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請設計一程式,將使用者輸入的數排序並剔除重複的數後輸出。使用者輸入的第一個數字N代表接下來會有多少個數字會被輸入,程式會將接下來的N個數由小到大排好,剔除重複的數後輸出。

sample input:
10
5 3 7 6 4 5 3 7 6 4

sample output

3 4 5 6 7
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 15442 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

edited by | 2.7k views

17 Answers

0 like 0 dislike
Hidden content!
** *** *** *

int main()



{
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* * ** ** ** ** * a[i];


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for(b = 0;b * ** i;b ++)

if(a[b] == a[b+1])
** * ** * * * * ** a[b]);







return 0;





}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * *** *

#include * ****** *

#include * * * ** ** *

int main()

{

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for ** * **

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}

if (a%2 == 0)

{

k = a/2;

h = k+1;

g = b[k]+b[h];

c = g/2;

printf * ** * * * * *

}

if (a%2 != 0)

{

k = a/2;

printf ** ****** * * ** * ***



}
***** * * * **** ** 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
* * ******* ***

int main()



{
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* ** * ** **** * * * * ** * * *****
* ** ** * *** a[i];


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* * ** * * *** *** * ** * * ******* = box;
** * ** * * ***** * * * *





for(b = 0;b < i;b ++)

if(a[b] < a[b+1])
* * * ** * * ** a[b]);







return 0;





}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * ** ** * *

int main()



{
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* ** *** ***** * ** **** * ** ** * * ** *
** * **** * *** a[i];


* * ** * * * = 0;b < i;b ++)
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** **** ** * * * = 0;c < i-1;c ++)
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* *** ******** *** = 0;b * * ++)
* ** ** * * * ** < a[b+1])
* ** ** * * * *** * ", a[b]);







return 0;





}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

int main()

{

   int a,j,t;
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*** ** ** * ** ** num[a],i;
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* * * ****** **** * * * * ** *** * * * * ** * * ",num[i]);

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>



int main()

{
* **** ** * ** i,j,k,n,num[n],m;
* ** * * * * * * * * ** &n);
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* **** ******* ** ** * * ",num[i]);


* ****** * **** ** **** 0;





}
answered by (-103 points)
0 like 0 dislike
Hidden content!
* ** * * *** **
* * *** * *** **
* *** * * ***** *
** * **

{
* ***
** ** * ***** * ** **
** *


* (i = * * ** * * *** * ***** ** * *** *
* (j = * * z - ** ***
** (i = j + * ** * * *** * ** * ** * * ** = **** ** * = ** ** = * *

}

j = 1;
*** (i = *** * * ** != ** * * * **** ** * ** * * j ++ ;}


0;

}
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** * * *** * ** * *

int main()

{

int a = 0,b[100] = {0},c = 0,i = 0,j = 0,k = 0,l = 0;
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for(i=0;i<a;i++){
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{
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** * * ****** * ************ **** * ** **** ***** * = 0;
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** * **** * * *

}



for(i=0;i<j;i++){
* * * ** ** * **** **** * * * * * ",b[i]);

}





return 0;



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** * *** * * **

int main()

{

int a = 0,b[10] = {0},c = 0,i = 0,j = 0,k = 0,l = 0;
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for(i=1;i<a+1;i++){
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* * * * * * * * * * ***
** ** ** *** = 1;
**** ** * ***
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** ** **** *

}



for(i=0;i<j;i++){
****** ** *** * **** * * * * * * ",b[i]);

}





return 0;



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* *** * ** * *

int main()

{

int a = 0,b[10] = {0},c = 0,i = 0,j = 0,k = 0,l = 0;
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for(i=1;i<a+1;i++){
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   i = 0;
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** * * * ** ******

}



for(i=0;i<j;i++){
* * ***** * *** *** ** * ",b[i]);

}





return 0;



}
answered by (-140 points)
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