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A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 26465 - Available when: Unlimited - Due to: Unlimited

edited by | 18.7k views

91 Answers

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Hidden content!
#include * * * * * *
#include ** ** *** ****

int water_amount;
double price=10;

int main()
{
* * ** ***** ** * * * ** ** * **** **** **** ** * *

* **** **** *** ** ** * * *** **** **** *

**** * ***** * ** ** ** * *** * ** ** * = price * * ** **
* ** ** ** * ** * *** * ** **** ** ** * = water_amount - (water_amount - 60);
** * * *** * ***
** *** * * * ** **** ** * * *** ** *

* ** * * * * * * ** *** * * * **** ** = price +(water_amount-50)*1;
* * *** **** * * * ** * * ** * * * **** = water_amount - (water_amount - 50);
* ** **** ** * **
* * * * * *** * * *** * * * * *** *

* * * ***** * * * * ** * * * *** ** = price ***** **
* ** *** * * ** ** *** * ** ** ** * * * * * ** * * * = water_amount - (water_amount - 30);
*** *** ** * ** *
* * ** * * *** *** **** * * ******

**** * * * * **** ** ****** ** * * *** * ***** * * = price +(water_amount*0.6);
** ** *** ** * **** ** * ** * * * * * ** *** ** * * ** ** * = water_amount - (water_amount - 30)
***** * **** ** * *** *

* *** * ** ***** ** ** * * **** ** price);
** * * *** ** ** * * * 0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00
0 0
Thanks!
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