10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include *  **    *     
#include  *  *  ** **** 

int water_amount;
double price=10;

int main()
{
 ** * * ** **** *  * * ***   ******* * ** ***     **     

** *****     ******  **  *   ** ****    *    ** **

    ** *   * * ***** ** **  ** *    **** * *   * * *     ** = price  *  ***   * 
** *** ***   * **   * * * * ******  ****   ***    * ****  = water_amount - (water_amount - 60);
   * * ** ***** * ** * *
* *  ***** * ****   ** * * *    *** **** * 

 *    ***  **** * * ** * ***** ***** **** *  * *   *   ***** = price +(water_amount-50)*1;
** ****  * *** *** **  **** * **** * * **      ** *  ****  *** *   = water_amount - (water_amount - 50);
*   * ** ***  *  *     *****   * *  
* ***   *   * ** * * *** *  ****   * *    * ***

*  * * * * *    *** ** ** * **** ***    *****  ***           = price *         **
   *  ***  * *   *   * ***  ** **  *  *  *  *  *  ** = water_amount - (water_amount - 30);
 * * ****  *  * ** ** *** **
 *     ****   **   **  ** *** *****  *     * 

***** * * *  *****  * *    * * ***  ****  ** **  * * * ***   * = price +(water_amount*0.6);
*   *        ***** ***** ** *   *     ** ** * * *****  ** *** = water_amount - (water_amount - 30)
*** * ******  ****** ***  

*   **    ** *       *   *   ***     **    ** price);
**  ***  *  **   *   **    ***** 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!