1 like 0 dislike
1.9k views
請設計一程式,將使用者輸入的數排序並剔除重複的數後輸出。使用者輸入的第一個數字N代表接下來會有多少個數字會被輸入,程式會將接下來的N個數由小到大排好,剔除重複的數後輸出。

sample input:
10
5 3 7 6 4 5 3 7 6 4

sample output

3 4 5 6 7
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 15442 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

edited by | 1.9k views

17 Answers

0 like 0 dislike
Hidden content!
* * * * *** * ***

int main()



{
* ** ** ** * *** * * = 0, c = 0, box = 0, i = 0;


* * * ** **** ** ** ** * ** ** * *
* ** * * ** ** ***** * a[i];


* * *** * * *** ** * = 0;b *** i;b ++)
* ** * * ** * * *** * ** * ** * *


*** ** * * ** * * ** = 0;c ** * (i-1);c ++)
** * ** * * **** * *** *** ** = c + 1;b * * i;b ++)
* * * * ** * * ** *** * * * * ** a[b])
** ** *** * * **** * * * ** *****
** * ** * **** **** *** * ***** ** * * * * = a[c];
*** ****** * * **** *** ** *** * * *** * * * ** ** = a[b];
** ** * * **** *** * ** * * * * ** ***** * = box;
* ** *** *** **** * * * * **** *





for(b = 0;b * i;b ++)

if(a[b] == a[b+1])
** ** * * ** * a[b]);







return 0;





}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include **** ** ** ** *

#include * * * * ** *

#include *** ***** **

int main()

{

 float c;
** ** * * * * a;
**** ** * * * * * *** ** *** ** * ***** ** **
** *** * * * *** * * * *




*** * * * * *** ** * * *** ***
* * * **** **** ** * * * * * * ** ***** *





for * * * * ***

{
* ** **** ***** * * *** ** * ** * **
* * * *** * ** ** **** * ** ** * *** **** ***
** * * ** ****** **
** *** * ** *** ** * * ** * *** ** **** * *** = b[j];
* * ** * * *** * *** *** * *** * * * = b[i];
**** ** **** * ** ** * ****** * * * ** * ** * * = d;
* * ** * *** * ** * *

}

if (a%2 == 0)

{

k = a/2;

h = k+1;

g = b[k]+b[h];

c = g/2;

printf ** * * *** *****

}

if (a%2 != 0)

{

k = a/2;

printf ** * ** * ****



}
****** * ***** * ** ** * ** * * 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
* *** * * *

int main()



{
****** * ******* * *** = 0, c = 0, box = 0, i = 0;


* ** * * *** * **** ** * * ** ** **
**** ********* * **** * * a[i];


*** ** * ** ** * * ** * = 0;b ** i;b ++)
**** * *** ** * * * ** ** *** ** * *


* *** *** **** *** * = 0;c *** *** (i-1);c ++)
**** ** * ***** * * * **** *** ** * = c + 1;b < i;b ++)
* * * ***** * *** * **** *** ***** * == a[b])
* ** *** *** * *** ** * **


* * * ** ** ** ***** * *** *




* * * * **** * ** * * ********* ** ** * a[b])
** * * ** * * * *** **** *****
** ** * ** * * ** **** ***** * ** ** ** * * * ** = a[c];
** *** * * * * * * **** * ** **** ****** * = a[b];
** * ** * * *** **** ** * * * ** * * * * ** * ** = box;
* * * * * ** ** * ** ***** ****





for(b = 0;b < i;b ++)

if(a[b] < a[b+1])
*** * * ** * * * ** a[b]);







return 0;





}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * * * *

int main()



{
***** * * **** ** ** * = 0, c = 0, box = 0, i = 0;


** *** ******** ** * ** *** *
*** ** ***** *** a[i];


** ** * ** ** = 0;b < i;b ++)
**** * *** *** ** * ***** **** * *** **


**** * ***** * * ** = 0;c < i-1;c ++)
** *** ** * *** ** * * ** ** * * = c + 1;b < i;b ++)
* * * ** ** ** * ** * * ** * == a[b])
** * * **** ************* * ******


* *** * * * *** *** * *** **




*** ** * *** * * *** * ** **** * > a[b])
** * ** ** ******** ** ** * ***** **
*** * ****** *** * *** * * ** ** ** * *** * * * * = a[c];
*** ** *** * ** *** **** **** *** * **** ** * = a[b];
* * ****** *** * * * * * * * ** *** *** * * ** = box;
****** * ** ** * ** * * ** * *




* * ***** * ***** * = 0;b ** ** ++)
** **** * * *** * *** ***** ** < a[b+1])
*** * ** *** ** * ** * * ", a[b]);







return 0;





}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

int main()

{

   int a,j,t;
**** ****** ** ** ** * * **** **** **
* ** ** ** ** num[a],i;
* ** ** * *** ** * * ** *** * *
** ** ** * * * ** * * ** * *** ** * *


* ** * * * * ******** (i=0;i<a;i++)
* ***** * ***** ****** * * ** * * * * ** *
** * ** ** *
* * ** ** ** * *** ** ** **** * ** * ******* (num[i]>num[j])
* ** *** * *** ***** * **** * ********* * ** * ** * * *
** *** ** ** *** **** * *** *** ** **** * ** *** ** **
*** * * ** * * *** * ** **** * * *
** *** ** * * *** * * ** * ** *** * ** * * * * **
** * * * * * ** *** * *
*** * * **** ** * (i=0;i<a;i++)
*** * ** * * ** * * **** * ** *** * * ****** *** * * * * ",num[i]);

