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AD 20161103 作業1
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請設計一程式，使用者輸入一個正整數N，程式會輸出相對應的費氏數列第N項。
sample input:
10
sample output:
55
[Exercise]
Coding (C)
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asked
Nov 3, 2016
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Shun-Po
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ID: 16957 -
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int plus11(int num)
{
* *** * ** * * ** ** * * a,b=0;
** ***** *** * * * ** ** * * *** *
*** * *** * * * * *** * ** * * * *** * ** * = b+a;
* *** * *** * * * *** ** * * * * * * *
*** ** * *** * ** * * * * *** ** *** ** *
* ** ** * * * ** ** * * * *
* * ** * * * **** * ** *** ** ** * *
int main()
{
*** * * * * * ** **** * ** num;
** * * ** ***** ** * * * * * * *** * ** *** *
** * * * * * * * * * **
* * ** ** ** * ** * * * **
** ** **** ** * * *
**** * * ** *** ** * ** * * * ** ** *
*** * * * * ** ** * ** 0;
* * * ** ** ** ** * * * *
* ** * ** *** * * ** **
* ** * ** ** * * * ** ** **
* * * ** * *** ** ***
**** * **** *** *** * **** *
* * ** * ** * ** * * *
answered
Nov 3, 2016
by
andreas lu
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * *** **** * * ** ** ** i,n,fi,last1 = 1,last2 = 1;
* * * * **** * ** *** * * *
* * ** *** * * * * * * * ** * * ** * * * ** * *
* ** * * * * ** * * * * * * *
* ** * ** * ** ** * * * * ** * ** * * == 1||n == 2)
* * * * * * * ** ** ** * * * * * ** * * **
* * * * ** **** ** * ** * * *** * * * *
* * ** ** * *** * * *** **** *
* ** * * ** * * ** *** * = 3;i <= n;i++)
* * * * * * ** ** *** * * * * * ** * + last2;
* * * * ** ** * ** * * * * * * = last1;
* * * ** *** * *** * * ** * * * * = fi;};
* * *** * * * ** * * * * ** * * *** ** **
* ** * * ** ** *** *** ** *
** * * * *** * *** * ** * * * ** * * ** * * * *
* ** * * * *** * **** *** * * * * 0;
}
answered
Nov 3, 2016
by
謝秉弘
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(int num)
{
** * **** *** * * * ** ** * * i, num1 = 1, num2 = 1, sum = 0;
* * ** * * ** * * * ((num == 1) || (num == 2))
* * ** * ** * ** * * * * *
* * ** * * * ** ** * * ** * * 1;
** ** * * * *** * * * *
* * * * **** * * * *
* * * ****** * * * ** *
* * ** *** * *** ** **** * * * * ** ** * ** * ** * * (i = 3; i <= num; i++)
** * **** *** * ** * * * ** *** ** * * ** *
* * ** * ** ** * * * * * * * * * *** * * * ** ** * ** * *** * * * * * * = num1 + num2;
* ** **** ** * * * * * * * *** * * *** * * * * * * * * *** * * *** ** **** * = num2;
** *** ** * ** * * * * ** *** **** * ** * * ** * * * ** * ** ** * * * = sum;
** * * ** * ** * ** *** ** * * * *** ** *
* ** * *** * * ** * *** **** ** * * ** * * * * * * sum;
* * *** ** *** * * ******** *
}
int main()
{
*** ** * * * * * num, sum;
* ** * *** * * * * ** ** * ** *** ** &num);
* * * ** * * * * = sumNfiS(num);
* * * * ****** * ** * * * * * ** ** *** *** * * *** * sum);
* **** * * * ** ** * *** * * * 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
** ** * *** * * * * * * * ** ** int num;
** ** * * * **** * ** * a,n,b=1,c=1;
* ** * * * *** * * * ** ** ** * * * * * ** * * * * * * *
* ** * * ** * * **** ** * * * * * * * *
{
** * * **** ** * * *** ** * * *** **** *** ***
* * ** *** * * * *** ** * * ** *** * * ** ** * *** ** ****
}
* * * * **** * * *******
{
** * * * * * * ** *** * * * * * * * * **** ** ** * *** ** **
*** * * ** *** * ** *** * ** ** * * * * * * * ** * **
* * ******* * * * * * ** *** * * *** *** * ** ** * ** * ** *** * * * * * * *
* ** * * * ** ** * *** * ** * ** ** ** ** * **** * * * *** * ** ** * ** *** **
* * * * * * * *** ** * * * ***** * * **** ** * * * * * * * *
* * * ** * *** * ** * * * * * *** *** ** * *
* ** * ** * **** **** * * * * * * ** * * * * * ** * ** * *
}
* * * * * * * * ** * * * * * * * * *
** ** * * * * ** * * * * **** * 0;
}
answered
Nov 3, 2016
by
steven0221
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(num)
{
* * * * * * *** * * * ** * i, num1 = 1, num2 = 1, sum = 0;
* * * ** * * * * * * ((num == 1) || (num == 2))
** * * * * ** * **
* * * * ** * ** ** * * * ** * * * *** ** * 1;
* **** * * * * *
* * * * * ** * ** * * *
* ** * * ** **** ** ** ** * *
* * * * * ** *** **** * ** ** * ** * * (i = 3; i <= num; i++)
* * *** * * * * * *** * * * ** * * **
** *** * ** * ** ** ** * * * ** ** * * * * ** ** ** * * * = num1 + num2;
* * * ** ** ** *** ** * * *** * *** * ***** * * ** * ** * * ** * ** * = num2;
