[Exercise 02] Simple Discriminant Calculation

Question

Please write a simple program that performs calculation and, shows its result equals to '10'

** There is no restriction as long as the result indicates 10 from its calculation **

** However, your codes should NOT be the same as the given example **

 

Example

#include <stdio.h>
int main(){

int a, b, c, d;

scanf ("%d %d %d", &a, &b, &c);

d = a + b * c;

printf ("%d", d);

return 0;
}

Input

2 2 4

Output

2 2 4
10

Suggestion

• Try to apply Addition, Subtraction, Multiplication, Division in your codes
• Be advised that 'Order of Operation' is crucial. The relative precedence levels of operators found in many C-style languages are as follows

Comments

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}
input 2 1 5 output 2 1 5 10

Answer 1

Hidden content!
** * * * *
* * * * * **
** ** * ** ** * {
*** a, b, c;
* *** *
* *** * */
* * * * ** * * * * by *
*** * ***** * * *** ** * ** **
******* *

c = a + b;
*** * **
** *** + %d = **
** **

** **
* 6
*
* *
6
10

Comments

Great

Answer 2

Hidden content!
*** ** * ** * * **

* ** ** * *
*
* ** ** ** *


*** *


** * * **


** **** *


** **** ** * ** * *


* ** *** *** * * * ** ***


* ********* *


* = a +


** ** **


* * *** + = **


* ***





**
*
*
* * *

*


* 5
**

Comments

Good job

Answer 3

Hidden content!
* ** ** **** *
* * **** ** **** * * %d * * **** * ** * ** * ** = a * b + ** ***** * ** *
** * *
*** *
** 1 ** * 1 + 8 = 10

Comments

Good job

Answer 4

Hidden content!
* * * * ** * ** ** * * * ** * **** ** **** * * ** ** the *** * or add ** own * ***** * **** or ** *** ** * * * ** * * a, b, ** **** the * *** * * * **** * ** * two ** * ** by * ** * * * *** * * * * * = a + * ** * ** * * ****** * + %d = * * a, b, ** * ** *** ** * *

Comments

Good job

Answer 5

Hidden content!
** * * ** *** *

Comments

We have already received your codes. Nicely done.

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}