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AD 20161103 作業1
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請設計一程式，使用者輸入一個正整數N，程式會輸出相對應的費氏數列第N項。
sample input:
10
sample output:
55
[Exercise]
Coding (C)
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asked
Nov 3, 2016
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Shun-Po
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ID: 16957 -
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int plus11(int num)
{
* * **** * ** ** ** * ** *** a,b=0;
* * ** * * * * * ** ** * * ***
** * ** * ** * * ** * *** * * *** ** ** ** * * = b+a;
* * * * * * * * **** ** ** * * * * * ** ** **
* * * * * * ***** *** * ** * * ** * **
* * * * * * * * *** * *** *** ***
* * * * ** **** * * * * *
int main()
{
* * ** * **** * **** * * * num;
* *** * *** * ** * ** * * * * * ** * * ** *
* * * * **** ** ** * ** * *** **
* * * * *** * **
* ** *** * * ** * *
* ** ** * ** ** * * * * * * ** ** * * *
* * ** * *** *** ** ** * *** * ** 0;
* * * *** * * * *
****** * * ** **** * *** *
**** * * * * ** *** *
* * *** * * * ** ** *** *
* * ** * * * *** *
* *** ** ** * * ** ** * * *
answered
Nov 3, 2016
by
andreas lu
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
** * ** * * * * * ** *** i,n,fi,last1 = 1,last2 = 1;
* ** * ** * *** * *
* * ** *** * * * * * **** * * * * * * ** *** *
* * * * * * * * * ** * *****
* * * ** * * ** *** * ****** * * == 1||n == 2)
** * * * *** * * * ** * * * *** ** * * * * *
* ** * * ** * * * * **
* * ** * * ** * * ** *** *** *
* * * * * * * *** * ***** ** * * = 3;i <= n;i++)
* * * * ** * * ** * * **** * + last2;
* * ** * ** * * *** ** *** * ***** = last1;
*** * ** * * ** * * *** * * *** * * = fi;};
* * ** ** * * ** * *** ** ** * * * ** * ****
* * * * * * * * * * * ** * ** **
** * * * * * * * * ** * * * * * *** * * ** * * * * **
* ** ** * * ** * * ** *** ** *** * * * * 0;
}
answered
Nov 3, 2016
by
謝秉弘
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(int num)
{
* ** ** * * ** * * * * **** * * i, num1 = 1, num2 = 1, sum = 0;
*** ** * ** ** * **** * * ((num == 1) || (num == 2))
* * * *** ** ** * *
* ** * * * ** * * * * * ** ** * * ** * * 1;
* *** * * * * * * * * * *
** * ** ** * ** * *
** *** * ** ** * ** * * *
***** * * * ** * * ** * * ** ** ** (i = 3; i <= num; i++)
* * ** * ** * * ** ** * * * ***** * ** * ** * *
* *** ** ** * * *** ** * *** * *** * * * * * *** * * * * ** * ** * = num1 + num2;
* * * * ** * * * *** **** ** * * * * **** * ** ** * * * ** * ** * * ** = num2;
* ** ** ** ***** * * * * * ** * * * ** ******* * * ** * *** * * ** **** * * = sum;
* * ** ** ***** * * * ** *** ** ** ** * * *
* * * ** ** * * ** * * * * * *** * **** * sum;
* * * * * * ** *** * *
}
int main()
{
* ** ** * * ****** * * * num, sum;
* ** * * * ** * ** * * *** * **** * &num);
* ** * * * * * *** * * = sumNfiS(num);
* * ** ** * ** * * * *** * * * * * * sum);
** * ** ** * * * * * * * ** * 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* ** ** * ** * * * * * ** * int num;
* * ** * * * * ** a,n,b=1,c=1;
* * ** ** *** ** * ** * *** * * * * * ** * * ** *
** ** * * * *** * * * * * ** * * ***
{
* * * *** ** ** ** * * * * * ***** * * ** ** ** * *** * * * *
* * * * * * * ** * *** * * **** * *** * * * * ** * * * ** *
}
*** ** * * ** * *
{
** ** * * * *** ** * * * * *** *** * * * ** * * ** * * * * * *** *
** **** * * ** * **** * ** * * * ** * * * ** * ** **
*** ** * ** * * ** * ** ** * * * * * ** * * ***** * ** * * *** *** *
** *** ** * ** * * * * * * ** **** ** * * * ** * ** * * ** * ***
*** * * * *** ** ****** ***** * ** * * * ** * * * *** * ** * * * ** ** ** * **** ** *
* * *** ** * * * * * * * * ** * * * * *
** * ** * * * * * * ** ** * * * * * * * * **** * * *
}
** * * ** ** * * * * * * * * ** * * * *
* ** **** *** *** * ** * 0;
}
answered
Nov 3, 2016
by
steven0221
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(num)
{
* * * * * ** * * ** i, num1 = 1, num2 = 1, sum = 0;
* *** * * * ** ((num == 1) || (num == 2))
** * ** ** * *
** * * * * * * * ** ** * ** * ** * * * *** *** *** * ** * * ** 1;
** *** ** *** * * * * * * *
* *** * * * * * *** * ** *
* * * * * * * * *
* ** * ** ** * * * * ** * ******* ** *** ** * * * * * *** (i = 3; i <= num; i++)
* * * * * * * * ** * * ***** ** * ** * ** ** *
* * * * ** *** * **** * * ** ** * * ** ** ** * * * * * * = num1 + num2;
* *** ** * ** **** ** ** * ** * ** * * ** * ** * ** * * * * **** * * * ** = num2;
