10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include * *   ***   * *  **
#include  *  *   *  **  

int water_amount;
double price=10;

int main()
{
   **  *   * *  ****  * ** *  **  ***     ***  *  ******   *** 

*   * *  *** *  * ****    *   * ** **  *    **   

               ****      ** *  ** * * *   *   **  **     * * = price *   ****  * *  *  
  **     *  ***    ***** *        ***  *  *      * **    **     = water_amount - (water_amount - 60);
  *** *** * ** *  **   * * *****
**   **     ** *  *  ***** *    * * * *** * *

*  ********** *   ** ****** **   **********   *     *  ** = price +(water_amount-50)*1;
******* *   *    * ******* *  **  *** *    ** *****   **  = water_amount - (water_amount - 50);
* *****    * *     ****  ****  
  * *   **  **** ****    ****   *   * *      ***

*  **  ** * **** **        * * * **   ***  ** * ** * = price   *** ** *  ** *
**   **  *  *******  *    * * *  ** ******* * ** *  **   * **  ** = water_amount - (water_amount - 30);
 * ****  * *   **   ********
*   *  *  *** * *  * * *     ***** *** * **  *

**  **  ** **  ** ** ***    * *   *  * **  ** *** = price +(water_amount*0.6);
**   **   ***** * ** ** ****** ***   * ***  *   * *  **** *** = water_amount - (water_amount - 30)
  **  **    **** ** * *  *   

    * * ***** * *  *  **  *  * **    ***  *    price);
* ** *  ** *  * **** **  *** * ***  0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!