10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include *  ***       
#include  * *   **** *** **

int water_amount;
double price=10;

int main()
{
  **    *    *  ** *** * *  **     **  **   * **  *** *     * 

 * * *  *   * * * * **  ***   *  *  * **   **

  * *  ***  *     ** **    *  ***** *****  *   * *    * *    = price ***  ** *** *
 * *** *       * *    **    ****   *  ***** ** *   *  * * * = water_amount - (water_amount - 60);
**** *  ****   ***  * **   * 
 * *  *      *** ** * ****   *  *  **  ****  

***   *******  *    ********       *  * **  ** **    = price +(water_amount-50)*1;
**  ****    *    ** ***   **   **   ***   ** * ******     * = water_amount - (water_amount - 50);
   * ***** ***   * * *    *
* *    ** *  * ** *   ***  ** **** *   ***** *

** * ****   **** **** * *   **      * * *   * **  * *  ****  = price **   * * ****** 
***   *   *  ** * ** ** *   * *** * * ** **  ** *    *  * = water_amount - (water_amount - 30);
 * * *    *  *    *** **** 
 **  *** ****    ** * **  ******* * *****  *   ***

* ********  *** **     *** * * * *   * *   * ** *******   = price +(water_amount*0.6);
  * **   *  ** * **   * * **     * ** **  **       ** *** * ***** = water_amount - (water_amount - 30)
 *  *  * *  *  * *   *

* *  ****   * *   ***  * ** *  ********  ** price);
*** **  * * *   *   * ******* * * 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!