11-01 Exercise 1: Find out all prime numbers between n and m

0 like 0 dislike
11.9k views

Write a program that get the input of two integers n and m(n < m). Find out all prime numbers between n and m (not include n and m), then display them on the screen.

寫一個程式 輸入兩個整數n和m (n < m)，找出所有n到m之間的質數(不包含n和m)。

Example input 1

1 10

Example output 1

2 3 5 7

 

Example input 2

10 20

Example output 2

11 13 17 19

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 11.9k views

99 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main(void)


{
int num1, num2,x,y,flag;


* * *  *   ****     *** ** ** ***   *  * *****     ** *   **  *** 

  for (y=num1+1; y<num2; ++y)
  {
**     *   * ** *   * **   * ** ** ********
* *    **  * *   **** *  * x<=y/2; ++x)
*  *** *  ***    *  *** *****  ** * 
* ** ** * *   **  * *    * *  **    * * * *****  *  **** **** *
  *** ***** * ** *** *  * * *   ****** * *** ******     **
  **  * * **   *** ******** ***** *** * *   * *  ***** * ***** * * *** *
   * *   *  ***   ** ******   **    ***   *****   * * *     **** * * 
**   * * * *** **    **** *     * * ***  **** ****
**  * *   ** ** *  *    *** * **  *  * **** *
******    **    ***  *   *     *** ** * ****    * 
  **  * ** ***     *     ***   *  * *** ** * *  ***********    *   * ",y);
  }


     ****      *******   ** *       0;


}
answered by (-107 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
   ** *   * **  *  *  

int main(){

**  * *   ****** * *   **** **  a,b,i;
 * * * *   * * *  *  *   *    ****   ***  * ** * * * * *  ** * *

      *  *  *  *      ** *  *    ** *  *  * *
*  *   *   **    * * *     ****   ***** *   * ***  **  * ** *  && i<=2){
* *    * ** * *     *** * * **   *   *  * *  * *** ***  * *  *  *   *    *  *  * * ** *      *  ",i);
****  *  ** * * *** *   ** * * *****  **  * *   * 
     ** *    * *** ** * **    *  *   ****   * * * * ** ** if(i>2 &&      **  * *  **   ");
***  * ****  **** ***  *  * *    ***  *** *   * * * if(i>3 && i<=5){
***** **** *** **** * * * *  ***  *   * ***     ***   *       ****** **    ***  * *****  * ***  * &&    *   ** ** ****  ",i);
*    **  *   * **    ** * **  *    ** * ***** **    *  * **
  ** **  * ** ****   * ***  **   **  **  **** * ****  ** 
*  * * ** *  * *   *    * *    * ****    ** ** **   ** **  *       * * *   **** *   * && i%3!=0 && i%5!=0)printf("%d ",i);
*  **  **  *    *** * * *  ** ***  *** *  *  *   **  **** 

*   *     ** *     *      *****


return 0;
}
answered by (-301 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *** **   ** 

int main(void)

//Code to displau the prime numbers between two integers

{
int num1, num2,x,y,g;


 * **** * *    **  * ** *  ** *  *  *   **    *  **** *** ** *   **   

  *  *   * ****   (y=num1+1; y<num2; ++y)
  {
 *  ** ****  ****  ** **   ****     * * 
  *  ** * ** ** **    *  ** **     x<=y/2; ++x)
*   *    ****    *  ** *** * *** * *  *** ***
*** * ** *      *****  **  ***  *   *     * *   *  ** *   * * * ** * 
 * * ** * ** **   ** *  * * *  *   * ***  ***** *  *
 **  **  *******   ***** ** * **  * * ******   *   ** *  ** *  ***  * *  
  **** * ***** *** *** ** ****  *** ***    **  * *   * * * *  * * *  ***  
**** * ** **   *  * *   * **** ***  *      **   **** 
****   **   ***** ***   *   *   * *    
***   * **  **  ***   **  ** ***    * 
*  *   ***  *      **    **** **  *      *** **  ***   *  **   ****   ",y);
 *   * ** *  * 







