1-11 Exercise 3: Prefix of a string

0 like 0 dislike
2.4k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 2.4k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
 *  *      **      *  *    *  *  *
 *     * * **    *** *  * * **  ***   **   ****  *   **  *
    {
** **  * **  *  **    *  *** *  * * *** * *   *  *  * ** **    (i=0; i<=strlen(string2)-1;i++)
****** ** *  *** **  * **** ***   *     ** *    *  ** * *
 *    * * **      *  ** *  ****  ** *     * * *** **    ***   * * * ****  (string2[i]==string1[i])
* * *** *        *  ***  * **      **  *** *     * *      **  *      
 ** *** ***** *   *  * * *** * * *** ***  ***  ***   ** *** ** *  * *** * ******** *  *   *     *  ** ****** ***** ** 
 ***   **  ****  *     * ** *  * **  * * *  *    **      *  *  *   *   * *** ** 
 *  *   ** *    *  **   *      *  ** **  *** * *   *  *
* * *** **   *   * *  *********   ***** * ** *** ** * **** 
  * *  *  ***  *  ** *  * **       ***         **  * *
   **  * ****  **   ***  ** ** *   **   ***** ****  *   *  *  * *  *  * ** * *  * ****** *  * ***** * is a prefix of %s", string2, string1);
 *  ***** * *   ***** ***   **  **     ** *** *     *   
*** *** ***    * ** *  **   * ***    *** **      *** *
*** *** *  *   * ****** ** *** ** ***  ** ***** **  * * *  *  
  * *    ********  *** **** * *** * * * * * * *   * *  ** * * ***** * * *  *  ** ** **  * *  *   **** is not a prefix of %s", string2, string1);
   * * **         *  ** ** *  *  * *   **   ** *  
    }
 *     *    **** * ** ** *   ** *   ****   * *  ** 
    {
*  *   * * **  ** * *       * *   *  *   *****  ** (i=0; i<=strlen(string1)-1;i++)
  * *** *  *******  *** *****    * ****  *      
 ********* * *   ** *  * ***  * *   * ***  *****  *    * *      * ****  ** *   * * **** (string2[i]==string1[i])
* *  *  ****    * ****** * * **  ****    ** *  * *       ** ** *  ** *** * ** 
 *           * * **   *   * * **   *  *** ***  **  *    *** ******* *   ***  *********  ** *** * * ***** ** * *
* *******   ****   * ***   ** *  *  * * ** * *** ***   * *   *    ** *  * *  * 
*  * **  * *** *   *** ****  *** *   *   *      *** *  
  ***  ****    ***    **   * **       *    ***** *  **   *  
**   *  *    * * ***     *  **  *    *  ******* *  *** 
* * **   * ** **     * *****    *    **  ** * **  **** *    *   ** *   * **  *  *    ******* is a prefix of %s", string1, string2);
         ** *    *       *    *** *      * ** *****    **
*  *    * ***  * * * **     * ** *  **  *    * *   ** 
** * ***      *  **** ** * *** * * *  *   ** **
**  **  *   ***  ** *    ***** ***  ***  *  **    ** **** ***  * ** *****  *  * *   *      * * is not a prefix of %s", string1, string2);
** * * *   * ****     ****  ** ** ***   *  *    ** ** ****  *   
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
 **** ***  ********** ** **  * **** ** %s", chaine1,chaine2);
** * ** ** * *  * ***   **   * **** 
 ******* **** *  * *  *  ** * **  *** * 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
****      ***  *   *     lenght1,lenght2,c;
*   **   ** *   * **** ** b[100];
***** * *          **** *  * **** a[100];
 ** *  *  *       * **      * *** d[100];
**   *  *   **** *     *   *   ***  ** *  * *  *
 ** **** *  **** *   * **  *    ****     ** *
 *  * **  * **  ** *  *** *   * *  *** 
*  **    **   * * ***   *** ******* ** *  *
  ** ** **     *    ** *   *   *** * * ****
******* * ***       * ** **   
**   * *  **    ****   **   *  * *      **  *  *  ***  is a prefix of %s",a,b);
*  **   **  *   ** * **  *  
**      *   ***    *    *   * 
 * ** ****** ****  ** 
  ** **  *** *** *   *** ***  *** ***        *  * * *   ** *  is not a prefix of %s",a,b);
 *  *** *  ***    ** *  *  
*   *** * * ***  * ****   * **** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  ****  **** * * 
#include **      ** ** 
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
* *** *** ** *   i;
*   *** * **** **    *** ** 
  {
*      **  **   *    *    *  *  *** ****  * * **  *  A[i]!='\0' && A[i]!=B[i]   )
  *  * **   * *  *  **  * * * * * *  *  ******    ** **** **  * 0;
   **  * *  *  * *   **** ****  * * * *** * **
***    **  *   ** *  ***   * **  *   * *    *  ***  ***   **   *** ***
  }
  ***  *   *   * 1;
}


