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AD 20161103 作業1
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請設計一程式，使用者輸入一個正整數N，程式會輸出相對應的費氏數列第N項。
sample input:
10
sample output:
55
[Exercise]
Coding (C)
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asked
Nov 3, 2016
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Shun-Po
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ID: 16957 -
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int plus11(int num)
{
*** * * *** * * * * * ** ** a,b=0;
* * * * * * ** * ** * * ***
* * * ** * *** * ** * * * ** **** * * *** * * * * = b+a;
* * * * * ***** *** * ***** * *
** * * **** ** * * * *** * *** * **** * ***
* * * ** * *** * *** ** * *
* * * **** * * ** ***** * * *
int main()
{
* * ** * * * * * * * * ** * num;
* **** ** * ** * * ** * * * *** ** * * ** **
* ** * * * * ** ** **** * * *
** *** * ** ** * ** **
* * * * * * ** * **
* * * * * ** * * * * * ** * * **
* * ** * * * ** * * ** * 0;
* * * ** *** *** * ** *
* ****** * * * **** * * ***
* ** * * * * *** * * **
* ** * * * * * ** ** * *
* ** * *** * * * * * * * *
* * *** * *** * * ** * *** * *
answered
Nov 3, 2016
by
andreas lu
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
** * * * * * * * ** *** i,n,fi,last1 = 1,last2 = 1;
* * * * ******* * * **
* * * ** * * ** * ******* *** * * ** * ** ** **** * * * ***
*** * * *** ** * ** * *** * *
** * * * * * ** * * * * * ** * == 1||n == 2)
* *** * * * ** * * * * ** * ** * * * *** *
* * * * * * * ** * **
* * ** * * * * * * *** ** * ** ** * * *
* *** * * ** ** * * *** * * * ** = 3;i <= n;i++)
* * ** * * * * * *** * * ** ***** * + last2;
* ** ***** ** * * * *** * *** * **** = last1;
* * * * * * * * * * ** *** * ** * ** * * ** * * ** = fi;};
* ***** *** * * ** ** ** **** * * * ** ** * * *
* * * **** ** **** * * ** * **
* * * * * * * ** ** ** * * *** *** * ** ** *** * * *
* * * * ** * * ** * * * 0;
}
answered
Nov 3, 2016
by
謝秉弘
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(int num)
{
* * * * *** * ** * * * ** * * ** i, num1 = 1, num2 = 1, sum = 0;
** * ** * * *** * **** * * ((num == 1) || (num == 2))
** * * * * * * **
* ** ** * ** * * * * ** * ** * ** * * * * ** *** 1;
* ***** ** * ** * * *
**** * ** * ** *** * * * *
* ** * ***** ** * ** *
** * * * * * * * * * *** ** * * * *** * *** ** (i = 3; i <= num; i++)
* * ** * * ** * ** * * * * * ** * * ** * ** *
***** * * * * * * * * * ** * * * ** ** **** ** * * ** * * *** * * * * ** * = num1 + num2;
* *** ** * ** * * * * * * * * ***** * ** * * * * * * * * * ** ** ***** ** = num2;
* ** * ** * * * * ** *** * ** * * * * ** ** * * *** * * * * * * * * * * = sum;
** ** ** **** * * ** ** * * * ** * * * **** * * ** * ** **
* * * * * ** * * * ** * * * * * * * *** **** sum;
* * * * ** * * *
}
int main()
{
* * ***** * ** * * * **** num, sum;
* **** * * * * ** * * * * * * &num);
* * ** *** * ** * * * * * * = sumNfiS(num);
* * * ** * * * * * * ** * * * * * sum);
* * * ** ** ** * 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* **** * * * *** ** ** ** * * *** * int num;
* * * * ** * * * * * * a,n,b=1,c=1;
* **** ** ****** * * **** ** * * ** ** * * *** * *
* * * * * * **** * * * *** * * * * * *
{
* * * * * * * ** ** * * ** * * *** * * **** * ** ** * *
*** * * * ** * * * * * * * * * ** **** * * * * * * * *
}
** ** ** * * * ** * ***
{
*** ** ** ** * ** * ** * **** * ** * ** ** * * * * * * * * * * * * *
* *** * * * ** * * * * ** * * * ** *** ** * *
* * ** *** * * * * * ** * * * * * * * ** ** * ** * * * * * * * ** * *** * ** * *
* *** * * * ** * *** * * * ** ** * * ** * * * * * * ** * * ** * ** * * *
**** * ** ** ** * * * ** * * ** * * ** ** * * *** *** **** ** * * ** ** * * **
* *** **** * ** *** ** * * * ** *** * * ** * * * * * ***
* * * * * * ** * *** * * *** * * *** * * ** ***** * ** ** * ***
}
* *** ** * * * **** * * * ** ** * ****
* * * * * * *** * * ** * 0;
}
answered
Nov 3, 2016
by
steven0221
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int sumNfiS(num)
{
* * *** * * * * * *** i, num1 = 1, num2 = 1, sum = 0;
*** * *** * * * ** ** ((num == 1) || (num == 2))
* ** * * * ** ** * **
* * * * ** * ** * ** * ** ** 1;
**** ** * * *** ** ** * * *
** ** *** *** * ** * * ** * ***
** * * * * *** ** *** *
* *** * * ** * * ** * * * * * * ** *** * ** ** * (i = 3; i <= num; i++)
* * ** * * **** * *** * *** * * * *** * ** ** * ** *
* * *** ** ** * * * * ** ** * * * *** *** * * ** * * ** * ** * * = num1 + num2;
