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AD 20161103 作業1
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請設計一程式，使用者輸入一個正整數N，程式會輸出相對應的費氏數列第N項。
sample input:
10
sample output:
55
[Exercise]
Coding (C)
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asked
Nov 3, 2016
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Shun-Po
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ID: 16957 -
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int plus11(int num)
{
* * * ** ** ** * * * a,b=0;
*** * * * ** * * * ** * *** ** * * * ** * ** ****
** * * * ** * ** * * * ** * * * * * * ** = b+a;
** * * * * * * * * ** *** * * * *** * *
* * * * * * * *** * * ** * * *** ** * * * * *
* * ** * * * * * * * * * **
******* * ** ** * * ** * * *
int main()
{
** *** * * * ** ** ** ** num;
* * * * * * *** * * * * * *** ** ** * * **
*** * * * ** * * ** * **
** * * * * * * ** * ***
** ** ** ** * * * * * *
* * * * * ** * * * * * * * ** * * * *
** * * * **** * * * ** * ** 0;
* * * * * *** * *
* * ** * * ** **
*** * ** * ** ** * * * * ** **
* *** * * * * * *** ** *
** ** * * * ** * * * * * *
* * * ** * * * ** **
answered
Nov 3, 2016
by
andreas lu
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * ** * * * ** * * * *** *** ** i,n,fi,last1 = 1,last2 = 1;
** * * * **** * ** ** * * * * * *
* ** ** ** * * * * * * ***** ** * ***** * **** * *
** * *** ** ** * *** *** ** ** * * *
** ** * ** * * * * * ** ** ** == 1||n == 2)
* * * * ** * * * ***** * *** ** * * ** *** ** *
* ** * * * * * * * ****** *
* *** * ** **** * * * ** ** *
** ** * *** * * * * *** * ** * * * * = 3;i <= n;i++)
* *** * * ** ** *** * ** * ** * + last2;
* * **** * * **** * ** * * ** * * ** ** * * * = last1;
* * * **** ** *** ** * * * ** * * = fi;};
* ** * *** * * ** ** * * * *** *** * * * ** * * **
* * * * ** ** ** * * * *
*** * * * * * ** * * * ** ******* * * *** ** * * *
** * * * * * * * * ** * * * *** * 0;
}
answered
Nov 3, 2016
by
謝秉弘
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(int num)
{
* * * * **** * * * ** * * * * i, num1 = 1, num2 = 1, sum = 0;
* * ** * * ** * * * ((num == 1) || (num == 2))
** ** * * **** ****** ** * *
* ** * * ** * ** * ** * * * * * * *** * * ** 1;
** * * * ** * * * * **
** * ** * * * ** * *
* * * * * ** * *
* * * * * * *** * * ** * * *** *** ** * * * (i = 3; i <= num; i++)
* * ** *** ** ** * * ** ** ** ** ** * * **** * ** * **
* ** * * * * * * ** * * *** ** * * * * * * ** ** * * *** * * = num1 + num2;
* ** * * *** * * * * *** * * *** * **** ** * * * * *** ** * * ** * * = num2;
*** * * ** ** * * * * **** * ** * * * * * * * * * * *** * * * * * = sum;
** ** * ** * * **** ** ** ** * * ** *** * * **** * * * *** *
* ****** * * ** * * * ***** * *** ** * ** * * ** sum;
* * * ** * * ** * **
}
int main()
{
** * * *** * ** * num, sum;
*** *** ** ** * * * * * ** ** * * ** *** &num);
* * ** * ** ** * * ** ** * = sumNfiS(num);
* * ***** * ** ** * ** **** ** * * sum);
* ** * ** * ** * ** * 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * * * * * * * *** * ******* ** int num;
** ** ** ** * * * * ** * ** a,n,b=1,c=1;
* * ** * * * ** * * * * * * *** * * **** * ** * *
* ** *** **** *** * * ** ** ** * *
{
* **** ** ** * * **** *** * ** * *** * * * * ***
** * * ** * * ** * * ** * * * ** * ***** * ** ** *** * * * ***** * **
}
* * *** * * ** *
{
** ** ** *** * * ** ** ** * * ** * *** ** * * *** ** * *
*** ** ** * * ** *** * * **** ** ** * * * * * * **
* * * * *** * ** * * ** ** ** * * ** * ** ** * * * * ** * *** *
** ** ** * *** *** * ** * * ** *** * ** ** * ** ** * * * ** *
* ** * ** * * * *** * ** * ** * * ** * * * *** * ** **
** ** * ** *** * * * * * * * ** ** * * ** * *
* * * * ** * ** ** * * * * * *** * ** ** ** * * *** * * ** ** * * * *
}
*** ** * ** ** ***** ** * * *** * * ** *
* * * * ** ** ** * ** * 0;
}
answered
Nov 3, 2016
by
steven0221
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(num)
{
** * * * * ** * ** * * * i, num1 = 1, num2 = 1, sum = 0;
* ** * *** * * * * * ** * ((num == 1) || (num == 2))
** * * * * *** ** * ** * * *
* *** *** *** ** ** * ** ** * * * ** *** * * * ** * * 1;
* * * * * * ** *
* * * * * * ** * *** *
** * * * ** * * ***
* ** * * * * * * ** ** ** ** ** ** * * ** * * * (i = 3; i <= num; i++)
* ** ** *** *** * ** * * ** *** * * * * ** * * * * * *
* * ** ** * ** ** * * * *** * ** * * * **** ** ** * ** * ** * * * * ***** = num1 + num2;
* * ** * * *** ** *** * * * ** * * *** * * * ** * * * * * = num2;
