Final Exam 2 (20%)

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A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
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37 Answers

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Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>


int isprefix(char prefix[], char txt[]){
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}


char prefix[100],txt[100],i;

int main(){
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}
answered by (-286 points)
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prog.c: In function 'main':
prog.c:24:16: warning: too many arguments for format [-Wformat-extra-args]
         printf(" is a prefix of ",prefix, txt);
                ^~~~~~~~~~~~~~~~~~
prog.c:29:16: warning: too many arguments for format [-Wformat-extra-args]
         printf(" is not a prefix of ",prefix, txt);
                ^~~~~~~~~~~~~~~~~~~~~~
commented by (4.3k points)
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Hidden content!
  **  *** *********  *
  **** **  *   * *    
char prefix(char string1[],char string2[] )
{
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}
int main(void)
{
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}
answered by (-168 points)
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prog.c: In function 'main':
prog.c:37:11: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1001]' [-Wformat=]
   scanf("%s\n",&chaine1);
           ^
prog.c:38:11: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1001]' [-Wformat=]
   scanf("%s",&chaine2);
           ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
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Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
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Hidden content!
#include<stdio.h>
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int main(void)
{
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 printf("%s is a prefix of %s",str1,str2);
**   *  * * **  ********* ** *  0;
}
answered by (-304 points)
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prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
     scanf("%s%s",str1,str2);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'int *' [-Wformat=]
     scanf("%s%s",str1,str2);
               ^
prog.c:7:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(str1);i++)
               ^~~~~~
prog.c:7:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:7:22: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=0;i<strlen(str1);i++)
                      ^~~~
prog.c:7:22: note: expected 'const char *' but argument is of type 'int *'
prog.c:10:23: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
             {printf("%s is not a prefix of %s",str1,str2);
                       ^
prog.c:10:45: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'int *' [-Wformat=]
             {printf("%s is not a prefix of %s",str1,str2);
                                             ^
prog.c:15:11: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  printf("%s is a prefix of %s",str1,str2);
           ^
prog.c:15:29: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'int *' [-Wformat=]
  printf("%s is a prefix of %s",str1,str2);
                             ^
commented by (4.3k points)
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prog.c: In function 'main':
prog.c:8:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(str1);i++)
               ^~~~~~
prog.c:8:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:8:15: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
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Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
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Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
   * *   ****    **** * * * str1[100],str2[100];
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}
answered by (-140 points)
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Hidden content!
# include <stdio.h>
# include <string.h>
 int main(void)
 {
*** * *     *  **   *   ****   ** *****  ** pre[100],str[100];
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    }
    return 0;
 }
answered by (-281 points)
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Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
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   ** ** *    * ** * ***
}
answered by (-323 points)
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Hidden content!
#include ** *   ***   *
#include    *     ** *  *** *
#include ***  *   ** * ** 

int main()
{
  ****  *  *   *****  * **    prefix[100];
  ******   ***  **  ** word[100];
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 ***       * **   **    ****** *  i;
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*  ** *   *** ** *  ** *  *
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 ** *    **         *** *   
* *    * **    **  ** *  *  * **** *  * is a prefix of %s", prefix, word);
** ** ** **    ** * ******* ****** 0;
}
answered by (-254 points)
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Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
** **  *  * * *  **    * **   n,count;
        **  * ****** *      a[100],b[100]={0},c[100]={0};
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  *   ** *  ****** *  **
**       *        ***  *     *  0;
}
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Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
*  * *   *  * * *   *   ** *   String[50],string[50];
   *   *  **   ** *    *     a,b=0;
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  * ***   ***  *   ****  ** ****
  return 0;
}
answered by (-107 points)
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Hidden content!
#include <stdio.h>
#include *** *** *  *** * 
#include   *  * *    *** 

int main()
{
* **  *      *** *** * *   a[100],b[100];
      ** * *** ******  *   *  *  ***  ** *  %s",a,b);
 **** ***  *   *  *** *   **  i,j,prefix = 1,len = strlen(a);
**     **  *******  *    ** * = 0 ; i < len ; i++)
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* *  ** ** * *  ****    *     ***   *******  * ***      ** * ** ** is a prefix of %s",a,b);


 *   * *** ** ** **    * ** ******  0;
}
answered by (-255 points)
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