1-11 Exercise 3: Prefix of a string

0 like 0 dislike
2.4k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 2.4k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
** *    *       *** ** * **** 
 ** *** *** *   **** *   *   ** *** ***      ***  * *  ***  **
    {
**  **     *   ** * *  * * **  * *  *  * *   **   **   (i=0; i<=strlen(string2)-1;i++)
    * *   **     * ***** *** * ****** * *  *  *   * **  
**  ***  ****    **  ***  *******   * *  * *** * *  * ** ** ****     ***   * *    * (string2[i]==string1[i])
  * *  *        *  * *****   * ** ** *    **  ***  **  *  *  ****** **  ***
*     **** *****  ** ** *** ***** *  ***** **** *  **   **** ** **   *** * *   *** * ** *    *****  *      ***   *  *
 * **   * * * **        ***  ******* **** *     *** *   **  * * *** *   *
** *     ** * **  *  *  *    * ****   ***  ** * ** 
 *** *  ** *   *  *  **      *   **    *** *  **  **   
    *  ****  *   **  * * **** **   ** * * *** *****   *   * *
**** * **      * **    * ** ** **  **   * ***  ** * *  **** ** *   **  ** *   ** ** ** *** *  *     * is a prefix of %s", string2, string1);
* * * **      *** **   *   * *  * * *       ***** ** * ***** 
      * ** * *** **** * * *  ** ** *   * *** *  * * ***** *
      **  *      * *  *        **  *    ******* * ** *   * 
* ****** *   * **  * **   * **  * ** *  *  * * * ** ** ***   **  *   **    * * *     is not a prefix of %s", string2, string1);
*** **       * *    ***  *  *  *   ** *  **** * **  
    }
  *   ***  **       * * * * * *  * *   ** * *  **  * * **
    {
    * * *** * *   * * *** * *   ***   ****    ***  ***** (i=0; i<=strlen(string1)-1;i++)
*  * **   ****  *   * * **    ** * **** *       * * ** 
  ****     ****  ***** **** * ***  * ***  **   * *   * *   ****  * * * * ** ** *   *** (string2[i]==string1[i])
** * * **  *  **  *   **** *** **  * *   * **     ***  * *** * *  *    *   ** 
 **     *  *** ***  *** *  * ***  ***** ** **   *   **   * * ****   *** **** * *    * ** * *****  ** ***
* * ******      ***    * ***    * *  *****     *  * **** ***    **** *   
* *   ** *** * *     * *    *  *** *** *     *
 *****  *   * * **       *  *   * *  *     * ** * *   *   * **  * 
     ***   *  ** **   *  * *** * *  **  *  * * * **** *   *
  *  * ****  **  *   ** ** *** *    * *   * *    *    * * *  ***   *      ***   *** * ***  is a prefix of %s", string1, string2);
*  ***       *  * * ** *****   * *  *** *    * *  ** *
   *  *****  *  **     ***  **     * * * ** * ** ***  * *
 ** *** *   ** * ***  ** **        ****  *    ***  * ** *
**** **   * *** *    ** *** ** ***   *     *   ** **** *  * ********* ***  *  * ***  is not a prefix of %s", string1, string2);
 ****   ****  *  *  * *    *******    ****    *** **  *
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
******       * ************ *  ****  %s", chaine1,chaine2);
   *** ******* *  **  ****   ******  * 
** *  * * *   *    *    * * *    *   0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
 ***   *  * * *  *  * *  *  *  **  lenght1,lenght2,c;
      ****  * ****  *  *****    b[100];
**   * *  *  ***     *    **  * a[100];
 *  * ** *   ****  * ****  * d[100];
*   * ** *  ***** * ***    *** * * *** *  
  ****    ** ******  *  * ** * **** * ***   
 **  ** *  ****  *  * *   *  **** *** * *
  *  ** **  ** **  * * ** ** * *   **  * * 
*** ***  *  **     **  *** *   *  **** 
 **    *     * ** **  ****
*   * * * * * **** * ***    *** ****  **         * *** ** is a prefix of %s",a,b);
*      ** *      *      ** 
***    * **  *  *** **** **** ***  
*  * * * * ***  *   *  *
*** ***  ** **  *  **   *   * *  *   *** ** *** * **    **       *****  is not a prefix of %s",a,b);
 * ** * *  *  ** * ** ****** *
*  *** ***   **          * * ** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include   ** *********
#include      *  * *   ** 
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
 *  *  * * * ****    i;
 ** *   **** * ** * ** *  
  {
 *** *   **     *   *   *** ** ****       A[i]!='\0' && A[i]!=B[i]   )
** * **      ** ** *   *** *** *   * **   ****  * ***  ** * *  ***    0;
 ***   * **   * ** * ******  *  ** * * * ***** ** ***
 **       *  ** *   *** **      *    *   * *   *******     ***** 
  }
 *** * ***   *  1;
}