***  **   ** *  ***  * *** * *  0;


}
answered by (-107 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main(){

    int a;
    int b;
    int n;
** ** * **  *** ** ** ** **  first=0;
 * **    **  *********** ***   *  *   * %d",&a,&b);
* ****      ******** ** *  **  * * (n=(a+1);n<b;n++){
 *    *     ******    ** **   *   *   * ** *  **   d;
*  ** ** *  *   *  **  **   *  ** ** * ** ** ** **   * *  *  (d = 2; d < n; d++){
   *   * *  *   ******  **   **   ******   ***  *   *   *** *  *  (n % d == 0)
   *     *    *  *  ****      **  * *   *   **        *********   **  *** ***  * ** * 
* ******   * *   *** *  * * * ** * **     * *
   * * * ** **    *  **  **    ****   *   *    **  * (d < n)
* *    *  **  ****  * * *** * * * * ***   * *   *****   ** ** *  ***
 **    * *   *  ** * * ***** *  *     * **   **  * *****
 ***  * **    **  *  **  *****  * * ***    ******    ***  * *   * *  * (first==0)
        * *  *** ** * *** ** *   *  *  ******* *  ** * *  ** *   * *** **   * ***     * ***
**** ** *  * ** ***** ** * *  * *** * *    *****   * *** ** *  * ******
  *******  *     * *** **** *     *   **     *     * * **    *   *  *  *  **  * ***      ****  ******* ");
* * * * **  *** ** **   ***      *** * * *** **  * ** *** *       **  
*****   * **** *    *   *  ** * ***   ***  ***  **  **  **  *  *  ** * ** * **    *    * * *  n);
   *    *** ** **  *   **** * * *  ** ***   ***   *
    }
     *   **** *  *** *  ***  0;
}
answered by (52 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
    int d,n,m;
* **** **** * * *  *   * ** ****  *** ** * * * %d",&n,&m);

* * *    ****** ***** *   *****    ***     * * 
***    *  *  **  **   * * * *  ** *** *  * 

 *  *     **  * *  *   *  *  **   * ** **** *      **    ( d = 2;  d < n ; d++)
****         *  * **   * ** *****  ** ** **   **  **  ***** **  
 *** ******  **** * *  *** * ** * *  ******* ** ** *    *******  *     * ****  *   (n % d == 0)
*   ** ** **  *******  * *  ** * ****  *  ** * ** ** ***  ****  *  *  ****        ** **
* * *  ** *  * ** *     *    *** *   *  * * *  

  * *  ** ** **** * *  ***          **** * *********   *    *** *   **  *  *  * **  **** * 
* * * * *    **  *   **    **       * *   *** *  *      *** **  *** * *   * **    * * * **  * ",n);
   * ****  * * * *      * ****  * * ****   *  ** * **  ****  *** * *    ***** ***** **** **

 **   **  *    * * *  0;
}
answered by (-196 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main() {
** **  * *    ** **** ***  *  * a,b,i,j;
*   **** *  *  ** *  ***   ***   ** **   * %d", &a, &b);
  *  *** *  ***   ***   *   **  *** * * **   ** *  {
 * **  *** *  **** **   *   * * *    ** ** *  **   *    *  *  ** *  **  {
* * *  *  **  ** **   * **  ** *  **   **** ** *** ****  *   *  * *  **     *     * ** * ** * *  * * break;
  *** *** ***  * * ***** ***     *  * * **  *      * 
*  *  * * **  **  ****    *  *  ** *   **   *** ***  ****   printf("%d ", i);
  ****    *   ***  * * ***  
}
answered
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
*  ***  * *   *******  **      d,n,m;
   * ** *   *** ***** * *  * *  ** * *  *   *** **** ****   *  ******

 *   ***  **     **  * **** ** *   *   
  * * **      *****  **** ** ***  ** *  *  *   ***  

***  *********      *  *** **  ***   *** ***** *** **  *  * ( d = 2;  d < n && n % d != 0; d++);


  * * **  ***** * * * * * **** * * * * ** * *** *  **   ** ** * *             **
*   * * **  **  ** ** ******** *****      **  * ****    * ***   * **** *  ** * *  **** ** ",n);
*  ** *  *  * ****    * ** ** ****** *  *** *  ** **  ****   ****  * *  * ** **  *        

*****    *  **  * ** **  *      0;
}
answered by (-196 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main(void)

{
    int n,m,i,def=0;

    scanf("%d %d",&n,&m);
*   ** ** **  ***** * * * **** *  * **  ******* *** * * ** **  (n<m)

        { def=0;
**   ** * * *   *    *** *   **     **  *  *** *   *    ** ***  **    *  *
*  *  **    * **  ** * *  ** *  ***  * *  *  * *  **** * ** *   ** *** *  i<=n/2; ++i)
 ***    **     ** *   ** * *  ** *  **  ** **  * ****** ****** * *  **  * *  ** *  *  *** * * *
*   * ****** * *** *   ** ****** *****   * *  *  *** **** **   **** ** * *** * * *  *         * **  * ** ** * * * * ***  **   * * * (n%i==0)
** ** *  *   * *      *  ****  ** *** **  *** *** ** **   ** * ** *** * * *  ** * * * ***   * *   *     ******** **   *     
**    * *** ** **  **  *** * **** * * * * *  ***  ** *       ***** **   ****      ****    *  *  ** *   *     *  * * *      ****  **** 
 *** * * ***     ** * **  * **  * ****   *** ***** * * ******  **  *  ***  ***     * *    * *  * **      **  *  **  **      * ***   **   * * *  
***  * *  *   ***  *  *  **** *        * * * *** **  *     ** * * ** **   ****** * **** ****       *  ** ***** ***    **  * **   ** *****
 ****  * * ****  ********* ** ** ** *****   *   *  ** **  *     *      * ** **     * *       * * *  *** ****
*      ***  **  ****   *    ** *    **     **** * *  *** **  *******  ** 
    **    **  *  ** *  ** **   * ********* *  ***  *** **   *  

