10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include  ** * * ****  
#include **  *  ** 

int water_amount;
double price=10;

int main()
{
** * **   ** * *** **  * **   *** ** *** * *  * *   **   ** * 

 * **  ******* *** **  ****    ****  ***

   *****   * * * *****   *  *  * ** **      * *  **     **** = price  * ***** * ***
 *** ***** *  ** **  * ** * *** *    *   **   * *  ****  ****  = water_amount - (water_amount - 60);
** *   *  **    * * **      *
  ** **     *   * **  *  **  *  **    *** ***  

 ***    **  **  *     *     *  ** *   *  * **   *  **** * = price +(water_amount-50)*1;
 * * **** *    **  * ** **  *  *  ** * *  ** **** ** ****     *  *    = water_amount - (water_amount - 50);
** *  ****   **** ** *   * *  * 
  * * * **  * ** * * * *** * *  **   *** ****  

   * * *      *** * ** *** * * *        ** *   *** ** ** *** *** ** = price   ****   * *** 
****   ** **** * * *   **** ******   **  **   *   **   ** = water_amount - (water_amount - 30);
*  ****   *****  *  ***** *
      ** *  * *    * * **  ** *  *  ***   ***

**  **  ***  ***  * *** *  *    *  * *        *     * *** * = price +(water_amount*0.6);
*  **  ** *  ** * *******  *** ** **   *** * **   **** * * *** **     = water_amount - (water_amount - 30)
 **  * *********  * *

* ** * *** *   *   * ** * *** ** *  ******  * price);
** **   **  ****  *       ***** * 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!