10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include * *  *  * ***** ***
#include ** **  *****  *  

int water_amount;
double price=10;

int main()
{
*    **  *     ****    *** *   ** ** *  * * *  ** * *** **   *

 * **  ****  * *  *** *****  * *   *  *  *    *

     *   ** * ** **  **** ******* * ** ** **  *  * *   *****     = price *   * * **** 
* * ******  ** * ***      ***    * ** *   ***  **  ** = water_amount - (water_amount - 60);
      *     ** ** *  ** 
* *     *    **** *    *  **  * **  *** **  *   

 ***  ******  **** ** *  **  * **   *  **  ***  *** **   = price +(water_amount-50)*1;
*****       *     * * *    **  *   ****    ****  * ********  = water_amount - (water_amount - 50);
   * * ***    * *     **   *
*  *  **   *      ****   * *    *** ***  *  * *** * *

**  * **** ***** ******         *****  ** ***** * *** *    * = price  * *     *****  *  
  ***  ********** *** * **  *  ** *  **      ****     *  = water_amount - (water_amount - 30);
*  * *   *  ** *  *  ** *** 
 *   *      *****   ***** ** *** ***     

 ***** * *  *      * * * * ** *   *** * ** * **** ** ***** * *** *  = price +(water_amount*0.6);
 *** ****      * *  ***     *** *** *  * **  **  ***       *      = water_amount - (water_amount - 30)
*  * * ** ** *  *  * **      

* *  * *   ** ** **    *   * * ** *  * *       price);
 *      *** * *****  **  *   *** *** 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!