1-11 Exercise 3: Prefix of a string

0 like 0 dislike
2.4k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (12.1k points)
ID: 41439 - Available when: Unlimited - Due to: Unlimited
edited by | 2.4k views
0 0
12345
commented by (-329 points)

27 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
char prefix(char string1[],char string2[])
{
    int i,s;
**   *    ** **    * *  **
*** ** *    ** * **  * *    *** ** *   * ** **    *
    {
**      *****  * ** *****  ** * **** *     ** **    (i=0; i<=strlen(string2)-1;i++)
 **    * ** *  **     * *  ** *    ** *   *   ** 
** **  *   *** *** *    * **    *  ** * **   * **  ***  **  * * ***   *  ** * ** (string2[i]==string1[i])
     **  *****  *  *    ** *** * *   * ***  * **    ***      ** ***  **** *  *****    *
 **  *      ***       * *****    *     ****    * *  * **     *** ***  *   * *     ** ** * *  **      * * * **  *** **
* *  * ** * ****  **** * *  ****  ** **  *     *   ** *****  *     ***  *** *  *  * ** *
   *   * ******** **   ** ***  **  *       *  **  *  *
    * *        * * * * ******     **   *       ** *** * *   *  *  
 *  *** *    ****     * * ** **** **** **** *  * * **    ******
** **  **  *  * * **** ****  ** * **  *   **  *  **** * ** ** *      *** ****  * **** ******* **  is a prefix of %s", string2, string1);
 ** *** *  *   **    *** ** ***   *****    **
  **  **  *   * **** *  **  *****  **  **      * **   
 *   * *** * *  ** *        * **       * **  *  **
** *******  *   ****  ** *****   ** * **  *  *  * * *  * * ** *    ** *     **  *  **  is not a prefix of %s", string2, string1);
 *  ** ***** ***   * ** * * * ** *  ******* ****    * 
    }
 *   *****  **   ***  ** *    *   ***     * *   *  *  ** *  **   * 
    {
  ****  *   *  * ** ** ** ** ***  * **              ** ** ***** (i=0; i<=strlen(string1)-1;i++)
*  * *****    ***   * ***   ***  **** *   *** * ** **  * ** *
** *  ** * **   ** * *  * * ** *    * * * * *    *  *   **   *********  *   * (string2[i]==string1[i])
 * *   * ***  *    ****      **** ***  *  *** *  **       * *** ** *   **    ** *** * ** 
*  ****   **      *  *  * * * *  ** **    * * ****  ** *  ***  *** *** **     *  ** * **    *   * *  **
 ***** *   *  *  * ** * *     *    *      * *     ***  **    *   *** ****    *  
     *  **  ** ***    ** ** * ****  *  *   * ** ** **
**  ***** * *  * ***  *   *    * ** *  * ** ** ******  ****  
      * **   ** ******   *  * ******  * *     ***** *  *
*** **  **  *   *** *****  * * ***    * **  *** **** *  * * *      *  *    **  * **** *  * *  * **  is a prefix of %s", string1, string2);
 * ***  *  * **** ** * ***  * **  * *   **   ** *  **
**  **   *  ***  ** * *    **    *** *  **** *  *   **
* **   ** * *      * * **  * **   * ******  *** * ***** *  *
* ** ***** ****  **  *     * ***** ****  ***  *** * *  * * ** * ***  **** * *  **     is not a prefix of %s", string1, string2);
 * ***  * * ** * * ** **  **      * ** * * *  ** *
    }
}
int main (void)
{
    char chaine1[1001], chaine2[1001];
 **  *****    ****  ***  **   * *** *  **  %s", chaine1,chaine2);
  * **  * * * ** **  ** *****  ***  ***** 
***     * * * ***   ** *****  *   0;
}
answered by (-168 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

#include <string.h>

int main()
{
  ***** ** ** ****   * * ** * * lenght1,lenght2,c;
 *   *   **   ** * **  * *  b[100];
* ** **   *  *  * * **   **  a[100];
 * * *** **** **  *     * *  d[100];
***       *****   ** * ********   * *****  *  ***  *
**  ** **     **  * * ***   *    ********* *** *   
 * * * * ******** *** * ****    * *  *  * *
  * *  ** ********  ***  *   ** ***    *
* ***     ** ***       * **  * *  
  ***   ***       ** *   ** ** **
* *  *** *   **  * ****** *   *    ***   * *****    * is a prefix of %s",a,b);
*****  **** * * *   *  ***       
 ***  *     * *** *  **  ****
*** *   * ** *  *** *  * *    *
* * * *     ** * **   ** *  ** **  * ****  *    ***** ***   *** *  is not a prefix of %s",a,b);
  *            ** * * **** ** 
*  *   ** *** ****  **    *** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include * ***    *  * 
#include **   * **     *  **
//#include <ctype.h>
#define n 100
int aa(char A[],char B[])
{
    *   * **  i;
*  *  **  *  * * ***     * * **
  {
* ** ** *   ****** *    **  *  ** **     A[i]!='\0' && A[i]!=B[i]   )
   * **      ****  *** *  *  * ****   **** ***   ******   ***  ***  **     * 0;
*     *    *** **** *** *     ****** ** * * * * ** *****
   *  *   *    **  *   *   * *   ******   ** * *  *   ** *   ** * ***  *
  }
  * * * *   ** * * ** 1;
}


