10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include  **   ***    **
#include   * *******    * 

int water_amount;
double price=10;

int main()
{
  *****  *     * * **   **** *  * ***  * *    *** **  ***** *

* *  * *  *    *** * *   *    * *** **     * 

*  ****** *          * ****   *** *  * * *  *    *****  *   * = price    **   *  ** ****
          * *  *     ***  ******* ** ***   *** *     **** **   ** = water_amount - (water_amount - 60);
**   **       *   *  * 
 **   * ***** *  * *    *****   *   ***  *  ****

* *****  * ** ****    *  *      * *    ***    ** * *  **  = price +(water_amount-50)*1;
    * ****   *  **** * *  *    *   **  *    *   *  **      *  ** = water_amount - (water_amount - 50);
   ****  ** ****  ** **** * 
   * *  *  * *  *  *  * * * * *  **   *

 ***  *   *    ** *    *  *   *   *  **   **    *   * *  = price   * * *  * *  * 
  * *  * ** * *   *  *   * *  *  **   **    *** **  *****  *** * = water_amount - (water_amount - 30);
* * *  *   **        ***  *
 ***** * **    * ****** *   *  * *  *   ****   * 

 * ******  * *  **  * **  * ***    **   *  ** **** * *  = price +(water_amount*0.6);
  **  * * * *     * **      **     ****    * **  ** *        ** * * = water_amount - (water_amount - 30)
       *     ***** ******   * 

* *   ** **  **** ** ** * *  *  * ** *** **** * * *  price);
*  ** *     *** *  ** ***   * ** 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!