10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include  **  **  *** ***
#include   **  *  ***  *

int water_amount;
double price=10;

int main()
{
    * * ********  *     ** *   ** ***  * * *** *     *** *  

* ***********  **  * **** *   ***  *** *  **** *

*****  *    *     ** * ** **  *   **  *  *** * **  * **  *  = price   ****  * * *  *
*** ** **  * * * *  *   ** **  ** *   *  *   * **    *   ** = water_amount - (water_amount - 60);
*    * *  *  ****** *  * *
 *   **  *    *  ** ****   *    *  ** ********  *  

 * * **   * *  ***** *  ***   * *** ****    ** ***   = price +(water_amount-50)*1;
*   ******   *  * * *** ** ******   * ****  * * ** ***** ***** *  = water_amount - (water_amount - 50);
  * ******  * *** *  * ****
  ***  **** *   * **   ***   ** *** * * **  * *

*** ** *** * *  **  * ******* **  * ***  * * * * * * ***** = price   *  *  *    
***  *** **** ***** ** *   *  ** *   **   ****   *   *** * * = water_amount - (water_amount - 30);
**      **** **  *  *** *  ***
 ****  * *    **** *****            *   ********

**   *** * *****  *  **  ** ** **   *    *  *  * *  ** * * *  = price +(water_amount*0.6);
   *      * * **  ** **   **     ****   ****** ******   *    ** = water_amount - (water_amount - 30)
   *      * **  *    *   ** 

    *** * * *    * ***  * * * *  ** *    *****    price);
*  *   *   ****** *** * ** 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!