** **** * ****** * * ** * * * * * ** * * * * * *** * * ** ** *** * * **** = sum;
** * * ** * * * ** ** ** ** * ** * * ** * *
*** **** ** * * * * **** * **** * * ** ** * * * sum;
** * ** * ** *** * * * * * **
}
int main()
{
* * * ** * ** * **** ** **** num, sum;
*** ** * * * * * * ** ** ** * * ** * &num);
** *** * * * * * * * = sumNfiS(num);
* ** *** * ** * * *** ** * * ** * ** sum);
** * * * * * * * ** * * * 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
** *** * * **** * *
#include<math.h>
int main()
{
* ** * * **** ** ** * * i,j,k=0,a=1,b=1;
******* * * * * * * ** * **** * * ** * *
* ** * ** * ** * ** || i==1)
* * * * * * * * ** * **** * * * *
* * * ** ** * ** * *
{
* * * * *** * * * * * * * *
{
* * * * * ** * * * * ** * * *
*** * * *** **** * * * * ** *
* *** * * * * * * ** * * *
}
** * * ** * * ** * *** * * ** * ** ** *
}
** **** ***** * * * * * 0;
}
answered
Nov 3, 2016
by
jack2234567
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-190
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* * * ** * ** * *** k, num1, num2, i;
* * * **** * *** * = 1;
** * * * * * * * = 1;
** ** * ** ** * **** == 1 || x == 2)
* * * ** * * * * * ** * * * *** * * ** * *
* * **** ** ** ** * **
** * * **** * *
* * **** * * ** ** * ** * ** ** = 3;i <= x;i ++)
* * * * * *** * *** * * *** *
* * *** ** * * ** * * **** *** **** * * ** * ** * = num1 + num2;
* * * * *** * * * * * * * * ** ** * * ** * * * ** = num2;
* * ** ** ** ** * * * * * * *** ** * * * * ***** * = k;
** * * ** * *** ****** * ** * *
** ** * * * * ** * ****** * * * * * *** * * * * * * ** * k);
** * * * * * * * * ***
}
int main()
{
* ** * * *** ** x;
* * *** * * * * *** **** ** * * &x);
** ** * ** ****** * * * * ****
* * * * * * *** 0;
}
answered
Nov 3, 2016
by
410511226
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int fas(int N)
{
* * **** * * ** i,sum=0;
* * ** **** * *** ** * **** ** ** x=1,y=1;
* * * * ** * * * * * *
* * * * * * ** ** * * * * * ** * 1;
* ** * *** * * ** * ** *
* * * * **** * * * ** * ** * ** * * * * * ** 1;
* * **** * * * * * ** * *
{
** ** * * * ** * ** * * *** * * * * * * ** * * *
* **** * * * * ** * * *** * * ** * * * * * *
* ** * * **** * * ** ** *** * * * ** * * * *** = x+y;
* ** * * * * ** * * * * * ** * ** *** ***** ** ** * *** = y;
* ** * * *** * * * * * * * * * * * **** * *** * ** * = sum;
* * ** ** * * * * * * * *** * *** * * *
* * ** * ** * ** ** * * * *** *
* *** * ** * ** * * * **** * sum;
}
int main()
{
* * * * * * ** * * * * a,total=0;
* * * * * ** *** * * *** * * *** * *** ** * * * *
* ** * * * * ** * * *** * * * = fas(a);
* * ** ** * * * * * * ** ** * * * ** * * *** ** * *
* * * * * ******** * * ** ** ** * ** ** * * * ** ***
* * ** ** *** * * * * 0;
}
answered
Nov 3, 2016
by
410523043
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156
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* * ** * ** * * * * k, num1, num2, i;
* * * ** * ** * * = 1;
* *** * ** * * *** * = 1;
** * * * * * == 1 || x == 2)
* * * * * * ** * * * * * ** * * * * * **** * * *** **
* * * ** * ** * **
** **** *** ** ** *
* * * * * * * * * * * * ***** * * = 3;i <= x;i ++)
*** * *** * * * ***** * * *** * **
* * * * * * * * ** * * * * * * * * ** * * ** * = num1 + num2;
* *** * * * * *** * * * *** * ** * * * *** * ** * *** ** = num2;
* * * * * * * * ** * * ** * * * * * * * **** * * = k;
** * *** *** **** ** * * * *** * *
* * *** * * * ** * * * ** ** ** * ** * ** * * *** * k);
** * * * * * **
** * * ** * * * 0;
}
int main()
{
* ** * * ** * * * x;
* * * * ** * * * * ** * * ** &x);
* * * ** * * *** *** *
* *** * * *** * * * 0;
}
answered
Nov 3, 2016
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410511226
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Hidden content!#include * **** * * * * *
#include * * ** * * *
int printFF(int n);
int main(int argc, char *argv[]){
* * * * * * * * * *** a,b,sum;
** * * * ** ** *** * ** * ** ** ** * * * ** ** *
** ** **** *** ** * * * *** = printFF(a);
* * * * * *** ** * **** * *
** *** ** * *** ** * ** **** * * * * * ** *
* ** * ** ** * ** * * * *** ** * ** * * ** * * ** * * * * *
* **** * * * * * * * ** * 0;
}
int printFF(int n){
** * ** * * * * * f[10000]={1,1,0},i;
* * ** * ** * * ** ** ** * * * i <= n; i++)
** ** * * * * * * * * * ** * * * *** * * * ** * * ** ** * * * * *** ** * ** **
* * * * **** * * * * * * * f[n-1];
}
answered
Nov 3, 2016
by
Dhgir.Abien
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