11-01 Exercise 1: Find out all prime numbers between n and m

0 like 0 dislike
21k views

Write a program that get the input of two integers n and m(n < m). Find out all prime numbers between n and m (not include n and m), then display them on the screen.

寫一個程式 輸入兩個整數n和m (n < m)，找出所有n到m之間的質數(不包含n和m)。

Example input 1

1 10

Example output 1

2 3 5 7

 

Example input 2

10 20

Example output 2

11 13 17 19

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 21k views

99 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main(void)


{
int num1, num2,x,y,flag;


 * ** ** *  *  **  ** **  ***   **  ****** *  ******   *   **** **   ** **

  for (y=num1+1; y<num2; ++y)
  {
    *   ** * *  *  ** * *  *  ******   * * * *
*  *  *  *      *** *** ***  *  * x<=y/2; ++x)
 * ** **    ***  *****  * ***    ********
    *** ****  ** * * * *  *  ****   *   **  **    **** * ***
* *  *  *  *** * *     * * *** *  ** *    * ***    ** **
 *     ***** *     *   **     *     **  ***  * ** **      *  ***** ***  * 
   **        **  * ***** *  * * *  *** *      * *   *   * **** ***   *
 *    * *     * *** **  * ** **  **     ** *  ***  * **** 
* ** *****  **    **  **  *** *    **  
* **    * *  **** **  *** * * *** * *  **   **** *
    *  *   * *     *** **   ** **   *** * **   **** *   ***  *  ",y);
  }


 * **  *   ** ** *  *   *   **   0;


}
answered by (-107 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
   ** *  *     ***

int main(){

 * * **  * *** ***** * **  a,b,i;
   ***      *   *   * **  * *  ***** *    *     * *  ** ***** *  * * * 

** **  *  ** * ******* **  *  *  *    ****
  * *  *    *    *****     **   * *   * *  ******   *** * && i<=2){
** *  **   *** ***  * *   ***     *** ** *      **   *  *** ** **  *    *       *   ** *    *  ** * *   **  * ",i);
***********  ** *  **** ****   * *****    ** * ***   *
 *   **** ** *  *  * *   *   * *  ***  ***** *  *  ** * if(i>2 && ***    ***   *      ");
  * **** **** * * *** *    ***   **    **               ***    if(i>3 && i<=5){
*  *    * * *   *     *** ****    **  ** **   **   * * ***** * ** *      ** ** *  *    *     && * ***     *** * * ",i);
     **  **** ** *** *    *****      ***       *   *
**** * **   *   *     ****   * *** ** *** ** **  ***  *   *
      ******   *   * **** **   * ** ** **  * ***** * ****   * **  **   ****   **  * **  * && i%3!=0 && i%5!=0)printf("%d ",i);
  ** *     ***  *   * *    **** **   ****  **** * *

     *  ***  **** *  * ** ***


return 0;
}
answered by (-301 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * *** ** *

int main(void)

//Code to displau the prime numbers between two integers

{
int num1, num2,x,y,g;


  ** * *  * * ***** ** * **    *** * **** * **** * * * *  * **  *   *

* * ** *** *    (y=num1+1; y<num2; ++y)
  {
 ****  *   *    *   *****   ***  ****  **  * 
***  *       *   ** *     ****  x<=y/2; ++x)
***  * * *****    ***   ****      ** **** *
*  * *   ***  ***      * **  * ******  * *  * * *  **    ** 
*  * * ** *****  * ***   * *** ** **  ***    *** ** 
** ****    ***     *** *       *   * ***  **    * *   * ** ** *  *  ** ** * 
*  *    * ****  ****** *    ** ****** **** **    *       **    *  **  *
*   *  *** *    *  *  ***   * * **    ***** **
*    * *   **** **   *   ** **  * ** *   *** * 
**  ** * ** * **** **   * *   **** ** *  *   
*   * ** ** * ** **** *** *** *  * ***  * **  * * **  *   ******* ",y);
** *    **  *   *







  *  ** *   *** **  ** ***** **  0;


