10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include * **     *  
#include   * *  ***  ** ****

int water_amount;
double price=10;

int main()
{
 *  ** * ** **    ***  ** **     ***    *  * * **  ** *   **  ****

 ****  * *   *   * * *  *** ** *** ** * ****   

* *  *  * **** *  **      ****** ***  *** *  ***  *** * = price * **   * *   * 
*  *     *  * * ***  *   *  *    *   **** ***   * ***** = water_amount - (water_amount - 60);
* * *** * **  ** ** * **  ****
** **  *  *  *** *    * ** *  *  *  * *     *  *  

  * ***** * *** **  * * ***      * **    ** ***     ** = price +(water_amount-50)*1;
  ****   **  * * **  *  ** *     * * * **** ****   * *** *   * * = water_amount - (water_amount - 50);
 *  **** * *** ** *   *  * *
*  * **  **  * *       ** **** * *  **     

   * *  *   *  *** *  **   ****  * ** **       * * ** *** * * = price *   ** * **  *
** ** **  *    **     *** * **** ** *  * ** *  ** *  * ****  *   = water_amount - (water_amount - 30);
  *  ** *** *  *   ** * *  *
 *** *   * * * *   *   **  **** ** * ****  

 *** * *   *** ** ***** ** ** **  *    *** *  ** *** **  = price +(water_amount*0.6);
* ***  *   ** *****  *   * ***         **  * ***         **    *  = water_amount - (water_amount - 30)
  *   *   * **   * *** * **** *

   *     ** * *  * ** **      *    *  ***    **  price);
*  *** **      **  *****  0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!