10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include * **  *** *  ** 
#include * *  * ** ** *  

int water_amount;
double price=10;

int main()
{
    **  ** * *  *** *    **  **** *    * * *  *  *** ****  

 *    * **  *  **  *  ** *  * ****    ********** *

**  *** **  *  *   *   *       * *   ***  **  * * ***  = price  ** **    ** ***
****** ***    ****  ** ***  *     **   *  **  * **** **** **  **  = water_amount - (water_amount - 60);
 **    ** * **    *****   * 
* ***  ** *  * *    *     ******* **  **    *

 ***    *  * ***     ** **  *  ******  *  ***  *****   ** = price +(water_amount-50)*1;
**  ***  *  **** ** **  **** ** ** ** * *  *   ** **   **  *     = water_amount - (water_amount - 50);
*** ** *      *** ***  *  *  
 **   *    *   ** ***   * * ********** **  ***

 **      ***  ***   ** * ***  * **     *** ** ***  *  ******  *** = price     *  **** * * 
* *  ** * ** ***  *     *  ***   *    ** *     *    * **** ** * ** = water_amount - (water_amount - 30);
     * * * **** **  *  *** *
* **  ***   *  **  ***   **   ***  * * * *  

 * * *  **   *** *** * ***      *    ** **** ****   = price +(water_amount*0.6);
 * ***  * *   * **** ** * ******  ** *  ** * ** ** * ***  *  ** = water_amount - (water_amount - 30)
  *  ** * **  ** *      

  * ** *   * *   *****      ***   **  *** **  price);
 *   *   * * *   * *   * * *  *** * 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!