11-09 Exercise 2: Reduce the fraction to lowest terms

2 like 0 dislike
2.5k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數，約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
edited by | 2.5k views

67 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{

      *   * **   *** **** * * * i;
* **  **         **  ** *  *  j;
**  * *****  *  *  **  ** *   newNum1;
   ***  *  *     *** *  *  **** *  newNum2;
 *     ** *     ***  *    ** gcd;
  *   *   **   *  **      * **  rem;
 *   * ***  * **   ***  * num1, num2;

  *    * *  ****  *  **  *   ***** *   **   * *  * * * *  *   * **  *  

 * *    ** **      ** * * ***  **
* *    * ** * *****  * *   *  *   

 * ***  * *    * * * *  * **   != 0)
**** *  *    *    * * * 
 *   *** *   ** *    ** *  ** * ***** *    *  *************  = j%i;
**** **           ** **  ****  *   **   * *** **    * = i;
 * **  **** * *     *    ** ** ******  ***** *     * = rem;
 *** * *  **  ***** * ****  
 **   * **  * ** *** * ** ***   

** * *** *   *  **  *  ** * *   = num1/gcd;
 ***     ***   *** * * *  ***   = num2/gcd;

 *      ** *  *    **  ** *  ****  ***   == 1)
    {
***   ** *** * ****  *    *  * *** *  ***  *  * * ** *** ***    * ** ****** **   
    }

 ** * ***  ** *   **    *   * *  
    {
**  * *** * ****** * *  * * * ***    *   * ****   *   **  **   ****      ** **   *     *
 **   * ** ****  **  *     *  * 

**  * *******  ** ****  *    0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
** *      **  **     **  *   *  *** *  * *  ** * ** *  ** * * ***   * ** * 

    * **      * ****  * *  ********  
 *** *   *     * *    * * * *    * * *  **    *****     * *** ** **   ***** ** **

    else{
*******      * ** *** * *** ***    **** *
    {
* * * **    *  ********   * *** *** *  ** * 
*  * *  * ** * *** * *   *   ** **  *    ***   * *** * **  **** * *   ******  * * * * ** && deno%i==0)
*****  * **   *   * * **     ** * *  **  *  * *     ****  *  *  * * *   ***     * 
  **  *** **  * ** *    * *  ** **    *    ******    * * *  * **           *   *   **** *     *  ** ***
*** **   **   *  * * ** *  * * *   **  *** **  ** * ***     ** ** *   * ****   **    ** **** *     *****
* *    *** ******  * * *  * *   * **       *     *****  * *  **   * *** ** ** *****
    }

*     *  ** *  ** * *****  ****  *  *** *   
    {
 *****  *  **** * *    * * **  *    *    *  * 
  * *  * ** ****  **********   * ******    *       *  **  ** * *  *   ******   *       ** && deno%i==0)
* ** *       *   * *  * *** ***    ** *    *  * *  *  **       **  *  * *** 
 **      * *  *  ** *  *** ** * ** ** ** * **   *  *   ****   *   * *  * *    * * *   *  *    **   *   ** * ****  
     * ** * ********  *** *     ****    ** * *  *    **    *     **   ***  *     *     ******    *      
    ** ** *   ** *  *     *     *     ** * *      **   *   **  *  *  ** * * 
    }
   *     **   *** ** ****  * * ** ** ** ** ****** *

    }




 *    ** ** * ***    **  **   * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    ** *   *    **
#include ** *   ****

int gcd(int n, int m)
{
********  *  **  * *  **** gcd, remainder;

   **** * *   ****  ****** *  (n != 0)
 ***   * *  *  ** **  ** * * *
  ***    ** * ***    *** **  *** *  ** *** *  *   *    **   = m % n;
**** *  ***   *** **  *   ****  *  * ***   *   * **   * ** * * = n;
*     * ****   * *    *   *  * *   ***** ******  *** = remainder;
* *****   ***** * ****    *

  *    **   *** * * ** ** *    ** = m;

    ***  ** **** *  *  ** *** * ** gcd;
}

int main (int argc, const char * argv[]) {

* ***   * * ***** * * number1, number2;
 *  * *  * *      * ***** newNumber1, newNumber2;

*    ****   ** * *   **** *  ****  *  * ***     *       **** * *   *** * * ***

 * **    **  *** ***  ***   *   *   * = number1 /  * *** *  number2);
*  *** *    ***  *    ** *     * * = number2 / *  ***  number2);

