1-11 Exercise 3: Prefix of a string

0 like 0 dislike
2.4k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 2.4k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
 ***  ** * * **  ** ** *
*  *** ** ****** **  *****   **  **     *         **   
    {
  ** *  ***  **** * *  *  *    **** ***       *    **** (i=0; i<=strlen(string2)-1;i++)
 ****  * **** **   ****  *   * ****** *** *** **** *    
  *  * *  * **** *** *** * *  **** * * ****     * * *** ** *  *   **  ***  * ***     (string2[i]==string1[i])
    *  *  *      ** ** * * *** * *  **  * ** *** *** *    *   *  ***  ***     *
**       ** **   *  * *** ** *** * ** *   * *** *  *     **   *  * **  *   * * **   * *  * *  * *  * * ****   * * *
   **   **** ** *****   **** *     *     * ** * *  **** * ***** ****** * ***  *
   * *     ***** * **** * *   *   ***** *  ** * *
 * * * ** ** *  *  * **   *  *  *** *     ** **** ** *    ** 
  *  **  * ****   * *  *   ** ****** *  * * * *   * *** *  *
* **   ** * * **   ** *****       * * ***   ****      * **  *** ***  *   *    *    ***   is a prefix of %s", string2, string1);
 * ****  ****** * ***   * * * *** *******  **   * ** ** *
* *  *  ** **    *** * * *  * ** ** * *** **  *  *    *  * * * 
*      * ** ** ** ** **   *  ***** *   * **    *  
*     *  * *  * * *  *   * ****   **** ** *** * * **  * *    *    ****  * *  ****    *  * is not a prefix of %s", string2, string1);
* ** ** *  *           *  * * **    **     *** *
    }
 *  **   *    ** * *    *      ***  *    * *** **  ***
    {
* * *   ** **     ** ****** *  ***** ** **    *  **  * (i=0; i<=strlen(string1)-1;i++)
  * * ** *   * ** * * *   ** * ***   ** *** *   ** ****  ** 
** ** **** * * ***** ****** *   *   ** *   * ***** **   **  *   *             * * ***** * (string2[i]==string1[i])
  *  *   **  **  ** ** ******* **  *** *    * ***  *** *** *** ** *   *   *    ** 
 * **      *  *  ** **  **  *  *    ****  *    * *  * *  ** ******  * *   ***    * **      *** *  * *
 ** ***  * *  ****    *    *** *   * **  ** * *  *  *  * *  ** ** *  ** *** **  
***   **** * *  * **    **  * *   ** **** *     *  
**       ***** ** ** *  ****     * ***   * *    **  *** *
 ** * **  * ***    *   *** *  *   *    **  ** * * * ***
   * **  *** ***  ***** ***    * *      *  ***** *    *   *  * *** ** **    *** **** ******* is a prefix of %s", string1, string2);
  *   ** ** **  * ****   *  * * *  *   ***  *    *
** ** ****** *** *  **  * *  **** ***   ** **** ** ***
 ** *   **     ** ** **    ***  *****  *  * **
 ** ** ***   *****  **  * * *  * **     ** *  *  **  * **** * ******** *** ** *    * ** * is not a prefix of %s", string1, string2);
* *      **  ** *** **  **  ***  * ****    *  * * * *   
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
* ** * *   * **       ******** ***  *   %s", chaine1,chaine2);
   ** ** * **  **  *  ****  * ** **** *  ***
 ***** *       * ******  * 0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
*    ** *  ****    * *  **  lenght1,lenght2,c;
*  * ****    **  ***  *  * ** * ** b[100];
     *** **** * * * **   **  a[100];
  * **   ****** *  *** * d[100];
* *** **    *  *** * ** **      ** *   **** ** *****
*** **  *    * *  ***  **   ** *    *   *** *  
* *  * **   **  ** ***   *** *** *  *   **  
 ***  * * *******  *  ** ****** *  ****
    **   *  **     **  *** *   *  *** *
**    ****  *** **   **   
* **    ** *** *** *  *** * ****      *  *****  **   **  *** is a prefix of %s",a,b);
 * **   * * *  * ** ** ***
 *  *** *  ****  *  *  ******
  **   * * **     * ** *   **
*     *** *  * ** **  * * **   *      *** * **    ***  *  * is not a prefix of %s",a,b);
*  *  *  ***  ***** *****  
* ** * * *** ******  ***** *   *** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include ** *    *  *  ** 
#include ** *  **  *****
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
**   *  * ** *  i;
** ***** * *  * * * **
  {
 * *** * **  *     ** * * * * * **    A[i]!='\0' && A[i]!=B[i]   )
** * ***  *  * **** *  *    **   * *      *** ** ** ****** **  *****   * ** 0;
 ***** ** **  **    * ** *   *  *  **  *    * * **** ** 
* **** ** ****** *  ***  *      * ** **** *  * ** * ** *****  * ** *** 
  }
* *** ** ***  *** 1;
}


