10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include  *  *  **     ** * 
#include *  ***   **** 

int water_amount;
double price=10;

int main()
{
*  ****** * *    *   * ***    * *  *  *  * ** ** **  * *      *

* **   *  ****   ** ***** ** **  * *        **  

 *  ****  *   * *****  ** * ** *** *******   ** * *** = price ** * ***  *** * 
       *   * **    *  **** * * * *  ***   *** * * *** *  *** = water_amount - (water_amount - 60);
* * **        *   ***** **   
  ** *  * ****** ** **        *  *   ***

* *  **  *** ** *   *  ****  *   *         ****      * = price +(water_amount-50)*1;
 * * *    * *  **** *** * ** *    *   ** **  *   *** **    = water_amount - (water_amount - 50);
* ***  ** ****   * **  ** * **   * 
*  * * * *** ** *   **** *   ** ***   *   * ***  

**  **** *   **   ***   *  *  ***  * *** *** *****  ***  *** = price  * * * *   
* *   * *  ** **    **  ** *** **   *      *  *   *   * *** * * **** = water_amount - (water_amount - 30);
***  *      ****** * * *  
* *  *    * * **** *      **  *** *     

* *  ** * * ******** * ** * **    ** ** ***   *  = price +(water_amount*0.6);
  **  * **   *  * *      * * ** *** **  * * **  **** **  *   = water_amount - (water_amount - 30)
 *** *** * *    **      **   *  

** ***     ****  ***   **        ** * *     **     * price);
*   *   * * *******   ***   *   0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!