10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include *** * *  ** **  *****
#include *  *  ** * * ***

int water_amount;
double price=10;

int main()
{
* ***   **  ** ****** ** *  *   *  **  *  **   *  * ***** *

  *    ** *   *  *    * * *** ***** *  *

  **    * * **   * *  * * * **  * *    ** ** ** ** *  ** * *     = price *  *   *   * ** 
 ** ***  *  **    * * **** ** *  * ***     *   * *  *** ** ** = water_amount - (water_amount - 60);
  *** *  ** *   ****** *   **  
*    * *  ** * ****  * *  ** * *     **** **  ** 

***   *** *     *  *  *    * * **   *  *    ********   ***  = price +(water_amount-50)*1;
** **        *  **** *     ***   *    ***    **   ***    **  *  ** * * = water_amount - (water_amount - 50);
**   ******   ** * ****  ** ** 
* ** * ****** * *      **      ** *  **  *

*   ******** *  *    ** *  ***   *** *   * * * * **  *  ****  * = price  ***** **** *  
*      *            **** ****       *  *  ***** *** ** = water_amount - (water_amount - 30);
* * ** **   *   * ** ***  
**   ***  **  **      *  * *  ***   *  * *

*****   * *   *  *   *      **  **    * **  **  ***   * = price +(water_amount*0.6);
**  **** *     *  ** *  * ** *  *     ****   * ** **** ** = water_amount - (water_amount - 30)
* * ***  *  *   ***   * *   

******  *  * ***   **  *    * * ****  price);
  ***   ***  *  * ***** ***  0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!