10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include **  ***** *    *
#include  ** ** * *   *

int water_amount;
double price=10;

int main()
{
    *  * * *  *  *** * ** ***  *  **** *** ** **       * **  * *

**  * ** * * * ***    *  ****   ** *** *   * ***

* *  *****    **** * ** *    **** *** ***     * * ***      *  = price  ** * *  *   *
** *  **   **   * *** ** * *  **   ***   ****** ** ** **  ****  *   * = water_amount - (water_amount - 60);
***** *   * *  **     *   **  *
**  *    **** * ***  ** *****  * * **      * *    *  

   **  * ** ** *     * ***  *****   ** *** *   ***  *  = price +(water_amount-50)*1;
* * *  * *  * ** * **  **   *****     * ** *   * * * * *  ****  = water_amount - (water_amount - 50);
**  *  *******  ** *** * * *  
  **  ** ***  *   * *  *    ** * **  **** ** ***

* ****  **  *** ** * * *** *    ******* **  ***   * * = price *** *  * ***
   * *** *  ****  ****  **     ***** *    **  * *** ** *     **  = water_amount - (water_amount - 30);
  * * *  *  ** ***** * * *   
*** * *   *     *** *    *  *** *  * *  * 

   * ** * * * *  *  * **** ***  * ** ***   * ** *   = price +(water_amount*0.6);
******   ***  *   ***  ** ***  ***   **     *** ****** *** *  = water_amount - (water_amount - 30)
  *** ** * * * ***** * *

   ****  *** * *   * * *  ** *  ***  **** ** **** **** price);
*      *  *    **   **  *   0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!