第二次期中考補考-第二題

3 like 0 dislike
4.2k views

若一個正整數的奇數位數字和與偶數位數字和兩者差的絕對值是11的倍數，則這個正整數就是11的倍數，否則就不是11的倍數。

請寫一個程式來判斷輸入的數是不是十一的倍數。

 

輸入說明：

會輸入一個正整數N，N不會超過1000位。

 

輸出說明：

如果輸入的數字是11的倍數就在螢幕上輸出YES，否則就輸出NO。

 

輸入範例：
 

11111111111111111111111111111111111111111111111111



 

輸出範例：

 

YES
[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 38939 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 4.2k views

16 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 * ** ** **   * ***** ***   *     arr[1000];
 * * **** *** ** *   *  **   even=0,odd=0,i,n,sum;
    
* ***  *   *  * *   * **    * **    ** * * * **   ****
    
*  * *  **  *  **   ***     *    *** ** *  
  * *   * * *   *  ***** **   ** 
 **    ** *  **  *** ***** *  *  *   **
    {
* *  *****  *  * ** ** * *** * **   *** ****  **  *   ** ****** **** *  ** ****    **  * * *** * *** *        * *      ** * * ** * **    * **  ***
   * * ** ** ** ***     * **   * *** **** *** *    **  * *** **   *    **** * ****  ***     **  * *   ** *        ****** ** *  *** * ****  **  *  ** *
** * * * *   ** * * * * *    **   ***   * ********  ****** *  ****   * *   ****     **  *** * *  **    ***** *** ***  **  * * * * **   
* ***   * *  *  *      **    *   **   *** *****  ***** * *   *  **  ** * **** * **  *      ***  *    *** *   **  * *  *  ** * *      ** *  * ** 
    }
    
 ** **   ** * ****  ******* * * *** ***  
*    * ** * *    * *     ***   * *   
  *  *    ******  **  ***   * * ** ** * ***** *  
*  *   *******  *****   **  **  * 
  ****  * ** *   * **  *   **  ****      *     
    
     **    ***  **   **   *  *     0;
}
answered by (215 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Case 5: Correct output
Case 6: Correct output
Case 7: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
* ****    * ******* ******    * num[1000]={0};
    int k, even, odd, i, j;
* * * * ***  ** *   *** * ** **    **   *  **** * * * ** * 
 * **   * ** ** **   *     **   
 **   *  *  **       *      * ** *  
 * * *** *   ** * *  ** **  *** ** ********   *      *** **   **  **  *  
   ***  * **   **** * ** **  ***   * * ** ***** ** **   *  **  ** *
*** * ** ****  **   * * ** **     * *****    * ** **    
* * ** ** * * *******  ***    *** *  **     *
  *** **   ********  * *     ** * ***   **
  **  *** ** ****  *  **** *  ** * ** * * *   **   
  ***  * **      ** *   *  **
*    ** *  * * **   * * **** ***  ****     ** ** **** **     
** **  ***   ***   ***  *   ** * 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:23: error: expected expression before ']' token
     scanf("%d",&array[]);
                       ^
prog.c:7:5: error: 'returm' undeclared (first use in this function)
     returm 0;
     ^~~~~~
prog.c:7:5: note: each undeclared identifier is reported only once for each function it appears in
prog.c:7:12: error: expected ';' before numeric constant
     returm 0;
            ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
    char c[1000];
*** * *      ***** * **** **   ** ***    *   **
    int a,i,x=0,y=0,z;
 ** **** ****    ** *  *  * *  
****   ** * * * **   *  ******     ** * ** ****  
    {
* *       ** * ***  ***  * *****  ***  *******  ** *****  **
  * **   *  ***    ** *** * **   ** * *   **** ****
 *   *** *  * **  * **    * ***     **** ******   * ** **     **  *     *****     ***   * *  
* *  **  *  * * * **  * *  ****** ** ** ** **** * * **   **   **   * * *     *  *  *  **
  **  **  ***  *  * * * *   *****   *     *  ** *    
  *** ** ***   *  ****   *****  * * ******  * *
* *            **   *****      * ***  ** * *  *** 
 ** *   ***  *  **** * * *  ****  **** * **   *** *  *  ***  *   * * **  *  ** ****  *    
*****  *   ****   * ***  ** * *   * ******  * ****     * * **** * *    **  *** * ** *  *  
 **    * *  *  ***     ** * *       *   ** *  ** **  
    }
   * * * * *  *       * *** **  *  *   * *
      * ** **  *   **  ***** *    *   ** *********  * **  ***  *  * ** ** ** **  *   *
    else
****** ******** * **       ** * * *** * * ** *     *  *** **  ** ** ** * **   **  *
}
answered by (100 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Case 5: Correct output
Case 6: Correct output
Case 7: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main ()
{
*    ****   *  * * **    *  *** str[1000]={0};
**   *  ** *   *    *********** j , n,sum1=0,sum2=0;
***    *   * ** *  * * **     * ***   *    **   
 * * **    ** ** **    ** = strlen(str);
*  ****   * ** ***  *  ** *  = 0;j < n;j++)
  ** ******** * ******    ** *** *
** *   *** * *     ** * **       ** *   *** * ***    **   ***  * * *  == 0||j%2 == 0)
** * *   *   * ** ******  ****   ***   *  * * **  *   * *  ******  ***  *  = sum2 + str[j] -48;
**     ** ****  **  **  *   * ** *  ***  ***** *   * **     * * *  *   if ( j%2 != 0 )
 *****    *    *** * *  ***  *  ** * *** **** **  * *  * ** * = sum1 + str[j] -48;
 * * **  *  *****   * *  **  *
 *     *** *        *     *   (sum1 > sum2)
**** *  * ** **** ** *
*  * ** *    *   *  ** * *** *  * ***  * *  *****  **  ** * - sum2) % 11 == 0 )
** *   **    * * **  * ******  **   *** **   **** *****           * \n");
**  * **  *** ***   **   ** ***  **** * **   ** 
**  *   ** *   ******* ** **   * *     *  ** *   *  \n");
  * * ** ** * *        * *** 
** * *** ***   *  * *******  if(sum1 < sum2)
   * ** ***** *  *  **   *  * 
***  *  ** * * * *   *** * *  **  *  * *  *   ** - sum1) % 11 == 0 )
*   * **** ** *     ** *   * **  **  * *      **  ** ** ***   ***  **  \n");
******  *  * *  * ***  * * ***  ***  * *  * **  **   
*   ** ***  *  *  **** **** ********  *         ***  * * *** \n");
 *    *   * **  * ***  *****    
     **  ** * *    ***  *  * *  if (sum1 == sum2)
  * **   **  ***   *  *  *** *** ** *   * *  *   * * \n");
*    * ******** **    *** ** ******  * ***  **
*** *** *  **     *****  *  * 0;
}
answered by (209 points)
edited by
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1000]' [-Wformat=]
     scanf("%s",&str);
             ^
prog.c:21:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system ("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1000]' [-Wformat=]
     scanf("%s",&str);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(str);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccwAQ4Bd.o: In function `main':
prog.c:(.text+0x3c): warning: the `gets' function is dangerous and should not be used.
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1000]' [-Wformat=]
     scanf("%s",&str);
             ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 * * * ** **    * ***   arr[1000];
***     ***** ***   * **  even=0,odd=0,i,n,sum=0;
   