}
answered by (-107 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main(){

    int a;
    int b;
    int n;
 ***** **  ** *  * **    **  first=0;
**   **  *  ** *  ***  * * ** * **  %d",&a,&b);
* * * ***  *** *  **  * ***  (n=(a+1);n<b;n++){
    *      ** *  ***  **  **** *  ** ** **  **    d;
******    *** ** ** ***   *   ** ** ** * ****       ******* (d = 2; d < n; d++){
** **   *   **** **  ** ***      **     * * * *     *   * **  *** *** (n % d == 0)
         **** *** *    ** ** ******   **  ****     * * *  * * ** * ** **   * *** 
 *** * ** *******  ***      ****  ** *****  *     * * *
    ** *** * **** **  * * **   * * * * **   *** *  **  *** *  (d < n)
 * * * ** * ****    *     * * ** *** ***** *** ***  ***   * *  *  
 ****   **  *  *     *****    ** *  *  *  ** *   * *   * 
*     *     ***** *   *  ***   *  * ****** *    *  **  * ***    (first==0)
*** ** **  **  *  * ******* *   *  *  *****   * **  * ***  *********    * **     *    * *  ***  * ***
    ** * *** **   *    ** * * * ** * * **  *****  *   *  **  * * ** * 
 ****   *         * *** * ** **    *   *      *      *  * * * ***     * * ** ***   ****  **        ***   ");
      ***   **** * *  **    ** *****    *** ** *   *** *****  * * *    *  
 * *  **    **** **** *  *  *  *  *** * * *  *        *     ** * **   * **   ***    * *  n);
      * ****  * *** **  *  *    *  ** **** **  * *    *      
    }
***  * * ** * ******** * * * 0;
}
answered by (52 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
    int d,n,m;
******  ***  ***  *     **   *          * * %d",&n,&m);

  **   *  ** * **** * ***  *** * *   * * *
 * ** ** *   **  * *   *    *       *  *  * *   *  

**   *  * **  * *  ***  ** ****    * **   * **** *  *  ( d = 2;  d < n ; d++)
* *     *** *   **** *   *  *   ** ** * **  **    * *   *
***** *    *  ***  *  ** * **              *  *** ** ****  ** **    *  * *  * *    *   * ** * (n % d == 0)
  * ** *   * *  **  ** *    *        * ** **** *  ****   ***  *  ** *** * **   **  *
*  ***  * * ** **  *  ** **   **  * ****  *   ***  **      * * 

  **  *   *    ***  * **    ** * ******  *  **    **  * **     **  *  ***    * *  *
****  **  * * *   ** ** * ** *** **  **** ****** **   *  **** ****          ** ***   *****   *  ",n);
* * *     ********      **   * *   ** **  ****  * *  *    *  * * * * ***  *  **

 * **  ** *****   **** **** * ** 0;
}
answered by (-196 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main() {
    **** **  * *    * * * * *     a,b,i,j;
 *  *** ** ** ****  **  **** *** *   ** * %d", &a, &b);
**   * *   **  **  * ********  ******  * ***  {
* **  **** * ** * **** * **  **  ***    * **** **   ****   *  **** ***  * ** * {
** *** *  *   * *      *****  * * ** *    * * * **     *  **** **   ***** *** **    break;
 * *** **     **   *   *  *** **   ** *  *****
 ***   *  ***  *** *  *** ************  ***  *   ****   printf("%d ", i);
   ***** ** ** *  *** * * 
}
answered
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
    * * *  ***   * *    *      * d,n,m;
    ** *** *****  * * *  *   ** **   *** *    ** *  * **** *  

** *  ***** **      * **    ** **    *    
** *    *      * **** *  * * *****  **  *  * * *** **  ***** **

  ** *  * *** *** * * *  *  * *  *      * ** **  *  ( d = 2;  d < n && n % d != 0; d++);


  ******** *   *  *  ** *****  **  * *  * * ***  *  *     *   * *  ****  ** *     **   **
  * *  *** ** *  ** *   *** ** **    *  ***  ******** * *  ***** *****         *  *  ",n);
   ** * *    * ****  ***  ** *  ***     *  ** * **   ** *  *   *    * *   ***   *  ** *** 

 *     ** ****  * *    * *  *** * 0;
}
answered by (-196 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main(void)

{
    int n,m,i,def=0;

    scanf("%d %d",&n,&m);
*** *     * *   * **    **** ***   **   **** * **   **  (n<m)

        { def=0;
* *  ** * ** * * **** *    ***  ** * * ***** ** ** ****  **  **    * * 
 **** ****  **   * *     *******  **   *    * ** * * **  * * **  ** *** *  ******    i<=n/2; ++i)
  * **** **   ** ***** * ****  **  * *      * * ***** ****  ****  *****    *   *****  *    * * * ** **  *   
* ***  ** * * *    ** * *  * ***     *** ***  * ** *** ***** *   *** ** *** *** *  *  *****  * ** *       **   *  * * *    *  * **   ** * * (n%i==0)
*** *  ** *  ****** * *  **   *   ** *      * ****** ** ** ** *** ***  *    * **  * **  *** *   **    * **    **  *  * *     ***  *** * 
 **   **  ** **  *  ** *    ***      ** *  ** ******     ***** *** * *** * * **   ** * *        ***** ** *  *  *   *** ***  ***** *** * *   **  * 
*   *  *  * ***   * **    ** **** ** * ** * *  ****    *   ***   **  **     *  ** * * ** *   **  * *    **** *   * *** ***    * *    *   
**** *** **  * ***   * * *  ** ** *** ***  * *    *****   * * *** * *  ****   * *   * **  * ***    * *   ** *   ****       *   *** 
  * **** ***     *     *   **   * ** *    * * **   ** ****  * ***    * * **       *   * * *  * **   *
* *** *   *  *** ** *    *    **  ** *** * *** **  ****    ***** * * *   ** ** * 
***  ** *   *     **  *** ***     ****  ***  **      ** *   *

