10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include * **  * * *  **
#include      ******* *** 

int water_amount;
double price=10;

int main()
{
***  *** * * **  *  *** ******* *  *  ** **   * *    *  * *   * *

*    ** *  *  **  ***   *   *** * * * ** *  * * ** 

 **   **     *  **     *  *  *  ** * *   * ** * ** ** * ** * = price   ** **      *** 
** ** * * * * **       ** ** * ** *  **      * *  *** **  **  = water_amount - (water_amount - 60);
 *  **** **** ***  ***  *  *
 *      * *  **        *         *  **  *

  *** * * ** **** * *** * *** *  **   *** * **** * ****  ** * = price +(water_amount-50)*1;
 ***  * ** ** ** ** * ** * ***** * ** *  ***** * **  *** **  * * = water_amount - (water_amount - 50);
 *** *    *   *  * ** ** 
  *   *** ** * **    * ** **** * ***  *** * 

** **   **        *    *  ** * *  * ** * *       ****    * = price **  *   * 
 *   *  *  *   *    *****    * * *  ** *  **  *  *  ** * **     = water_amount - (water_amount - 30);
 *  **  * *** *  * * * * * *  *
  ** ****** ************ ***    **    * ** *  *   *** 

    **  *****   *****  *  ** *  * *** *** **  **   * ***** = price +(water_amount*0.6);
** * * **  * * *  ** ******   *   **   *** * ****  *       * *     = water_amount - (water_amount - 30)
 * ***   *  ** ** * ***  **

* **  *  * * ** * *** **   ** *  *   * *  ** * price);
**     * *  ** ***  *     *** *  0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!