 ** *  ** ** **** *********  *  * **    *****  *  ***
 * * * * *** *  * **    *****  ***** ** ***** **** ** *    *** *
* *  ***    *    ***** **    * *  ***
*  * * ** *  *******    **  *   *  ** ****  ***** *   **** * 
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
** **********  ** *  
*** ** *    *  *** *    *

int * *** n, int m)
{
      **    ***** ** int gcd,      

********* ** * * ***  (n != 0)
 *** *   ** *    {
 * ** * * *  ****   *  *  ***   ****  = m % n;
 *    * *  * *    * * **  * *  *** m = n;
**  ***   *   *  ****     *  n = *****
*** *  ** *  * *   }

 *  ** *   * *** gcd = m;

****        * *  **  gcd;
}

int main (int ** *   ** char * **  {

* **    *  * int *  ***  * *  
  * *   * *** int *****   * **

 ***   * *   ** *  * * *   *   **   *   *** ** *     * ** ** *  

  ** *  *  *  * ** *  = ****  / *  * **   **   *  
**    *  ** *     **    =    /  ** * ***    * 

  *** * ** *  if ***  *  * * * **  *   **
* *   * * ** *** ** *  ** *  ** **  ***     ***   ** *  **
 *  *   *  * *   else
*  *  ** * ** ***** ** ****   * * *   ***  *   ******  * 
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
* ***  * **  *    *       * i;
         ** *  *     * *** *   j;
*  ***       *  *  *     * *    newNum1;
 *** ** *  * * *  ** * * *    *  newNum2;
* **   ***   *  * ** *** gcd;
***       ** *  **  *    ***  * rem;
*** *****   ***** ** *    *  **** * num1, num2;
    
**  *   **  ****** ***   *****   *  * ******** **       *** *   *  * 
   *  *   *  *        * *     *
   *  *    * * ** ** *  ***  *** **
 **    ** *  ***  *   *** *  ***
*** *** *  *****  ***   *   **
* **  * *** ****** * *  * ** * ** != 0)
 ***  ** * ***   **      * * 
**  **  * ****     * ** * * * *  * ***  ******* ** = j%i;
   **  *  ***  **    *  * * *    * * *** * * * ****  *       = i;
** **  * **    **   **  *  ****  *   ** *  * * * *  = rem;
 ***** * ** *  *   *  *  **
 **    ** * ****    * **** * 
    
 *  **** *     *   * * ******  *  * = num1/gcd;
    *      **    * *** *  ** *** = num2/gcd;
    
  ** **  ** *** *** **    ** *** *   * == 1)
 **  *  * * *** *  *  ** *
   *****   *   *  **   **       **     ***** *  **** * ***** * *     * **  **** **
  *  *** *     ***     ** 
    
    ** *   *    ***** ***  ** *
* * *  ***  *   * ** **  **
* * ****     ** * *  **     * * ** * * * *       **  **** *   * ******    **** *     
 *  *  ***  *  *    ** ******
    
* ** * *    **   ** ** **    ** *    0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
 
* *   **    ** *   ***  * * *****  i;
    * *   * ** *    *  j;
 *   **  *** **** * **    * newNum1;
  **  * ** **  *  *  ** *** *** newNum2;
 ** * *    *  * *** * * * * ** gcd;
 *  ** **  *  * * *  *     rem;
    *  ****  * **  * *   **  num1, num2;
    
   ***    *    ***  **** * ** *  **** *** ***   ***    **  ** ****** 
** *  * ** ** *   *  *  
 ** * **  *    *  **  * ***
   *     *   *    *  *  ** **
  ***   ** * * ** *** **
 ** * *      *  * *   ****   ** != 0)
* *   *   **   *  ** ***  
 ******** *  * **   *   ****  **  *** *     ***   * * ****  * = j%i;
 ***  *    ****   ** *** *** * ***    * *    * ** **  = i;
** *** **  ****   **   **  * * ****   *        ** * = rem;
** *   * **  ***  **  * *
** *     **  ***   **   **  *   
    
  *** **** **  **** * **    *** = num1/gcd;
* *** ***   *   **    ****    ** = num2/gcd;
    
  ***** * **  **  *  *    **** == 1)
  * ***** *   ** *      *** 
    *  **    ** *  ***  *  **** *** ****  ******      **  * **** *      **    *    * 
  * *** ***     ** * **   *
    
*** *  * *** ****    * * **  * ***
* ***   *    **** ****   
   **  **** ****** * * * *  **  *   *   ** * ** * * **** * * ******  ** ***** * * * ** 
 *** * *  * * ***   ***  **  
    
   ** *  ***   ** *** **     * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
 * * * *  ** ** **     * ***    * ** *  **** **** ** ** * ** 
  * **      **   **  *   *    ***    * * ** ***  ** *
    {
* *** ** * *** ***  * *** ****     ***    * **  * * *      ****     * ** **
*** *   **** ** *****    *  * * **** * * ***      ** * * **** **   ** 
   *    *** * ** **** * *   **    ** ** *  
  * *    ***  * * *  ** *  * * *****  *  *  *
*   *  ** *   * ** ** * * *   * ** * * *

