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AD 20161103 作業1
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請設計一程式，使用者輸入一個正整數N，程式會輸出相對應的費氏數列第N項。
sample input:
10
sample output:
55
[Exercise]
Coding (C)
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asked
Nov 3, 2016
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Shun-Po
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ID: 16957 -
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int plus11(int num)
{
** ** ** * * * ** * * * * * ** * a,b=0;
* * * * * * ** * *
* * * * * ** * ** * *** ** * ** * * * ** * ***** * = b+a;
** * * * * * * ** * * **** * * **
* * * ** ** ** ** * ** ** ** * ** * * *
* * * ** * * * ** * * * **
* * ** * * * * *** * ** *
int main()
{
* * ** ** * ** ** * *** * num;
** * ** ** ** * * * ** * * ** ** * * *** ** ** *
*** * * * ** * * * * * * **** *
* * ** * * * * ** * * * *
* * * * * * ** *
*** ** * * *** * * * * ** * * * *** ** **** *
* * * ** * ** ** ** **** ** * * 0;
* * ***** * * * * *
* * * * * ***
* * *** * **** * * * * **
** * * * * ***** * * *** * *
** * ** * * * * ** *
** ** ** * * * *
answered
Nov 3, 2016
by
andreas lu
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * * *** ** * ** **** * * * i,n,fi,last1 = 1,last2 = 1;
* **** * * * * * * **** ** *
** * * * * * ** * * ** *** * * * * * * ** * * * *** *
* **** * * * * ** * ** * * *
* ** * ** * * * * * * * ** == 1||n == 2)
* * ** * * * * ** * ** * **** ** * ** * *** *
* *** ** ** * * * * * * * * *
*** * * * * * * * * *
** * * ** ** * * * ** * ** ** ** * = 3;i <= n;i++)
* ** * * * * * ** * ** * * * * + last2;
* * * * * * *** ** * * * ***** * ** * * * * = last1;
* * * **** ** * * * * * * * * * * * * = fi;};
** * * * * ** * ** * * **** * *** ** * ** * * ** * *** * *
* * *** * * * * ** * * * ****
* *** * ** ** ** **** * * * * *** * ** * * * * **
*** * *** * * * * * * * ** * 0;
}
answered
Nov 3, 2016
by
謝秉弘
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(int num)
{
* ** ** ** * * ** * i, num1 = 1, num2 = 1, sum = 0;
* * ** * * * * ** * * ((num == 1) || (num == 2))
* *** *** * * ** ** * **
* * ** * * * *** * * * ** * * * * * * * 1;
* * * *** * **** ** ** * ****
* ** **** * ** * *
*** *** *** ** * * ** *** **
* * ** * * ** ** * * * ** ** * * *** *** * (i = 3; i <= num; i++)
** * * * * **** * ** *** * * ** * * * * * **** ***
* ** ** * * *** * ** *** *** ** * * * * * ** * *** * * * ** * * * ** * ** *** * * * = num1 + num2;
* * * * * *** * * ** * ** *** * * * * ***** * * * * * ** * * * * * = num2;
* ** * ** * ** * ** * * ** ** * ** * * * *** * ** ****** * * * ** ** * * * ***** * = sum;
* *** ** * **** * * * **** ** * ** * * ***** *
* ** * * * ** * ** ** * ** ** * * ** *** *** sum;
** * * * * * **** ** * *
}
int main()
{
* ** * ***** ** * ** * * *** num, sum;
* * * **** * * * * * ** * * *** * * ********* &num);
* * * * * * **** ** ** * * = sumNfiS(num);
* * ** ** ** *** * ** * * * ** ** * * ** * ** * * sum);
**** * * * ** * * * 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * ** ** * ** * * **** * ** int num;
**** * ** * * * * * ** ** * * a,n,b=1,c=1;
* * * * ** ** ** * *** * * ** *** * ** * *
**** *** ** * *** *** * * ** * * *
{
* *** * * * * * ** * ** ** *** * ** * * * * * * ** * * * *
* * * * * **** * * * * ** * * ** ** * * ** * * * *** ** ** ****
}
* * * * * ** * * * *
{
** *** * ***** ** ** * ** * * * * ** * **** * *** ** * *** * * *
* * * ** ** * * * * ** * * ** * * * * *** * * *
** *** *** * * * * * ** * * * * * * * * *** * ** ** ** * *
* ** *** * * * * ** * * * * * * * * * * ** * * * * * ** * ** * * ** *** ** * *
* * ** * ** * ** * ** * * * * ****** * * * * ** ** ** * *** * ** * * ** **
* * * ** * * *** * * ** * ** * ** * * * * * ***
**** * * ** * * * ****** * * ***** * * * * ** * * * * ** * *
}
* *** * * * ** *** *** * ** * **** * * * ** *
* * * * * ** * ** *** * * * 0;
}
answered
Nov 3, 2016
by
steven0221
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(num)
{
** * ** ** * *** * *** * i, num1 = 1, num2 = 1, sum = 0;
** * * * * ** * * * ((num == 1) || (num == 2))
* * * * * ** * * * * * *
* * * * * * * * *** * * *** * *** * ** * ** * * * * 1;
*** * ** * * * *** *** **** * * *
* * * * * *** ** * * *
* * * * * * * * ** *
* ** * * * * ** ** * ** * * ** ** * * * * * (i = 3; i <= num; i++)
* * * ** * * * * * * ** * * * ** * * ** * *
* * * * * ** ** ** * ** * ** * * * * *** * * * * ** ** * * **** = num1 + num2;