int main()
{
 ** ****  **** *  ***  ***** a[n],b[n],c[n];
*  * * *  * ***** *  ** *  **  i;
* ***** *  **  *  *        ****  * *  ** * **  * *    
   **** ****   * ***     **  **  **    *   *
    ** * * **      *  * **   (aa(a,b)){
 *** ***    *  * ***** * *  * * ******   * *     * ** * **** ****    ** *
*   **  ** * ** ***    * ***   * * ***  ******* **  **      * *   **    *     *    * *  * 
  *   **  *** *   ****   * *   * * ***  * ***** ***    * ** *** *    *** ****   ***    ** ** ** ***    ** ** *  *  * *** **
*** ** *  ** * * * *  * * * ** ** * *   *    ****  * **   ** **   **      

  *  *   *   **   ** *  * *    * *   ** **** *  **** * ** *
 * ** ***  * *  * *    * *  **  *  ****  * ***  ** ** * * * *** *   is a prefix of %s",c,b);
     *** * **    **** * *  *
 *****  ** *     * **     ** *  **
 ******     **  **** ** * * *   **   * *  **  **** *  ** ***      *    is not a prefix of %s",a,b);
**   *  * *     *   **  * **** * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ***  * *** *
    *    * * **     
int main (){
char   * * ** *
char  *  ** *  
***       *  *   * string1:  * **  **
 * ***  ***   ***   **** * 
 ** * * ******* ***  string2: *  ** 
   *  *** * * ** *     ****
 * **** * *   ***** *** 
  * * **** * **  **     *   **  *  is *  ** * *** of **  ***    * ** **
else
****  *  *****  * **  ** ** *     * ***  ** is not prefix of   * * **  * ******   

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *  * * *   **** 
#include *  ** ****  *  
#include * * * ***     **   *
#include   *** *   *    * *
int prefix(char p[],char s[])
{
*** * *****   ** * ** **** **** *   * * * 
 *    *   *   * *    ** * 0;
 *** **  * * ** **** *** * if *   ** ** **  *  **
*   ** * ** **** * *    **** **  *    1;
*  **  *  ****   **  * 
 * *** ** * ** *  *      *   *   * 0;
}

int main()
{
  **  * ******* * * * ***  *  p[999],s[999];
  * ** **  **  ******   *  * * ***** *** ** ***
***     *  ***** * * **   **  ** * *** ***

 * *     *   * * ***** * * *     
****  ****    *  * * *** ***  ***** ***** is a prefix of %s",p,s);
**   * *  *** **   *   
***     ***** ******  *** **  *   **** * * is not a prefix of **   ****    ** 

   *   * *****     *   **  0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *** *** **   **  *
int main()
{
  *      *   ** *   **  * * length1,length2,c;
* *** ***  * * ***   ****** ** a[100];
 * * *     *  * ****  ** ****  *  b[100];
  *  ** * **  ** ** ***    ** d[100];
 * *  *  *   ** **** ** * * *  **  *  **    *  **
 *  ** **** ***  *** ** * **** ** * ** *****    *
         *****  **     ***    *  * **
  ***** ** * ** *  *   *    *   *  * *   
if (strcmp(a,d)==0)
**   *     * *   * ** *** 
**  ****  ****  **    * **  *       * ** ** * * ******* *    * ** * is a prefix of %s",a,b);
 *** **   *    * *  * *  ****
*    ** * * *   ** * *   *  **  *
  ** ****** **  *   * **** *
 ******* * *   ***             * *********** **** ** ** *   * is not a prefix of %s",a,b);
** *    ******** **** *  ****
     ***  *  *  *  0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ****  **    * ** *
#include ** *  *   ***** *** *

