1 like 1 dislike
4k views

Please write a simple program that performs calculation and, shows its result equals to '10'

** There is no restriction as long as the result indicates 10 from its calculation **

** However, your codes should NOT be the same as the given example **

 

Example

#include <stdio.h>
int main(){

int a, b, c, d;

scanf ("%d %d %d", &a, &b, &c);

d = a + b * c;

printf ("%d", d);

return 0;
}

Input

2 2 4

Output

2 2 4
10

Suggestion

  • Try to apply AdditionSubtraction, MultiplicationDivision in your codes
  • Be advised that 'Order of Operation' is crucial. The relative precedence levels of operators found in many C-style languages are as follows

[Exercise] Essay (Open question) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 25725 - Available when: Unlimited - Due to: Unlimited

edited by | 4k views
1 0
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}
input 2 1 5 output 2 1 5 10

15 Answers

1 like 0 dislike
Hidden content!
* *** ****
* *** * ** **
* * * *** ** {
* a, b, c;
* * * ** **
* * ** * * ** */
* * * * * * * ** by *** ** *
* * * * * * **
* * ****

c = a + b;
* * * * * *
** * ** + %d = * *** * * *
**
*
* *******
6
** *
*
* 6
10
100/100 answered by (243 points)
0 0
Great
1 like 0 dislike
Hidden content!
* * ***** ***** **

*** * * * ** * * **

** *** *** * * * * *


** * *


*


** * ** * **


* * * *** * ** ** ** * * *** ** * *


* * * ** * *** * * ** * * ***


* * ***


** = a +


*


* * * * * + = *** * * ** *


* *





* *

*
*** *

* *


5
*
100/100 answered by (269 points)
0 0
Good job
1 like 0 dislike
Hidden content!
** * * * * ** ***
* ** * * * %d ** *** * * * *** * * = a * b + ** *** ** * ** * ***
*
*
** 1 *** * * 1 + 8 = 10
100/100 answered by (271 points)
reshown by
0 0
Good job
1 like 0 dislike
Hidden content!
** * * ** ** ** *** * ** *** *** ** ** * **** * the *** * or add * own *** * **** **** * * or * ** * *** * ** * a, b, * the ** ** * *** ** *** * two * * * by ** * * **** * * * * ** ** * * * = a + * * *** ** ** * * *** + %d = * ** a, b, ** *** * * * ****
100/100 answered by (252 points)
0 0
Good job
1 like 0 dislike
Hidden content!
**** * * ******
100/100 answered by (153 points)
reshown by
0 0
We have already received your codes. Nicely done.

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.28.177
©2016-2026

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users