2 like 0 dislike
2.5k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 2.5k views

67 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{

* * * * * *** * * *** ** i;
* * ** * ** ******** ** * j;
* ** * * * * ** * * * newNum1;
*** * ** *** * ** ** newNum2;
* * * *** ** ** gcd;
*** * *** * ** ** ** * * rem;
* * * *** ** ** * ** * * * num1, num2;

****** * * ****** ** * * * ** * ** * **** ****

* *** ** * **** *** *** **
*** *** * **** * **** *

**** * ** * *** ** ** * != 0)
***** ** * * ** ** * ***
*** * * *** * * *** * * * * **** * ** * **** = j%i;
** *** * *** ***** ** * * ** ** * * ****** * ** = i;
** * * **** * * * ****** ** ** **** ** * = rem;
*** * * * *** ** * *
*** ** ** **** * ** *** **

* * **** ** * * *** = num1/gcd;
** * * * ** **** ******* = num2/gcd;

**** * * ** * **** * *** == 1)
    {
* * * ** * ** *** *** * * ** * * ** * * ** * * * ** * **** **
    }

** * * * ** * * ** * **
    {
* * **** * * ***** * *** * * * **** ** ** * ** * *** ** * ** * * ** ** *
* ***** * ** ** * **

* **** *** *** ** **** **** 0;
}
answered by (-140 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdlib.h>
#include <stdio.h>

int main()
{
    int num,deno,i;
* * * * ** * * ** * * ** ******* * *

* **** * ** * * **** * * *
* * * * * * **** * * * * * * * * ** **** ******

    else{
* * *** ** **** ***** **** * *
    {
*** * *** * * ***** **** * *
*** * * **** ** * *** *** ** ** ** * *** * * ** ** *** ** **** ** * **** ** ** && deno%i==0)
** * ** * * * * * ** *** ** * * **** ** * ** *** *** * *** *
* ** * ** ** ** *** *** * **** * * ** * * * **** ***** * * **** ** * ** **** *******
* ** *** * * **** * * ** ** ** ** ** ****** ***** ** * ** * ***** * * *** * *
* *** ** ** * * * * * ** * ******* * ** ** * * ******** *** *** * **
    }

** * * * * * * * ** ****** ** * *** **
    {
* * * *** * * * * ** * ** ****
* *** ****** ** * ** * *** ** *** * * ** * * * * * * *** **** && deno%i==0)
** ******** *** **** *** ** * *** * * ****** ****** * * * ** ****
*** * * *** * ** *** * * * ** ** * * ***** ** *** * * * * *** * ***** *
* ** ********* ** * * *** ** ** ** * * ** * ****** * * * * * ** * ** *** **** * **
* * * * ** *** *** ** * * ** ** *** ** ** *** ** ****** * ** * * ** *
    }
* * * * * * *** * ******** ** *** ** * * ** *

    }




** * ** * *** * ** * ***** * 0;

}
answered by (-16 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include **** * ** *
#include * *** * **

int gcd(int n, int m)
{
* **** **** * * gcd, remainder;

**** ***** * *** **** *** * * (n != 0)
***** * * ** *** ** ** * **
* **** ** * * ** ** * *** ** ** * * = m % n;
** * * * * * *** ** * ** * ***** * ** = n;
** ***** * ** ** * ***** ** * * = remainder;
** * * * * ** * ***

** ** * * ** * **** ** * = m;

* * * **** * * ** gcd;
}

int main (int argc, const char * argv[]) {

* * ** *** *** ***** * number1, number2;
*** *** **** ** * *** * newNumber1, newNumber2;

* ** *** * ** * * * * * **** * ***** *** * **

* ** * ** * * * * * = number1 / ** * * number2);
* ** ** * * ** ** ** * = number2 / * ** number2);

