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AD 20161103 作業1
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請設計一程式，使用者輸入一個正整數N，程式會輸出相對應的費氏數列第N項。
sample input:
10
sample output:
55
[Exercise]
Coding (C)
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asked
Nov 3, 2016
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Shun-Po
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ID: 16957 -
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int plus11(int num)
{
* **** * * * ** * * * * * * a,b=0;
* * ** ** * * * * * * ** * * *
* * * ** * * ** * * * ** ** * *** * * * * = b+a;
* * * * * ** *** * ** * *** * * *
* * **** * * * * * * ** * * * * ** * * * **
** * * ** ** ** * ** * *
* * * * * ** *** ** * * **
int main()
{
* * * * * * * * *** *** * * num;
* ** * * ** ** * * * * **** * *** ** * *** *
* * * ** ** **** * *** * *** *
* * * *** *** * ** *
* * * * * *** ** *
* * ** * * ** * * * * *** ***** * ** ** *
* * * * * * * * * *** * 0;
** * * **** * *
* * *** ** * * * * * ** * *
* * * *** * ** * **
** ** * ** ***** * * * * *
** * * * *** * ** * ** *
** * * ** * ** * * ** ** ** * *
answered
Nov 3, 2016
by
andreas lu
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * * * *** * * **** * * ** i,n,fi,last1 = 1,last2 = 1;
* ** ** *** * * * * * * ** * * * *
** ** *** ** ** * *** * ** * * *** * * * * * * ** **
**** * **** * * ** *** * * * ** * **
* ***** * * * * * * ** * ** * * == 1||n == 2)
* ** * * ****** * * * * * * * * * * ** **** ** * ** * *
* ** * * * * ** * ** **** * ***
**** * *** * * * **** * * * * * **
**** * * *** * **** * = 3;i <= n;i++)
** * * ** * * * * ** * * * *** * ** + last2;
* * * * * ** * *** * * * * **** * = last1;
** *** * ** * * ** * ** ** * ** *** = fi;};
***** * * * ** * * ** **** * * *** * * *
*** * * * * *** ** * ** ** * *
* * * ** * *** * * ** *** * * ** * * * *
* *** * ** * ** ** * * **** * ** 0;
}
answered
Nov 3, 2016
by
謝秉弘
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(int num)
{
*** ** * * *** * ** * * i, num1 = 1, num2 = 1, sum = 0;
* ***** **** * * * * ** *** * ** ((num == 1) || (num == 2))
* ** ** * * * * **
** ** * ** * *** * ** ** ** * * * ** ** * ** * 1;
* *** * * * **** ** ** *
** * *** * * * * * * * *
** * * ** * ** * *** * * * *
**** ** * * * ** *** * ** ** ** * * * * ** * * * ** * (i = 3; i <= num; i++)
* ** **** * ** ** * * * * ****** * * * * * ** *
* ** * * * ** * * * * * ** *** * ** * * * * * * ** *** * * ** * * * = num1 + num2;
** * ** ******** * * * * * ** * * * * ** * * *** * * ** * * ** * ** * * * = num2;
**** * * * ** ** * * * * * * * ** * * * *** * *** * *** ** * * = sum;
* ** * ** ***** * ** * ** * * *** * * *
* * *** ** ** * ** ** * ** * * * * * * * * **** * * * * * * sum;
***** * ***** * * * * * * *
}
int main()
{
* * * * ** * * * ** num, sum;
* * ** * * * * * ** **** * * * ** * ** * ** * &num);
* * * *** ** * * = sumNfiS(num);
** ** * * *** * ** * * * * * * ** * * sum);
* *** * * * * * * * * *** 0;
}
answered
Nov 3, 2016
by
410314217
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-214
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* ** * * *** ** * * * * * int num;
* * * * ** * * ** * * * * a,n,b=1,c=1;
* ** * * *** ** * * * * ** * * * ** * * *
* ** * * *** * ** **** * * **
{
**** ** * * * ** * * ** ** * * * ** *** * * ** *
***** **** * * * * * ** ** ** * * ** * * * * ** * ** * * ** ** ** * *
}
* ** * * * *** * * ***** * **
{
*** * * * * * ** * * * * * **** ** * * *** * * * * * ** *
* **** * * * * * *** ** * * **** *
* ** * * * * *** ** ** * * * * **** ** ** * ** ** ** ** ** ** ** * * * ** *
** *** * ** * ** ** * ** * ** * * * * * ** * *** * **** * ** ** * * * * * ** * *
* * * ** ** * * * * * * * * * *** * *** ** ** * ** *** ** * * * * *
** ** * ** * *** *** * * * * * * * ** ** **** *** * * * *
* * ** * * * ***** *** * ** * * **** ** **** * * **** * ** * * *** * * *
}
* * * * * ** * * ** * * *** * * ** **
* * ** ** *** * * ** * ** * * ** * 0;
}
answered
Nov 3, 2016
by
steven0221
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(num)
{
* * * * ** * * * * * * * i, num1 = 1, num2 = 1, sum = 0;
* * *** * ** *** * * * ((num == 1) || (num == 2))
*** ** * * * * **** * *
* ** * ***** * * * ** ** *** * * ** ** **** * ** * 1;
* * ** * * * **
** * **** ** ** ** *** * * * *
* * * ** ** * * * * **
** ** ** * * ** * * * ** * * * * * * * (i = 3; i <= num; i++)
* * * * * ** ** * * * * ** * ** ***
