10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include   **    ** *  *** 
#include  **** * * **   **

int water_amount;
double price=10;

int main()
{
*  *    ***  *  *    *   ** * ** * * *  * **  *  ***  ****  *  *

    *** *    ***  ******   * *  ** ***    

 ** *  *   **** *  ***        *  ****  *   ***     * ***  *  = price      ** *  *   
** *** * * **  * **   ****   ** * **** ****** * * ** * ***    = water_amount - (water_amount - 60);
********  * *****  * *******  
**  * * * **  *  * **     * *  ****** **  *** 

****  * *  ****** *   ** ***  * * **   ** *** ** *  *  = price +(water_amount-50)*1;
  *  *   *    * ** * * **   *    *   ** * * * * * *** *   *    = water_amount - (water_amount - 50);
 *  **** **   ** **  ** * *
*  * **  * ***     * **    * *  **  **   

*  ** **   *  ** *  *  **  * * ******* *** * ** ** * * *** = price *   *************
    *      ***    **** * **   **  **  *****     ** *  *   **  = water_amount - (water_amount - 30);
 ** * ***** *   *  **  * * * 
**   ***    * ** **   *  * * * * *** *  ***  *   *

  *** *  * * ***    *  * *  ** **** *   *  *  * **  **    * = price +(water_amount*0.6);
   ** *** **    *** * ***   **     **  * *  *  *     ** *    **   = water_amount - (water_amount - 30)
  ***  **** * *      *   *

 * ** * ******** * ** * *** *  **** *** *   price);
 ******* * ***   * ******      **** * 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!