* * ** * * * *** * * ** ** * *** * ** * * *** * * ** ** = num2;
** ** * ** * * * ** * * * ** * * ** * ** * * * * * * * * *** ** * *** = sum;
* * * ** ** * ***** * ** ** * *
* * * * * * * * * * * * * ** * **** * *** sum;
* * ** * ** * * * ** * * * *
}
int main()
{
** * * *** * ** * num, sum;
* ** * *** * * ** ** *** * * * ** ***** * ** * &num);
** ** * * * * ** * = sumNfiS(num);
* * *** **** **** * ****** *** ** * * * * * sum);
* * ** * * * * *** ** * 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
* *** * ** *
#include<math.h>
int main()
{
* * * * * * * ** *** ** i,j,k=0,a=1,b=1;
* * * * * * *** ** * * *** *** * * * *** * *
* * * * * * ** * * ** || i==1)
** * * ** ** * * * * * * ***
* * * * * * * ** * * *
{
** *** * * * * * ** *
{
* * * * * ** * * ** *
** * * * * ** * * * * * *
* * ** ** * ** *
}
* * **** ** ** * * * * ** ****** *
}
* * ** ** * * * * * ** 0;
}
answered
Nov 3, 2016
by
jack2234567
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
** * * ** * * ** *** k, num1, num2, i;
* * * * * * = 1;
* * ** * ** * * * * = 1;
* * * *** * ** ** ** == 1 || x == 2)
** * * * ** * * ** * ** ** * * ** * ** **
** * * ** ** * ** ****
* * * * * ** * *
* ** * ** * ** * ** * * * * * = 3;i <= x;i ++)
****** ** * * *** * *** * ** * * ** ** * *
***** * ** * * * * * * * ** **** * * * * ** *** * = num1 + num2;
* * * * * * * * * ** *** *** ** ** ** * * * * * * * * * ** = num2;
* ** *** **** * * * ** * *** * * * ** * * * ** * * * = k;
* ** * **** ** * *** *
* * * ** * * * ** ** * ** * * ** *** *** ** ** ** *** k);
* * * * * * * **
}
int main()
{
* * * * * * **** * x;
** * * * *** * * * ** * * * &x);
* * * * ** * ** ** ** **
*** * * * * ** * * * * 0;
}
answered
Nov 3, 2016
by
410511226
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-188
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int fas(int N)
{
* * ** * * * * * i,sum=0;
** * **** ** * * * x=1,y=1;
**** * * * ***** * ** *
* * * * * * * * ** * * * * * * * *** *** * * 1;
* * * * * * **** * * *
*** * * ** ** * ** ** * * * * * * * * * 1;
* * ** ** * * * *** **
{
*** * **** * * * * * * * * * ** * * *** *
** * ***** * * ** *** * * * ** ** * *
** * * * ** ****** * * * ******** * *** * * * * *** * * *** * * = x+y;
* * ** * * *** * * * *** * * * * ** * ** * * ** ** *** * = y;
* ** * * * * * *** *** * *** ** * ** ** ** * = sum;
* ** ** * **** ** ** *** *** * * **
** * * * * * * *** *
* *** *** ** * * ** * *** ** sum;
}
int main()
{
* * * * ** * ** * * a,total=0;
* * ** * * ** * * *** * * * * * * ** ** ** ** *
* * * * ** * * * * * * * ** *** = fas(a);
* ** * **** ** ** * * * * * * ** ** ** * * *** * *
* ** *** * ** * ** ** ** * *** ** **
* * ** *** * *** * ** *** * * 0;
}
answered
Nov 3, 2016
by
410523043
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* * ** * ** * * * k, num1, num2, i;
* ** * * ** ** * * ** = 1;
* * ** ** * * * * = 1;
** ** ** * ** ** * == 1 || x == 2)
* *** * * ** * ** * ** * *** * ** *** * *** * ** * * ****
** * * * ** ** ***
** ** *** ***** * * **
* * * ** * ** * *** * * ** ** * * **** ** = 3;i <= x;i ++)
* * * * * *** * * * ** * *** * * * ** ** *
* * ** ** * ** * ** ** * ** * ** * *** * * * * ** = num1 + num2;
* * * ****** * * * ** * * * * ** ** * * * * * **** ** ** *** = num2;
* * ** * ** * ** ** * ** **** * ** * * * * * * = k;
** * * * * * * * ** *** *** * * *
** * * * ** * * * *** * * *** * * * * * * * k);
* *** ** * * * * * * *
* ** ****** * * * ** 0;
}
int main()
{
* * * **** * * ** ** * x;
* ** * * ** * ** *** *** **** * * *** &x);
***** * *** * * * ** **** *
*** * * ** *** * ***** 0;
}
answered
Nov 3, 2016
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410511226
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Hidden content!#include * *** ** * * **
#include * *** * * *
int printFF(int n);
int main(int argc, char *argv[]){
*** ** * * ** * *** ***** * ** * a,b,sum;
* * *** *** ** * * *** * ** * * * * * **** *
* * * * ** * * * * * * * = printFF(a);
* **** * * ** ** *
* * * ** * * ** ** * * ** * ** * * ** * ** **
* * ** * * * * * * * ** * ** ** * * * * *** * ** * * *** *
* * * * **** * * * * * * * 0;
}
int printFF(int n){
* ** ** *** * * * ** * f[10000]={1,1,0},i;
** * * *** ** *** ** * * i <= n; i++)
** ** **** ** * ** ** * * * * ** * ** *** * * * * * *** * * * *** ** ***
* * * * *** * * * * ** * f[n-1];
}
answered
Nov 3, 2016
by
Dhgir.Abien
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