* **** * *** * * * *** * * **** * * ***
* ***** * * ****** ****** ** * * * * * ** * **
* ******* *** * ** * *
** ** * * * * *** ** * ** ** ** *** * * *
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
*** * ** * ** * * **
* **** * ** ** *

int ** n, int m)
{
* * ** int gcd, *

* * * ****** (n != 0)
* *** ** {
*** ** * *** * *** ** * * * = m % n;
*** ** * ** * m = n;
* *** * * * * * * * ** n = ***
** * * * *** }

* * ** * ** gcd = m;

*** * ** ** * ** ** gcd;
}

int main (int * * * * char * * {

** * * ** int **** * **
* ** ** ** int **** * ***** *

* **** * ** * * * *** *** ** ** * * * * ** *

* ** **** * * = * * / * *** ****
* ** **** *** = * * / * * **** *** * *

** ** * * if *** *** * * *
* * ** * ** * * * * * * ** *** **** *
* * * * ** else
** ** **** ***** * * * *** * *** * * *** *** **
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
**** *** *** ***** * i;
**** ******* ** **** *** j;
** **** * **** * * newNum1;
* ** ** ** ** * ********* newNum2;
*** ** * ** **** * gcd;
* ***** ** * ** * * rem;
* ** ** * ** *** * ** ** num1, num2;
    
******* * *** * *** * *** * ** ** * *** * * * ** * *
* * * *** * * **** * **
* ******** * ** * * **** **
* * *** * *** * ** * **** * * *
* **** ** **** **
** * * ** * **** ***** != 0)
* *** ** ** * * * **
** ** * * ** * *** * * * ** * * * = j%i;
**** ** * * *** **** * *** * * * * *** * ** = i;
** * ** ** * *** ****** **** ** * = rem;
** * * * * ** * ****
** * * * ** *** *** *
    
** *** * * ** * ** ** * = num1/gcd;
***** * **** *** * * * = num2/gcd;
    
* ** * ** * * * * *** == 1)
* ** * * * * * **
** ** ** * * * **** ** * * * * *** *** *** *** *** ***
* ****** ** * * *
    
* ** ****** * * ****
* * *** **** * * ** *
** * * *** * ** **** ** **** ** * * * * * * *** ***** ** * * *
***** * **** ** * **
    
** * ** * ** ***** ** ** 0;
}
answered by (-284 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
 
* ** ** ** ** ** * i;
* ** *** * ** * ** ***** j;
** * ** * * *** *** * newNum1;
***** * ** *** ** *** * *** newNum2;
*** * ** ** *** ****** * * * gcd;
* * ** ** ** * * *** rem;
* * * * * * * **** ** num1, num2;
    
**** * ***** ** * *** *** **** ** * *** ****
**** * * *** ** *****
** ** ** * ** *
** * ** ******* * *** ** * *
** ** * * *** ** ** * **
*** * *** * **** *** * != 0)
* *** * * ** ** * *
** *** ** * * **** ** ** * * *** ** **** * * * * = j%i;
** * *** * *** * * *** **** *** *** ** = i;
* * ** * ** * *** *** * ** **** ***** ** = rem;
* ******* * * * *
* *** *** *** * * *
    
* * * * ** ** ** * * = num1/gcd;
* *** ** ******* ** = num2/gcd;
    
** * ** * * ** ** * * * ** ** == 1)
** ** * * * *** *
** * ** * * * * * ** * * ** * * *** **** * * ** * **** * *** *
** *** ****** * *********
    
* * * * ** * * ** **
* * * * ** * *
***** * * * ****** * * * * * ** ** **** * **** * ** ** * * * *
* *** * * * ** ** *
    
** * * * ** * * * ***** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main()
{
    int n,m,i,gcd;
* ******* * * * * * * * * * * * ** ***** *
* * *** **** *** ** * * * * ** *** *** * *** ***
    {
* * *** * ** * ** * ** * ** ** * * * * *** * ** *
* * ***** *** *** * ** ** ** ** * * ** * ** *
* * *** * **** * ** * * * * * * * **
** ** ** * * *** ** * * ** ** * * *
* **** ** ****** **** * ** * * *** ** *** * **