int main()
{
* * ****  *****  *  * * *  * a[n],b[n],c[n];
     * *** ** *** *** **    i;
*  * *    **     **   *   **  **         *
  *  * * *  *****   *** **   * *   ****   ******
  * * *    ** * *** **  **  * (aa(a,b)){
*  *   **   * ** * *   ****   **  **  ***    * * * *  * **** * ** * *
 ***   **   **** *   ***   *   *   *  **  * * ** *  * * *** * * *   * ****  *   * **
  * * * ** ** *   * * ***  *   *** * *   ***  ** *    * ******* *****  ***** *  * * **  **** ** ***  * ***  **
****    * ******* *    *   *  *  * **   ****      **     ** **   *** ****** *  

 *   ******  *  **** * **** *       * *  *   *** **   *
**  *  *  ** * * * ** ** *******     *  *   **** ***** * *   * **  * is a prefix of %s",c,b);
***** **    *  *    * *** *** 
 ** ***  *  **   *  *   * *  *    
    *    **  *** **  **** *** ** *  **   *    **** * * *   ** ****   **   is not a prefix of %s",a,b);
*** * *   **  *     **  * ***** * * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ***  ** ** ** *
 ** *    ***  ***  
int main (){
char     * * 
char   * * *   *
 ** *  ** *   * **  string1: **  *  
    *   **  **** * *   ** *** **  
** *           string2: *  ** **
**** ** *** ** *    ****  **
     ** * *  ** 
 *** * * * * * **** *   *   *    is *   **   of  **  ***  * * **   * *
else
* * ****  *     ** ***** * *  * *  * is not prefix of *        ** * * * *

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  ** * ***   
#include * *  ******  *  
#include **   ***     *  
#include    *** ***
int prefix(char p[],char s[])
{
**    *  *   **    *  *    ** *** ******** 
* *** *  * ** * *** ****** ** **  0;
  * *** *  ** ** ** ** if ******* *    *  ******
* **     *   *  ** *  ****  * *** 1;
   * * * *** *   **  *  * 
* *  ***** *  *  **** ** **** *   0;
}

int main()
{
* * *  *  * ***    *  p[999],s[999];
 ***** ****  ****  *         *****  ** *   * * **
 *   ** ** * **    * *** *     ***    *     ** 

    * *  ***      * **  * *  *  **
  ***** *  * *   ***  ** *******  ***** ** is a prefix of %s",p,s);
** * * *  *   * * **  * 
 * *** * ** * **     *  *  ** ******  is not a prefix of   *  *  **

  ******* * ** ** * **** 0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include * * * ***    **
int main()
{
*  * **  ** **** ** **   * *** length1,length2,c;
** **  * * *    ***** ***** *  a[100];
   ***   ****  ** **** *  * ** b[100];
 **** *   **    ***** *   ** ***  d[100];
*      **  **** *** ****   * * * * *  ****     
***  * **   ** * * **** ****  ** ******** * *** 
 *     ** ****   **   *    *   ** ***** * * 
 * *   *   *   * *  *  *** *  ** 
if (strcmp(a,d)==0)
*      ** ** **  ** *  ****   
***   *   * ******  **  * *  * *  *    *  ** *      *   ** *   is a prefix of %s",a,b);
**  * *  **   *  *   *   
  * *   *  * *   ** *  ***  *   * *
  * *  *   **** **   *
   ****  **  * *    * ***         * ***  *   ***** *  ****    **   is not a prefix of %s",a,b);
 ********       *** ****   **
   ***  ******  * ** 0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * ***      ** **   
#include  *    *  *    *