int main()
{
*****    *   * **  * ** *** a[n],b[n],c[n];
* * ***    *     ******  * i;
  *     * *  *    **  *      * ****   * **   ****
 **    * * * * * *    ******       * **   ** *  * 
 ** *     *    * * ** **  (aa(a,b)){
   * ** ** *  **  *   *   **  ** **       *   ***** ****      * *  **  * 
   ***   **  *  * * ** ***   *   *  * * *  * * ***  ** * ***  ***     *   ** * *  ** **   **  *   
** **   ** *  * * * *    * *   *  **   **   *  * *   ** *** **** **    * *  *    **  *   * *** * **** ***    * * *
  *  * ***    *****  ** **   ** **   ******* ******** ** *   *   *   **  * *

   * * *  * ** *  ***  **     ****** * * *** ***  **
     *** ** * *  * * * *    *    * *** *** * **** *   **** *  *       is a prefix of %s",c,b);
*   * *   *   *  ** ***  *
***  *  ** *   *** *    * ** 
 *** **     *** **     **  *   **   *        ***      *    *** *  is not a prefix of %s",a,b);
**** *  * *** *****     *  *   0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *  ** ** * 
***    ***  **   *   ** 
int main (){
char  *** * 
char * ***  
**  *   ** *  string1:  ***
   * * * * * **  *     ** ** *   
** * *** *** ***  string2: * **** 
  *  *    ** **  * * **  
**    * **  *   * **
 **    * * **    ** *  **      *  ** is *  *********   of    **  ** ** * * **  **
else
 *****     ***      ** *  *   ** *  **  * is not prefix of **  **   *   **  *   

return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:7:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
 scanf("%s",&string1);
         ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** * * * *** ** 
#include **  *  *   *** * * 
#include ***  ***  **  *  
#include ***  **   * ***
int prefix(char p[],char s[])
{
*  * * ** * ***  * * **  * ***  ** *
 *** **  **    ****     ***** *  0;
* * *     *****  ***** if  ****       ** *
  ***  *  ** *  *** *** * *   1;
**** *  ** * ***  * ***** *
   ** * * ****** *** **  *  *  * 0;
}

int main()
{
 * *     **       *     * p[999],s[999];
 *** * ***  *  * ***** **  *** * *****  ** *
*   * **  ** *    ** ***** *****  ****** **  

* *  **     * *    *** * *  **  
***  *  *** * ******    *  *   ***  *** * is a prefix of %s",p,s);
* * **  *  *       **
**  ** ****** ** ** * * ** * ****  * ** is not a prefix of ****   * * * 

*     *  ** ***** * **     0;
}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include * *******    
int main()
{
    ** *****   * **** ** *** length1,length2,c;
  **  * ** ** * **   *  a[100];
 *   * * ** *   *  ** *****    * b[100];
*  **   ***** **  **    * d[100];
*  **   *   *  * ** * ***   ** *** * *   **  * * * *
* ** *      **  *   *  ***    **  * *  *  *    *
** ******* * **       ***  ** **
  **   ***   * ***** *    * * * * *    *
if (strcmp(a,d)==0)
 ** ******** ****  * ** * ** 
* * ** *  ***  **  **  * * **  **    * * ** *     *     *     * ****  is a prefix of %s",a,b);
*** * * **     ** ** *   * *** *
    ** **   **  *   * ***** ** 
 ****    *      *   ** * * ** *
* *  * *  ***  ***  *** ***  ** ******* *     * ** ***   *** * *    ***   is not a prefix of %s",a,b);
  *   ****  *  * *  **   
 * * ***  * * ***  0;
}
answered by (-229 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  ** * **  
#include *  *    *   

int prefix (char *  *   str2[])
{
  *  **       *  *  *   ***  length=0,  ** * 
 * *   **   **  
* * ** * **** * *****   * *** ** = ********* *   
    * *  * *     *   ****  **
*  ***     *** ***   ** *  * * ***  **   * * *
 *** *  ** *    * * *   ****   *****    ** 
 * * ****   * * ** * *  *  if  *       
 * *** *     *  **               ***     *   *    
* *** * *        *   * * **       }
* *  **          *     * **  **    
* ** *   *  * **   *** **  (count == length)
*  **   * *  * * **    * ****  * **  ** 1;
  *********   * **     *   else *    * *     0;  **  ***   ** ** *   
   ***      *    *   *  ***   
}
int main(void)
{
 *********   *  ** * **      ** *  ***
***** * *** *** ** *  ****  
*  **  * * * ** * **  * *     *** ** * * *  * str1, str2);