int main()
{
*  *    * ** *   *   *  * **** a[n],b[n],c[n];
*** ****** *  * ***     * i;
  * *  * *** * **  **  * *  *   * * * *     **   * *
  *   *  **  * ** * *** **  **   **** *      *
 * ***  ****   ** ****  * ** ** (aa(a,b)){
** *** * **   ** *  *  **   * *** *  *  *    *   ****** ***  * **   *  *
  *****  * *  * ***   *  ** ***  ****** **  *  * * *** ***  ** * *** ****** *   *   ** **** **
 ** *  *   *** * **    ******   *   *  *  * * * **   *  **     *  * ****  **   *  *    ** **   *   ** * *   *** 
    * **          * ** *     * * *    **  * ** ** *** ***   ***  * ** ** * ** * *  *

*** **** *  *  * ***  **   *  ****  *** * ****** ** 
**      ** **    * * * *     ** ***  **    *** ** *  *** * ****  ** is a prefix of %s",c,b);
    *  *  *     * ** **  * **
    **** * *  ** ****  * 
    ***  ** * * ***     *  ** *  ***  * ***  *  *** *  *  ******* is not a prefix of %s",a,b);
 **  * *** **   * *  ***   *****  0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** *   **  **
** *    * *  * * *  
int main (){
char * * *** 
char  **** 
 ***   *  *   ***** string1:  * ** *  
*** *** *   *  **  * ****    
* *   **   *   string2: ***   ** 
*** * * *** * *  *     ****
 ** *** *   ** *         
* ****   *** ***  *     ** ** ** *  *  ***   is ** ** of   **  *****     *
else
 * *    *   *   **   * ** ** *** *** is not prefix of       *     ****   * 

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ***  *   *  **
#include *   ** *  ***
#include  * *   *****  ***
#include  *** *** **  *   
int prefix(char p[],char s[])
{
** * *  *    *   *   * ***   ***  ****  
* *   * *   ** **** *  * ** 0;
*** * ** **    *   *    if  * *   *******  * *
* ***  *    **** ***   **  * 1;
** *  *   ***** *** ** **
*** * *** ****   ******* * ***** * * 0;
}

int main()
{
  * ***  * ***  p[999],s[999];
  * **    * * ********  **    **** **   * **
* *     * *  ***  ****   ****   *** 

 ****  ** ***  *** *   * ***  * *
*  * * *    *   ** *** * ****   ** *     is a prefix of %s",p,s);
** ** *  * **   *    * *** 
* * *  *    * *    * ** **    *** *** ** * * is not a prefix of  *   ***   *  

*** *******  * * **** *   0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  * ***   *  
int main()
{
 *****    * ****   *** *** *  length1,length2,c;
*  **  ***  *   ****       ** a[100];
***** *** *  * *  * *   *  b[100];
    **   ******  ** **    ***   d[100];
 *  *    * ***     *  *** ****     * *   * *     
*   ******  *  *  **   **  * **   *****  *****  
 *  *  **    * *  *  * * *   **    **
 **        * * ***  * **  *  ***** ** *** 
if (strcmp(a,d)==0)
  * ***   ****     **  *   * * *
       *** ***   *  *  *  *** *  **   *  ** **** **  ***   *  is a prefix of %s",a,b);
**   * * *** ***  * *   **
** ** *** *  **   *  * ***  ** 
 **    ***     ***  ****** 
   * **  *******  ** * * *  ** * ** *** ***       **  *   *     ** *  * is not a prefix of %s",a,b);
     *** * * ****  * * * **
*******  * **   ** 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  * * * *   *
#include   * *  *   ** * * 