* * ** * * * ** *** ** ** ** * *** * ** * * * *** * * * * * * * * = sum;
** * * ** * *** * * * * ** * **** * * * * ** * ** **** *
** * * * ** * * * * ******* * *** ** ** * * * ** ** ** sum;
* * * ** ** * ** *** *
}
int main()
{
* * * * ** * * * * ** * num, sum;
* * * * * ** * * * * * * * * * ** * *** &num);
* * ** * * * * * * = sumNfiS(num);
* * * * * * * ** ** * * * ** * * * * * ** * sum);
* * * * * ** * * * * * * 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
** * * ** ** * * ***
#include<math.h>
int main()
{
* ***** * * ** * i,j,k=0,a=1,b=1;
*** * * * *** * * * * * ** ** * * ** ** * *
* * * * * * * *** * * || i==1)
*** * * * * * * * *** * * * * ** *
* * ** * ** *
{
* ** **** *** * **** * ***
{
** * * ** * *** ** * * ***
* * * * * * ** * *** * *
* * ** **** ** ** ** *
}
* * * * * * ** ** *** * * ******** * *
}
* * * * * * ** * * * * * 0;
}
answered
Nov 3, 2016
by
jack2234567
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-190
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* ** * * * ** k, num1, num2, i;
* * * * **** * * * ** = 1;
* * * * * ** * = 1;
* ***** * * * * * == 1 || x == 2)
* * * * ** * * ** ** * * **** * * * ** * ****** * ** ** *
* * * * * *** * *
**** ***** * ** *** ** * *
* * **** ** ** * * * *** * * * * ** * * * = 3;i <= x;i ++)
* * * * * * * * *** * * * * * * ** * *
* * * *** * **** * ** * ** * * * **** * * * * * * = num1 + num2;
* * ** * * ** * * * ** * * * * * * * = num2;
*** * * ** * * * * * * * ****** ** * * * * ** * * ** * *** *** = k;
** ******* * * * * * * *
** ** * **** * * * * *** * *** * * * * * ** ** * k);
* ** ** * * * *
}
int main()
{
* *** ** ** * ** * ** * x;
* ** * * * ** * * *** * * * * * ** ** &x);
** * * * ***** *** * **
** * * * * * * * ** * 0;
}
answered
Nov 3, 2016
by
410511226
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int fas(int N)
{
* ** ** * ** * ** *** ** * i,sum=0;
* ** * ** * * ** * ** * x=1,y=1;
* ** *** ** ** ** * * * * ** *
* ** *** * *** * * ** * * ** * * * * * * * * * 1;
*** ** * ** * * ***** ** * *
* ** ** * * * * * * * ** * * *** * * * 1;
* * * ** * * * ***
{
**** * * * * * * ** * * * * ** *** * ** * * * * *** ** *
** * ** * *** * ** * ** * *** ** *** ***
*** * ** *** * ** * ** * * *** * * **** * * * **** * * ** ** * * ** * * = x+y;
** * * * * * * * *** *** ** * * * * * * * * * ** *** * * *** * = y;
* * * **** * ** * * * * * * * * * * ** * * * ** = sum;
* ** * * * * ** * * * * * * * * ** *
* * * * ** * ** ** ** * *
* * **** * * * * ** * * sum;
}
int main()
{
* * ** * * * * * ** a,total=0;
* * * * ** * * *** * * * * * * * * * * **
** ** ** * *** * * * * ** * = fas(a);
** * * * ** * * ** * *** * * * * *** * *
* ** ** ** * * * *** * * * ** * * * * * * * * **
** * * * * * * * 0;
}
answered
Nov 3, 2016
by
410523043
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156
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
* * * * ** ** ** * * ** k, num1, num2, i;
*** * *** * *** * * = 1;
** *** ** * * * * * * = 1;
* ** ** * * * == 1 || x == 2)
* * ** *** * ** ** * *** ** * *** * ** * ** ** * * ** **
*** ** * * * *
**** * * *
**** ** ** *** * * ** ** ** * * * *** ** **** = 3;i <= x;i ++)
* * * * *** * * ** *** *** * *** *
* * ** * ** ***** * ** * * *** * ** ** *** * * * * * ** * = num1 + num2;
** * * * * ** *** ** * * * * * ** * ** * * *** * = num2;
** ** * ** * * * * * * * ** * * * * ** * * * * * ** = k;
* ** * * ** ** * * * * ** * * * * * **
* * * * * * * * * *** * * * * * * * * * * *** ** * k);
* * * ** * * * *
** * ** * *** *** * * 0;
}
int main()
{
* * * * * * * x;
** ** * **** * ** ** * * * * * * * ** * * &x);
** * *** * * * * * ***** * ** * * *
** * * * ** * ** * ** ** 0;
}
answered
Nov 3, 2016
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410511226
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Hidden content!#include * * * ** *
#include * * * * *
int printFF(int n);
int main(int argc, char *argv[]){
* * ** * * ** * * * a,b,sum;
** * ** * * ** * *** * ***** * ** * * ** * * * * ***
* * * * * * * ** ***** * * * = printFF(a);
*** ** *** * * **
**** * * * *** *** * ** * *** ** * ** ** **
* * * * * ** * *** * ** * * * * ** *** * ** ** *
* ** * * * ** ** * * * 0;
}
int printFF(int n){
** ** * ** * * ** * * * * f[10000]={1,1,0},i;
* *** ** * * ** * i <= n; i++)
* * * * * ** * * * * * ** * * * * * * * * * * * * ** * ** *** * ***
* ** * * *** ** f[n-1];
}
answered
Nov 3, 2016
by
Dhgir.Abien
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