10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include **     *     **
#include  *** * **  *** *

int water_amount;
double price=10;

int main()
{
 ** ** * *****  **   * * *****  * *******  **  ***  *** **

***   *  *   * *   * ***  *   ***   * ** ** *     **

**** * *  ** * * * ***   * ** *   * * *  ****  **  * ** ** = price   * * *       
 *  *** *   ***** **    *  * * *  **  ** **  ** ** **   ** = water_amount - (water_amount - 60);
**  * * **** **** **  **** 
* * *  *  **  * * * ** *** ** ****  *  **  *  * * *

**  * * ** * *  ** **** *  ***    **  ***   *     *  * *** = price +(water_amount-50)*1;
******* * *  ** ***         ***** * *  * *** ** *****  * = water_amount - (water_amount - 50);
** *    *  *         ***  *
*  *   * **** * ** ****  **   *   *  *** *   ** 

 ***      ***     *  * * ***    ** *** **     * ** * **  *  = price   * *    ***  ***
  * * ***  **** ** *** * * *      * *    * * *     ** *    **** = water_amount - (water_amount - 30);
*****   *  *** * ** *  * *****  
*  * ***  * **   *   **   *       **** * *  * **

 *****  ***   *  **  ** *****    * **** ** ***  ** ***** ** = price +(water_amount*0.6);
      *   *****  **  *****    * * **** ** ** *  **   *   *   *** = water_amount - (water_amount - 30)
 *   ** *** ** ****    **  

*    **   * **** * ** * **  *  ****** *    ** price);
  *  ***  *****  ********   *    0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

---

Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

---

Thanks!