10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include **  ***    **  
#include *        *   * * 

int water_amount;
double price=10;

int main()
{
     *  * **   *  **  ** * ****** *  * ** ** *    *  *** *** **  

 *** * *   ** *   * **   *** *   ** *  *

*   **  * *** *    *   ** **   ***  ** *  **  **** * ***   ** ** = price ***  *  *   *** 
 *  *** **   **** ***** ****  **** *  ** *    * * *** * = water_amount - (water_amount - 60);
  *  * **     ** *  *  ***** *
**  * **** * ** * *      *   ** ** * **     **   * 

     **   * * ** **   *      * *  * ** * ** *  ** * ** *    * = price +(water_amount-50)*1;
 * * * ***  *** **  * **** ******   * *  *   *   *   ** * **  = water_amount - (water_amount - 50);
  *  *     *    ** **  *
**  *   * *   **  *    **** ***  * ****

  *** ** *** *    **  ***  * *  **** *  *  * ** *** ***  *  * *   = price *    *** **      
 * * *** * ** * * **** *       *  * *** ***  *** ***   *    = water_amount - (water_amount - 30);
  *****            *** * ** **  
** ** ****   ***  *** ** ****** *  * ***  *

*** **  **      * ** **     *** **    *  * **   *** ** = price +(water_amount*0.6);
 *   * **  * * ** * * **** * ** ***** *  *  **** *   *  ***    = water_amount - (water_amount - 30)
**  **** *  ** ** *  **  *    

        **    *   * *  * *     *  *  **** price);
*  ***  * * ***     **  ** 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!