10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include ** *   *      
#include *  * *  ***     * 

int water_amount;
double price=10;

int main()
{
  * *       **     ** *    *  *  *   * *  * * *** *** * *

*****   * **      ***   * *  * * ** *   ** *  **  

 * *      ** ** **  *       * ** ** * *  * *** *   * * *  *** = price  ** * *  *** * * *
**  *** ** ***     **       * ** *   ** **   **** * *     *** ** = water_amount - (water_amount - 60);
 ****** ****  * *   * ** * *
*    * ****     ** ****    *   * ** *

  * ***   ** * ** ** *   **  *     **    *  *  ****  *    *  = price +(water_amount-50)*1;
** ** **  ***  *    ***  **** * ** ***      *    *  ** * = water_amount - (water_amount - 50);
*  **   * *     ** ******     **
* ***  * **     ** * * *  * *    ***    * * * 

     * * * **  *     * * *  *** **  * ** *  * **** *   **   = price   *   * ** * * *
* *** * **** *** ***  *  ****    *  *** ***  * * ** *   *** = water_amount - (water_amount - 30);
** *  **   * ***    *  *
     * * * **  * ** *  **   *  ** *  ***  **** 

**    ** * *** ****       ** *   **    * *       *    = price +(water_amount*0.6);
*  **  *  ***** * *  **   **   *  *  * ******  *  *  ***  = water_amount - (water_amount - 30)
  *   * **  *     * *  *  

* ***  **    ****     *** **  **   ****  ** * price);
******  *    **  **** *   *****   0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!