**  *****  **        ***** *    **** *  *   ** *  **      *  * **  ***  ***** *** *     ***     * **   * *  *   ",n);

*  * * ***  ** * * * *  ** * **  * ****  **  *  *   *******  * * 

  *** ********  ** *  ** *  ** **  * ** **  ** ***  **   * * **** *
       return 0; }
answered by (-304 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
    int n,m,i,j,k,c=0;
    scanf("%d %d",&n,&m);
    for(i=n+1;i<m;i++){
        for(j=2;j<=i;j++){
  **  *  **  *** **  * ****  **   * ** ** ** ** *  *  ***  *   * *  * ** * * * *** 
*   *   **  ********   * ***  * **  **  **  ***** ****     * **  *** ***   * * **** *  *    *   **  **
** ***   **** *  *  **    *   *   *** *  ****   *  *   ** * *    **  **** ** **
* ***   * *   *** ** *  *   ** ***  * ***  ***  ******    ** ** **  * ****  *    ***  ** ***   * *       *   
 ***  ******  * ** ***** ***** ***  ** * *****  * *  * *   *****  ***  **** * *** ** * ** *  ** * **   **  *** **** ***   **  *  **  **   *    
 ***** ***  **** **    *        **  *** *     * *  ***  ****  ***   * *  * **  ***  ** * *   ** * *  **  * **** ** ** *  * *   
** **  *  *   ** *** * *  **  * * * ***** * **   *   *     * * ** *    **   ** *** * *  ***   *       * * * **  *  *   * ** *    *     **    ****
*  *  * ** *******  * * *  *      * *  *  **** *    ** ** *** **** *  **  ** ****    **     *** ****   *  * ** ***** 
** **   * * ******    * *** *   *  * * *  *  **  *  *** ***** * *  ** **** * *  * * **** * * *   **  ** *  ** * * * 
*  ** * * * *  ***  **  *** *     **** *  ******    *  ** *  *  **** * ******      * *  *   *   ***  ****  *      *  * *  ** **  *   ***  * **** ***  %d",i);
* *  *   ** *   * * ****  * **   ** * **** *   * *  * **  **** *** *      ***  ** *  **  ****  ******  *
* *    **  ** ***********  * * * *       ** **** **** * ** *****  *  *** *** ** 
 * *  *   *      ** ****** * *** ***** *   * * ***  **  * *   * **** * *** * * **  if(k==0){
  ** ****  * * * ** ** ** *  **   ***   **         *  *    *******  * *  ** * *   **        *   *    **  * * *     *** 
  ** ** *    * * * * *  * *      *    ***   **  ** *** **   * *       **  ** *** ***   * * *
        }
    }
    return 0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
 *  * **  **** ** ** * *    ** ***** %d",&a ,&b );

 ***       **  * *** ** * *** * i=a+1;i<b;i++){
**** ******  *  ***    * *** *   * *****  * * * *** **  j=2;j<=b;j++){
  *   *   * *** ** *    *   * * ** *      *** *** *** *    *** *  *    *** && i%j==0) break;
***** *** ******* ***** * ***** ** * *     * * ***     *  ***  ***  *** * ******  *   * if(i==j){
 * **  *    **  *** **  * ***  ** * **  *  * *  **** * * ** * * **    *   *** **** *  * *  * * ***  ** * * *****
** *  ***** ****   **    ** **   **  * *  ** ***** ** * **   ***  ** *    ****** ****   **  * ** ** ***    *  *   **  **    * ******    *** *** * * **  * * * *     
* * * * *  * *** *  *   * *   * ** **  ** *** **  *  *      **  *****  * ***** *  * **   * *  ** ***    * *******  ***   * ***  ** **  
* ****  *    * * **   ** * ***   * *  * ** * *   *** ** **  * *  *******  ** **   *     ***** ***** *  ***  * *
**     ***  * ** * * ****    * *  *  *  ***** * * **  *   ** *   *****  *  **  ** *   * *** *  ** printf(" %d",i);
**   *  ** ** *   *** *        *  ***    *   * **    *  * *** ** * ** * * *  **
   * *** ***   **   ****** * * **  **  *   ** * 

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.104
©2016-2025

Related questions

0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 14.5k views
0 like 0 dislike
93 answers
11-01 Exercise 3: Fibonacci numbers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 17.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users