10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include   * ** *    ** * 
#include    **  *  **** 

int water_amount;
double price=10;

int main()
{
 *     *  ******* *  * *   *  ** * *  *  **  *  * * ***  * *

 * ** **** **  *  **  **** *** *   **  * **  

***    *** ** *  ** * *    *    *  *   ** ** *        *     *  = price          * ***
 * * *    *   * ** ** *** ** ** * ******   ****** ** = water_amount - (water_amount - 60);
   ***** **** *****   *   **
  *  *  *   * ** *   *    * * *  * * *   * 

* * * *     * ********* *  *** * ** * * ***** * **** = price +(water_amount-50)*1;
 * ** *   * *****          *  * *       * *  **   *      * *  = water_amount - (water_amount - 50);
       ****  ***   *  *   ***
*** ** *  **    * **  *    *  ** *  **  *   *

 * ** ** ***** * * **  *    *   **  ** *  ** * * *  *       = price  * *  *    **
***  * **  **   *   *  ***  *** * *  * * **  *  * *  * *    *  *   = water_amount - (water_amount - 30);
    *** * * ** *** **** * *** **
** * *     * ** **   ***      * * *   * * 

*  *   *    **** * ** * **   *** * * *  **** **  *    = price +(water_amount*0.6);
***  * ** *  *   *  ** **  ***   **   ***  * * *** *   *  * ** = water_amount - (water_amount - 30)
 ****  * ** *** ***** *

*    **** **   ******** ** ** * *** * *  *   *   price);
   **   * * * **   ***** ** * * * 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

---

Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

---

Thanks!