int prefix (char  **     str2[])
{
  * * ** **** **** *  **** *       length=0,  ****
*   ***  **   * ** * * *
  *   ***        *   **       = *****  **   *   * 
****** *******  * ** ** *  *  **
*   *  *  *****     ***  **** ***** * *    *** 
*   * **    **  *  *         *  ********     **
**  * *  * *  **  ****   *     if  ***  * * * 
   *   *   *** *     * ***        ***   *   *   **   ** *      
 *** * *** **** *** * * * *    * ****   }
  **   **          **** *  **  * *** *   ***
** ***   **  *** ** (count == length)
  **  *  **  ***    *  ** ** *    *** * 1;
  *    *   *******    *    **  else * **  **   0; ** *****  * **    ** 
   ** **  *   *   ** *  ** 
}
int main(void)
{
 **   **   ** ******   **** *  * *   * * *** 
 *   * ** * *  ******
***  **  * * **   * ***  *     ** * *  **   * *  *  *  * *  str1, str2);

*     *  *   ***   **  **       * **     *
** *  * *  *  * {
 ** **** *  ** ***** ***   *** * * ** *   **** *  *  * * ** is a prefix of  ** *   * str1, str2);
   ********    * * *** 
   *****    **** ***  **   
* * *   ** ******* **** *****  * ** *** *****  ** *** ***** ** ** *  is not a prefix of  * * ** str1, str2);

******** *  * * ***   ** * *   * 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** *** ***   **
#include * * **  * *  **   
#include ** * *    *   *

int main()
{
***   *           **  * * prefix[100];
 * ** **      * *  * * *  * word[100];
* *  **   ** ****   * **  *  *      %s", prefix, word);
  * ***** *     * ****  *** * i;
*  *    *  **  *      ********  = 0; i< strlen(prefix); ++i)
  * ** **  *   *     **  *
*** *  *  **   *  *** *  **  **  ** **  * * *      ***** *   ****
 **  ** **    **  *  *   * ******   * *  * * **  ** **
* * *  ***   * * ** **    *** *** ***   *  * ****  * **    * **  * *    *   ****      *   is not a prefix of %s", prefix, word);
 *  *    ***    *  * *   ** ******    * *    ** ****** ***** **  *    *     * ** ***   *  * 0;
*  ********* ** * *   * ****  ** * *  *  *  *** *
    *  **** *  * ***** **    * **
*      * ***  *** ** ***      **   * * is a prefix of %s", prefix, word);
*** *   ****   ***   **  ** * 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** * *     
#include *  *   *   * ** *
#include        **** * ** *

int main()
{
* **** *    * ****   *  **** ** * prefix[100];
 * * * *******  * * *** ***   word[100];
 * ****   *  ****   * ***      * *  *   %s", prefix, word);
 **  ****     ** ** ** *  * i;
*  *    * * *    * *  * **** = 0; i< strlen(prefix); ++i)
* ** **  *** ** ****   *
**   *  * *  * **** *   *     ** *** *   * ******* * * *  ****   *  
    * ****   * ** * **   * ***  * *       ***  * *  *  *   
    **  **** *** **  **     * ***  ** **  **    * **  * ** * ** **  *    *   *   * **  ****  **  *    is not a prefix of %s", prefix, word);
 **  ******* *   * *******  *  **   *  *** * *** *  **  *  *  ** ***   * *     ** 0;
**  ** ***  * **  ***  ** *   *  * * ***   *      **
  **** *  ***  * **    ***
 *     *  * *  ****   ***     **     ** is a prefix of %s", prefix, word);
**** * *****      **  * ** *** * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*  *** *   *   * * * 
*****   ** * ****  
 * *  * * ****  ** ****

int main()
{
     *      ** char  ***   
    **     *    char * * ***
*  *  *   * **  * *   * * *   * **   ** **  word);
  *   *  * **  int i;
** **    ******* for(i = 0;    *  * **     * ++i)
  ****  *  *** {
 ** ** **  *      *   **    *   * ***   *    ** *  
** *      *** ** *        *  *  {
** * **   * * * **** * * *  *** ** *** ** *  * **   ***  is not a  *   of  *    *  * ** word);
*  **    * * *  * ***  **** *       * **    **  * 0;
 ***  **  * *    *  *   *    }
  *  * *   **** * }
*     *** *** *   *  ** * * is a prefix of  * **      ** *** word);
** *       *   * **    0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.16
©2016-2024

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 3.1k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 2.1k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 2.9k views
12,783 questions
183,443 answers
172,219 comments
4,824 users