1-4 Exercise 1: String compare function

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Each string will have two strings (string A and string B), each sub-string has 5 characters. 

Write a program with a function compare(string A, string B) for comparison

輸入兩個字串(string A, string B), 每個字串有五個字元

寫一個compare(string A, string B)函數。不能用字串函式庫

If String A == String B returns 0

If string A> string B returns 1

If string A <string B returns -1

Do not use string libraries

Example input:

gamesbegin

Example output: (because g>b => 1)

1

Example input:

iamigiates

Example output: (because m<t => -1)

-1

 Example input:

111qq111qq

Example output:

0

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40713 - Available when: 2018-01-04 18:00 - Due to: Unlimited
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#include<stdio.h>

int main(void)
{
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#include<stdio.h>
#include<stdlib.h>
#include<string.h>

int  compare(char A[10] , char B[10])
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#include <stdio.h>
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0 0
prog.c: In function 'main':
prog.c:20:15: warning: implicit declaration of function 'compare' [-Wimplicit-function-declaration]
  printf("%d", compare(string_A, string_B));
               ^~~~~~~
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prog.c: In function 'main':
prog.c:20:15: warning: implicit declaration of function 'compare' [-Wimplicit-function-declaration]
  printf("%d", compare(string_A, string_B));
               ^~~~~~~
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prog.c: In function 'main':
prog.c:20:15: warning: implicit declaration of function 'compare' [-Wimplicit-function-declaration]
  printf("%d", compare(string_A, string_B));
               ^~~~~~~
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answered by (-285 points)
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prog.c: In function 'main':
prog.c:20:15: warning: implicit declaration of function 'compare' [-Wimplicit-function-declaration]
  printf("%d", compare(string_A, string_B));
               ^~~~~~~
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#include<stdio.h>
#include<stdlib.h>

int main()
{
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}
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#include <stdio.h>
#include <stdlib.h>

int main()
{
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#include <stdio.h>
#include <stdlib.h>

int main()
{
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