[Exercise 02] Simple Discriminant Calculation

Question

Please write a simple program that performs calculation and, shows its result equals to '10'

** There is no restriction as long as the result indicates 10 from its calculation **

** However, your codes should NOT be the same as the given example **

 

Example

#include <stdio.h>
int main(){

int a, b, c, d;

scanf ("%d %d %d", &a, &b, &c);

d = a + b * c;

printf ("%d", d);

return 0;
}

Input

2 2 4

Output

2 2 4
10

Suggestion

• Try to apply Addition, Subtraction, Multiplication, Division in your codes
• Be advised that 'Order of Operation' is crucial. The relative precedence levels of operators found in many C-style languages are as follows

Comments

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}
input 2 1 5 output 2 1 5 10

Answer 1

Hidden content!
** ** * ****** *
* ** ***** * * *
* * ** * * * *** * {
* a, b, c;
** * *
* ** ** * */
*** * * * * *** * by ** *
* ** * *** * * * *** ** **
* * ** **

c = a + b;
* * * * *
* ****** * + %d = * ** * * *
** *

*** **
6
* *
***
* 6
10

Comments

Great

Answer 2

Hidden content!
* ** * ***** *
*
* * * * * *** * *

* ** * * ** **


* *


* * * *


*** *** **


* *** * ** * * * ** * ***


** * * * * * * * ** * * * *


*** * ** **


= a + *


* * * *


**** ** * ** + * = * * * ** ** * **





*



*
*
***
*
** *


5
***

Comments

Good job

Answer 3

Hidden content!
* * * **** *** *
* * ** **** ** *** ** %d ** ****** * **** * * * = a * b + ** ** * * * ** **
**** ** *
*
** 1 *** * * 1 + 8 = 10

Comments

Good job

Answer 4

Hidden content!
*** *** ** * * * * * ** * *** the * * or add ** own ** **** *** * * or * ** * ** * * ** * * * * a, b, *** * the * * * ** * ********* two * * * * by * * * * * **** * ** * * = a + * * ** * * * + %d = * * a, b, * * ** ** * ***

Comments

Good job

Answer 5

Hidden content!
*** * *** * *

Comments

We have already received your codes. Nicely done.

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}