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A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 10.4k views

37 Answers

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answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 0
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Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
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answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
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answered by (-108 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
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#include<stdio.h>
#include<string.h>

int main() {
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answered by (-120 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
# include <stdio.h>
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# include ** * * * ** *

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answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
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answered by (-196 points)
0 0
prog.c: In function 'main':
prog.c:9:8: warning: implicit declaration of function 'prefix' [-Wimplicit-function-declaration]
     if(prefix(p,s))
        ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
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#include <string.h>
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answered by (-127 points)
0 0
prog.c: In function 'main':
prog.c:8:11: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     int n=strlen(a);
           ^~~~~~
prog.c:8:11: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:8:11: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
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