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A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 26465 - Available when: Unlimited - Due to: Unlimited

edited by | 17.6k views

91 Answers

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Hidden content!
#include **** * *** *
#include * * ** ** *

int water_amount;
double price=10;

int main()
{
* * * * ****** ** ** ** * *** ** ** *** * * ***

* ** *** ** * **** * * * ****

* *** **** * * ** ** * ** ** * * * * = price * **** * *
* * *** * ** ***** ** * * * *** **** * = water_amount - (water_amount - 60);
* * * **** ** * **
* ****** ***** * *** *** * * * *

* ***** ********** *** * * ** * * * * **** = price +(water_amount-50)*1;
* * *** * * ****** * **** * ** * *** *** * *** **** * = water_amount - (water_amount - 50);
** * * ** ********
** ***** * ** ** ** * ****** ** ****

* ** * **** * *** * * ** * * * * *** = price * * ** ***
** * * * * * * *** ** ** ** * ** ** *** ** *** = water_amount - (water_amount - 30);
* * * ** ** *** **
* * * * * * ** * ** ** * * *

* * ** *** * * * * ** *** * *** **** ** = price +(water_amount*0.6);
* ****** ******** ** * * ** * * ** ****** ** * ** *** = water_amount - (water_amount - 30)
** * **** * * *** **

* * * * ** ** * ** **** **** * * price);
* * * * ** * * * * ***** 0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00
0 0
Thanks!
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