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AD 20161103 作業1
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請設計一程式，使用者輸入一個正整數N，程式會輸出相對應的費氏數列第N項。
sample input:
10
sample output:
55
[Exercise]
Coding (C)
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asked
Nov 3, 2016
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Shun-Po
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ID: 16957 -
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int plus11(int num)
{
* ** * *** * * * *** *** a,b=0;
* * * * ** ****** * * * ***** * ** ***
* * * ** ** * ** * * * * ** * * * ** * * * * * = b+a;
** * ** * * * * * ** * * *** * *** *
** ** * * * * * * ** * ** * * * * ** * * ** *
** * * * * ** * ** * ** * *
* * ** * * **** ** * * * *** * **
int main()
{
* * ** ** * *** *** ** num;
** ** ** **** * ** * * * * *** * * * * *** * * * *
* **** * * * ** **** ** * * * *
** * * ** * * ** * * * **
* * * ** ** * * * *
* * * ** * * * **** ** * * * *** **** *
* * * ***** * * * * * ** ** * 0;
* *** * **** ** ** * * **
** * * * ** ** * *
* ** * ** * **** ** * * *
** * ** ** * * ** * ***
* ** ** ** * * * * * *
* * * * * * * **
answered
Nov 3, 2016
by
andreas lu
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * * **** * ** ** * * * i,n,fi,last1 = 1,last2 = 1;
* * * * * * ***** * ** * * *
**** ** * * ***** * **** * ** * * * * * * * * * ** **** * * * *
** * * ** * ** * * * * * ** **
* * * * * * * * ** ** * * * * == 1||n == 2)
* * *** * * ** * * * * * * * ** ** * * *
* * * * * * * * ** *
*** ***** *** * * * ** ** * ** *
* * ** * ** **** * ** ** * = 3;i <= n;i++)
* * * * * * * ** *** ** ** * * * + last2;
* * * * * * * * *** ** *** * ** = last1;
** ** ** * * * * * * ** * * * * * **** * * = fi;};
* * * * * ** * ** * ** ** * * * * * ** * ** ** *
* * ** * * * ** * * * * * ** * * *
* *** * * * ** * * * * *** * ** * *** * ** *** ** *
* * * ** * *** * *** * *** * ** ** 0;
}
answered
Nov 3, 2016
by
謝秉弘
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(int num)
{
* * ** * ** * * * ** * * * i, num1 = 1, num2 = 1, sum = 0;
* * * ** ** ** *** ** *** * ((num == 1) || (num == 2))
* * * * * *** * * ** * * *
* * * ****** ** * * * * * * ** *** * * * * * * * ** 1;
* *** * * * * ***
** * * * ** * ** * * * **
* * * * ** ** * ** * **
* ** * ** * ** * * ** ** * * * ** * (i = 3; i <= num; i++)
* * * * * * * * * * * * ** * * *
* * * * * * ** * * ** * ** ** **** * * * * ** * ** ** * * * * * * * * *** = num1 + num2;
** * * ** * * * * * * * ** ** * * * * * *** ** ** * ** * * * ** ** * *** * ** * * * * * = num2;
** * * * **** *** ** ** * * * * * ** * ** * * * * ** ** * * ***** * = sum;
** * *** * * * * ** * * * * * * * * * **
** * * * ** * * * * ** * * *** * * ** * * * * sum;
* ** ** * * * * ** * * ** *
}
int main()
{
* * ***** * * ** * * * ** * num, sum;
* * * * *** * ****** * * * * * ** * &num);
* * **** * * ** * * * * = sumNfiS(num);
** * * ** * ** * * * * * ** * ** ** * * * sum);
** * ** * * *** **** * *** * 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * ** ** * * * * *** * * * int num;
* * * * * ** * ** *** * a,n,b=1,c=1;
** * * * * * * * ** * * * * * ** * * *
* * * *** * * * ** * * * ** *** **
{
** * *** * ** * * *** *** * * ** * * * * ** * * *
* * **** * * ** * * * * *** * **** * * *** * * *** ** * * ** * *
}
***** * ** * * ** * * * *
{
* * * * ** * ** * * * * ** * ** * ****** * * * ** * *
* *** * * * * * * * *** ** * * * * ** * * ** * *
*** * ** * * * * *** * * ** * ** * * * * *** * *** * * * * * * * * *
* * * * ******* ** * * ** * * * * * * * * * * * * * * ** * * * *
* ** ** * * *** * ** * ** * *** * *** * * * * ** ** *** *** * * * ** * ***** **
** * *** ** * * * * * ** * * **** *** ** *
* * * * *** **** * * * ** * * * ** ** *** ** * * * **** * * *** ****
}
*** * * * * * * * * * * * * * * * ** * * *
* * * ** * * * * * * * * ** 0;
}
answered
Nov 3, 2016
by
steven0221
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(num)
{
** ** * * * * * ** ** i, num1 = 1, num2 = 1, sum = 0;
* * ** * * * **** ** * * ** * ((num == 1) || (num == 2))
* *** * *** * ** ** * ****
** ** * * * *** * * * ****** * * * * * ** * * * 1;
** *** *** *** ** * ** * **
* * * ** * ** * *** * ** * * * *
** *** * **** * ** ** * * * *
* * * * ** * * * * * * ** * * * * *** * * (i = 3; i <= num; i++)
* * * *** ** ** * * * * * * **** ** ** *
* * * * * ** * * ** * * * * ** * * * ** * * * * * * * * * * ** * * = num1 + num2;
