10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include *   *  * ****  * 
#include * * *  ** **   **

int water_amount;
double price=10;

int main()
{
*****   * * * * *   **  **      *** * * **  **    *    *  *   * *******

  **** * *  *** * ** *  **** ** ** ** * ***

  *   **  *   *** * ***** **  *****    * ***   **  ***    *   = price ** * ** ** **** ***
  ** *** ***** *** * *   **  *  * *   *  *  ** * **  * * ** * = water_amount - (water_amount - 60);
* ***    * **   **   **
 * * *   ***     * *  *   *  ***  *    *  * ***  *

 *     ** *  * ***       **** *     **   * *  * *   ** *  *   = price +(water_amount-50)*1;
*  * *   *    * * ** *******  **      *** **  **  *  * * *** = water_amount - (water_amount - 50);
***** ***      *   *** **    ** 
*** *  *** *  ****  * ******        * 

**  * **** *  **   *   ** ***** *  * ** *** * * * ** = price   *  *  **   *
  * * ** *       ** *  *  **  *  * * * **     **    *    = water_amount - (water_amount - 30);
* * *   * ** *   ** *  **
*  ***   ****** * *** ***** *  *  * * * 

 *  **     **  *     *****   *  ****  * ** **  ****  = price +(water_amount*0.6);
 **  *** ****    **    *  **    **  *  *  ***  * ** ***  *       = water_amount - (water_amount - 30)
**  *    ***** ** *   ***  

*   * *    *  **       **  *    *** * **  **  *  *** price);
 *** **  * ** ***   *   *** *   0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!