 *  * * *****   * ***** ** **  * *
 **   **  * *****  ****  ** **** * *    ****  ** *  *** ******  *  *  ** ***  *  ** ****  *  *   **      **** 
*  *** *   * **  **** ** * **      * ****** * *****       * ***  ***   


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
   *    ***  * ****** **  ** a,b,GCD;
*****      *  * *        * *  *  * * *   * ** *  *** * * ***** * * ***  
**  *** * **   ****   * ** *   ** **  
 *    ****** ***   ** * **  **** **
 *  *  * ** *** *  ***      *** *  **  * *   *  ****  * * ***  * *** ****
*  *  *  **** * *  **** *** * *   **  
** **** ****     * ** ** *****  * **  ** * * **   * *  **     ***    *  
  ** *  **  *    * *****   *   0;
}
* **  ***   * ** * ****  *  * ** gcd(int a, int b){
* ****  * * ***  ** **** *** ** * * ** ** ****     *****  * *    (!b) return (a);
 ** *  **  * ****   ** ***  ** *    * * **   ***  * * *  * **    gcd(b, a % b);
 **  **  **  * *  *   **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **** *****   *  *
#include *   **      ** 

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
 *** ****** * * ** *  * * **     gcd, remainder;
** *** *  *** *     * * * *  
  *   * *  ***  ****   *  * **  *** (n != 0)
  *  **  **  **   * ****  * * *
 *  *  *  *   ** *     ****   ***    *  **   ********   *** = m % n;
*****  * **   *  *    *** *  * *  *** ** *****   ** *   = n;
*   **  **** **    **    *    * * ******    **  * *  **   = remainder;
* ****     *    **  *    *  
* * * * ** *** *   **** **
** * **  *  *     *  *   *  * = m;
   * *** *  **** ** * * *   * 
   **  ****  ** *   **  *  *** gcd;
}
int main (int argc, const char * argv[]) {
**   ** *  **   * *  *   **  *** number1, number2;
* *******     **  ** *****  newNumber1, newNumber2;
* * *  **  *** ***  ****** *  * 
***   ** ****** *   ****  *** 
   *   **  *  ***  **   *  *  *  * *   *  **  *    ** * *     ** **
*** * *  * *  * *   *  *
** ****  ***  *   *  **   ******* = number1 / gcd(number1, number2);
***   ***   *** ****  *    **   = number2 /   *  ** number2);
* *  * ***    **  ** *   
   **** ***** * *** *** 
 ** * *** *    *** * *  *   ( ****** 
***** ***  *   ** * **** *  *     ******* ** * * **** * ****** * ** newNumber1);
** *  *   * *   *  ******* 
* ***    *    * ****** *  * 
** * * *****  *** **  * ***  **  **** ** **  *** *  * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
 **  ****   * *    * * *    * a,b,c,d,e,f;
** * **       **  * *    ** *  **  ***   *      * *  *    *****  *
 * *  * **    * *     * 
    *  *  ***  ** ** *  *  
 ** *   * ** *   ** *    ***
    {
   ****   *   ****    *  ** *   *    ** ** *   *** 
**  **      ***  ***  *  *  **   ** *  *    *  *** *  *****  
** ****  *  * *  ****** * **  **   *****     * * *   *  * 
    }
 *  * * **  *  * ***   *    * **    *
    {
 **** **   ** * * *  **** * *  ** * * ** *      * *** *  **  
  ******    * * *    ** *    *  * *** *  * * *   *    * * * *      ***  ** ** * *
    *  * * *  *    *  *  *    **  *** **  **** *   * **
* ** **  *  * ****   **      ******   **  **** *** ** **** *  ***   *** *** *  * 
    }
  *    ** ** * **   ** *
    {
 * * * * *   * *  *  ***** ***  *   *****   * *****   ** ** *   ** 
 **  *       *      *     **   ** **    *   * * ***** *  * ***    * *     *   
 *   * * ***    ******  * ** *   *   * **   *   **   *    *
  *   *   **  * *** **   * * *** **  *  **** * ** ** *    ** * ** *   ** ** *   ****
    }
 **  **  *   **    **  **   * **   0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.130.225
©2016-2024

Related questions

0 like 0 dislike
71 answers
11-09 Exercise 1: Print a one-month calendar
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 3.1k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 2.6k views
1 like 1 dislike
85 answers
10-26 Exercise 2: Displays the number of its digits and their sum
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 3.5k views
0 like 0 dislike
69 answers
10-26 Exercise 1: Calculates and displays the GCD of 2 integers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited | 2.5k views
12,783 questions
183,443 answers
172,219 comments
4,824 users