*  *  ***  * *  * * *   * *** *   
* ***** **  * {
**  * **** * *****   * ** * **    * *   ***** * * *   ***  *  *   is a prefix of  ****** str1, str2);
 * *    **  * ***    *    *     **
*****   *     * * **  * *     * 
 ***       ****   * ***  ** *  * * *  * *** ***   ** * *  * is not a prefix of * **  *   str1, str2);

*  ** * **  *** ** *  * **    *   0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * ***     *
#include *   * *  * ** ** *
#include    ** ****  ***

int main()
{
    **   **      **   *****   *   prefix[100];
** **   ***   *  **     *  *    word[100];
**  ***  ** * * *****  **    ****   %s", prefix, word);
*** ** *****  *  **    **  i;
**** **    *  *   ** * *  * * = 0; i< strlen(prefix); ++i)
* *    ** ** **  ** ** *  ** * *  
 * * ***  *    ** * *  * * *      * **  ** ****  ** **   *** *    * *
  ** **    **   * *  *** * * ***** ** *     ** **  
 *  * *  ***    **       ***  *  * *** **    *  * * ***   *     *     *  **  *  **  * * is not a prefix of %s", prefix, word);
* * *** *****  *  * *** *      * *  * **** ** * ****    * * *      * ***   **  *  *   ****  *   0;
** *      **      *  *    ***   ** *  *  ** *  *****      
  **** ** *  *   *  ** ** **** 
* * ******  ***   * ***  * * * **     is a prefix of %s", prefix, word);
   *  * *** *** *  **   *   0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include       *   *** 
#include *  **  * **  ** *
#include **  **  ** *

int main()
{
  *    ** *   **** ***    ** prefix[100];
*  *** ** **  * ** ** * ***   * ** word[100];
***  ** **    *  *  *  *   * ** *   * *    %s", prefix, word);
 * *****      ***  *  *** i;
 **** ***  **  * **      ** * = 0; i< strlen(prefix); ++i)
  *   ** ****** *     ***  **
* ******  *** ** *  ****  *   **     * **   *  *    *****   *** *
****    *   ******   *  *   ***  **   ** *   **  ** *     ******
*    * * ***   *  ** * * *    *  * * *    * ****  * * ** *   *****  *  **** ** ** *   *******  ** is not a prefix of %s", prefix, word);
*           ** **   ** *     *  ** ***  *   * **  * * * ****   *     ***** *   * *****  0;
 * *******    *   *  **** ** * ** ***    ***    * *** 
****** *** * * **** **** *** **  
 *    ***   ****  * ***   *** ** ** *** * is a prefix of %s", prefix, word);
 ***  * *   *  ** *** ** **  *  ** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*  *  * * *** * **** 
** *    *  ***  * *    * 
*   *   ** *   *******

int main()
{
** ** **   ** char  * ***  
 * *  *   ***   char ** 
 * **   * * *  ** ****      **  ****   * word);
*** ***  *    int i;
  **** ***    for(i = 0;   *  **    *  ++i)
   *  *   **   {
*   *       *   *    * * * * * **  * ***   **  **
* ****** *  **** *****   *** *** {
* **  *    * ** **   * * **   ** ****  **     *  *  *  ***  *  is not a * *  of * *** *    *  word);
*  *    * **  *** * *  * *   **   * ****  **   ** *   0;
**** *      ***  * * * *  * *  }
***  *   *** * * }
**** ** * ******       *** * ***  is a prefix of ***    *** *  * word);
**  ***   ****   * * 0;
}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.38
©2016-2024

Related questions

0 like 0 dislike
57 answers
1-11 Exercise 1: UPPER and lower letters
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings
ID: 41431 - Available when: Unlimited - Due to: Unlimited | 3.1k views
0 like 0 dislike
29 answers
1-11 Exercise 2: Reverse a sentence
[Exercise] Coding (C) - asked Jan 11, 2018 in Chapter 13: Strings by thopd (12.1k points)
ID: 41436 - Available when: Unlimited - Due to: Unlimited | 2.1k views
0 like 0 dislike
53 answers
1-4 Exercise 3: String details
[Exercise] Coding (C) - asked Jan 4, 2018 in Chapter 13: Strings by semicolon (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited | 2.9k views
12,783 questions
183,443 answers
172,219 comments
4,824 users