10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include * *       ** *  *
#include *  * *     * **

int water_amount;
double price=10;

int main()
{
**  * *    *  ***    * *   * *  ** *****      *   **  

 * ** * **  *   *** **     ** ** *** * * * **** **

 **  * ***** **  * ******   ****   * *   **      = price * *   **     
  **  ** *** *        **** *** *****  ** * * ** *   * *****  = water_amount - (water_amount - 60);
      *** * ** **  **  * *
  ****    **  *  * * *  * * *  ** ** *     * **   

  ***  * * * **      *  * *  **** ***  * * ** ***    ** * = price +(water_amount-50)*1;
* *  * *  *******  ***** **** * *   ***     *   * * *    ** **  * *  = water_amount - (water_amount - 50);
*     * * *** *  *  *  * ** **
*   ** * *  *   ** **  *  *** ** * *     ** * 

*    * ***  ** *  *  *** *  **  * *   * *   *  *   * * ** = price *** * *** ** *
*** * * * *  ***** *  ****  **  * **     **    *           *     = water_amount - (water_amount - 30);
 *  *  ***       **     
 *  ******        * *  * **** *** ** **   * ** *

*    * *** * * ** * ** **  * * **   *       *  **** = price +(water_amount*0.6);
 * * *****  ***  *  *   *****  * **   * *    ***  *    *  **** * = water_amount - (water_amount - 30)
 **  * *** ************   **

   ***    *     *   **  * ***   *** *  *  *   price);
  * *   ** * ** ****     **** 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!