10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include  *    *** ** **
#include **  *       * 

int water_amount;
double price=10;

int main()
{
   ** **    *  ****** **   ****     * *  ** *** **** *  ** 

    *   * * **  *  ****   **** *  **  ***

  ***  ***  **   *** *    *   * *  *  *    * *******  *****   = price  *  * ***** **
*     * ***   *** *  *   *** * ** * ** ******* *   * **** **** = water_amount - (water_amount - 60);
* *  *** * ********   *   * *
*****    ** * * * * ** *   *** ****  * ** **** 

 * *   * * *** **  *   * ** * *  *   ****  ** **  * *   *  = price +(water_amount-50)*1;
* *** *****   * *** * * ***    * *   **** *  **         **    = water_amount - (water_amount - 50);
   * ***** **   * *** 
* * **** *  * *** *    * *  *   * ***** 

 ***   **     * *   *  ***  *  **** * *****  **   **  ***  ** = price *    ***  **
*   * ***   **  **  * ** ****** *  *   *** ********  *  ****   * ** = water_amount - (water_amount - 30);
*  **  *** **** **** ** **** 
  * *   * *    ** *  **  *   *    ***   

*   ** *  ** *  *** ***      *  *    * **  **  ****    ***  = price +(water_amount*0.6);
**    ** * **   *   * **  **   * *      *  * ***    * *     ** = water_amount - (water_amount - 30)
 * *     *  ** ******* * 

     *    ***** ***           *     *   * * price);
*  * *   * *   *    * * *** *  0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

---

Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

---

Thanks!