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>



int main()

{
*** *** ** * **** i,j,k,n,num[n],m;
*** *** * * * *** * * ** * *** &n);
* ** * * * * ***


* ** * * ** * * *** ** *
* *** * ** * * ** * ** ** * * * &num[n]);


*** * *** * ** * ****


******** * *** ***** * * ** * **** *


* * * *** * *** * ** *****

   {
** **** * * * **** * * * * * * * **
** * ** ** * * * ***** ** * * * *** *
** *** * * * ** * ** * ** * ** ** * *
* * *** ** *
* ** * ** * * * ** *


**** *** * ** ** *** ** * ",num[i]);


* * ** ** **** ** 0;





}
answered by (-103 points)
0 like 0 dislike
Hidden content!
* * * * *** ** *
* * **** ***** * *
** * * ***** **
* * * *

{
* * *
* **** * ** *
* * **


** (i = * * * ** *** * *** *** * *** ***
** (j = * * z -
** (i = j + * ** * * * *** *** *** * ** = * ** = ** * * ** * =

}

j = 1;
** * (i = * ** * * * != **** * **** ** * * **** j ++ ;}


* * 0;

}
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* *** ** *** **

int main()

{

int a = 0,b[100] = {0},c = 0,i = 0,j = 0,k = 0,l = 0;
* * **** ** ** ** ** *

for(i=0;i<a;i++){
* *** *** **** *****


* * * * **** ** * *** * ** *
** ** * ** *** ** **
*** ** * *** = 1;
* * * **** ** ** * *
* * * ****** ***


* * * * ** ** *
** ** ******* **
* ** * * * *****
** ** *******


* * * **** ** ** = 0;
* ** * ** * * *

   i = 0;
* * * * * ** * ** *** * * *

{
*** * ** * * * * * * ****
* ** * * ** ** * *** **** **** *** * **** ***** ** *
* * * * * * * * * ** *** * ** * ** * * ** * * ***** = b[l];
* ** ** * ** ** ** ** *** * * * ** * * ** * = b[i];
** * *** ** ** *** * * * ** *** ** * ***** * * = k;
* * ** * * * **** ***** ***** ** * * ** * ** * ** * * * * * * = 0;
* ** ***** * * ** ** ****** * ** ** ** ** *


** ***** ** * * ** *

}



for(i=0;i<j;i++){
* * ** * ** ** * ** ***** ** ** * ** ",b[i]);

}





return 0;



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
***** * * ** * ***

int main()

{

int a = 0,b[10] = {0},c = 0,i = 0,j = 0,k = 0,l = 0;
* * **** * *** * * *

for(i=1;i<a+1;i++){
****** ** * * ** *


* ** * ** *** * *** * *** ***
*** *** **** ** ***
** ** *** * * * * = 1;
*** * **** ** * *
* *** * ** * *


* **** * * ** *
* *** * * * ** *
* * * ** * ** *
**** ** * * * **


**** * ** *** ** = 0;
** * * * *

   i = 0;
*** * * ** * * * ******* ** *

{
** ** ** * * * ****** ** * ** ****
** * * * ** ** * * ** ******* **** ** *** ** * ** ***
** * * * ** *** **** * * * * * *** * * * * * = b[l];
* * ** **** *** ** * * ** * *** * * * * ****** **** * * = b[i];
******* * * *** * ** ** ** * * **** *** * = k;
** * ** ** ** *** * * ** ** = 0;
* * * *** * ** * *** * * * *** *** * * ********


*** * * ** *** *****

}



for(i=0;i<j;i++){
* * * * ** * * *** * * * **** ** ",b[i]);

}





return 0;



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** * * * ** **

int main()

{

int a = 0,b[10] = {0},c = 0,i = 0,j = 0,k = 0,l = 0;
* * * ** * ****** * *

for(i=1;i<a+1;i++){
* * *** ***** ** ** *


* * * ** ** * * ********* *
**** * * ** ** ****** * **
* * * * ** * = 1;
* **** * * *
* * ** ** *


** ** * * ** *
****** *** * **** ** *
*** ** *** * * * * *
** ** * * * ** *


** * ******* * ** = 0;
** * ** * **** * * * ***

   i = 0;
**** *** * * * * * * * *

{
** * * * ** ***** ** ** *
* **** *** * * ** ** * ** * ** * ** * ** * * ** * ** **
** * ** ** * * *** * * * ** **** * * *** * *** * ** * = b[l];
* ** ***** ** * **** * * * ** ****** * ** ** * * * = b[i];
* * **** * ** ** **** ***** * **** *** * *** * **** ***** = k;
*** * ** ** ** * *** * **** * ** **** ****** ** * ** ** ** = 0;
*** * **** ** ** ***** ** ** ** * *


** ** *** * *** * * * * ** ****

}



for(i=0;i<j;i++){
* * ***** * **** * * ** * ",b[i]);

}





return 0;



}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.130.204
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15475 - Available when: Unlimited - Due to: Unlimited
| 13 views
0 like 0 dislike
5 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15447 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.1k views
1 like 0 dislike
37 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15446 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 3.5k views
1 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15440 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.8k views
0 like 0 dislike
112 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15426 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 8.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users