10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include  *   ***  *  
#include  **  *  *  * ** * 

int water_amount;
double price=10;

int main()
{
*   * * * * ** *  * * * * *  * * ** *  *  ***    ***  *** *** **

 *** *    **   **  *  ** ***    ** ***  * *   

 **** ***  *  ***   *** * * *  ***   *   ** * *   *   ** ** = price  *** *   *** ****
**        **  *  * **** ** *  *   *   ***  **  ** ** **** = water_amount - (water_amount - 60);
* *  * * ***   **   **  ****   
 *  * * * ** *      *  **** **** *** **   ** * 

* *    * *  *  ****** ** * **** ***        ***    * ***   = price +(water_amount-50)*1;
 **   **    *  * **  ** ** * **  *** ****   * * **  *   * ** **** = water_amount - (water_amount - 50);
 ****   * *** * * *****    * 
 *  *     *** ***   ******  ** *    ** * * ** * *  ***  

**  *  ** **      ** *** **  **  * **    ** ** ****  = price  *** *   *
**** * *   * **  *    *   *  *   *** *  *    ****   **      = water_amount - (water_amount - 30);
      **  ** *** *******  **** ** 
 ** **         * ***  ** *  **  * **** **  * * 

*       *  **** *   **   * **  ***  **    * *     ******  = price +(water_amount*0.6);
 * * * * * * * ***   *  ***   *     * ** *    *   *  **     * *** = water_amount - (water_amount - 30)
*  ***  *   * ** *  ** *  *  **

**   ** *    * ***  **  *   **  * ****   *** price);
 *   **  *    ** * *  * * ****  0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!