10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include  *    ** *   **  
#include **    *  ****   

int water_amount;
double price=10;

int main()
{
 ***   ** *  ** **  * *    ** * ****** *** *    *   *  ***

*** ***** ****  ****  * ***    *     **    * 

   * **  ** ** ** *   ** * *** *  **** * *  ********  = price ***  *** * **  
 *****  * **    ****  *  * * **  * **** ** **  **    * *** * = water_amount - (water_amount - 60);
* * *    * * ** ***  * ** ** ***
*  *** ** *   **  *** *****       ******  ***

 *****   ***** *  *  *   * *   ** ** *** * ***    *   ** **  **  * = price +(water_amount-50)*1;
 *    *     **   * ** * *  * **   *** *  **      **   ******    * = water_amount - (water_amount - 50);
**   *  * **** * ***  
 ****  *  ** * *  * *   *  ***  **  *** * **

******  * *  ******    ****        ** *  * **   **    *  **** = price  * **          ** 
*    * ** ******  **  *    **   *** ****   ** *** * *  *     *  = water_amount - (water_amount - 30);
*   * *  ***   * ** *** * * 
 * *    **  ***  ***      ***  **** * ** * *

** * *** ** *   *  **** ** **   * ***   * ** * *** = price +(water_amount*0.6);
****  ** * ** ****  *    * *** **   ***  *    **   *** *  **  = water_amount - (water_amount - 30)
  **** **   *  ***    **    ***

   * *** **      **   ***  *** * *  *   ** * *     price);
* ***** *   * ***** * **        0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!