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A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 26465 - Available when: Unlimited - Due to: Unlimited

edited by | 13.8k views

91 Answers

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Hidden content!
#include * *** *
#include ** * * * ** *

int water_amount;
double price=10;

int main()
{
* * * * * ** * * * * * * * * ** * * *** *** *** *** **

*** * ** ** * ** *** ** *** * *

**** *** * *** *** * * * *** * ** * * * ** ** = price *** * *** ****
** ** * * **** ** * * * *** ** ** ** **** = water_amount - (water_amount - 60);
* * * * *** ** ** ****
* * * * ** * * **** **** *** ** ** *

* * * * * ****** ** * **** *** *** * *** = price +(water_amount-50)*1;
** ** * * ** ** ** * ** *** **** * * ** * * ** **** = water_amount - (water_amount - 50);
**** * *** * * ***** *
* * *** *** ****** ** * ** * * ** * * ***

** * ** ** ** *** ** ** * ** ** ** **** = price *** * *
**** * * * ** * * * * *** * * **** ** = water_amount - (water_amount - 30);
** ** *** ******* **** **
** ** * *** ** * ** * **** ** * *

* * **** * ** * ** *** ** * * ****** = price +(water_amount*0.6);
* * * * * * * *** * *** * * ** * * * ** * *** = water_amount - (water_amount - 30)
* *** * * ** * ** * * **

** ** * * *** ** * ** * **** *** price);
* ** * ** * * * * **** 0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00
0 0
Thanks!
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