* ** ** **** ** * * ** * * ***** ** * * * * * * * * * * ** * **** * * * * * = sum;
**** * * ** ** * * * ** * * * * * * * * *
* *** ** *** *** **** * * * ** * *** * * * * *** ** ** * sum;
* * * * *** * * * *
}
int main()
{
*** * * * * ** * * * num, sum;
* * * *** * * * * * * *** ** * ** **** &num);
* * * * * * * * * = sumNfiS(num);
* *** * * * * ** * * * * * * ** * * * * sum);
* * *** * * * * * * ** ** 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
* * * * * ** ** * ** *
#include<math.h>
int main()
{
** * ** * * * i,j,k=0,a=1,b=1;
* * * * * * * ** *** * * * * ** ** ** * * * *
* ** **** *** ** ** * *** * || i==1)
* * * * * * ** * ** * * ** ** * **
*** * ** * * * *** * *
{
* * * * ** ** * * ** ** *
{
* ** ** * ** ** *
* * ** * ** ** **
* * ** * * * * * * * ****
}
** * * *** * * **** *** * *** * * * **
}
* * * * ** * * * * * * 0;
}
answered
Nov 3, 2016
by
jack2234567
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
** * * * ** * * k, num1, num2, i;
* * * * ** ** = 1;
* *** * * ** * ** = 1;
* * * * *** *** * ** == 1 || x == 2)
** * * * * * * * ** ** *** ** * **** * * *** * * *
* * ** ***** ** * * * *
* ** * * * * ** **
* ** ** * **** **** * ** * * * * * *** = 3;i <= x;i ++)
* * * * * ** * * ***** ** * * *
** * ** * ** * * * * * * * * * * * ** * * ** * ** = num1 + num2;
* *** * ** * * * * ** * * * * * *** ***** * **** ** * ** * = num2;
*** ** * * * *** * *** ** *** * * * * ** * * = k;
* * *** ** * *** ** ** * * ** * * *****
*** ** *** * * * * ** ** ** * * ** * *** * ** * ** * k);
* * ** * * *** **
}
int main()
{
* * ** * * * * * *** * x;
** *** * ** * * * ** * ** ** &x);
* * *** * * * ** * ** *
* * * * * ** * ** * 0;
}
answered
Nov 3, 2016
by
410511226
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int fas(int N)
{
* * * * * * ** * * i,sum=0;
* * * * * * ** * * ** x=1,y=1;
* * * ** * * ** * **** * * * * *
* * * ** * *** * ** * * **** * ** ** ** * 1;
** * * * * * * * ** ** *
*** ** ** *** * * * * * ** ** ** ** * * * * 1;
* * * ** * * * * * **
{
** * * *** * ** ** * * * ** ** * * * *** * *** * ** ** * **
** * *** * * *** * * * ** * * * ** * *
* * * ** ** **** * * * * ** ** * ** * * * * * * ** * *** ** = x+y;
* ** * * * ** * * *** * * * * *** * * **** *** * * ** * * = y;
* * * * * * ** * * * * ** * * *** * * * * * * ** * * * = sum;
* * ** * ** ** * * *** * ** * * ** * * * ** * * **
** * * * * * * * * * * *
** * * * * * * ** * ** * * * sum;
}
int main()
{
* **** ***** * * ***** * a,total=0;
* * * * * * * * ** ** * * ** *** * * * *
* * * * * ** * **** * * ** * * = fas(a);
* * * ** * ***** * ** * * ** * ***** ** * *** ** * * *
***** * * * *** ***** * * * * * ** * ** *
** * * * * **** * * * 0;
}
answered
Nov 3, 2016
by
410523043
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156
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* ** ** * * ** ** ** * k, num1, num2, i;
* * ** ** * *** ** = 1;
* ** * * * = 1;
* * ** * * ** * == 1 || x == 2)
*** ** * *** *** * ** *** ** *** * * ** * *** * * ** * *
* * * *** * **** * * * **
* ** * * ** * *
* * * ** ** ** *** * * * * * * * * * * **** = 3;i <= x;i ++)
** *** * * * * * * * * ** ** * * * **
* * * * **** * * * * ** * * **** ** * * * *** * * * * * = num1 + num2;
* * **** ** ** * * ** * * * ** * * *** * **** * * * *** * ** = num2;
* *** ** ** * * * * ** ** * * ** * * * * * * * * * ** ** * * = k;
* * * * *** ** * *** ** *
* ** * * * * * ** ** * * * ** * ** * * *** k);
**** * * * *** **
** ** * ** * ** ** * ** * 0;
}
int main()
{
** ** ** * *** * ** x;
* ** * * * * *** ** * ** * * * &x);
** * * * * * *
** * * * * * * * * 0;
}
answered
Nov 3, 2016
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410511226
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Hidden content!#include * ** **** * ****
#include *** ** ** **
int printFF(int n);
int main(int argc, char *argv[]){
** **** * * ** *** * * * a,b,sum;
** * * * ** * * * ** *** * ** * ** * ** * * *
* * * ** * ** * * * * = printFF(a);
*** * * ** ** * * * * * *
* ** * * * * * * * * * *** *
* * * * * * * * * * * ** ** * * * ** * * * * * *
** ** * * ** ** **** ** * * 0;
}
int printFF(int n){
*** * * ** * * **** ** ** * f[10000]={1,1,0},i;
*** ** ** * * ** * **** * *** * i <= n; i++)
* * ** * * ** * ** * ** * * * * * ** *** **** ** ** * * * ** **** * * * * ** *
** * * ** * * * ** * * *** * f[n-1];
}
answered
Nov 3, 2016
by
Dhgir.Abien
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