**** ** * * * *** * * ** * * * * ** * * * * * * *** * * * * * ** * = num2;
* * * * * *** *** * * * ** * * ** * ** * * * * * * * * * * * = sum;
* ** * * *** * * ** ** ** **** * * * * * **
** * * ** * * * **** ** * * ** * * * ** ** * * * sum;
* * * * ** * ****** *
}
int main()
{
* * * * * * * ** ** *** num, sum;
* * * * * *** ** * * ** * * * * &num);
* ** * * * ** * ** ** = sumNfiS(num);
* * ** * * * ** * * * * *** *** * * * *** * sum);
* * * * ** ** * * ** 0;
}
answered
Nov 3, 2016
by
410314217
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Hidden content!#include<stdio.h>
* * * ** * ** * *
#include<math.h>
int main()
{
* * * * * *** *** * i,j,k=0,a=1,b=1;
* *** * * * * ** * * * * * * * * * * ** * *
* *** * ** * * * || i==1)
* * * * * ** * * * * * * *
** **** *** * * * **
{
* ** * ** * * * ****** * ** * * * *
{
* * * * * * * * ** ** * * **
* * * * ** * * * **
* * * * * * * * ** * * *
}
* * ** * * * ** * ** * * ****
}
* * * * ** * * ** 0;
}
answered
Nov 3, 2016
by
jack2234567
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
** ** ** ** * k, num1, num2, i;
* * ** * * * * * * = 1;
*** * * * * * = 1;
** ** * *** * *** * ** * == 1 || x == 2)
* ** ** * * * * * * ** ** * * ** * ** * * *
* *** ** * * *** ***
* * * * * * * *
* * *** ** * * * ** * *** * * * * = 3;i <= x;i ++)
** * * * * * *** * ** ** * **
* ** * ** * ** * * ** * * * * ** * * ** * * * * = num1 + num2;
* * * *** * * * ** *** *** * * ** * ** * * ** * ** * * = num2;
* * * * * * ** * * * ** * *** * * * * * * * * *** ** ** * = k;
* * * * * * * *** ** * * * **
* *** * *** * * ** * ** * ** * * * * **** * * * * * * * ***** * k);
*** ** ** ** * * * **
}
int main()
{
** * * * * * * **** ** * x;
* ** * * * * * * * * ** * ** * &x);
* * * * ** * * * * ** *
*** * * * * *** * ** 0;
}
answered
Nov 3, 2016
by
410511226
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int fas(int N)
{
* * * * * * *** * * i,sum=0;
* * * * * * ** * * x=1,y=1;
* ** * ** * ** * ** * **
** * * * * * * * ** * * * * *** * ** ** *** * ** 1;
** * * *** * * * * * * * * *
** * * ******* * ** * * ** *** * * ** * ** **** 1;
* * ** * ** * * * * *** *
{
** * * * * * * *** ** * ** * **** * * ** *
* *** * ** * * *** * **** * * * * * * * ***
* * * * * * * * ** * * * * * * * * *** ** * * * * * * *** *** ** * * * = x+y;
* * * ** **** * * ** * * * * * * ** * * * = y;
** * * * ** ** * * **** * * * * *** **** * * ** *** = sum;
* * * * * *** ***** * * ** ** * * *** * ** ***
* * * * * * ** *
** ** * *** * * * * * ** * * ** sum;
}
int main()
{
* * * * *** *** * * * a,total=0;
* ** * ** *** ** * ** * * * * * * * *** * * * *
**** * * **** * * ** ** = fas(a);
* * * ** * * * * ** ** * * ** * *** * * *** **
*** * * *** * * * * ** * *** * ** ** * *
** * *** * *** * * *** * 0;
}
answered
Nov 3, 2016
by
410523043
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Hidden content!#include <stdio.h>
#include <stdlib.h>
void Fibonacci(int x)
{
** * *** ** * *** * k, num1, num2, i;
* ** * * * * ** * ** = 1;
**** *** * * * * * * = 1;
*** * **** * **** * * == 1 || x == 2)
* * * * * * * * * ** * *** *** * * * ** * ** * * * *
**** * * * * * **
** ** * * *** * **
* * * * * * * ** * * * * * * * * * * = 3;i <= x;i ++)
* * * ** * * * * * * * * *** *
* * * * * * * * **** * * *** *** * * ** * * **** = num1 + num2;
* * **** * ** * * * *** * *** ** * * ** * * ** = num2;
* * ** * * * * * * ** * ** * * * * *** * * ** ** * ** * ** = k;
* * * * * * * * ** ** *** * **
* ** * * ** ** * * * * ** * ** ** * * ** * * * * ** * ** k);
* * * * * *** * * **
* ** *** ***** * * ** 0;
}
int main()
{
* ** * * ** **** * * x;
** **** * * * * * *** ** * * &x);
** * * * * ****** **
* * * * * ** ** * 0;
}
answered
Nov 3, 2016
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410511226
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Hidden content!#include ** ** * * *
#include * * * * * * *
int printFF(int n);
int main(int argc, char *argv[]){
* * ** * * * ** ** ** * * a,b,sum;
**** ** ** * *** ** * * ** * * * * * * * * ** * * *
* * * * * * ** *** * = printFF(a);
** * * ** * ** * * * * * * *
* * * * * *** ** **** * * * * *** * *
** *** * * * * * ** ** ** * * * * * * * * ** ** * * * * * * * ** *
*** * * * *** ** ** ** ** * 0;
}
int printFF(int n){
* * * * * * * * * * * f[10000]={1,1,0},i;
* *** *** ** ** * ** ** * * i <= n; i++)
* ** ** * * * ** * ** ** * * * * ***** ** *** * ** * * * ** * ** *** * * * * ***
** ** * * *** * ** * *** f[n-1];
}
answered
Nov 3, 2016
by
Dhgir.Abien
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