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AD 20161103 作業1
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請設計一程式，使用者輸入一個正整數N，程式會輸出相對應的費氏數列第N項。
sample input:
10
sample output:
55
[Exercise]
Coding (C)
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asked
Nov 3, 2016
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Shun-Po
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int plus11(int num)
{
* * ** * *** * * ** * * * * a,b=0;
** *** * * **** * * ** ** * *** *** ** ** * *
* *** * * * ** * ** * * ** *** * * * ** ** * = b+a;
** * * * * ** * *** * ** * * * * * ** * * *
* * * * * * * * * * * * * * * * ** *
* * ** * **** ** * ** * * * *
* * * * ** * * * * *** *
int main()
{
* * ** ** *** * * num;
* ** *** * * * * * * *** * * * * *
* * * * * * * * * *
* * * * * * * * * * * *
* * * * * * ** **
* *** * * * * * * ** * * * * *** *
* ** ** ** * ** * ** * 0;
* ** * ** * * * *
* * * * * * ** * * ** * ***
* * **** * * * ** * ** ** *
* * ** * * ** ** * *
* ** * * ** * ** * *
* ** * ** * * ***** * *** *
answered
Nov 3, 2016
by
andreas lu
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
*** * * * * ** ** * *** *** * ** i,n,fi,last1 = 1,last2 = 1;
** * * * * ** * * *** * * * * * *
** * * ** * ** * ** * * * * * * ** * *** ** * * *
* * * * ** * * * ** ** * * *
* ** *** * ** ** * * * * * ** * * * == 1||n == 2)
* ** * ** *** * * * * * * ** * ** * * *** * **
* *** ** * * *** ** * * ** * * *
* * **** ** ** * * * ****** ** ** * *
** ** * * **** * * * * ** ** * * ** * = 3;i <= n;i++)
* *** * * * * * * * ***** + last2;
* * **** **** * ** * * * * * * * * * = last1;
* * * * * *** * * * ** * ** ****** ** = fi;};
*** * * * ** * * ** * ** * * * ** *** * ** * ** * ** * **
* *** ** * * * *****
* * ** * ** * ***** * ** * * ** * ** * **
** **** ** ** * * * * * ** 0;
}
answered
Nov 3, 2016
by
謝秉弘
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(int num)
{
* ** * * * * * * *** * * * i, num1 = 1, num2 = 1, sum = 0;
**** * ** *** ** ** ** ((num == 1) || (num == 2))
* * ** * * * * * * * *
* * * * *** **** * * ** * * * * ** * * * * * * * * * * 1;
* * * * * *** *
* * ** * * *** * * **
*** *** * * * * * * * * *
*** * **** * *** * * * ** *** * *** * * * ** * * **** (i = 3; i <= num; i++)
* * * * * * * ** * * *** * * * *** ** *** * * * ** *
* * * * * * * * ** * * *** * * ** ** * * * **** * ** ** * *** * ** = num1 + num2;
* * * * * **** ** ***** ** * * ** * * * * * * * **** * ** ** * * ** ** * ** ** = num2;
* ** * * * * * ** *** ** ** * *** * ** * * * ** ** * * * * **** * * *** * * * = sum;
* * * ***** * *** * * * *** * * *** * ***** * * *
* * ** *** * * * * ** * ** * * * * ** * ** * * *** sum;
* ** * * * *** * * ** * * *
}
int main()
{
* * *** ** * * * * * * num, sum;
* * * * * * ** * * * *** ** * &num);
** * ** **** *** * * * = sumNfiS(num);
* * ** * * ** ** *** * * * * * * ** * * * sum);
** ** * * * * * *** 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * **** * *** * * *** * * ** ** int num;
* * * * * * ** * * * a,n,b=1,c=1;
** *** * * * * * ** *** * ** * * **** ** * **
* * * *** *** * * * ** * ** *****
{
** * * * * * * ** ** * * * ***** * ** * * * *** * *** * * *
* * * * ** * * **** * * * ** * * * * * *** * ** * * * * * * *
}
* * *** * * * * * * * *
{
* * * * * * * *** * *** * * * * * ** * ** * * ****** * * * ** * * * ** **
** ** * * * * * * *** ** * * *** ** ** *
* * * * * *** * ** * ** * *** ** * * * * **** * ** ** * * ** *
* * * ** *** * * * ** * ** * * ** * * ***** * * * * * * * *** * * * **** * ***
* * * * * ** ** ** * *** * * * **** ** * *** *** * * * * ** * ** *** * * * * * * *
*** * **** **** ** *** * * ** * * * * ** ** *
* ** **** ** * * * * *** * * *** * * * ** ** * * * * * * ** * * * ** **
}
* ** * * * * * * * *** ** * * * * ** * * *
* * * ** * * * * * * * 0;
}
answered
Nov 3, 2016
by
steven0221
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(num)
{
* * * * ** * ** * ** * * * i, num1 = 1, num2 = 1, sum = 0;
*** * * * * ** * ** ** ((num == 1) || (num == 2))
* ** * * * **** * * * * * **
* ** * * * * * * * * *** *** * *** * * ** ** * * * ** * 1;
** * * ** * * ** * **
* * * * * *** * * * ** ** *
** ** * * * * ** ** * * *
** * * ** * * ** ** * ** * **** * * (i = 3; i <= num; i++)
** * * * ** * ** * * ** * * * * * * * ***** * *
** * * * *** * * *** * * * * * *** ** * * * * * * * * ** * * * ** ** *** = num1 + num2;
* * * * * * * * * ** * *** ** * * **** ** * *** * * * * * * = num2;
