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A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 26465 - Available when: Unlimited - Due to: Unlimited

edited by | 11.7k views

91 Answers

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Hidden content!
#include **** **
#include * ** * *****

int water_amount;
double price=10;

int main()
{
** * ***** * * ** * * ** ** ** ****** *** * * * ** **

*** * ***** ******* * *** ** * * * *

* *** ** * *** * ** * *** * *** * * * = price * ** ** * * *
* **** * * ** ** ** *** * * * * **** ** ** * * ** = water_amount - (water_amount - 60);
* *** ***** * * *
* * *** * ****** * *** ** *

** * ***** *** * * * * ** *** * ** * * * = price +(water_amount-50)*1;
** * * ******* * * ** *** * * **** * * ***** = water_amount - (water_amount - 50);
*** ***** ** * *** * * **
* * **** ** ** ** **** **** *

** * * * ** *** **** ** **** *** * * ** * * = price ** * * ** *
* **** ** ** * ** *** * *** * **** ***** * **** * **** = water_amount - (water_amount - 30);
* * ***** * ** * *
* * * ** * * **** ** **** ** * **

******* ******* **** * ** * * * ** * = price +(water_amount*0.6);
****** * ****** **** * * *** * * * = water_amount - (water_amount - 30)
* * ** * * * * * ** *

** * ** *** * * * **** * *** * * * price);
** ** ** *** * * ** 0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00
0 0
Thanks!
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