10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include  ** *  *  **** * 
#include  *      **** **

int water_amount;
double price=10;

int main()
{
   ** *  ** * ** * *    ****  ** * *  * **  * * *  ** ** *** *

 ** * **  *  * * *    *    *   * * ** *   *  

* ** **  *  * **  **   * * * **  * **  *  * *** *   * **  * = price    ****  * * * 
***** *  **  *** * * *  **    *********   *   ***** * *** * * = water_amount - (water_amount - 60);
 * **  *     ** *  *   ** *
 ***   * *  *  * *  *   **** ****  **  ***   

* ****  *  * *  * * *  * ***  *  ** *   ** * **  = price +(water_amount-50)*1;
  *  ** **   * **  ** ***  * **** *    ** * *  * ** *** *  ** *   = water_amount - (water_amount - 50);
****  *         ******    *
*** * * ** **** ** *    *  *    * * **** ***    * *

 *  ***** *****       *****  *  * * * ***  *        * = price **  *   ** ** 
 *      ** **   **  ** * **   ***  *  * *   * ** ***  = water_amount - (water_amount - 30);
* * ***** ****   *  ** * *   * **
* *****  ** ** * * *    ****  ** *  ** 

 **    ***   ***  * *   *  ***** *  * *  *   * *  *** = price +(water_amount*0.6);
 ** * * **  * **  **** *    *** ** **  * ** **     *   *  = water_amount - (water_amount - 30)
     ***  *** **     * 

*    * * *** * *  *   *  * ****  **  * **  * price);
** ****  *  *  ******  **   **  *  0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!