* * * * * * * * * * * ** * * * ** * ** ** ** ** *** * * * = sum;
** * * * ** * * * * * * * ** ** * * *** * * * *
* * * * * ** * * ** * ** ** * * * ** sum;
** **** * ** ** * * * ** * *
}
int main()
{
* * * ** * * * * * * num, sum;
* **** * * * * * * * **** * ** &num);
* * * * * * ** * = sumNfiS(num);
** * * * * * * **** * *** * ** *** * * *** sum);
** * * * * * * * * * * *** 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
** * * *** * * *
#include<math.h>
int main()
{
* * * * * ** i,j,k=0,a=1,b=1;
* * ** ** * * ** * * ** * * * ** * * * * *
* *** * *** *** * || i==1)
* * ** * * * * *** * * * * * * * * ** *
* **** **** * * * * *
{
* * * * *** ** * * ** ** * ** ***
{
* *** * * *** * * * * **
* * *** * * * * * * *
* * * * * * * * *
}
* * * *** * ** * * * *** *** * * ** * *
}
** * ** * ** ** * ** * ** 0;
}
answered
Nov 3, 2016
by
jack2234567
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-190
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* ** * * ** * * * * * k, num1, num2, i;
* ** * ** ** * *** ** = 1;
* * * * * * * ** = 1;
* * **** * ** * == 1 || x == 2)
* *** ** ** ***** ** ** ** * * * * *** * * * * * ** * ***
* * * * ***** **
** ** * * * ** ** ** **
** * * * * * * ** * ** *** *** * ** * * * * * * = 3;i <= x;i ++)
* * * * * * * *** ** * * * * * * * **
* ** * * * * * ** * * ** * * * * * ** *** * * ** * = num1 + num2;
** * * * * * * * * * * * ***** ** ** * ** * * *** ** = num2;
* ** * * ** * ** *** * * ** ** * * ** * * * * ** ** = k;
*** ** * * * * * * * * ** * *
* ** * **** * ** ** *** * * * ** * ** * * * * * * k);
*** ** * * *** *
}
int main()
{
* * * *** * x;
* * * ** ** * * * * *** ** *** &x);
** ** * * * * *** * * *
** * *** * * 0;
}
answered
Nov 3, 2016
by
410511226
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-188
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int fas(int N)
{
* *** ** ***** * * * * * i,sum=0;
** * ** * * ** ** * * * * x=1,y=1;
* * ** * * ** * * * *** * * ***
* * * ***** * * * * ** * * * ** * * * 1;
* ** *** ** * ** * * ** ** *
* * * *** *** * * ** ** ** * ** *** 1;
* ** * **** * * * ** * *
{
* * * *** ** ** *** * ** * ** * * * *
** * * * * * * * * ** * * * ** * * * *
* * ** *** * **** *** ** * * * * * * * * * * * * * ** *** * = x+y;
** * * * * * * * ** * ** * * ** * ** * * ** *** = y;
** * * * * * * * ** ** * ** ** * ** * * * * * *** * ** ** = sum;
** ** ** ** **** * * ** * ** ** * * ***
* * * * * ** * * ** ** * **
** *** * *** * ** * * * ** sum;
}
int main()
{
** * ** * * * * * a,total=0;
* * * *** * * ** * * ** * ** * **
* ** * * ** * * * * * * = fas(a);
* * ** * * * ***** * * *** * ** * *** ** * * * ** *
* ** * * * **** *** * ** * * * * ** * *
** * *** * * * * ** 0;
}
answered
Nov 3, 2016
by
410523043
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156
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* * ** ** ** * *** * * k, num1, num2, i;
* * *** ** * ** ******* = 1;
* * ** * * ** ** * = 1;
*** *** * * * == 1 || x == 2)
****** * ** * * *** ** **** ** * ** *** * * * * * * * **** *
* * * * * * * ** ** * *
* **** ** * *
** *** * ** * ** **** * ** ** * * ** * * = 3;i <= x;i ++)
** ** * * *** * * * *** * * * ** * * *
* * * * ***** * **** * * ** * ** *** ** * = num1 + num2;
** * ** * * * * * * * * * ** * ** ** * * *** *** *** = num2;
* * * * * ** * * ** ** * * * ** * * ** * * ** * * * * * *** = k;
** * * ** * *** * ** * * *** * **** * **
**** ** * * * * * * * * * **** * * * * * *** k);
* * ** ** * * *
* ** * ** * * * **** ** 0;
}
int main()
{
** * ** * ** **** x;
*** * * * * * ** * * ** * ** &x);
* * ** ** ** * * ** * * ** ***
** * ** * *** * ***** * 0;
}
answered
Nov 3, 2016
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410511226
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Hidden content!#include ** * * * * ** *
#include * * *** ** * *
int printFF(int n);
int main(int argc, char *argv[]){
* * * ** **** *** *** * **** ** * ** a,b,sum;
** * * * * **** * * * * * * *** **** * *
** * * ** ** * * * = printFF(a);
** * * **** ** * ** * *
* * * * * * ** *** * ** ** * * * ** *
* ** ** ** * * * ** * * * * * * * * ** ** * ** * * ** ** ***
** * * * *** ** ** ** 0;
}
int printFF(int n){
* **** *** * ** ** * f[10000]={1,1,0},i;
* * ** * * * * ** ** * * * i <= n; i++)
* * * ** * ** * ** * * * * * * * ** * * * * ** * *** * * *
* ****** *** **** * * f[n-1];
}
answered
Nov 3, 2016
by
Dhgir.Abien
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