第二次期中考補考-第二題

3 like 0 dislike
4.9k views

若一個正整數的奇數位數字和與偶數位數字和兩者差的絕對值是11的倍數，則這個正整數就是11的倍數，否則就不是11的倍數。

請寫一個程式來判斷輸入的數是不是十一的倍數。

 

輸入說明：

會輸入一個正整數N，N不會超過1000位。

 

輸出說明：

如果輸入的數字是11的倍數就在螢幕上輸出YES，否則就輸出NO。

 

輸入範例：
 

11111111111111111111111111111111111111111111111111



 

輸出範例：

 

YES
[Exam] asked in 2017-1 程式設計(一)AD by (30k points)
ID: 38939 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 4.9k views

16 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
*   **  *  **   ***  ** ****  arr[1000];
 *  * *  * *  ** * *** ** even=0,odd=0,i,n,sum;
    
*  ** * ** *      * *  **   *** **  *  *** **  *** * 
    
** **  **   *  * *** **    *** * * **  **  
 ****  *** *** ** *  * * *****   *  *
  ***   ***    **   *  **    * **  ** *   * ****
    {
***  *****    *  * **  *   ***    * * **  **   *   * ** ** * **  **  * **   **    ***       **  * * *** **  ** **  *  *  **** * *** * *  **      *** 
****    *         *  * ***  **    **  *    ** *  ** *  * * **  ** *** *   * ** ****   *    *** ****     **** ** * **** ***** *    *    **
*  **** * **  * *  *   ********  ** * ********** ***  *    * * ** *  **** *  * ******** *** **    ***    ***** ** * *  ** * * * ***   * ** *  **
***** ** **** ** *  *** ****   * *    *   **  ** * * **  ** * * *** *  **  ***** * *  *** * * *  ****  *   *****        *    ** *  * *    ***    **  * ***
    }
    
* * * * * *      ** ** ** *  * * 
**** *  **** * **    **  **  *****    * *
   ** *  ** * ** ** **  * **** * * *    ***    * ** 
* **  ** **** **  *    * *** *** **  * *
    *  ***      *     *** * ******  ** ** *    **
    
 **   ** * * ** *    **  **** 0;
}
answered by (215 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Case 5: Correct output
Case 6: Correct output
Case 7: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main()
{
* * ** * * *   * ***** *** num[1000]={0};
    int k, even, odd, i, j;
 *    **   **  * *   * *  *** ** **    * ** * ** *  **     
** *  ***  *  *** *   **  *   *** 
**    **** *  * * * *  **** **  
    *  **   * *    * **    *****     *****  ****  ***  * **** * *  *** *
**   *****  ** * * *** *** *   *      **     ***** * *** **  
  ** ** ****  *** *  * * ** *   * ***  ***** *** *  *** * *
* * * *   *    **   *   ****** ***     *** *      **
**** * *  ** * **  *  *  *   * ***   * **
* * *  **    ** *    * *  ** *  *    *** ******   
 **** ***   * * * * ***  * *  *
*    ** ****  ***   *  ***** ** ****   *  *****   
*    ****** ** *  *  * **    * ** *** 0;
}
answered by (144 points)
edited by
0 0
prog.c: In function 'main':
prog.c:5:23: error: expected expression before ']' token
     scanf("%d",&array[]);
                       ^
prog.c:7:5: error: 'returm' undeclared (first use in this function)
     returm 0;
     ^~~~~~
prog.c:7:5: note: each undeclared identifier is reported only once for each function it appears in
prog.c:7:12: error: expected ';' before numeric constant
     returm 0;
            ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
    char c[1000];
**   ***   *** * *  *  *      *   ***   * * ****
    int a,i,x=0,y=0,z;
    ****** **  ****     ****      **
* ** *   ****  ***  *********** *    ** 
    {
     *** * * *** *****  *** **  *****  *** ***** ** * 
     *   ***  *  * * ***** **  * *** ** **** * **        
* * ** ***   *    *  *  ***  **  ** * *  **  * ***  * * *   *  *****   **** **** ***      **
***** **     ***         *  * *  **  *  * **     ** **  * *   ** ***  *
  * ** ** *** *  **  *  * **  *  *  *** *  * **** **** *   * 
   * ** **   *  *** ** *    *    *** ** *  ** *  * * *  *   * 
*  **** **    *    * *****   * *  * * *  ** *          **  
****** ***  * * ** ** *** ** *  *     ** ****   **  *   *  **     ******** *
 ** *****  ** *  ****** ****  **** *    *   *** *     ** *  * **** *  
* ****  **   ***** * ** * * **  ** **   * * ** *  *   
    }
* **** **** **   ************  ** * *
 *     *  ** ** * *    * * **  *** *    *** * **    * ** ****  ***
    else
  * **  *** ** * **** **       ** ** ***   ****      *  ** * * **** *  * *  
}
answered by (100 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Case 5: Correct output
Case 6: Correct output
Case 7: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main ()
{
*  ****  ** * * ****  *  * * str[1000]={0};
* *   ** ** * *   **** * j , n,sum1=0,sum2=0;
  * *** ******* *****    ***   * *   * * * ******
*** *** *   * *    * * * = strlen(str);
 * ** ** * ***    **** ** *    = 0;j < n;j++)
  ****    **  * * ** * ****  *** 
**** * ** * **     *** ** **     *****  * **** **** * *   *** * *  *** * == 0||j%2 == 0)
    *  *** * *  * *******   *    **** *** **    * *** * **  *  = sum2 + str[j] -48;
  ***        *    * ** * ***  * * *  * ** * ** ****      * * * **  ** * if ( j%2 != 0 )
** *   ***  ***  *  ******** **    ** ******** **** *    *  ** * * *   ** ** = sum1 + str[j] -48;
      * **** *** **     *
* * ***  *  *    **     (sum1 > sum2)
 **** ** **  **  * ** * ** **
** * * * ****   *** *    *  * * * **** * *  **  *   - sum2) % 11 == 0 )
* ***** * ***  ** * * *  * *** *** *  *  * **  **  * * * * \n");
**   ****  *  * *    *** *  ** **  ****     * *    **
* ******    *   *  *  *** *  * * *  **** ** *********** * \n");
 * *  **********  ***
*    *  *  *** *  * ***  * *    if(sum1 < sum2)
***  * ***  ***** * *    *** * 
*   *   *  *  *** *** * ***  ** *  ** *  ** * - sum1) % 11 == 0 )
***  **** * *  ** * ****       * * *  **  *  * ******       \n");
  *   *  *** ***** *  ** ****  **  * **  **    ** *
  **** *   ****   *  **     ****    ** *** **  *   ****  *  **  *  \n");
 **   *** * * ****  * 
    ** *   ****  ***   ****  if (sum1 == sum2)
 ** **** * *** ** *** * *****  * *  * *   ** * * * ** **** *** ** \n");
*** * ***          **    * * **     ****
 **   * ** *   * * * *   *    * ** 0;
}
answered by (209 points)
edited by
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1000]' [-Wformat=]
     scanf("%s",&str);
             ^
prog.c:21:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system ("pause");
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1000]' [-Wformat=]
     scanf("%s",&str);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(str);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccwAQ4Bd.o: In function `main':
prog.c:(.text+0x3c): warning: the `gets' function is dangerous and should not be used.
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1000]' [-Wformat=]
     scanf("%s",&str);
             ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
Case 5: Wrong output
Case 6: Wrong output
Case 7: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
   **   * **** * * ** *** arr[1000];
 * **** *  ********   even=0,odd=0,i,n,sum=0;
   
