10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include ***     **  
#include   **  ***  ** **  

int water_amount;
double price=10;

int main()
{
  * * *******  * *   * **  * **  *  ***  **  ** *  **  **

  * * ***    * * ****  ***       * ** * ***

*   *   *   ***   **   *  ** *** * ** ***   **    ** ** *  = price * * *  * ** **** 
*   **  **   ******  *  *** * *** * * *    ***    ****** **    = water_amount - (water_amount - 60);
** *    * * **  **  * *  
* ****  *   *** *   *   *       ***** **** ****  * 

 ****     ** **  * *****   * *  *    * * ** *   ***   *  * = price +(water_amount-50)*1;
 ****     * *** * *** **** ** ** * * ***    **** **  * *   = water_amount - (water_amount - 50);
*  **   *  *****  ***    **
* ** **   *   * ** ****  ***  ** ** * * **   *    *

* * ***** * ****** * * ** ***  **  * *  ** **** * * * ***  = price  **   ** * **  *
* * **   * * **  *** *** **  *  *   * * ****   **     **** = water_amount - (water_amount - 30);
    * *** **** ** *  **
**** * **  * * **    **   *****   ** ** *   *

***  **    **      **   * *********    * ** * **  * * *   = price +(water_amount*0.6);
   *  *  **   *   * *  ** *** * *  * *** * **    * *** * *  = water_amount - (water_amount - 30)
 * ***    *** * * **** * ***

*   **  **  *** *** ********** ***** ** **** *****  price);
  ***   * *      ***  **  **  0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!