*** ** * * * ** * *
* ** ** ** ** *** ** * * * ** * ** ** ** ** * * * * * * * *** * * * ** * ***** **** * ** ***
** * *** **** * * * * ***** ** * * *** * ** ***


return 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include <stdlib.h>


int gcd(int,int);
int main(){
* * * * *** *** ** ** a,b,GCD;
* ***** * *** ******** ** * * * * ** * **** * **** **
* * *** **** **** ** *** ** ****
**** * * ** ** * * *** * * **
*** ** * ** *** **** **** ** **** **** * *** * * ***
* *** **** ** ** * ** *
* * * * * * *** * * * ** * * **** ** * ******** ** ** *
** * * * ******** ** 0;
}
** *** * ** gcd(int a, int b){
* * *********** * ** *** *** * **** **** **** ** ** (!b) return (a);
**** *** * ** * **** *** ** ** gcd(b, a % b);
* ** * ** **
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:6:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa51\xe5\x80\x8b\xe5\x88\x86\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82:4/8\n");
 ^~~~~~
prog.c:6:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:6:1: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
prog.c: In function 'main':
prog.c:7:1: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
 scanf("%d/%d",&a,&b);
 ^~~~~
prog.c:7:1: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:7:1: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:1: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
 printf("%d/%d",a/GCD,b/GCD);
 ^~~~~~
prog.c:9:1: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:9:1: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include *** * *** * *
#include * * * * **** *

//gcf function - return gcd of two numbers
int gcd(int n, int m)
{
** *** * ** ** gcd, remainder;
* * ** ** ****** * * **
***** ***** ******* * * * (n != 0)
**** ** * ** ** *
*** *** ** * **** ** * * *** * ********* * ** * ** * = m % n;
**** *** * ** * ** *** * *** *** **** *** = n;
* ** * ** * * * ** *** ** *** * * * = remainder;
*** * ** **** * * ******
* **** * * ****
**** **** ** * ** ** * *** ** = m;
*** ** * **** * **
* * ****** * * *** * * ** ** gcd;
}
int main (int argc, const char * argv[]) {
*** ** * **** ** number1, number2;
*** * * * ** * * * * newNumber1, newNumber2;
* * * * * **** * * ** * *
** ******** *** *** ** * *
* ** * *** ** * * *** ** ** * *** * ** * * ** * * * **
** ** *** * **** * *** *
*** * * * *** * ** **** * * = number1 / gcd(number1, number2);
* *** ** *** * *** **** * = number2 / * *** number2);
** ** * * ** *****
*** * * * * **
**** * * *** * ** *** * ( * * **
** ******** ** ** ** * ***** *** *** **** ** ** * * * *** newNumber1);
* *** ***** * * * * * **
** ** *** * ** ** ****
** * **** *** * * * * * *** * * * * * newNumber1, newNumber2);
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* **** *** * * **** *** ** a,b,c,d,e,f;
* *** *** *** * *** * ** *** * * * * * **** *
* * ** * ** * * ** *
* ** **** * * * * *** * *
** * * * **** *** * ** * **
    {
* * ******** ** ****** *** ** * * ** **
* * ** ** * ** * * * * ** ** * * * ****
**** ** *** ** * * *** ** ******* * ****
    }
**** ** ** **** * **
    {
* ** * **** * ** **** *** * * * ****
* *** *** * * ** * ** * *** * ** * * *** * *** * *** *** *
** *** * *** *** *** * ***** ** * ***** * * * *
** * ***** * * * * * * **** ** ** *** * ** ** ** * ** * ** *** * * **
    }
** * * * ** *** * * **
    {
* ** ** **** ** ** *** ** * *** ** * * * *** * **
* *** **** ** ** * * ** * ** * ****** * ** * *** * *** * **
** * * * ***** * ** * *** **** * ** ***
** * *** * * * *** ***** *** * *** * ** *** * **** * *** *** **
    }
* ** ** ** ** * ** *** ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.6.133
©2016-2024

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 3.1k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 2.6k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 3.5k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 2.5k views
12,783 questions
183,443 answers
172,219 comments
4,824 users