10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include ** ****    **  * *
#include **      *****  ** 

int water_amount;
double price=10;

int main()
{
  * **** *   * *    **  ** ** *** ** *     * * * ** * ** *     * **

   *** * * ***  *   **  *  * *   **  ***** * 

***  *   * *   **  **   ***  *****   **** ** **  * **  ***** = price *** *      ** 
***      **  * ** **  *  *   *   ** *** **  *   * ** ***  ******  * *  = water_amount - (water_amount - 60);
***  * **  *  **     * ** 
** * * *****  **  ** *** *  * *  *  * 

**** *  *    * **   ** *  *     *** ****** ** **  ****  = price +(water_amount-50)*1;
 * **   ** * *  ***  **** ***  ** * ** * **** ** * **  *    ** = water_amount - (water_amount - 50);
 ****** *  *  **** ** *  
    ** **  ** **** **  **    * * * *     ** *** * 

 * *** * *  * *      * **  *        **  **** * * **   = price  *   **  *  * *** *
 *   * **    * ** ** * ** *  ** ** * *  *  * * *  *   * * ***   = water_amount - (water_amount - 30);
*      ** * *** ****  *    *
 *    *** ****** *** * *****  *  * ****  ***     

  *   **  *  ****       **  ****   ** ******* ** = price +(water_amount*0.6);
** *** **  *  * * * * *** *** *  ***** *** ****  * ** ****  **  = water_amount - (water_amount - 30)
 **       * * * ****  **  *  * *

*   *   ** *  *  ***  ****  * ****    * *    **** price);
*** **   ***** *** * *** **  0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!