**** * * * *** * *** *** ** ** * * * * ** ** * * *** ** * * * * ** = num2;
* * * * * * *** * **** * * ** ** * * * * *** * * * * * * * * ** ** * * = sum;
* * * **** * * ** ** ** **** * * * * ** * * *** * **
* *** * ** * *** ** * * * * * * * * * * ** * * * * ** **** sum;
** ** * *
}
int main()
{
* * * ** * ** *** num, sum;
* * * * ** * ** * * * ** * ** ** * * &num);
* ** ** *** * * * * * * * = sumNfiS(num);
* *** * * * * * * * * ** * sum);
** **** * ** ** * ** * ** 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
* ***** * * * ** **
#include<math.h>
int main()
{
** * * * * * * ** * * ** i,j,k=0,a=1,b=1;
* * * *** ** *** ** * * * * *** * * *** ** * * ** ****
* * * * * ***** * || i==1)
** ** ** * *** **** * *** ** * * *
* * * ** * ** *
{
*** ** * * * * * * ** ** ** ***
{
* * * * ***** ** * * * *
** * ** * **** * * * **
* * * * * ** * ** * * ** **
}
* * **** * ** ** *** ** * * * ** *
}
* * * * * ** * * * * 0;
}
answered
Nov 3, 2016
by
jack2234567
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
*** ** * *** * * ** k, num1, num2, i;
** * ** * ** * = 1;
* * ** * * * * * * = 1;
* * * * * ** ** ** * * * ** == 1 || x == 2)
** * ** * ** * * * * * *** * ** * * * ** *****
* * ** * * * * *
** * ** * ***
* * ** * * * **** ** * * * *** * * = 3;i <= x;i ++)
**** * ** * * ** ** * * ** * ***
* * ** * * * * * ** * * * * ** * * *** * * * = num1 + num2;
* * * * ** * * * * *** ** ** * * ** * * ** ** * = num2;
* * **** * ** ***** * ** * * * * ** * * * *** * = k;
* **** * * * * * * * * ** * *
* * * * * * *** * * * ** *** ** ** * ** * ** k);
** *** * * **
}
int main()
{
* * * * ** * * * * x;
* ** * * * * * * * * * ** * * * &x);
* ** *** * * * * * * ** * *
*** * * ** * * ** 0;
}
answered
Nov 3, 2016
by
410511226
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-188
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int fas(int N)
{
* ** * *** * ** ** * ** * ** ** i,sum=0;
* * * * * * ** * * ** * *** * * * x=1,y=1;
* ** ** ** * *** * * * * ***
* * ** * * * ** * * * * * ** * * *** **** * 1;
* * * * * * * * ** * * *
* * ** * ** * * ** * ** * * ** ** * * * * * * 1;
* * * * * *** * * ** *
{
* * * **** * * *** * * * * * * * ***** * * ** ** **
* ** * * * * * * *** * * * * ** * * **
* ** * * * * * *** * ** * * ** * * * ** ** * ** *** * * = x+y;
* * * * * ** * *** * * * * * * *** * * ** **** * * * *** * * * = y;
** * ** * * * * * ** * * * * ** * * ***** * * * * ** ** * * * * = sum;
* * * * * * * * ** * ** ***** * * * * *
* * * * * ** ** * * * * **
** * * * *** ** * * *** * * * sum;
}
int main()
{
** *** *** ** ** ** ** * * * ** a,total=0;
* ****** *** * ** ** * * * ***
* * * * * ** * * * * * ** ** = fas(a);
**** * **** * *** * * * * ** * * * * * * *
* * ** * * * * ** * * * * * * * * *** * * *
* ** ** * * * * ** ** ** * ** * 0;
}
answered
Nov 3, 2016
by
410523043
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* * ** * * ** * ** * * k, num1, num2, i;
* * * * * * * * * * = 1;
* * * ** ** * * * * * = 1;
** * * ** ** * *** == 1 || x == 2)
** ** **** * ** * * * ** ****** * * *** * * * ** * **
* * * * ** * * *
* **** * * ***
* * ** * * * * * * * ** ** * * * * * = 3;i <= x;i ++)
** ** ** * *** * * * * ** * * ** * ***
* * * ** * *** * * ** ** * *** * * * * * * * * ** = num1 + num2;
* * *** * *** * * ** ***** * * ** * * * * * * * ** * * * = num2;
* * ****** * ** * * * * * * ** * * * **** * ** * * * ** ** * = k;
* ** *** * *** * * * * * * * * *
* * ** ** **** * * * * ** * * * * * * ** ** ** * * * ** * k);
** * **** * * *
** * ** * ** * ******* 0;
}
int main()
{
* * ** ** * * * ** x;
* * * * * ** ** ** * ** * ** &x);
* * * * *** * * ** ** ** * *
* ** *** * 0;
}
answered
Nov 3, 2016
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410511226
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Hidden content!#include * * *** ***** **
#include ** *** * * * * *
int printFF(int n);
int main(int argc, char *argv[]){
*** * * ** * ** * * * **** * a,b,sum;
** * * * * * * * ** ** * * * * *** * * * * *
*** * * ** * * * = printFF(a);
* ** * * ** * * * *
* * * * * * ** * * * ** *** * ** ** * * *
*** * * * *** * * * * *** * * * * * * * * ** * * * * ** **
* * * *** **** ** * * 0;
}
int printFF(int n){
* * ** *** * * * * * * ** f[10000]={1,1,0},i;
** * * * * * ** *** * * * * * i <= n; i++)
* * * * * * *** * * * * * ** ** ** ** ** * ** * ** *** * *** * *** ** * *** * **** * * ** * **
* ** * * ** * * ** * f[n-1];
}
answered
Nov 3, 2016
by
Dhgir.Abien
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