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A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 26465 - Available when: Unlimited - Due to: Unlimited

edited by | 24.4k views

91 Answers

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Hidden content!
#include * * *** **
#include ** * * * **

int water_amount;
double price=10;

int main()
{
* *** *** * ** ***** * ***** * * * ***

*** ** ******* * ** * * *** *** *

* * * ** ** ** **** ** **** ** * = price * *** * **
* ** ** * * **** ** *** ** * * ** *** *** = water_amount - (water_amount - 60);
* * * ** * ** * * * **
***** * ** ** * ** * * **

* * ****** ** * * * *** * * * *** * = price +(water_amount-50)*1;
** ** ** * * * * * * * * *** * * ******* * * *** ***** = water_amount - (water_amount - 50);
* ** * ***** ** **
* * * ** * *** ** * ** ****** *

*** *** * ** * *** * * *** * ** *********** **** * = price * * * *** ** * *
* * ***** ** * * * ***** *** ** * ** ** ** **** = water_amount - (water_amount - 30);
** * *** * **** ** * **
* * * *** ** ** * * ** * *** **** ** *

* **** * ** * * * * ** *** *** * * * * * * = price +(water_amount*0.6);
** * ** * ***** * *** *** * * ***** * * ** = water_amount - (water_amount - 30)
** ** ** **** * * ***

* * * ** **** ** ** ** * * * price);
** ** * * * ** * ** ** 0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00
0 0
Thanks!
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