1 like 0 dislike
1.9k views
請設計一程式,將使用者輸入的數排序並剔除重複的數後輸出。使用者輸入的第一個數字N代表接下來會有多少個數字會被輸入,程式會將接下來的N個數由小到大排好,剔除重複的數後輸出。

sample input:
10
5 3 7 6 4 5 3 7 6 4

sample output

3 4 5 6 7
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 15442 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

edited by | 1.9k views

17 Answers

0 like 0 dislike
Hidden content!
**** **** * ****

int main()



{
* ** *** * *** * *** *** = 0, c = 0, box = 0, i = 0;


* ** * ***** * ** * * *** * * * * * **
***** * ** * * * a[i];


* ** ** * ****** * = 0;b ** i;b ++)
** ** ** *** *** * * ** ** * * **


*** * * * * ** = 0;c * ** (i-1);c ++)
* ********** **** ** * ** * = c + 1;b * *** i;b ++)
** ** * * * * * * * ** * ** * * a[b])
* * * ** ** ** * * ** ** ** *** * ****
* ** * * * * * *** * ** * * * * = a[c];
***** * ** ** *** ** ** ***** ** * * ** * * ** = a[b];
**** ** **** *** * ***** * ** * * *** * ** = box;
******* * *** *** * ** *** *





for(b = 0;b ***** i;b ++)

if(a[b] == a[b+1])
** *** * * * * a[b]);







return 0;





}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * * * ** **

#include * * *** **

#include * ** * * *

int main()

{

 float c;
* * * ** ** * a;
** ** * * * *** * ** * * ** * * *
* * ** ** ** ** *** * **




*** * * * ** **** *
* * ** ***** ** * * * * *** * * ** * **





for ******* * ***

{
** *** * ** *** * * ** * *
* ** * * * * *** **** * * ********** ** * ** **
* * *** ***
* * ** ** ** ** * *** * ******** * ** * * = b[j];
** *** ** * ***** * ** ** * ***** * ****** = b[i];
* ** ** *** * * * * ** * *** ** * * * ********** = d;
***** ******** * ** *

}

if (a%2 == 0)

{

k = a/2;

h = k+1;

g = b[k]+b[h];

c = g/2;

printf ***** * **

}

if (a%2 != 0)

{

k = a/2;

printf * * * * * ** *



}
* * ** * * * * * ** * *** * 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
**** * * ** *** *

int main()



{
* ********* **** * * = 0, c = 0, box = 0, i = 0;


* * * * ** * *** ******** * **
** * * ** ** a[i];


*** * ** **** * = 0;b ** * i;b ++)
* * * ** *** * ** * *** * * *


*** * * * *** ** = 0;c ** (i-1);c ++)
** * * * * * **** * * * **** *** ** * * = c + 1;b < i;b ++)
** * *** * * *** * ** ** ** * *** == a[b])
* *** ****** * * ** * * **


* ** * * ** *** * * * * ***




* **** * * ** *** * * ** * * ** * * *** a[b])
* ** * ** * * * * * ** ** *** * * *
* **** ********* ** * * * ** ** ** * **** * = a[c];
*** *** * ***** **** * *** * ** * * * * * * * = a[b];
* * * * *** ** ** ** * * * **** ** ******* * * = box;
* *** * ** * **** * *** * * * *





for(b = 0;b < i;b ++)

if(a[b] < a[b+1])
** **** a[b]);







return 0;





}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include **** **** * * *

int main()



{
* * * * *** = 0, c = 0, box = 0, i = 0;


**** ***** * * *** * * ** * *** ** ** *
* * ** * *** *** a[i];


** * **** ***** *** = 0;b < i;b ++)
* ***** **** * * * ** * ** * * * *


* ** * *** ** * ** = 0;c < i-1;c ++)
* * * *** * ******** ** ** * * * * = c + 1;b < i;b ++)
** ***** ** * ** ** *** * * * ** ****** == a[b])
*** *** * ** * * ** **** *** * *


*** ** * ** ** ** * * * *




* * * *** * * * ** * * * * * ** **** ** > a[b])
* * * ** * *** * ****** *
* * ** ** * * * * ** ** ** * * * * ** * ** * ** = a[c];
** * ** * * * ** ** * * * ** * ** * *** **** = a[b];
* * **** * **** ***** ** * * * ** * * ** ** * = box;
* ******* * ** * *** ** ***




**** ** * ** * * = 0;b * ** * ++)
*** * * ** **** * * < a[b+1])
*** * * * ** * *** * * *** ", a[b]);







return 0;





}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>

int main()

{

   int a,j,t;
*** ** *** **** * * * * ** * **
* **** * ** ** num[a],i;
* * * ** *** ***** ** * *** * *
* ** * * ** **** ** * * * ** *** *** * * ** ** *


* * ** ** * ** *** * (i=0;i<a;i++)
* ** **** * * * ** ****** ***** **
**** * * ****** ** **** **
* * *** * *** ** * * ***** * * * * ****** (num[i]>num[j])
** *** ** ** * * ** ** ** *** * **** *
*** * ** * ** *** ** * ** * *** *
** ** ***** **** *** * * * * * * *** **** * * ** *** * ***
*** ** ** * * * * * ** ** ** * * ******* * **
* * ******** **
* * ** ** ** * * (i=0;i<a;i++)
* * *** * *** * * ** *** *** * * *** ** ** * ",num[i]);

