10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include ***** ******* ***
#include *  ** *****  *  **

int water_amount;
double price=10;

int main()
{
 *** *  ***** ***  **  * *  * *  ** * * **  **        *** *  

*    * *  *****  ****    **   * * * *   ** * *

* * ***  *   *        ** *  ***  *  ***** **  *   * **   *  = price ** * * *  * *   *
    ** *   *******    **  **  ****   * ** * *  * *  ***  ** = water_amount - (water_amount - 60);
* ** *  **  *** ***     *** * *  
****   ********   **    *    *          * ** 

**    **    *  *     ** *** *******  *      *  **   * = price +(water_amount-50)*1;
 *  * *      ** **  *  **  *    ** *****  *  **** * *    * *     = water_amount - (water_amount - 50);
* ** * **      * * *** 
**** ***  ******* *** *   * **   *** *** * * 

**  *  * **    *      *** *** *    * ******  *  ** *  ** * = price   **     * *
  ** * * * ****  **     *  *     * **  ** * **   *   **   **   = water_amount - (water_amount - 30);
* *    ** *   ***** *     *
 **** **  * ** ** * **   *      *  * * *    **  

*      ****  **      * *** **** *    ** *   ***   ** = price +(water_amount*0.6);
  *    *  ** *** ****  *  **  ***  *   * *   * ***   *    *  *   *  *  * = water_amount - (water_amount - 30)
  *    **  **  *   ***

   * * *  *  *  *  *    **  ****** *** *   * * price);
**  **** * **   *******   * *** * * 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!