * * * * * * ****
* ** ** * * * ** * * *** * * ** * ** * * ** * * ** 1;
* ** * *** * * * ** * *
*** * * * * * * *** * * ** ** ** * * *** * * 1;
* ** ** * * * * ** *** * *
{
* * ** ** * * * ** * * *** * * * ** * * ** ** * ** ** ** *
** * ** * * ** * * ** * ** ** * * ******
* * * * * * * * * * * ** * ** * ** * * * * ** * ** * * * = x+y;
* ** * *** * * * ** *** * * ** * *** * * * ** * * * *** = y;
*** ** * * ** ** ***** * * * * **** * * * * * * ** * * = sum;
* * *** * **** * *** * *** * * * ***** * ** * *
* * **** * * ** * ** * * *
* * * * * ** ** * * * * * sum;
}
int main()
{
* ** * * * * ** a,total=0;
* *** *** *** * * * ** ** * * * * * * ***** * *** *
**** * * ** ** * ** * **** = fas(a);
* *** **** ** * * ** * * * *** * * ** ** **
* * * * * * ** *** * * * * * * * * * * *
* *** * * * * * * ** * * * * * 0;
}
answered
Nov 3, 2016
by
410523043
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156
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* * * *** * *** * * * k, num1, num2, i;
* * * **** * ** * ** = 1;
* * ** ** * * * * = 1;
** ** * * * * * * *** * == 1 || x == 2)
* * * * * * ** ** * * ** * ** * ** *** **** *
** * * * * * * *
* * * ** *
* * * ** ** * *** * * * ** * * * = 3;i <= x;i ++)
* * *** * * ** ** ** * *** ** * ** *
* * ** *** *** * * *** ***** *** * ** * * ** * * * = num1 + num2;
*** ** * ** * * * * ** ** * * ** * * * * * * ** * ** = num2;
** * * * * * * * * *** * * * * * * ** * * * * * * * ** = k;
** * *** * * * * ** * **** ** * *
* ** ** * ** * **** *** ** * * ** * ** * * * * * k);
* ** *
* *** * *** * * * * * ** 0;
}
int main()
{
** * * * ** * * x;
* * * **** ** * * * * *** ** * * &x);
** ** * * * **** * *** * *** * *
*** * * ** * * * * * * 0;
}
answered
Nov 3, 2016
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410511226
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Hidden content!#include ** * ** *
#include * * * *** *** * *
int printFF(int n);
int main(int argc, char *argv[]){
* *** * ** * * * * * a,b,sum;
** * * *** *** *** * * * ** ** * * *** * * * * * *
** * * * * ** **** * * = printFF(a);
* * **** ** * ** *
* * * * * * * ** * * ***** ** * *** * * *
* * *** * ** * * * ** ** * * * * * * *** * * ** * * ** * * *
* * * * * * ** * * * 0;
}
int printFF(int n){
*** *** ** * * * *** * * * ** * * f[10000]={1,1,0},i;
* ** * * ** *** * * * * i <= n; i++)
* ** * * ** ** ** * * * * * * ** * * ** ** * * * * * ** * * **** * ** ** * * * * *** *
* ** ** * *** ** * * *** f[n-1];
}
answered
Nov 3, 2016
by
Dhgir.Abien
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