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A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 26465 - Available when: Unlimited - Due to: Unlimited

edited by | 18.3k views

91 Answers

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Hidden content!
#include * * * ** *
#include ** *** * *

int water_amount;
double price=10;

int main()
{
*** * ** * ** ** * * * * * *** ** ******** * ***

* *** * * * * ** * * * **

* * ******** ** * *** *** * * **** * * = price * * ** ** **
* * *** * * ** * ** ****** * * * * * * * * * = water_amount - (water_amount - 60);
** * *** * ** *** *
** * **** ** ** ** ** ** ** * * ****

* ** ** * * *** *** * ** ** ** ** * ** = price +(water_amount-50)*1;
*** *** ** ***** **** * * ** * ******* ** * * * * = water_amount - (water_amount - 50);
* ** ** *** ***** * *
*** * * * ** ** * ** * * *

*** * * ** **** * * **** * * *** = price * ******* * **
** ** * * **** ********* * * *** ***** ** ** *** = water_amount - (water_amount - 30);
** ** * * **** * *
** ** *** * ** *** * ** ****

*** *** ** * * *** *** **** * * *** ** *** * * = price +(water_amount*0.6);
** **** * * * ** * * *** ** *** * *** * * ** * * = water_amount - (water_amount - 30)
******** ** *** ** * ***

* ** ** ** *** * * *** ** *** * * price);
* ******** * * ** * ** * * * 0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00
0 0
Thanks!
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