** * * * * * * ** * ** * * * * ** * * * ** ****** * * * ** * ** * *** *** * * = num1 + num2;
* ** ** ** ** ** * * ** **** * * * * * * * ** * ** * ** * **** * **** * = num2;
*** ** * * * *** * * ** * **** * * * * * *** * * ** * *** ** * = sum;
* * *** * *** ** * * * ***** ** * * ** **
*** * * * * ** *** * *** * ** * ** * * * * ** ** ** * **** sum;
* ** ** * * ** *** ****** * **
}
int main()
{
* *** * ** ** * * * **** * num, sum;
* **** * ** * * ** *** * * * * * * * * * &num);
* * ** * * * ** ** ** * = sumNfiS(num);
* ** *** * ** *** * * * ** * * * * * * sum);
* * * ** *** * * * 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
* ** * ** * * **
#include<math.h>
int main()
{
**** * ** ** * * * * * ** i,j,k=0,a=1,b=1;
* * * * * **** * * *** * * ** * * * ** *
** **** * ** * * * || i==1)
* ** * ** ** * * * * * * * ** * *
* * * * *** * * **
{
** * ** * * * ** * * * * * * ***
{
** * * ** ** *** * * ** * ** **
* *** * * * * * ** ** *
* * * ** * ******* * *
}
* ** **** **** * * * * * * ** * ** *
}
* ** * * ** * * *** ** 0;
}
answered
Nov 3, 2016
by
jack2234567
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
** * * ** ** * * ** ** * k, num1, num2, i;
* * ** * ** * *** * = 1;
* * * * * ** *** * = 1;
* * * * ***** ** ** * == 1 || x == 2)
* ** * **** ** * * ** * ** **** * ** ****** ** ** * ** * * *
*** *** * ** * *
*** ** * * ** * **
* * * * * **** * * ** ** * ** = 3;i <= x;i ++)
* * ** * ** ** * ** *
* * ** * * * * * * * * * * * * * * * ** * = num1 + num2;
* ** ** * * * * * ** * *** * * ** * ** * ** ** * = num2;
* ** * * * * * * * * * **** * * * * * * *** *** *** * ** = k;
* * *** * * *** * ** ** ** ** * * *
* * * *** **** ** * * * * * * * * ** * * * * * ** * ** ** k);
* * ** * * ** * *
}
int main()
{
* ***** * * ** ***** ** x;
* * * * ** * ***** * * * * * &x);
** * ** * * * *** * * **
* *** * * ** * * * ** 0;
}
answered
Nov 3, 2016
by
410511226
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int fas(int N)
{
* * * * * ** ** ** * **** i,sum=0;
* ** * * ** * ** * x=1,y=1;
* * * * * * * ** **** **** *
* * * ** * *** * * *** * ** * * * * ** * * * * * ** * * 1;
* * * * * * ** * * * ** *
** * * * ** * ***** * * * * * *** * ** ** * 1;
* * ** ** * ** * *** ** * *
{
* * * ** * * * * * * * * ** * * ** ** * * * * * * * * **
** * * *** ** * * * * ** * * * * * ** *
** * ******* *** ** * * * ** * *** * ** ** * * * ** * * ** *** = x+y;
* * * ** ** * ***** * *** ** * * * * *** * * * * * * * = y;
* ** *** *** * ** * ******** * * * * * * * ** * * * **** * ** = sum;
* **** * * * ** * * *** * ** * * *
*** * *** * * * ** ****
** ** * * ** * ** sum;
}
int main()
{
* * * * * * * * * * * a,total=0;
* * * * ** *** * * * * * *** *** ** * * ** * **
* * * * * * * ** * * ** * = fas(a);
** * * ** ** * * * ** * ***** * * * **** * * * *
*** ** ** ** * ** * * * * ** ** * **
* ****** * ** ** *** * ** * * 0;
}
answered
Nov 3, 2016
by
410523043
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156
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
** * * * * ** * * * k, num1, num2, i;
* ** * * * ** * = 1;
* * *** * * * * * * * * = 1;
*** * * * ** * ** * * == 1 || x == 2)
* ** * * ** ** * * * * * * * * * *** **
** ** * ** *
* * * *** **
**** ** * * ** * ** ** * * * * * ** = 3;i <= x;i ++)
* * * * * * ** * * * * ** * ** * ** **
** * * * * * ****** ** * **** * * * ** *** ** * * = num1 + num2;
* * ** *** * ** * * * * ** ****** ** * ** * * *** * = num2;
** ** * * * ** * * * * * * * * * ** ** * * ** * = k;
* ** * * * * * * * ** * * * * * * *
** * * ** *** ** ** * * * * * * *** ** * * ** ** ** * * * * k);
* ** * * * **
** ** * *** ** * * 0;
}
int main()
{
* * *** * * * x;
* ** * ** * * *** **** * ** ** * * &x);
* * * * ***** ** * * * * * **
* * * ** * ** ** *** * 0;
}
answered
Nov 3, 2016
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410511226
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Hidden content!#include ** ** ** * *
#include *** * * *
int printFF(int n);
int main(int argc, char *argv[]){
** * ** *** * ** * ** a,b,sum;
* * * * * * ** * * ** * * * * * * ** * ** ** *
* * ** * * * * * * ** = printFF(a);
* * * * *** ** ** *
* * * * ** * ** * * * * * * *
* * * * * * * ** * * ** * ** *** *** * * * * *
* * ** * ** * * * ** * * * ** 0;
}
int printFF(int n){
* *** * * ** * * ** ** * * * f[10000]={1,1,0},i;
* *** *** * * * ** * * *** ** * * i <= n; i++)
* * ** ** *** * * * * ** * ** * ** ** *** * * **** * * * * * ** * *** * *** * ** * *
* * ** * ** * * * ** * f[n-1];
}
answered
Nov 3, 2016
by
Dhgir.Abien
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