    * * **     ***    * * *   *    *** *
   
  ***  *  **  *    * ** ** *      *
      **   ** *  * *    *
   
  ** * ****   **     ** *** * *
* **    *  * * ***  * ** 
*******   *     **   * * *  *   * ** ****
   *  * ** *** ***          *     * *  * * ***  *   ** ****   ***** *   *  * *  *  ****     
  ** **** * **** **  * *    **  * * * *      * ** if(i%2!=0)
 *** *      *  **   *   * *    *   *     ****   * * *** ** ****      **    **** ** **  *  *** **   * * **   ** *** *** *     ** ** *  **    * * ***** ** **   *** 
* **    **  * *** **     
   * * *     ** **  ****   *
   
 *  ** ** * **   **    ****
*  ** * * **  ** ** **  
    *** ** ***** *** * *  **  * *  ** *      *  * **  **** * ** *   * *     **  * * * *   *    *   **** **** ***  * ** ** *
   **   *  * * *   ** **
 *   **  **  *******   ***  if(sum%11!=0)
 *  **  *** * *  
 *    ***       *  * **  **** * **   * * **   ** *  ** *  *  * *  ** *   * **  * 
  *    *  *  *** 
   
  
* * * **   **  *** **   ****
    * * *****  ****    **
}
answered by (174 points)
0 0
prog.c: In function 'main':
prog.c:8:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
    scanf("%s",arr);
            ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Case 5: Correct output
Case 6: Correct output
Case 7: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main(){
*  ** **      * ****  *** ******   * one=0,two=0,i,ans;
*  ** *  * *  **  *  ***  ch[1000];
***      *** *      ***** *  * **    **** * *** *
    
    *    *    **  ** *** *    ***  *  **** ***  
 *    **  ****** ***  *** * ** ***  * *   *********  
* * * * *   *    ****  *** *  *   ** * ****  * *  * *   ** * **** ** **     **  * * 
* *   *   * *  *  *   *    **     ** *** *  * * * *
*  *  *  *    * *  **  * ** ***   ***   * ****  ***
 **** * **** * *  *  ** *  **    * ****   * **** * * *   *** ****    ***  ** 
*  * **   *   * *   **  *   *****  * * ** ** ** *** 
    }
    
    *    *   *  ***  ***   *   ****
    
*** *     *    *** *** * ****   ******
****   *      **      **   * *  ** ******      * ****    *
** * **     *  * **** *  ***     * ** *
*  *****  * ** *  ** ** **  * * ** **** **   * **
}
answered by (192 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Case 5: Correct output
Case 6: Correct output
Case 7: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.133
©2016-2025

Related questions

2 like 0 dislike
5 answers
第二次期中考補考-第五題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38942 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 1.5k views
2 like 0 dislike
18 answers
第二次期中考補考-第四題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38941 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 3.6k views
4 like 0 dislike
16 answers
第二次期中考補考-第三題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38940 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 6k views
3 like 0 dislike
12 answers
第二次期中考補考-第一題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38938 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 2.9k views
2 like 0 dislike
3 answers
第二次期中考補考題庫 -10 唐．喬凡尼
[Normal] Coding (C) - asked Dec 20, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38168 - Available when: Unlimited - Due to: Unlimited | 975 views
12,783 questions
183,442 answers
172,219 comments
4,824 users