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請設計一程式,將使用者輸入的數排序並剔除重複的數後輸出。使用者輸入的第一個數字N代表接下來會有多少個數字會被輸入,程式會將接下來的N個數由小到大排好,剔除重複的數後輸出。

sample input:
10
5 3 7 6 4 5 3 7 6 4

sample output

3 4 5 6 7
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 15442 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

edited by | 2.5k views

17 Answers

0 like 0 dislike
Hidden content!
* ** * ****** ** *

int main()



{
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for(b = 0;b * ** i;b ++)

if(a[b] == a[b+1])
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return 0;





}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * * ** * * * *

#include * * ****** ** ** *

#include *** * **** * *

int main()

{

 float c;
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for *** ***** **

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}

if (a%2 == 0)

{

k = a/2;

h = k+1;

g = b[k]+b[h];

c = g/2;

printf * ** **** *

}

if (a%2 != 0)

{

k = a/2;

printf *** * **** ***** * * * **



}
** *** * * * * * 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
* ** ** * ** *

int main()



{
* ** * * * *** * ** *** * = 0, c = 0, box = 0, i = 0;


* * * * *** ** * * ** * ****
* * * * ***** ** **** a[i];


**** ** ** * ***** = 0;b *** i;b ++)
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* * * * * ** * ** *** * ** * * * *** **





for(b = 0;b < i;b ++)

if(a[b] < a[b+1])
* *** * ** * * a[b]);







return 0;





}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * * * ** ** *

int main()



{
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* ** ** ** * ****** ** ***
* * *** **** ** a[i];


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* ** * ** * * ** * ** ***** *


*** * ***** ** ***** * * *** * *




**** **** ******* ** * ** * ** ** * > a[b])
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* * * *** * * * * *** ****




* ******* * *** * = 0;b **** ++)
** **** * *** * < a[b+1])
* * * *** * *** * **** *** ** ", a[b]);







return 0;





}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

int main()

{

   int a,j,t;
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}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>



int main()

{
* *** * * ** ** i,j,k,n,num[n],m;
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*** * * ** * ** * * ** * ",num[i]);


* * *** ** * * * 0;





}
answered by (-103 points)
0 like 0 dislike
Hidden content!
** *** **** ***
* ** * ** *** *
* ** *** ****
* * ** *

{
*** *
*** *** ** ** * *
*** * *


(i = ** ** * * * **** * * *** ** *** * **
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* (i = j + ** * * ** * * ** ** *** ** = * ***** * = **** * = * **

}

j = 1;
* * (i = * *** * ** * * ** != ** ** * * * * * * * * * j ++ ;}


** 0;

}
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* *** **** * ***

int main()

{

int a = 0,b[100] = {0},c = 0,i = 0,j = 0,k = 0,l = 0;
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for(i=0;i<a;i++){
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*** *** * ***** * **** *

}



for(i=0;i<j;i++){
* * * ** **** ** ***** * * * ",b[i]);

}





return 0;



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** ** *

int main()

{

int a = 0,b[10] = {0},c = 0,i = 0,j = 0,k = 0,l = 0;
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for(i=1;i<a+1;i++){
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* ** * * *** ** ** = 1;
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** * * ** ** * ** = 0;
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* ** ** * * * * * *

}



for(i=0;i<j;i++){
** * * *** * * ** * ** *** ",b[i]);

}





return 0;



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * * *** **

int main()

{

int a = 0,b[10] = {0},c = 0,i = 0,j = 0,k = 0,l = 0;
** * ** ** **

for(i=1;i<a+1;i++){
*** * *** * * * **


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}



for(i=0;i<j;i++){
** * * * ** * * ** * * * **** *** ** ",b[i]);

}





return 0;



}
answered by (-140 points)
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