10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include *** ***  ** **
#include  **    *    ** *

int water_amount;
double price=10;

int main()
{
 *     ** * * * *  *** ****    **  **** * ** *  *  *    *  

* *   * ** ** * **  *  ****   * ************  

****  *** * ** **    * *   ** **  *** **  * ** ** *  *  * *  **  = price ******   *  ** 
 ** *  ** *   ***   ** **** ****  ***** * *******    * * = water_amount - (water_amount - 60);
* *  * **   * * *** *
* **** *    ******  * **  * *    **

    *  *  *      ***** ***** ****  **      * *  ****  * *** = price +(water_amount-50)*1;
*    **  * * **  *  * * * **  * ** **   *  *     *  ***** *****  *****  = water_amount - (water_amount - 50);
  *   *   *** ******* * * * 
**  *    *   *  * *    *  *   **  **** * **

*  *     ** *  * * *   **   *** ****     **** * ******     = price * ** ***  ****
**        ** *     * ********  ***  ******   * **  *     *  * = water_amount - (water_amount - 30);
*  * *** *************   **   *
**** ** *** ** ****** * **   **     ** **** *   **  

*****  ****    *   **  ** * ****  * *  ** **  * * *      = price +(water_amount*0.6);
   *  ** *  * *       * * *   * **         * *    * *** ****  *    * = water_amount - (water_amount - 30)
 ** ***   * **  ***** * ** ** * 

 * * **** **  ***       * **   * *  **** *  *    price);
** *  ***   ***  *  ** * **** **** 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!