   *    * * * * * *  *  *  ** *** *   *** *
   
** * *       **  *       **   ** **    
** * *    *   *  *** 
   
*** ****   ***  **      * *  * * * 
 *  *** ****  *** * * *
      ***** * *** **** * ***   * * ** ** * *   * 
*** * * ***** *   * * **   * * ** ****** ***  ****  ** * **  * **   ****  **   * ** **     *
    ** *  * **** *  ** * * * ***  * *****     if(i%2!=0)
  *** *    ** **** ** ** * **** *** *  *  *   ** *      ** **  * * *******   *   ***     ***  **  *   *   **  *  * *  ** *  ****** ** *  ***** * *  *** * 
**  ** * *  *  * **    
**   *  *    * ******** ***** 
   
*   **  *   ** *  ** *  *** 
 * **    * *  ** *  **
  * *** *** ** * **    * *  ***   ** * **     ***** *     * ***   ***** * ** * * ***** **** * *    * ** **  * * *    * **   ** *  **  *  
* ***   **  ******  
*      ** *  *** if(sum%11!=0)
**  ** ***   *  * **     
 * * *   * **   * * *  *   ***   *** * *    ****   * ** * * *      ** * 
 ****  **   * *     ***
   
  
  ** *****      *  * *  * *  *  
**   ** *** **  **** *  * ** 
}
answered by (174 points)
0 0
prog.c: In function 'main':
prog.c:8:12: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
    scanf("%s",arr);
            ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Case 5: Correct output
Case 6: Correct output
Case 7: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main(){
  * ** *  *** ***  * *   ***** * one=0,two=0,i,ans;
**     *** ** * * * *  ** *    *  ch[1000];
 *   **  *  ***** *  * ******  **   ***   ** **     
    
**  *** ** * ** *    * *  *  * *** * ***  *
*  *  ** ***  * **   * **  *  * *    ** *    *** *   **  * 
   ** *** *    * *    ****    **** *   * *  *** ** **    ** * *   *     **       *
*  * ** **** *     ***** ** * *    * * * **** 
 **   ** *  *** * ** **   *    *  **  * * ** ** ***   * 
      *   *   * * *  * *  * * ********  * **         ** **   * *   *      
*  *  **** *** *    * * * ******  **     *
    }
    
*      *   *     *** **  *     **
    
 * *****  * *      *  ***  *      **  * 
*****  * *   ****** *****   ***    **** *  **    ***
  **    *       * ** *   *  * 
**   * * ******    *  **** **  * * **  **  
}
answered by (192 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Case 5: Correct output
Case 6: Correct output
Case 7: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.179.102
©2016-2025

Related questions

2 like 0 dislike
5 answers
第二次期中考補考-第五題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38942 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 1.7k views
2 like 0 dislike
18 answers
第二次期中考補考-第四題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38941 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 4.1k views
4 like 0 dislike
16 answers
第二次期中考補考-第三題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38940 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 6.8k views
3 like 0 dislike
12 answers
第二次期中考補考-第一題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38938 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 3.4k views
2 like 0 dislike
3 answers
第二次期中考補考題庫 -10 唐．喬凡尼
[Normal] Coding (C) - asked Dec 20, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38168 - Available when: Unlimited - Due to: Unlimited | 1.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users