*  ****  **** * *   *   *  **  ** ** * **    ** **  **    *** * * ***   * ***** *****  ***   * *    * *    **   * ",n);

        ****  *         * *      * ***  * ** ** *    ***  *  *

   *****     * *    * ****   **  * * *  * **  ******* *  **
       return 0; }
answered by (-304 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
    int n,m,i,j,k,c=0;
    scanf("%d %d",&n,&m);
    for(i=n+1;i<m;i++){
        for(j=2;j<=i;j++){
    **   * ** * **      ******** ** ** *  * *    *** **  ****  * ** ***  * *   **
*    * *  **   *  * * * ***** ** *****  *****    ** *   * * * * *  * **      * * ***    ***** *  **
  ** ** ****** *     **   **    *  **     ** **  * * ** *  *** *    *   ****     *  ** ** * ** *  **  
 * **** *  ** **  **       ** *    *  ****  *  *  *  ****  **  ****** * **  * **   * ** * *  * ***     **  *  *  * 
**   *** * **  **    ***      *  * *   ** ******* *  *  * * **  **     *** ** * ****  **   *** * * *   * **** * *   *  ***     ***     *  **         
* *  **      *  **    ****       *  ** **  ***  ***   * *   ** *  * * * * *    * * ******   ** *   *** ** * *  **  **      ****   *****   *
* *   *  **       ** ***  *****    *  * *     ****** ***  **    ********  ****   *  * * *** *  ****   *  *  *    *     *** *   *  * * * **  * **
 ****  * * ** * * **   *  **  *  * * **** **     *  ***  ******   *  * * *   *  * ***** *   * ** ****  * 
 *  * *  *    *        * * *******  *       **    ****  * * * *  * * **** * *** **   * * *   * *** **    **     * ***** **   
 **  * *  ********   * **   * *****  * * *  * **      ********** * *      *  ***  * * ****   * *    *   ** * ********** * ***          * *** *** **   * * *   %d",i);
****** *  * **  ** * * ****  * **  **     ***  **  * ********  *****   *     * ** **   **      *******
   ***  ***       ***  ** *  *  *   *** *  ** * * * ***** * ** * ***  ***     
*   *   * ** **  ** *   *  *    **  **  ****** **      *  *  **    *  ** *** **   *  * if(k==0){
 **  *        * *  ** ****  * ***    * **  **   *    ** *** *******   ** * * **   *  *   * * * ** * *   ***** ** 
** *   *******  * * *    * *** * *  * **  *   *     *  ** ***  ** * * *  ***
        }
    }
    return 0;
}
answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
 *  *  *  * * * *** * **** *    **** *  %d",&a ,&b );

     * * ** * *  *  ******  **  *** i=a+1;i<b;i++){
* *** ****   ****  * *    **     ** ** * *  ***** ***  j=2;j<=b;j++){
**  * *  *   **   **  *  * ** *   ** ******   *  ****     ****  *** * * **        && i%j==0) break;
   *     **  * **      * **     * *   ****  ***   ****** **  ** ** ***  *  * if(i==j){
 ***** **     **    * *    *   ***   **  *  ** *   * ****   * ** *  ***    *** ** ***  ****    * ***  * ** * ***  * * 
**  *** * * **** * *    * *******  *** *  *** *  **** *   **** *   * ** ********  *   ***    *   ** ** *  ***    * ***** *  ***  * * ***  *  *** *** *  *  *     *   ** *  * 
*** ***  **   *  * * * ** ** *   ****      ** ****   *  * * * **  **** * **   ***   * **   **  *    *  * ***    *** ****   ****    **   **
* ***** * * *  ***   ***  ** * * ***  *      * *   *  * ***     **        * * **  *    ** **  **  * *** **** 
***  * *  * ** * **** * *  ** *** *  **   *** **** *  ** * ** *       ***   *  *** ****  *  * *  *   *    ** printf(" %d",i);
 * **   **   **  *   * ** ****    **   *   ** * **  *     **   ****** * *  **
****   * **  * *   *  * * ***  ***   ***  ********    

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.92
©2016-2025

Related questions

0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 8k views
0 like 0 dislike
93 answers
11-01 Exercise 3: Fibonacci numbers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 9.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users