10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include      *      * * **  
#include     * * * * ***

int water_amount;
double price=10;

int main()
{
  * * * *    ** ****  *     *  *  *** ** * * ** * *** 

*       ** *    *   *   ******  ** *   ** *  

  ****  *****     ***  ** * ** *    *** **** *****  **** * = price ** * * *  ** 
 *      *  ** ***  ******* * *  * ** **** *  *  ****    ***   ** *   *** = water_amount - (water_amount - 60);
* ** ***** * ** *    ***   
 *** * *  * ** * *  **  ***  ***   **** **    ****  *

 *    ***** **  *** *** *   *      *    *   *  *      *    * = price +(water_amount-50)*1;
** ** ***    **** *   **  *******  *****  ****  *** *  = water_amount - (water_amount - 50);
**  ** * *        * ** *  
****   * * ** * * *   * ** * **  * * * **** *   *

 **  **         **  *  *     *  **    ***   *** **** ** **    = price *     *** ** **
*  *     **  * * ****   ** *  *  ****   * *   ***     *      ** = water_amount - (water_amount - 30);
 *  *  ****  *   * **    ***
 **   **      * * *  *    **  ****    * * ** *    

* **** *   **** * **   * *   * * *  *  ** *  **    ****       = price +(water_amount*0.6);
** * * *  **** *  ** *   * ** **  ** **  *    * *      *  ** = water_amount - (water_amount - 30)
   ***  * *  *    *   ** **  **

*  *****  ** *  *   **  *  *   *   * *** *  price);
** **   *   *  * * **  **  **** * 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!