10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include  * *   *  * ***
#include *** *  *   **    

int water_amount;
double price=10;

int main()
{
 *** *** * **  * *   * ****** *** * **** ** *  ** * **  ***  *  * **** 

   * *  ***  *  ** *   *  *  *** * *    **  **

 * * ** **    * *   * ** *  *********  **   *** *  * **  = price   ***   * ** 
* **  ** **     * *    *      *** *   ** ***   **  ** **** *   = water_amount - (water_amount - 60);
 ***  *** **  * *  **** ** *
   ***** *** * *** ****  *  * *    * *  

**  *    **** ** * ** *  * **  *  *   ****** ** ***  ** = price +(water_amount-50)*1;
 ** *   ***   *** * * ***   * * * ** ***  ** *** ** * ** *    ** ** = water_amount - (water_amount - 50);
 ***   ****  **    *  ****    
**  ** ** **     * * *   *  **  ****    *****

 *       **** * **  ****** ****  *  ** ****   ***  = price    * *   *** * ***
 * *  ****  ** ******* *             *   * * *   * *  **  *    = water_amount - (water_amount - 30);
*   *  *  *    ***  * *******
  * *** **  *       **   * **  *  ***   *

 * ** ***       * ***** *  * ** ***    *  ****    ** * = price +(water_amount*0.6);
   ** *  * *  ***   ******              *  *  *********** * ***     * = water_amount - (water_amount - 30)
*  ** *  **   *** **   ****     **

******  *   *  ***   **  * *  *    **   **  *    price);
 *   * *** **  ** *  ** * ** *    0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!