[Exercise 03] Caesar Cipher Decoder

Question

You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

Answer 1

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#include   *   * * *  ** *
int main(int argc, char *argv[]) {
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** ****  *    *   * *  ** * * letterz;
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** * *    ** **    * **        letterc;
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***   ** ** ****   *  **  * * **  **  **  *  **   *   ****** ** ****   * *    *  **  **     *    **   * *    * 
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***** *  * * * * * **   * *  = letterz + 3;
  ** *  * **  *** ***     **  *  = letterx + 3;
    * **  **** *  **   ****  *** * = letterc + 3;
 * **  *   **********  * ***    *  *  = letterv + 3;
* *   **      *** *** 
** *    **   * * *  ***** **** ** * *  ***   * * ** **    ***   ** *    * * * *
  * * * *  * * 
***** ***   *  ** ******* *   0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output

---

Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.

Answer 2

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*******  * *    *  char     ****
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*  * * * ***  *   b =  ** *
** *** ** ** c = ** ***   
  ** * * * * d =    ****
  * *** ****   * e =  ****  *
**  * *    *** * ** 
**  ** **   a += 3;
 *   ** ****   b += 3;
 ***  *  ***    * c += 3;
 ***  * * **  d += 3;
***  * *  * * ** e += 3;

* **    ***          *
* * *  *  **   *
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   * ***** ** * *   *** * **
  *     * **   *  
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**** **     **  
**       **   * * *** **      0;
}

Comments

Case 0: Correct output