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A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 26465 - Available when: Unlimited - Due to: Unlimited

edited by | 18.4k views

91 Answers

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Hidden content!
#include ** ** ** *
#include ** * ** *** * *

int water_amount;
double price=10;

int main()
{
* ** ** ** * * **** ** * *** * *** ** * *

** **** *** * * **** **** * * **

* **** * ***** ** * **** * * * * * * * * = price * *** *** * * *
*** * * * ** ** * ** *** ** * ** ** ** = water_amount - (water_amount - 60);
** * * *** ** **** **
* * ** *** ** ** **** * * * ** ** *

** ***** * ****** **** * * * ** *** ****** = price +(water_amount-50)*1;
* *** ** *** * * *** * * * ********* * * *** * * = water_amount - (water_amount - 50);
* **** ** **** * *
* ** * ***** * ***** *** ** ** *

* * * **** ** ** * ******* ** * * * * * *** = price **** * * *
** * *** ** **** ***** * * ** * * * *** ***** ** = water_amount - (water_amount - 30);
* *** * * *** * ** ** *
* * * * ** ***** ** * * * * * ** *

*** * ******** * *** *** ** *** *** * *** ** = price +(water_amount*0.6);
* **** * ** * * ** * * * ** * * ** * ** * * * * ** = water_amount - (water_amount - 30)
** * **** ** ****

** ***** ** ** ** **** *** * **** * price);
* * ** ** * * * ** * ** ** 0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00
0 0
Thanks!
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