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A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 26465 - Available when: Unlimited - Due to: Unlimited

edited by | 25.3k views

91 Answers

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Hidden content!
#include * * * ***
#include * ** * * *

int water_amount;
double price=10;

int main()
{
****** * * ** *** ** **** *** * * ** * ** **

* * * * ** ***** * * * * * ** * *** *

*** * ****** * ** * * ***** * * *** ** ** = price * *** ** **
** * * ** * * *** * * ** * ***** **** * * ** * ** ** = water_amount - (water_amount - 60);
** ***** * * *** *****
*** * * *** * * ** * *** ** ****** **** *

** * ***** *** ** * ****** **** * * = price +(water_amount-50)*1;
** * * ******* ** ** ** * * *** **** *** *** = water_amount - (water_amount - 50);
* * **** ** * * *** * **
* * * * ** * *** **** **** * *

** * * ** ** **** **** ** ** ****** *** = price * ** **
* ******* ** *** * * * ** ****** * * * * ** * *** ** = water_amount - (water_amount - 30);
* * * ***** *
* *** * ** ** ** **** * * * **

* ** *** *** * *** * *** * * * *** ** = price +(water_amount*0.6);
** *** * ** **** *** **** ***** **** * * * * ****** = water_amount - (water_amount - 30)
** ** ** * * ** ** ** *

** *** ** * *** ** * **** * ** * price);
* * * *** **** 0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00
0 0
Thanks!
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