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>



int main()

{
* ** ** * * * * * *** i,j,k,n,num[n],m;
** * * ** * ** * ** * ****** *** &n);
* * * *** *


* * * * ** ** * * *** ** **
* ****** * * *** ***** * ****** ** ** * * &num[n]);


* * ** **** ** * *** * ** * ** * *


* ** ** ** * ** ** ** ** ** * *


** * * * * ** * ***** * * **

   {
* ******* * * * ** * ** ****** **
** * * ** ****** ** * **** ** ** * **
* ** ** ** **** * * * ** ** * ** *** *
* * * * * *** **
**** * ** * ** * * * * * *** **


** *** ** ** * * *** * * ",num[i]);


* **** * * ** * * 0;





}
answered by (-103 points)
0 like 0 dislike
Hidden content!
** ** **
** * *** * ** * *
***** * *** *** ** *
** *** *

{
* ***
* ** * * * * * ** * *
** * * *


** (i = * * * * * ** * *** ** *
(j = * * z - * *
* (i = j + ** * * ***** * * ** ** **** ** = ***** * = * **** **** = *

}

j = 1;
* (i = * ** * ** ** * ** != ** * ** * ***** * *** *** *** j ++ ;}


* ** 0;

}
answered by (-276 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** ** * * * **** *

int main()

{

int a = 0,b[100] = {0},c = 0,i = 0,j = 0,k = 0,l = 0;
* *** * * * * * * * * **

for(i=0;i<a;i++){
* ** ** ****** * * *


*** ** ** *** * ** ** * *
** * ** *** *******
* * *** ****** * * = 1;
*** * * * * * **
* *** * * * *


* * ****** *** * **
*** ** **** * * * * ***
* ** * * **
*** ***** ** *


* ** ** * ** * = 0;
* ** ** * * * *

   i = 0;
*** * *** ** ** ******* ** ***

{
****** * ***** * * ** * *** * *
*** * *** * ** ******* ** ** **** ** ** ** ** * *
* **** ** *** * * * * * ** * * * * ** *** * * * ** = b[l];
* ** ** ** *** **** * ** * **** *** * * ** * * * = b[i];
* * * ** ** ** * * * ******* ** ** **** * * **** = k;
* * * ** * ** ** * * *** ** * ** * * * ** * = 0;
* * **** * * * ******** ** * * **


*** * * * **** ***

}



for(i=0;i<j;i++){
**** ** *** ****** *** * ** * * ** * ** * ",b[i]);

}





return 0;



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * ** ** * * *

int main()

{

int a = 0,b[10] = {0},c = 0,i = 0,j = 0,k = 0,l = 0;
******* * ****** **

for(i=1;i<a+1;i++){
** *** **** *** * **


* *** **** * ***** * ** * ** ** *
***** * *** **** *** * * *
** * *** *** * * ** = 1;
** * ** ** *
* **** * * **** **


**** * * * * * ** **
* * ** * *** * * *
* *** ** * ** **
** * ** * ***


*** ***** *** * = 0;
* * * * * * * * *

   i = 0;
* * ** **** * * ****** ******

{
* **** ** ** ** * * * * * ***
** * * * * * * *** *** * ** ** ** * * * *** ** *
* ** * * * * **** * * ***** * ** * * ** = b[l];
* ** ** * * **** * ** * * ** * ** * * * ** * * * = b[i];
**** ** ******* *** * * ** * * * * *** * * *** * * ** *** ** = k;
****** *** * *** * * **** * **** *** *** * ** * ** = 0;
*** *** ** ** * * * * * ** ** ** *


* *********** ** ** *** *

}



for(i=0;i<j;i++){
***** ** ****** * * ** ** * ** * ** * * ",b[i]);

}





return 0;



}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * ** * * * **

int main()

{

int a = 0,b[10] = {0},c = 0,i = 0,j = 0,k = 0,l = 0;
*** * ** * * *** ****

for(i=1;i<a+1;i++){
**** * * ** ** *** ***


******* * * *** * * * *
***** * *** ** * *** **** **
* * ** ** * ** = 1;
** * *** *
** * ** * ****


* ** *** * **** *
* * * * ***** ** **
* * * ** * * *** **
** * ** * ** * *


* ** ** * ** = 0;
* ** *** * * * * *

   i = 0;
** ** * * * * *** * ** *

{
** ** ** ** * * *** * * *
** * * * ** ** * ** * ** * ** *** ** * * ** *
* ** * * *** * * ** ** * * * * * ** *** *** = b[l];
** ** *** * ** * * *** * * ** **** * **** * **** * = b[i];
* * * * * ** * **** * ** *** ***** * * * ** * *** ** *** = k;
**** * **** * **** * ** * * ** * *** ** * *** ** ** * ** = 0;
** * * * * * * * * * * **** * ***


* * * *** * *** ** * ***

}



for(i=0;i<j;i++){
* * * ** * * **** * ** ** *** * ",b[i]);

}





return 0;



}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.255.33
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15475 - Available when: Unlimited - Due to: Unlimited
| 13 views
0 like 0 dislike
5 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15447 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.1k views
1 like 0 dislike
37 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15446 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 3.5k views
1 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15440 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.8k views
0 like 0 dislike
112 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15426 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 8.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users