[Exercise 02] Simple Discriminant Calculation

Question

Please write a simple program that performs calculation and, shows its result equals to '10'

** There is no restriction as long as the result indicates 10 from its calculation **

** However, your codes should NOT be the same as the given example **

 

Example

#include <stdio.h>
int main(){

int a, b, c, d;

scanf ("%d %d %d", &a, &b, &c);

d = a + b * c;

printf ("%d", d);

return 0;
}

Input

2 2 4

Output

2 2 4
10

Suggestion

• Try to apply Addition, Subtraction, Multiplication, Division in your codes
• Be advised that 'Order of Operation' is crucial. The relative precedence levels of operators found in many C-style languages are as follows

Comments

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}
input 2 1 5 output 2 1 5 10

Answer 1

Hidden content!
* * * * * ** *
** ** *** * * *
* ** ** ** * * * {
* a, b, c;
* ** *
* ** * * *** */
*** * ****** **** * * by * ** ** *
* * * ***** ** * ** **
* ** *

c = a + b;
**** *
** * ** + %d = *** * ***
**** *
*
** * *
** 6
** *
* *
* 6
10

Comments

Great

Answer 2

Hidden content!
* ** * ** ***

*** ** ** ** **

* ** * * ** * * * *


*


** ** *


* * * * ***** *


* * *** * * * * *** *** *****


* * * ** * * ** * * ** ** *


** * * **


** = a + *


** **


** ** * + = **** * * ** * *


* *





**


** *

**** *


** 5
**

Comments

Good job

Answer 3

Hidden content!
** **** *
* * * *** ** * ** %d **** *** ** ** ** * * = a * b + * ** * ****** *** ***
** **
* *
* 1 * * * 1 + 8 = 10

Comments

Good job

Answer 4

Hidden content!
* * * * *** * * ** * * * * * ** * * * ** ** * * ** * the * * ** or add * own *** * *** ** * or * * ** * * * * * *** *** a, b, ** * * the ** * **** * ** *** *** two ** ** by ** *** **** * * * ** ***** **** = a + * ** * **** * * + %d = ** a, b, ** * **** ***

Comments

Good job

Answer 5

Hidden content!
** ** * **

Comments

We have already received your codes. Nicely done.

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int a, b, c, d;
    /* prompt the user
    and read input numbers */
    printf("Input three numbers separated by space: ");
    scanf("%d%d%d", &a, &b, &c);
    //computation itself
    d = a / b * c;
    //print the result
    printf("%d / %d * %d = %d", a, b, c, d);
    return 0;
}