int prefix (char   *** str2[])
{
*** *** *  * ***   ** *   ** length=0, *** ***  
 ** *         * *  *
* * *   *   ** * *     * * **   =      ***  ***   
**     *    ***  ** *    *
  **     *  * *    * **  **** ***  **   ****    *
 ** ** *     ** * **  * ***  *     **  * ** 
 ****   *  *       **** ***  *** if **  *****  ***  *
 ** **     *  ** * *   * *        ****  * *  *   ****  **  * *  
****  ** * * **  **   * ** * *   }
  ** *         * *     * * ** * *
**  * ***    * **   *****   (count == length)
 ***** ** *  **   *    *   ** *     *  ***    1;
 * *  * *  **     ** *  ** * * else    ****     0;    *** **    **  ** * 
**     *** **  * ** *  *  * ** * 
}
int main(void)
{
***   ****** *  * *** ******** *     *    *  *
**** **   **** *   * * ***
*   **** **  * * *  ***    *  * ***    * **    str1, str2);

 *** ******* **    *******   *   **  ** ********
* **** ** *   * {
 ** *  ***** ** * ***  * *   ***  *  *      *** ***    ** ** * *** is a prefix of * ******* str1, str2);
** ****  **** **    *** 
 **     ** * * ***  * *    ***   *
 ** ** ** ** * * ** ** * * * *** ** * ** ***** *  *****   * **    ****** is not a prefix of *  * *   str1, str2);

*  *  * *     ***  *    * 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *  ***  * * * *
#include  * * * * * * * 
#include  * ** * **** *  

int main()
{
  * * ** *  *** *  *****  *    prefix[100];
*  ***   **    * ****   ***  *  word[100];
** ** *** **   *    *  ** ****  *  *** %s", prefix, word);
***    ** **     *** *   * * *  ** i;
**   ***  ** **  **  **  **** = 0; i< strlen(prefix); ++i)
* *  **   *  ** *
   *  **** ****    * *  ****  * * **  ***  *  *** ** * *  *  ** * 
   ***   * ** * * ** *** * ***    *   ** ** ***********    
 * ***   * * *      **** * *** * *   * ******* *    ***  * **  **  ***  * *  ** *** ****   is not a prefix of %s", prefix, word);
 ** ** *  ***  **    * * *   * * * * * *   * * *****     *   * *** ******* * 0;
****     **** * *** ****  *  *  *   * ****     *** ***  
  ***  ** *** *  *  **    
 * * *    * ***** ** *** * *  ** ** ** * is a prefix of %s", prefix, word);
   *  **  *    **** **  *  *  **  *  0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    **  * *    * *
#include     *  ** ***  *
#include ********   * * * 

int main()
{
 ******   * * * ** * ***  ** prefix[100];
*     **  ***   *** *      *** word[100];
 *   **  * * ***   ****  * **** ****     %s", prefix, word);
*   ***   * *   * *   * *** i;
   * *** *   * *    ** *  *  *   = 0; i< strlen(prefix); ++i)
********  *  *** * * *  * ** *
*** * *    * * * *  ***** * * ** * * ** * * ** ****     * *** * 
  **  **** ** ** *   *** * *  *  *  * * *    ****   ****  * *
 *** * * **    * *  ******     *********    * * *     *   ****   * **    ****  * ****** * *** *  is not a prefix of %s", prefix, word);
   *** ******* * *      ** * *     ******* ****** * **    *  * * **** **    **   0;
*  ** *  ******** *  * *    *** ***  * * **  * ******    
**   *****   **    *   * *
 **     ** ** * ** ** * * * ***** *  *** * * is a prefix of %s", prefix, word);
 * *    ***   ****    **** ***   * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
        *  *** * *  **
 *       * **   * **** ***
** *   *     * * ** * * 

int main()
{
* * ** * **   **  char       
   *   ** *  char    **** *
 ** ***   ****   * **  ** * ** *** * * ** *    * word);
  ***  ** * * * *** int i;
 **   *   *    for(i = 0; ** *  **  * ++i)
* * * * *** {
****    *****  **    **  *    * **  **   ***  *
* ****   ***   * ******   * * {
 * **   ***     ** *    * **  *** * *    *  * * *** *****   is not a   *  of  ***  **** ***  word);
**  **   * ****   ***  *******  *****   **  *     *** 0;
* * *** * *     **** *  *  *   * }
** *  *  *  **** }
** **  *  **    *** **** is a prefix of   ** *   ****  word);
   ****  **** **   * *  0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.152
©2016-2024

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 3.1k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 2.1k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 2.9k views
12,783 questions
183,443 answers
172,219 comments
4,824 users