int prefix (char  * * ** str2[])
{
 *  **   **       *     ** * * *  length=0, * * *
 **   * ***   ******
**** * * ** **  ***** ***   * *   =   ****  * * * ***
**** *****  ** *   **** *  * * 
  * ***    * * * ***  **** ***    ** ****** ** **
**   ** ** *** * * * **  ** *  ** ** *
*  **   *    * * **     ****  if  * * *   *
* ***  *     *  *  *   **         ***  * ****   ** *   *   
  *** *  *   **  *** *   *  * * *   }
 ***            *   *      * *     **
  * **  **    *  * ** **  ** (count == length)
****  *  * * *   * ****          ** * ** *  1;
** * ** **** ** ***   ******  else  *  *  *  0; *     *** * **  *    
  *      *  *      *****   *  * 
}
int main(void)
{
    *   * **   **** * ** **  ** * **  *
  *** ****** ** ***** ***  * 
      *   *  **  * * * * ******  **    *    * str1, str2);

* *  * **** ***   ** * **    ** *  **   *  * ***
  **   ***      {
  ** *  * **** *  **   ** *  * **  * *      ***  * ** ** ****   *  is a prefix of   **  *  str1, str2);
**   *     ** * * * *  **  *
* **  * *  ***  *  * *** ***  
 * **  ** *  ****   *  * ** *       **** *     * **  *  ** * *  * *  is not a prefix of   ******* str1, str2);

*  * * ** *  *   *   ***    0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *   * * *  *  *
#include * * *** *    ***
#include    **   ** *  

int main()
{
***    *********** ***** prefix[100];
* **   *  ****    *  ** **  * **** word[100];
** *  * **  *** **  **      *   *  *     %s", prefix, word);
 * * ****    *   *   *    **  * i;
   ******  ** * * * **    *****   = 0; i< strlen(prefix); ++i)
*  **      *** * * **    *  *
 * *   * * ***   * **** *    **** *  **     **  **  *   *    *  ***   *
*    *    ** *  ***  ******  * **** ****  **  
 ** ****  * * ***   *  *  * * *  ** ** *  *  * * *    *** *   *  ** ***** *     ** *  **    **  * is not a prefix of %s", prefix, word);
* **   * *  **   ***** ** *  ****** ** ** * *** ***  **** ***** *   *** ***  * *    ***   0;
 * ***   ** *** *  * ** ** *****   *  **** * ****  **  *  ****
*  **  * *        * * *  *  * *
  *** **   * ** ** *** ****** ** **   * *** is a prefix of %s", prefix, word);
  * *      ** ***  ** *** ***   0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ** ****   **
#include  *   *  * ** * *  *
#include ****    * * *****

int main()
{
***   * * *  *          *   *  prefix[100];
**   ** * *  *  ** *  * **  *      * word[100];
  *  * * ** **  * * ** *** *  ** * **  %s", prefix, word);
*  * **   **** *   ***    * * i;
 ** * ** **    ***  *   *       * = 0; i< strlen(prefix); ++i)
  * ***    * * *  **     
*** **  *  **   ****  **   ******     * **   * *   * *     **  * *  ** *
   ** **  * **  **    ****    * * * **     *   * *  ***  
 **  * *   ** ***    *   ***   **     *** *******       **  * *   ***** *** **    * **** **  is not a prefix of %s", prefix, word);
* * ***   *** *  * **  *** * * * *  **   *  *  * **  * *      * **     *  ***   0;
** **    *    *  * * *   ***        *** *  *  * ***   * 
     ** *   *  ***   *** * 
*** *  ** **  ** **  **** * ** ******** is a prefix of %s", prefix, word);
*   ** ** *  * **    *  **  **** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
       *** ** *  *** *
* * *  **** * ***  **
    ***   * * **  *  *  * 

int main()
{
***  * * * ** char **   ** *
* **** *** * char * **
 *  *  *     *  **** **** *  ** ** *   ** word);
  *    ** *** int i;
** ***  ***  *  for(i = 0;   *     ** *  ++i)
  **** *  *    {
   ** **   ****   * ***   * ** * *     *   **     
   ******     * **  *  *** * * *    {
 *  *** *    **   *    ***   * *     **   *    * * *** *****    ** is not a ****  of * *** * *     word);
 * *** **  *  **  * **  ** * * * ****  * * *   *** 0;
** *  *  **      ** ****  *    }
**  *    ** ** * }
** ** * ****     *      * is a prefix of  *  * *  ***  *  * word);
**  *  * ****  ** * * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.173
©2016-2024

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 3.1k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 2.1k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 2.9k views
12,783 questions
183,443 answers
172,219 comments
4,824 users